यदि (n=4), तो (\frac{(n+2)!}{n!}) का मान क्या है?
If (n=4), what is the value of (\frac{(n+2)!}{n!})?
#factorial_notation
#permutations_combinations
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#medium
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A (20)
B (24)
C (30)
D (36)
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Explanation
Simple Explanation
(n=4) रखने पर \(\frac{6!}{4!}=6\times5=30\)। पहले चर का मान रखकर फैक्टोरियल अनुपात सरल करें। / Putting (n=4), \(\frac{6!}{4!}=6\times5=30\). Substitute the variable first and simplify the factorial ratio.
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\(\frac{8!-7!}{6!}\) का मान क्या है?
What is the value of \(\frac{8!-7!}{6!}\)?
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#permutations_combinations
#class_11
#medium
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A (42)
B (48)
C (56)
D (49)
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Explanation
Simple Explanation
अंश (7!(8-1)=7\cdot7!) है। \(\frac{7\cdot7!}{6!}=7\times7=49\) मिलेगा। / The numerator is (7!(8-1)=7\cdot7!). Thus \(\frac{7\cdot7!}{6!}=7\times7=49\).
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यदि (\frac{n!}{(n-2)!}=56), तो (n) का मान क्या है?
If (\frac{n!}{(n-2)!}=56), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (7)
B (8)
C (9)
D (10)
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Explanation
Simple Explanation
(\frac{n!}{(n-2)!}=n(n-1))। \(8\times7=56\), इसलिए (n=8) है। / (\frac{n!}{(n-2)!}=n(n-1)). Since \(8\times7=56\), (n=8).
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\(\frac{6!+5!}{4!}\) का मान क्या है?
What is the value of \(\frac{6!+5!}{4!}\)?
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#permutations_combinations
#class_11
#medium
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A (25)
B (30)
C (32)
D (35)
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Explanation
Simple Explanation
अंश (720+120=840) है और (4!=24)। इसलिए मान \(\frac{840}{24}=35\) है। / The numerator is (720+120=840) and (4!=24). Therefore the value is \(\frac{840}{24}=35\).
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\(\frac{9!}{6!}-\frac{7!}{5!}\) का मान क्या है?
What is the value of \(\frac{9!}{6!}-\frac{7!}{5!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (462)
B (480)
C (504)
D (546)
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Explanation
Simple Explanation
\(\frac{9!}{6!}=504\) और \(\frac{7!}{5!}=42\), इसलिए अंतर (462) है। दोनों अनुपात अलग-अलग सरल करें। / \(\frac{9!}{6!}=504\) and \(\frac{7!}{5!}=42\), so the difference is (462). Simplify both ratios separately.
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(\frac{(n+3)!}{(n+1)!}+\frac{(n+2)!}{n!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+3)!}{(n+1)!}+\frac{(n+2)!}{n!})?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A ((n+2)2 )
B (2(n+2)2 )
C (2n+4)
D ((n+3)(n+1))
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Correct Answer
B. (2(n+2)2 )
Explanation
Simple Explanation
पहला पद ((n+3)(n+2)) और दूसरा ((n+2)(n+1)) है। समान ((n+2)) लेने पर (2(n+2)2 ) मिलता है। / The first term is ((n+3)(n+2)) and the second is ((n+2)(n+1)). Taking common ((n+2)) gives (2(n+2)2 ).
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यदि (\frac{(n+2)!}{n!}=42), तो (n) का मान क्या है?
If (\frac{(n+2)!}{n!}=42), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (3)
B (4)
C (5)
D (6)
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Explanation
Simple Explanation
(\frac{(n+2)!}{n!}=(n+2)(n+1))। \(7\times6=42\), इसलिए (n=5) है। / (\frac{(n+2)!}{n!}=(n+2)(n+1)). Since \(7\times6=42\), (n=5).
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\(\frac{12!}{10!,2!}+\frac{8!}{6!,2!}\) का मान क्या है?
What is the value of \(\frac{12!}{10!,2!}+\frac{8!}{6!,2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (84)
B (88)
C (90)
D (94)
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Explanation
Simple Explanation
पहला पद (66) और दूसरा पद (28) है। दोनों को जोड़ने पर (94) मिलता है। / The first term is (66) and the second term is (28). Adding them gives (94).
