Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 1-10 of 584 questions.
What is the solution of the inequality (x+5>12)?
A. (x>7)
दोनों पक्षों से (5) घटाने पर (x>7) मिलता है। परीक्षा में समान संख्या दोनों पक्षों पर लगाएं। / Subtracting (5) from both sides gives (x>7). In exams, apply the same operation on both sides.
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What is the solution of the inequality \(x-4\le 9\)?
A. \(x\le 13\)
दोनों पक्षों में (4) जोड़ने पर \(x\le 13\) मिलता है। चिह्न नहीं बदलता क्योंकि जोड़ किया गया है। / Adding (4) to both sides gives \(x\le 13\). The sign does not change because addition is used.
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What is the solution of the inequality \(5x+2\ge 17\)?
A. \(x\ge 3\)
पहले (2) घटाएं और फिर (5) से भाग दें, तब \(x\ge 3\)। बराबरी वाला चिह्न अंत तक बनाए रखें। / First subtract (2), then divide by (5), giving \(x\ge 3\). Keep the equality part of the sign till the end.
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What is the solution of the inequality (4x-7<9)?
A. (x<4)
दोनों पक्षों में (7) जोड़कर (4x<16), इसलिए (x<4)। पहले स्थिर पद हटाना आसान रहता है। / Adding (7) to both sides gives (4x<16), so (x<4). Removing the constant term first is easier.
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What is the solution of the inequality \(7-2x\le 1\)?
A. \(x\ge 3\)
(7) घटाने पर \(-2x\le -6\), फिर (-2) से भाग देने पर चिह्न पलटकर \(x\ge 3\) होता है। ऋणात्मक गुणांक पर विशेष ध्यान दें। / Subtracting (7) gives \(-2x\le -6\), then division by (-2) reverses the sign to \(x\ge 3\). Be careful with a negative coefficient.
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What is the solution of the inequality (2x+3<x+8)?
A. (x<5)
दोनों पक्षों से (x) और (3) हटाने पर (x<5) मिलता है। चर पदों को एक तरफ रखें। / Removing (x) and (3) from both sides gives (x<5). Keep variable terms on one side.
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What is the solution of the inequality \(6x-1\ge 2x+11\)?
A. \(x\ge 3\)
(2x) घटाने और (1) जोड़ने पर \(4x\ge 12\), इसलिए \(x\ge 3\)। समान पदों को सावधानी से मिलाएं। / Subtracting (2x) and adding (1) gives \(4x\ge 12\), so \(x\ge 3\). Combine like terms carefully.
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What is the solution of the inequality (3(x+2)>15)?
A. (x>3)
(3) से भाग देने पर (x+2>5), इसलिए (x>3)। कोष्ठक खोलना या पहले भाग देना दोनों ठीक हैं। / Dividing by (3) gives (x+2>5), so (x>3). You may open brackets or divide first.
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What is the solution of the inequality \(\frac{x-1}{4}\ge 2\)?
A. \(x\ge 9\)
दोनों पक्षों को (4) से गुणा करने पर \(x-1\ge 8\), इसलिए \(x\ge 9\)। धनात्मक हर चिह्न नहीं बदलता। / Multiplying both sides by (4) gives \(x-1\ge 8\), so \(x\ge 9\). A positive denominator does not change the sign.
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What is the solution of the inequality \(\frac{2x+1}{5}\le 3\)?
A. \(x\le 7\)
(5) से गुणा करने पर \(2x+1\le 15\), इसलिए \(x\le 7\)। पहले भिन्न हटाना अच्छा तरीका है। / Multiplying by (5) gives \(2x+1\le 15\), so \(x\le 7\). Removing the fraction first is a good method.
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