Class 10 easy MCQ Questions

Question 1/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

समांतर श्रेणी $22,25,28,\ldots$ के पहले (14) पदों का योग ज्ञात कीजिए।

Find the sum of the first (14) terms of the arithmetic progression $22,25,28,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (581)

Step 1

Concept

The fourteenth term is (61), so (S_{14}=\frac{14}{2}(22+61)=581). Correct calculation of the last term gives the correct sum.

Step 2

Why this answer is correct

The correct answer is B. (581). The fourteenth term is (61), so (S_{14}=\frac{14}{2}(22+61)=581). Correct calculation of the last term gives the correct sum.

Step 3

Exam Tip

चौदहवाँ पद (61) है, इसलिए (S_{14}=\frac{14}{2}(22+61)=581)। अंतिम पद की सही गणना से योग सही मिलता है।

Open Question Page

Question 2/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (16) विषम प्राकृतिक संख्याओं का योग कितना है?

What is the sum of the first (16) odd natural numbers?

Explanation opens after your attempt

Correct Answer

B. (256)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$, so $16^2=256$. This formula is worth remembering.

Step 2

Why this answer is correct

The correct answer is B. (256). The sum of the first (n) odd numbers is $n^2$, so $16^2=256$. This formula is worth remembering.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ होता है, इसलिए $16^2=256$। यह सूत्र याद रखने योग्य है।

Open Question Page

Question 3/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

यदि (S_n=\frac{n}{2}(a+l)), (a=14), (l=84), और (n=15) है, तो योग ज्ञात कीजिए।

If (S_n=\frac{n}{2}(a+l)), (a=14), (l=84), and (n=15), find the sum.

Explanation opens after your attempt

Correct Answer

C. (735)

Step 1

Concept

(S_{15}=\frac{15}{2}(14+84)=735). Take the average of the first and last terms and multiply by (n).

Step 2

Why this answer is correct

The correct answer is C. (735). (S_{15}=\frac{15}{2}(14+84)=735). Take the average of the first and last terms and multiply by (n).

Step 3

Exam Tip

(S_{15}=\frac{15}{2}(14+84)=735)। पहले और अंतिम पद का औसत लेकर (n) से गुणा करें।

Open Question Page

Question 4/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

यदि किसी समांतर श्रेणी में $S_5=65$ और $S_{11}=242$ है, तो छठे से ग्यारहवें पदों का योग कितना है?

If an arithmetic progression has $S_5=65$ and $S_{11}=242$, what is the sum of the (6)th to (11)th terms?

Explanation opens after your attempt

Correct Answer

B. (177)

Step 1

Concept

The sum of the (6)th to (11)th terms is $S_{11}-S_5=177$. The difference of partial sums gives the answer directly.

Step 2

Why this answer is correct

The correct answer is B. (177). The sum of the (6)th to (11)th terms is $S_{11}-S_5=177$. The difference of partial sums gives the answer directly.

Step 3

Exam Tip

छठे से ग्यारहवें पदों का योग $S_{11}-S_5=177$ है। आंशिक योगों का अंतर सीधे उत्तर देता है।

Open Question Page

Question 5/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

समांतर श्रेणी $2,9,16,\ldots$ के पहले (13) पदों का योग क्या है?

What is the sum of the first (13) terms of the arithmetic progression $2,9,16,\ldots$?

Explanation opens after your attempt

Correct Answer

D. (572)

Step 1

Concept

The thirteenth term is (86), so (S_{13}=\frac{13}{2}(2+86)=572). Use ((n-1)d) when finding the last term.

Step 2

Why this answer is correct

The correct answer is D. (572). The thirteenth term is (86), so (S_{13}=\frac{13}{2}(2+86)=572). Use ((n-1)d) when finding the last term.

Step 3

Exam Tip

तेरहवाँ पद (86) है, इसलिए (S_{13}=\frac{13}{2}(2+86)=572)। अंतिम पद निकालते समय ((n-1)d) का उपयोग करें।

Open Question Page

Question 6/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

यदि किसी समांतर श्रेणी में (a=20), (d=-3), और (n=7) है, तो पहले (7) पदों का योग कितना होगा?

If an arithmetic progression has (a=20), (d=-3), and (n=7), what is the sum of the first (7) terms?