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(\frac{(n+1)!-n!}{(n-1)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+1)!-n!}{(n-1)!})?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A \(n^2\)
B (n+1)
C (n(n+1))
D (2n)
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Correct Answer
A. \(n^2\)
Explanation
Simple Explanation
((n+1)!-n!=n!{(n+1)-1}=n\cdot n!)। ((n-1)!) से भाग देने पर \(n^2\) मिलता है। / ((n+1)!-n!=n!{(n+1)-1}=n\cdot n!). Dividing by ((n-1)!) gives \(n^2\).
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\(\frac{7!}{4!,3!}\times3!\) का मान क्या है?
What is the value of \(\frac{7!}{4!,3!}\times3!\)?
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#permutations_combinations
#class_11
#medium
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A (105)
B (140)
C (210)
D (240)
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Explanation
Simple Explanation
\(\frac{7!}{4!,3!}=35\) और (3!=6)। इसलिए गुणनफल \(35\times6=210\) है। / \(\frac{7!}{4!,3!}=35\) and (3!=6). Therefore the product is \(35\times6=210\).
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यदि \(x=\frac{8!}{6!}\) और \(y=\frac{5!}{3!}\), तो (x+y) का मान क्या है?
If \(x=\frac{8!}{6!}\) and \(y=\frac{5!}{3!}\), what is the value of (x+y)?
#factorial_notation
#permutations_combinations
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A (66)
B (72)
C (76)
D (80)
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Explanation
Simple Explanation
\(x=8\times7=56\) और \(y=5\times4=20\)। इसलिए (x+y=76) है। / \(x=8\times7=56\) and \(y=5\times4=20\). Therefore (x+y=76).
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(\frac{(n+5)!}{(n+3)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+5)!}{(n+3)!})?
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#permutations_combinations
#class_11
#medium
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A ((n+5)(n+4))
B ((n+5)(n+3))
C ((n+4)(n+3))
D (n+5)
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Correct Answer
A. ((n+5)(n+4))
Explanation
Simple Explanation
((n+5)!=(n+5)(n+4)(n+3)!)। इसलिए सरल रूप ((n+5)(n+4)) है। / ((n+5)!=(n+5)(n+4)(n+3)!). Therefore the simplified form is ((n+5)(n+4)).
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\(\frac{11!-10!}{9!}\) का मान क्या है?
What is the value of \(\frac{11!-10!}{9!}\)?
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#permutations_combinations
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A (90)
B (99)
C (100)
D (110)
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Explanation
Simple Explanation
अंश (10!(11-1)=10\cdot10!) है। \(\frac{10\cdot10!}{9!}=10\times10=100\) है। / The numerator is (10!(11-1)=10\cdot10!). Thus \(\frac{10\cdot10!}{9!}=10\times10=100\).
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\(\frac{9!}{7!}\div\frac{6!}{5!}\) का मान क्या है?
What is the value of \(\frac{9!}{7!}\div\frac{6!}{5!}\)?
#factorial_notation
#permutations_combinations
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#medium
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A (10)
B (12)
C (14)
D (18)
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Explanation
Simple Explanation
\(\frac{9!}{7!}=72\) और \(\frac{6!}{5!}=6\)। इसलिए भागफल (12) है। / \(\frac{9!}{7!}=72\) and \(\frac{6!}{5!}=6\). Therefore the quotient is (12).
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यदि (\frac{(n+1)!}{(n-1)!}=72), तो (n) का मान क्या है?
If (\frac{(n+1)!}{(n-1)!}=72), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (6)
B (7)
C (8)
D (9)
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Explanation
Simple Explanation
अनुपात (n(n+1)) के बराबर है। \(8\times9=72\), इसलिए (n=8) है। / The ratio equals (n(n+1)). Since \(8\times9=72\), (n=8).
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\(\frac{5!,3!}{2!,4!}\) का मान क्या है?
What is the value of \(\frac{5!,3!}{2!,4!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (10)
B (12)
C (15)
D (18)
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Explanation
Simple Explanation
\(\frac{5!}{4!}=5\) और \(\frac{3!}{2!}=3\)। इसलिए मान \(5\times3=15\) है। / \(\frac{5!}{4!}=5\) and \(\frac{3!}{2!}=3\). Hence the value is \(5\times3=15\).
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\(\frac{8!}{5!}+\frac{6!}{4!}-4!\) का मान क्या है?
What is the value of \(\frac{8!}{5!}+\frac{6!}{4!}-4!\)?
