Mathematics MCQ Questions for Class 11
Practice Class 11 Commerce Mathematics MCQ questions with answers, explanations and level-wise revision. Start from Easy levels and move toward Expert practice when your accuracy improves.
Class 11 Commerce Mathematics MCQ questions with answers, chapter wise quiz, topic wise practice, objective questions, exam revision aur answer explanation ke liye ye page banaya gaya hai. Mathematics me formulas, algebra, trigonometry, calculus, geometry, probability aur statistics jaise topics ko level-wise MCQ practice se revise karein.
Class 11 Commerce Mathematics MCQ Questions with Answers
Class 11 Commerce Mathematics ke liye chapter wise MCQ questions, topic wise practice, objective questions, quiz levels, correct answers aur simple explanations ek hi page par available hain. Students board exam revision, school test preparation, daily practice aur concept clarity ke liye yahan se focused practice start kar sakte hain.
Mathematics Chapters for Class 11
Choose a Mathematics chapter to practice focused MCQs with topic-wise revision, answers and explanations for Class 11 Commerce. Chapters include Linear Inequalities, Permutations and Combinations, Relations and Functions, Sets. Topics include algebraic solution of linear inequalities in one variable, Graphical solution of linear inequalities in two variables, Introduction to inequalities, representation on number line, Combinations.
Level Map for Mathematics MCQ Practice
Select a ready level to practice questions in a clean exam-style flow. Each level keeps the subject, class, difficulty and question count clear for faster revision.
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Searchयदि \(\theta\) चतुर्थ चतुर्थांश में है और \(\cos \theta=\frac{8}{17}\), तो \(\tan \theta\) क्या होगा?
Explanation opens after your attempt
C. \(-\frac{15}{8} \)
Concept
In the fourth quadrant, \(\sin \theta\) is negative and \(\cos \theta\) is positive. Hence \(\sin \theta=-\frac{15}{17}\) and \(\tan \theta=-\frac{15}{8}\).
Why this answer is correct
The correct answer is C. \(-\frac{15}{8} \). In the fourth quadrant, \(\sin \theta\) is negative and \(\cos \theta\) is positive. Hence \(\sin \theta=-\frac{15}{17}\) and \(\tan \theta=-\frac{15}{8}\).
Exam Tip
चतुर्थ चतुर्थांश में \(\sin \theta\) ऋणात्मक और \(\cos \theta\) धनात्मक होता है। इसलिए \(\sin \theta=-\frac{15}{17}\) और \(\tan \theta=-\frac{15}{8}\)।
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यदि \(\sin x+\sin^2 x=0\), तो \(0\leq x<2\pi\) में कितने हल हैं?
If \(\sin x+\sin^2 x=0\), how many solutions are there in \(0\leq x<2\pi\)?
Explanation opens after your attempt
A. (3)
Concept
Since (\sin x\(1+\sin x\)=0), \(\sin x=0\) or \(\sin x=-1\). In the given interval, \(x=0,\pi,\frac{3\pi}{2}\).
Why this answer is correct
The correct answer is A. (3). Since (\sin x\(1+\sin x\)=0), \(\sin x=0\) or \(\sin x=-1\). In the given interval, \(x=0,\pi,\frac{3\pi}{2}\).
Exam Tip
(\sin x\(1+\sin x\)=0), इसलिए \(\sin x=0\) या \(\sin x=-1\)। दिए गए अंतराल में \(x=0,\pi,\frac{3\pi}{2}\) मिलते हैं।
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फलन (f(x)=\sin 2x+\sin 4x) का मूल आवर्त क्या है?
What is the fundamental period of (f(x)=\sin 2x+\sin 4x)?
Explanation opens after your attempt
B. \( \pi \)
Concept
The period of \(\sin 2x\) is \(\pi\) and the period of \(\sin 4x\) is \(\frac{\pi}{2}\). Their common fundamental period is \(\pi\).
Why this answer is correct
The correct answer is B. \( \pi \). The period of \(\sin 2x\) is \(\pi\) and the period of \(\sin 4x\) is \(\frac{\pi}{2}\). Their common fundamental period is \(\pi\).