Explanation opens after your attempt

Correct Answer

A. (77)

Step 1

Concept

The seventh term is (2), and (S_7=\frac{7}{2}(20+2)=77). Do not make a sign error with negative (d).

Step 2

Why this answer is correct

The correct answer is A. (77). The seventh term is (2), and (S_7=\frac{7}{2}(20+2)=77). Do not make a sign error with negative (d).

Step 3

Exam Tip

सातवाँ पद (2) है और (S_7=\frac{7}{2}(20+2)=77)। ऋणात्मक (d) में चिन्ह की गलती न करें।

Open Question Page

Question 7/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (19) सम प्राकृतिक संख्याओं का योग कितना होगा?

What will be the sum of the first (19) even natural numbers?

Explanation opens after your attempt

Correct Answer

B. (380)

Step 1

Concept

The sum of the first (n) even numbers is (n(n+1)), so $19\times20=380$. Even numbers start from $2,4,6,\ldots$.

Step 2

Why this answer is correct

The correct answer is B. (380). The sum of the first (n) even numbers is (n(n+1)), so $19\times20=380$. Even numbers start from $2,4,6,\ldots$.

Step 3

Exam Tip

पहले (n) सम संख्याओं का योग (n(n+1)) होता है, इसलिए $19\times20=380$। सम संख्याएँ $2,4,6,\ldots$ से शुरू होती हैं।

Open Question Page

Question 8/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (22) प्राकृतिक संख्याओं का योग कितना है?

What is the sum of the first (22) natural numbers?

Explanation opens after your attempt

Correct Answer

B. (253)

Step 1

Concept

The sum of the first (n) natural numbers is (\frac{n(n+1)}{2}), so the answer is (253). Put the value of (n) directly in such questions.

Step 2

Why this answer is correct

The correct answer is B. (253). The sum of the first (n) natural numbers is (\frac{n(n+1)}{2}), so the answer is (253). Put the value of (n) directly in such questions.

Step 3

Exam Tip

पहले (n) प्राकृतिक संख्याओं का योग (\frac{n(n+1)}{2}) होता है, इसलिए (253) मिलेगा। ऐसे प्रश्न में सीधे (n) का मान लगाएँ।

Open Question Page

Question 9/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $2,5,8,\ldots$ के पहले (14) पदों का योग ज्ञात कीजिए।

Find the sum of the first (14) terms of the arithmetic progression $2,5,8,\ldots$.

Explanation opens after your attempt

Correct Answer

C. (301)

Step 1

Concept

The fourteenth term is (41), so (S_{14}=\frac{14}{2}(2+41)=301). Finding the last term correctly is the main step.

Step 2

Why this answer is correct

The correct answer is C. (301). The fourteenth term is (41), so (S_{14}=\frac{14}{2}(2+41)=301). Finding the last term correctly is the main step.

Step 3

Exam Tip

चौदहवाँ पद (41) है, इसलिए (S_{14}=\frac{14}{2}(2+41)=301)। अंतिम पद सही निकालना मुख्य कदम है।

Open Question Page

Question 10/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $14,17,20,\ldots$ के पहले (10) पदों का योग ज्ञात कीजिए।

Find the sum of the first (10) terms of the arithmetic progression $14,17,20,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (275)

Step 1

Concept

The tenth term is (41), and (S_{10}=\frac{10}{2}(14+41)=275). Finding the last term first makes the sum simple.

Step 2

Why this answer is correct

The correct answer is B. (275). The tenth term is (41), and (S_{10}=\frac{10}{2}(14+41)=275). Finding the last term first makes the sum simple.

Step 3

Exam Tip

दसवाँ पद (41) है और (S_{10}=\frac{10}{2}(14+41)=275)। अंतिम पद निकालकर योग लेना सरल है।

Open Question Page

Question 11/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $9,13,17,\ldots$ के पहले (15) पदों का योग ज्ञात कीजिए।

Find the sum of the first (15) terms of the arithmetic progression $9,13,17,\ldots$.

Explanation opens after your attempt

Correct Answer

A. (555)

Step 1

Concept

The last term is (65), so (S_{15}=\frac{15}{2}(9+65)=555). Using the last term can simplify calculation.