#factorial_notation
#permutations_combinations
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A (318)
B (330)
C (336)
D (342)
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Explanation
Simple Explanation
\(\frac{8!}{5!}=336\), \(\frac{6!}{4!}=30\) और (4!=24)। इसलिए (336+30-24=342) है। / \(\frac{8!}{5!}=336\), \(\frac{6!}{4!}=30\), and (4!=24). Thus (336+30-24=342).
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(\frac{(n+5)!}{(n+2)!}) में कितने क्रमागत गुणक बचते हैं?
How many consecutive factors remain in (\frac{(n+5)!}{(n+2)!})?
#factorial_notation
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A (2)
B (3)
C (4)
D (5)
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Explanation
Simple Explanation
(\frac{(n+5)!}{(n+2)!}=(n+5)(n+4)(n+3))। इसलिए तीन क्रमागत गुणक बचते हैं। / (\frac{(n+5)!}{(n+2)!}=(n+5)(n+4)(n+3)). Therefore three consecutive factors remain.
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यदि (\frac{(n+3)!}{(n+1)!}=90), तो (n) का मान क्या है?
If (\frac{(n+3)!}{(n+1)!}=90), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (6)
B (7)
C (8)
D (9)
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Explanation
Simple Explanation
(\frac{(n+3)!}{(n+1)!}=(n+3)(n+2))। \(10\times9=90\), इसलिए (n=7) है। / (\frac{(n+3)!}{(n+1)!}=(n+3)(n+2)). Since \(10\times9=90\), (n=7).
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\(\frac{13!}{11!,2!}-\frac{6!}{4!,2!}\) का मान क्या है?
What is the value of \(\frac{13!}{11!,2!}-\frac{6!}{4!,2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (55)
B (60)
C (63)
D (70)
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Explanation
Simple Explanation
पहला पद (78) और दूसरा पद (15) है। अंतर (78-15=63) है। / The first term is (78) and the second term is (15). The difference is (78-15=63).
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(\frac{(n+2)!-n!}{n!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+2)!-n!}{n!})?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A \(n^2+2n\)
B \(n^2+3n+1\)
C \(n^2+n-1\)
D (2n+1)
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Correct Answer
B. \(n^2+3n+1\)
Explanation
Simple Explanation
(\frac{(n+2)!}{n!}=(n+2)(n+1)), फिर (1) घटेगा। सरल रूप \(n^2+3n+1\) है। / (\frac{(n+2)!}{n!}=(n+2)(n+1)), then (1) is subtracted. The simplified form is \(n^2+3n+1\).
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\(\frac{10!}{8!}+\frac{7!}{6!}+0!\) का मान क्या है?
What is the value of \(\frac{10!}{8!}+\frac{7!}{6!}+0!\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (96)
B (97)
C (98)
D (99)
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Explanation
Simple Explanation
\(\frac{10!}{8!}=90\), \(\frac{7!}{6!}=7\) और (0!=1)। कुल (98) है। / \(\frac{10!}{8!}=90\), \(\frac{7!}{6!}=7\), and (0!=1). The total is (98).
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\(\frac{n!}{(n-1)!}\times\frac{(n+1)!}{n!}\) का सरल रूप क्या है?
What is the simplified form of \(\frac{n!}{(n-1)!}\times\frac{(n+1)!}{n!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (n+1)
B \(n^2\)
C (n(n+1))
D ((n-1)(n+1))
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Correct Answer
C. (n(n+1))
Explanation
Simple Explanation
पहला अनुपात (n) और दूसरा (n+1) है। इसलिए गुणनफल (n(n+1)) है। / The first ratio is (n) and the second is (n+1). Therefore the product is (n(n+1)).
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यदि (\frac{n!}{(n-3)!}=210), तो (n) का मान क्या है?
If (\frac{n!}{(n-3)!}=210), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (6)
B (7)
C (8)
D (9)
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Explanation
Simple Explanation
(\frac{n!}{(n-3)!}=n(n-1)(n-2))। \(7\times6\times5=210\), इसलिए (n=7) है। / (\frac{n!}{(n-3)!}=n(n-1)(n-2)). Since \(7\times6\times5=210\), (n=7).
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\(\frac{9!+8!}{7!}\) का मान क्या है?
What is the value of \(\frac{9!+8!}{7!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (72)
B (80)
C (88)
D (96)
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Explanation
Simple Explanation
अंश को (8!(9+1)) लिखा जा सकता है। \(\frac{10\cdot8!}{7!}=10\times8=80\) है। / The numerator can be written as (8!(9+1)). Thus \(\frac{10\cdot8!}{7!}=10\times8=80\).