Exam Tip
\(\sin 2x\) का आवर्त \(\pi\) और \(\sin 4x\) का आवर्त \(\frac{\pi}{2}\) है। इनका सामान्य मूल आवर्त \(\pi\) है।
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\(5\sin x-12\cos x\) का अधिकतम मान क्या है?
What is the maximum value of \(5\sin x-12\cos x\)?
Explanation opens after your attempt
A. (13)
Concept
The maximum value of \(a\sin x+b\cos x\) is \(\sqrt{a^2+b^2}\). So (\sqrt{52+(-12)2}=13).
Why this answer is correct
The correct answer is A. (13). The maximum value of \(a\sin x+b\cos x\) is \(\sqrt{a^2+b^2}\). So (\sqrt{52+(-12)2}=13).
Exam Tip
\(a\sin x+b\cos x\) का अधिकतम मान \(\sqrt{a^2+b^2}\) होता है। इसलिए (\sqrt{52+(-12)2}=13) मिलेगा।
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यदि \(\cos x=-\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
If \(\cos x=-\frac{1}{2}\), what are the values of (x) in \(0\leq x<2\pi\)?
Explanation opens after your attempt
B. \( \frac{2\pi}{3},\frac{4\pi}{3} \)
Concept
\(\cos x\) is negative in the second and third quadrants. Hence \(x=\frac{2\pi}{3},\frac{4\pi}{3}\).
Why this answer is correct
The correct answer is B. \( \frac{2\pi}{3},\frac{4\pi}{3} \). \(\cos x\) is negative in the second and third quadrants. Hence \(x=\frac{2\pi}{3},\frac{4\pi}{3}\).
Exam Tip
\(\cos x\) द्वितीय और तृतीय चतुर्थांश में ऋणात्मक होता है। इसलिए \(x=\frac{2\pi}{3},\frac{4\pi}{3}\)।
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यदि \(\sin x=\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
If \(\sin x=\frac{1}{2}\), what are the values of (x) in \(0\leq x<2\pi\)?
Explanation opens after your attempt
A. \( \frac{\pi}{6},\frac{5\pi}{6} \)
Concept
\(\sin x\) is positive in the first and second quadrants. Hence \(x=\frac{\pi}{6},\frac{5\pi}{6}\).
Why this answer is correct
The correct answer is A. \( \frac{\pi}{6},\frac{5\pi}{6} \). \(\sin x\) is positive in the first and second quadrants. Hence \(x=\frac{\pi}{6},\frac{5\pi}{6}\).
Exam Tip
\(\sin x\) प्रथम और द्वितीय चतुर्थांश में धनात्मक है। इसलिए \(x=\frac{\pi}{6},\frac{5\pi}{6}\)।
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\(\cos 3x\) का सही विस्तार कौन-सा है?
Which is the correct expansion of \(\cos 3x\)?
Explanation opens after your attempt
C. \(4\cos^3 x-3\cos x\)
Concept
The triple angle formula is \(\cos 3x=4\cos^3 x-3\cos x\). In exams, do not confuse it with \(\sin 3x\).
Why this answer is correct
The correct answer is C. \(4\cos^3 x-3\cos x\). The triple angle formula is \(\cos 3x=4\cos^3 x-3\cos x\). In exams, do not confuse it with \(\sin 3x\).
Exam Tip
त्रिगुण कोण सूत्र \(\cos 3x=4\cos^3 x-3\cos x\) है। परीक्षा में इसे \(\sin 3x\) से confuse न करें।
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\(\sin 3x\) का सही विस्तार कौन-सा है?
Which is the correct expansion of \(\sin 3x\)?
Explanation opens after your attempt
B. \(3\sin x-4\sin^3 x\)
Concept
The triple angle formula is \(\sin 3x=3\sin x-4\sin^3 x\). In exams, avoid sign mistakes.
Why this answer is correct
The correct answer is B. \(3\sin x-4\sin^3 x\). The triple angle formula is \(\sin 3x=3\sin x-4\sin^3 x\). In exams, avoid sign mistakes.