Step 2

Why this answer is correct

The correct answer is A. (555). The last term is (65), so (S_{15}=\frac{15}{2}(9+65)=555). Using the last term can simplify calculation.

Step 3

Exam Tip

अंतिम पद (65) है, इसलिए (S_{15}=\frac{15}{2}(9+65)=555)। अंतिम पद से गणना आसान हो सकती है।

Open Question Page

Question 12/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

किसी समांतर श्रेढ़ी के पहले (9) पदों का औसत (25) है। इन (9) पदों का योग कितना है?

The average of the first (9) terms of an arithmetic progression is (25). What is the sum of these (9) terms?

Explanation opens after your attempt

Correct Answer

C. (225)

Step 1

Concept

Sum equals average $\times$ number of terms, so $25\times9=225$. When the average is given, the long formula is not needed.

Step 2

Why this answer is correct

The correct answer is C. (225). Sum equals average $\times$ number of terms, so $25\times9=225$. When the average is given, the long formula is not needed.

Step 3

Exam Tip

योग (=) औसत $\times$ पदों की संख्या, इसलिए $25\times9=225$। औसत दिए होने पर लंबा सूत्र जरूरी नहीं।

Open Question Page

Question 13/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $\frac{4}{5},\frac{9}{5},\frac{14}{5},\frac{19}{5},\ldots$ का (6)वाँ पद ज्ञात करें।

Find the (6)th term of the AP $\frac{4}{5},\frac{9}{5},\frac{14}{5},\frac{19}{5},\ldots$.

Explanation opens after your attempt

Correct Answer

B. $\frac{29}{5}$

Step 1

Concept

Here (d=1), so $a_6=\frac{4}{5}+5=\frac{29}{5}$. Convert the whole number to a fraction with the same denominator.

Step 2

Why this answer is correct

The correct answer is B. $\frac{29}{5}$. Here (d=1), so $a_6=\frac{4}{5}+5=\frac{29}{5}$. Convert the whole number to a fraction with the same denominator.

Step 3

Exam Tip

यहाँ (d=1) है इसलिए $a_6=\frac{4}{5}+5=\frac{29}{5}$। पूर्ण संख्या को समान हर वाली भिन्न में बदलें।

Open Question Page

Question 14/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $14,14,14,14,\ldots$ का (40)वाँ पद क्या होगा?

What is the (40)th term of the AP $14,14,14,14,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (14)

Step 1

Concept

Here (d=0), so every term remains (14). In a constant AP, $a_n=a$.

Step 2

Why this answer is correct

The correct answer is B. (14). Here (d=0), so every term remains (14). In a constant AP, $a_n=a$.

Step 3

Exam Tip

यहाँ (d=0) है इसलिए हर पद (14) रहेगा। स्थिर एपी में $a_n=a$ होता है।

Open Question Page

Question 15/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि $a_9=70$ और (d=3) है तो (15)वाँ पद क्या होगा?

If $a_9=70$ and (d=3), what is the (15)th term?

Explanation opens after your attempt

Correct Answer

C. (88)

Step 1

Concept

The (15)th term is (6d) after the (9)th term, so (70+18=88). This method is simple for nearby terms.

Step 2

Why this answer is correct

The correct answer is C. (88). The (15)th term is (6d) after the (9)th term, so (70+18=88). This method is simple for nearby terms.

Step 3

Exam Tip

(15)वाँ पद (9)वें पद से (6d) आगे है इसलिए (70+18=88)। निकट पदों में यह विधि सरल है।

Open Question Page

Question 16/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $9,15,21,27,\ldots$ का (28)वाँ पद क्या है?

What is the (28)th term of the AP $9,15,21,27,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (171)

Step 1

Concept

Here (d=6), so $a_{28}=9+27\times6=171$. For the (28)th term, add (27d).

Step 2

Why this answer is correct

The correct answer is B. (171). Here (d=6), so $a_{28}=9+27\times6=171$. For the (28)th term, add (27d).

Step 3

Exam Tip

यहाँ (d=6) है इसलिए $a_{28}=9+27\times6=171$। (28)वें पद के लिए (27d) जोड़ें।

Open Question Page

Question 17/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि $a_1=22$ और (d=13) है तो (5)वाँ पद क्या होगा?