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\(\frac{6!}{3!,3!}+\frac{7!}{5!,2!}\) का मान क्या है?
What is the value of \(\frac{6!}{3!,3!}+\frac{7!}{5!,2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (35)
B (39)
C (41)
D (45)
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Explanation
Simple Explanation
पहला पद (20) और दूसरा (21) है। दोनों का योग (41) होगा। / The first term is (20) and the second is (21). Their sum is (41).
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(\frac{\frac{(n+4)!}{n!}}{\frac{(n+2)!}{n!}}) का सरल रूप क्या है?
What is the simplified form of (\frac{\frac{(n+4)!}{n!}}{\frac{(n+2)!}{n!}})?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (n+4)
B ((n+4)(n+3))
C ((n+2)(n+1))
D \(\frac{n+4}{n+2}\)
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Correct Answer
B. ((n+4)(n+3))
Explanation
Simple Explanation
यह भाग (\frac{(n+4)!}{(n+2)!}) बन जाता है। इसलिए सरल रूप ((n+4)(n+3)) है। / This division becomes (\frac{(n+4)!}{(n+2)!}). Hence the simplified form is ((n+4)(n+3)).
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यदि \(a=\frac{7!-5!}{5!}\), तो (a) का मान क्या है?
If \(a=\frac{7!-5!}{5!}\), what is the value of (a)?
#factorial_notation
#permutations_combinations
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#medium
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A (40)
B (41)
C (42)
D (43)
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Explanation
Simple Explanation
\(\frac{7!}{5!}=42\) और \(\frac{5!}{5!}=1\)। इसलिए (a=42-1=41) है। / \(\frac{7!}{5!}=42\) and \(\frac{5!}{5!}=1\). Therefore (a=42-1=41).
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यदि (\frac{(n+1)!}{(n-2)!}=60), तो (n) का मान क्या है?
If (\frac{(n+1)!}{(n-2)!}=60), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (3)
B (4)
C (5)
D (6)
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Explanation
Simple Explanation
(\frac{(n+1)!}{(n-2)!}=(n+1)n(n-1))। \(5\times4\times3=60\), इसलिए (n=4) है। / (\frac{(n+1)!}{(n-2)!}=(n+1)n(n-1)). Since \(5\times4\times3=60\), (n=4).
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\(\frac{\frac{12!}{9!,3!}}{\frac{5!}{3!,2!}}\) का मान क्या है?
What is the value of \(\frac{\frac{12!}{9!,3!}}{\frac{5!}{3!,2!}}\)?
#factorial_notation
#permutations_combinations
#class_11
#medium
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A (18)
B (20)
C (22)
D (24)
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Explanation
Simple Explanation
ऊपर का पद (220) और नीचे का पद (10) है। भाग देने पर (22) मिलता है। / The numerator term is (220) and the denominator term is (10). Dividing gives (22).
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(\frac{(n+3)!+(n+2)!}{(n+2)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+3)!+(n+2)!}{(n+2)!})?
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#permutations_combinations
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A (n+2)
B (n+3)
C (n+4)
D (2n+5)
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Explanation
Simple Explanation
अंश ((n+2)![(n+3)+1]) है। इसलिए सरल रूप (n+4) है। / The numerator is ((n+2)![(n+3)+1]). Therefore the simplified form is (n+4).
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\(\frac{10!-8!}{8!}\) का मान क्या है?
What is the value of \(\frac{10!-8!}{8!}\)?
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A (80)
B (88)
C (89)
D (90)
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Explanation
Simple Explanation
\(\frac{10!}{8!}=90\) और \(\frac{8!}{8!}=1\)। इसलिए मान (90-1=89) है। / \(\frac{10!}{8!}=90\) and \(\frac{8!}{8!}=1\). Therefore the value is (90-1=89).
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\(4!\times\frac{6!}{5!}-3!\) का मान क्या है?
What is the value of \(4!\times\frac{6!}{5!}-3!\)?
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A (126)
B (132)
C (138)
D (144)
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Explanation
Simple Explanation
(4!=24), \(\frac{6!}{5!}=6\) और (3!=6)। इसलिए \(24\times6-6=138\) है। / (4!=24), \(\frac{6!}{5!}=6\), and (3!=6). Hence \(24\times6-6=138\).
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\(\frac{11!}{8!,3!}-\frac{9!}{7!,2!}\) का मान क्या है?