Exam Tip
त्रिगुण कोण सूत्र \(\sin 3x=3\sin x-4\sin^3 x\) है। परीक्षा में sign की गलती न करें।
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यदि (x) तृतीय चतुर्थांश में है और \(\tan x=\frac{4}{3}\), तो \(\sin x\) क्या है?
If (x) lies in the third quadrant and \(\tan x=\frac{4}{3}\), what is \(\sin x\)?
Explanation opens after your attempt
A. \(-\frac{4}{5} \)
Concept
In the third quadrant, both \(\sin x\) and \(\cos x\) are negative, while \(\tan x\) is positive. Hence \(\sin x=-\frac{4}{5}\).
Why this answer is correct
The correct answer is A. \(-\frac{4}{5} \). In the third quadrant, both \(\sin x\) and \(\cos x\) are negative, while \(\tan x\) is positive. Hence \(\sin x=-\frac{4}{5}\).
Exam Tip
तृतीय चतुर्थांश में \(\sin x\) और \(\cos x\) दोनों ऋणात्मक होते हैं, पर \(\tan x\) धनात्मक होता है। इसलिए \(\sin x=-\frac{4}{5}\)।
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यदि (x) द्वितीय चतुर्थांश में है और \(\sin x=\frac{5}{13}\), तो \(\cos x\) क्या होगा?
If (x) is in the second quadrant and \(\sin x=\frac{5}{13}\), what will \(\cos x\) be?
Explanation opens after your attempt
D. \(-\frac{12}{13} \)
Concept
In the second quadrant, \(\cos x\) is negative. From \(\sin^2 x+\cos^2 x=1\), \(\cos x=-\frac{12}{13}\).
Why this answer is correct
The correct answer is D. \(-\frac{12}{13} \). In the second quadrant, \(\cos x\) is negative. From \(\sin^2 x+\cos^2 x=1\), \(\cos x=-\frac{12}{13}\).
Exam Tip
द्वितीय चतुर्थांश में \(\cos x\) ऋणात्मक होता है। \(\sin^2 x+\cos^2 x=1\) से \(\cos x=-\frac{12}{13}\)।
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फलन (f(x)=\cos 4x) का आवर्त क्या है?
What is the period of (f(x)=\cos 4x)?
Explanation opens after your attempt
C. \( \frac{\pi}{2} \)
Concept
The period of \(\cos ax\) is \( \frac{2\pi}{|a|} \). Hence the period of \(\cos 4x\) is \( \frac{\pi}{2} \).
Why this answer is correct
The correct answer is C. \( \frac{\pi}{2} \). The period of \(\cos ax\) is \( \frac{2\pi}{|a|} \). Hence the period of \(\cos 4x\) is \( \frac{\pi}{2} \).
Exam Tip
\(\cos ax\) का आवर्त \( \frac{2\pi}{|a|} \) होता है। इसलिए \(\cos 4x\) का आवर्त \( \frac{\pi}{2} \) है।
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फलन (f(x)=\tan 3x) का मूल आवर्त क्या है?
What is the fundamental period of (f(x)=\tan 3x)?
Explanation opens after your attempt
B. \( \frac{\pi}{3} \)
Concept
The period of \(\tan ax\) is \( \frac{\pi}{|a|} \). Here (a=3), so the period is \( \frac{\pi}{3} \).
Why this answer is correct
The correct answer is B. \( \frac{\pi}{3} \). The period of \(\tan ax\) is \( \frac{\pi}{|a|} \). Here (a=3), so the period is \( \frac{\pi}{3} \).
Exam Tip
\(\tan ax\) का आवर्त \( \frac{\pi}{|a|} \) होता है। यहाँ (a=3), इसलिए आवर्त \( \frac{\pi}{3} \) है।
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More Mathematics Practice
Class 11 Commerce Mathematics FAQs
How many Mathematics questions are in each level?
Each ready level is designed for 50 active questions for the selected class, subject and difficulty.
Which difficulty levels are available for Mathematics?
Students can practice Easy, Medium, Hard and Expert levels according to their preparation stage.
Are answers and explanations available?
Yes, question pages include answer reveal, correct option, explanation, related questions and share options.