What is the value of \(\frac{11!}{8!,3!}-\frac{9!}{7!,2!}\)?
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A (120)
B (126)
C (129)
D (132)
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Explanation
Simple Explanation
पहला पद (165) और दूसरा (36) है। अंतर (129) मिलेगा। / The first term is (165) and the second is (36). The difference is (129).
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(\frac{(n+5)!}{(n+2)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+5)!}{(n+2)!})?
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A ((n+5)(n+4))
B ((n+5)(n+4)(n+3))
C ((n+4)(n+3)(n+2))
D (n+5)
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Correct Answer
B. ((n+5)(n+4)(n+3))
Explanation
Simple Explanation
((n+5)!=(n+5)(n+4)(n+3)(n+2)!)। इसलिए तीन गुणक बचते हैं। / ((n+5)!=(n+5)(n+4)(n+3)(n+2)!). Therefore three factors remain.
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यदि (\frac{(n+4)!}{(n+2)!}=132), तो (n) का मान क्या है?
If (\frac{(n+4)!}{(n+2)!}=132), what is the value of (n)?
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A (7)
B (8)
C (9)
D (10)
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Explanation
Simple Explanation
(\frac{(n+4)!}{(n+2)!}=(n+4)(n+3))। \(12\times11=132\), इसलिए (n=8) है। / (\frac{(n+4)!}{(n+2)!}=(n+4)(n+3)). Since \(12\times11=132\), (n=8).
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\(\frac{7!}{5!}+\frac{5!}{2!,3!}+1!\) का मान क्या है?
What is the value of \(\frac{7!}{5!}+\frac{5!}{2!,3!}+1!\)?
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A (51)
B (52)
C (53)
D (54)
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Explanation
Simple Explanation
\(\frac{7!}{5!}=42\), \(\frac{5!}{2!,3!}=10\) और (1!=1)। कुल (53) है। / \(\frac{7!}{5!}=42\), \(\frac{5!}{2!,3!}=10\), and (1!=1). The total is (53).
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\(\frac{(n+2)!}{(n+1)!}\times\frac{(n+1)!}{n!}\) का सरल रूप क्या है?
What is the simplified form of \(\frac{(n+2)!}{(n+1)!}\times\frac{(n+1)!}{n!}\)?
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A (n+2)
B ((n+2)(n+1))
C (n(n+2))
D ((n+1)2 )
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Correct Answer
B. ((n+2)(n+1))
Explanation
Simple Explanation
पहला अनुपात (n+2) और दूसरा (n+1) है। गुणनफल ((n+2)(n+1)) होगा। / The first ratio is (n+2) and the second is (n+1). The product is ((n+2)(n+1)).
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\(\frac{8!,3!}{6!,2!}\) का मान क्या है?
What is the value of \(\frac{8!,3!}{6!,2!}\)?
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A (112)
B (140)
C (168)
D (196)
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Explanation
Simple Explanation
\(\frac{8!}{6!}=56\) और \(\frac{3!}{2!}=3\)। इसलिए मान \(56\times3=168\) है। / \(\frac{8!}{6!}=56\) and \(\frac{3!}{2!}=3\). Therefore the value is \(56\times3=168\).
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\(\frac{9!-7!}{7!}\) का मान क्या है?
What is the value of \(\frac{9!-7!}{7!}\)?
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A (63)
B (70)
C (71)
D (72)
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Explanation
Simple Explanation
\(\frac{9!}{7!}=72\) और \(\frac{7!}{7!}=1\)। इसलिए (72-1=71) है। / \(\frac{9!}{7!}=72\) and \(\frac{7!}{7!}=1\). Hence (72-1=71).
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(\frac{n!+(n-1)!}{(n-1)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{n!+(n-1)!}{(n-1)!})?
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A (n)
B (n+1)
C (n-1)
D (2n)
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Explanation
Simple Explanation
(n!=n(n-1)!), इसलिए अंश ((n-1)!(n+1)) है। भाग देने पर (n+1) मिलेगा। / Since (n!=n(n-1)!), the numerator is ((n-1)!(n+1)). Dividing gives (n+1).
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यदि (n=5), तो (\frac{(n+3)!}{(n+1)!}-\frac{(n+1)!}{n!}) का मान क्या है?
If (n=5), what is the value of (\frac{(n+3)!}{(n+1)!}-\frac{(n+1)!}{n!})?
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A (44)
B (48)
C (50)
D (56)
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Explanation
Simple Explanation
(n=5) पर पहला पद \(\frac{8!}{6!}=56\) और दूसरा \(\frac{6!}{5!}=6\) है। अंतर (50) है। / For (n=5), the first term is \(\frac{8!}{6!}=56\) and the second is \(\frac{6!}{5!}=6\). The difference is (50).
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\(\frac{6!}{2!,4!}\times\frac{4!}{3!}\) का मान क्या है?
What is the value of \(\frac{6!}{2!,4!}\times\frac{4!}{3!}\)?
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A (45)
B (50)
C (55)
D (60)
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Explanation
Simple Explanation
पहला पद (15) और दूसरा (4) है। गुणनफल \(15\times4=60\) है। / The first term is (15) and the second is (4). The product is \(15\times4=60\).
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\(\frac{14!}{12!}-\frac{13!}{11!}\) का मान क्या है?
What is the value of \(\frac{14!}{12!}-\frac{13!}{11!}\)?
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A (24)
B (26)
C (28)
D (30)
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Explanation
Simple Explanation
\(\frac{14!}{12!}=14\times13=182\) और \(\frac{13!}{11!}=13\times12=156\)। अंतर (26) है। / \(\frac{14!}{12!}=14\times13=182\) and \(\frac{13!}{11!}=13\times12=156\). The difference is (26).
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यदि (\frac{(n+2)!-(n+1)!}{n!}=36), तो (n) का मान क्या है?
If (\frac{(n+2)!-(n+1)!}{n!}=36), what is the value of (n)?
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A (4)
B (5)
C (6)
D (7)
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Explanation
Simple Explanation
सरल रूप ((n+1)2 ) है। ((n+1)2 =36) से (n+1=6) और (n=5) है। / The simplified form is ((n+1)2 ). From ((n+1)2 =36), (n+1=6) and (n=5).
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(\frac{\frac{(n+3)!}{n!}}{\frac{(n+2)!}{n!}}) का सरल रूप क्या है?
What is the simplified form of (\frac{\frac{(n+3)!}{n!}}{\frac{(n+2)!}{n!}})?
#factorial_notation
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A (n+1)
B (n+2)
C (n+3)
D \(\frac{n+3}{n+2}\)
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Explanation
Simple Explanation
भिन्न को सरल करने पर (\frac{(n+3)!}{(n+2)!}) मिलता है। इसका मान (n+3) है। / Simplifying the fraction gives (\frac{(n+3)!}{(n+2)!}). Its value is (n+3).
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\(\frac{10!}{6!,4!}+\frac{10!}{7!,3!}\) का मान क्या है?
What is the value of \(\frac{10!}{6!,4!}+\frac{10!}{7!,3!}\)?
#factorial_notation
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A (300)
B (310)
C (320)
D (330)
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Explanation
Simple Explanation
पहला पद (210) और दूसरा पद (120) है। दोनों का योग (330) है। / The first term is (210) and the second term is (120). Their sum is (330).
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\(\frac{15!-12!}{12!}\) का मान क्या है?
What is the value of \(\frac{15!-12!}{12!}\)?
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A (2728)
B (2729)
C (2730)
D (2731)
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Explanation
Simple Explanation
\(\frac{15!}{12!}=15\times14\times13=2730\) और \(\frac{12!}{12!}=1\)। इसलिए मान (2730-1=2729) है। / \(\frac{15!}{12!}=15\times14\times13=2730\) and \(\frac{12!}{12!}=1\). Therefore the value is (2730-1=2729).
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यदि (\frac{(n+4)!}{(n+1)!}=504), तो (n) का मान क्या है?
If (\frac{(n+4)!}{(n+1)!}=504), what is the value of (n)?
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A (4)
B (5)
C (6)
D (7)
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Explanation
Simple Explanation
(\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2))। \(9\times8\times7=504\), इसलिए (n=5) है। / (\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2)). Since \(9\times8\times7=504\), (n=5).
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(\frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+4)!}{(n+2)!}-\frac{(n+3)!}{(n+1)!})?
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A (2(n+3))
B (n+3)
C (2n+4)
D ((n+3)2 )
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Correct Answer
A. (2(n+3))
Explanation
Simple Explanation
पहला पद ((n+4)(n+3)) और दूसरा ((n+3)(n+2)) है। अंतर लेने पर (2(n+3)) मिलता है। / The first term is ((n+4)(n+3)) and the second is ((n+3)(n+2)). Taking the difference gives (2(n+3)).
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