If $a_1=22$ and (d=13), what is the (5)th term?

Explanation opens after your attempt

Correct Answer

C. (74)

Step 1

Concept

$a_5=22+4\times13=74$. $a_1$ is treated as the first term.

Step 2

Why this answer is correct

The correct answer is C. (74). $a_5=22+4\times13=74$. $a_1$ is treated as the first term.

Step 3

Exam Tip

$a_5=22+4\times13=74$। $a_1$ को प्रथम पद माना जाता है।

Open Question Page

Question 18/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $33,29,25,21,\ldots$ का (14)वाँ पद ज्ञात करें।

Find the (14)th term of the AP $33,29,25,21,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (-19)

Step 1

Concept

Here (d=-4), so (a_{14}=33+13(-4)=-19). Add (-4) thirteen times.

Step 2

Why this answer is correct

The correct answer is B. (-19). Here (d=-4), so (a_{14}=33+13(-4)=-19). Add (-4) thirteen times.

Step 3

Exam Tip

यहाँ (d=-4) है इसलिए (a_{14}=33+13(-4)=-19)। (13) बार (-4) जोड़ें।

Open Question Page

Question 19/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $6,17,28,39,\ldots$ का (16)वाँ पद क्या होगा?

What is the (16)th term of the AP $6,17,28,39,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (171)

Step 1

Concept

Here (d=11), so $a_{16}=6+15\times11=171$. For the (16)th term, add (15) differences.

Step 2

Why this answer is correct

The correct answer is B. (171). Here (d=11), so $a_{16}=6+15\times11=171$. For the (16)th term, add (15) differences.

Step 3

Exam Tip

यहाँ (d=11) है इसलिए $a_{16}=6+15\times11=171$। (16)वें पद के लिए (15) अंतर जोड़ें।

Open Question Page

Question 20/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि (a=120), (d=-9) और (n=13) है तो $a_n$ ज्ञात करें।

If (a=120), (d=-9), and (n=13), find $a_n$.

Explanation opens after your attempt

Correct Answer

B. (12)

Step 1

Concept

(a_{13}=120+12(-9)=12). First subtract $12\times9$.

Step 2

Why this answer is correct

The correct answer is B. (12). (a_{13}=120+12(-9)=12). First subtract $12\times9$.

Step 3

Exam Tip

(a_{13}=120+12(-9)=12)। पहले $12\times9$ घटाएं।

Open Question Page

Question 21/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $-15,-9,-3,3,\ldots$ का (18)वाँ पद क्या है?

What is the (18)th term of the AP $-15,-9,-3,3,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (87)

Step 1

Concept

Here (d=6), so $a_{18}=-15+17\times6=87$. Add the negative first term correctly.

Step 2

Why this answer is correct

The correct answer is C. (87). Here (d=6), so $a_{18}=-15+17\times6=87$. Add the negative first term correctly.

Step 3

Exam Tip

यहाँ (d=6) है इसलिए $a_{18}=-15+17\times6=87$। ऋणात्मक प्रथम पद को सही जोड़ें।

Open Question Page

Question 22/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $12,17,22,27,\ldots$ का (24)वाँ पद ज्ञात कीजिए।

Find the (24)th term of the AP $12,17,22,27,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (127)

Step 1

Concept

Here (d=5), so $a_{24}=12+23\times5=127$. For the (24)th term, add (23d).

Step 2

Why this answer is correct

The correct answer is B. (127). Here (d=5), so $a_{24}=12+23\times5=127$. For the (24)th term, add (23d).

Step 3

Exam Tip

यहाँ (d=5) है इसलिए $a_{24}=12+23\times5=127$। (24)वें पद के लिए (23d) जोड़ें।

Open Question Page

Question 23/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि $a_8=44$ और (d=-2) है तो (12)वाँ पद क्या होगा?

If $a_8=44$ and (d=-2), what is the (12)th term?

Explanation opens after your attempt

Correct Answer

B. (36)

Step 1

Concept

The (12)th term is (4d) after the (8)th term, so (44+4(-2)=36). Add the negative difference carefully.

Step 2

Why this answer is correct

The correct answer is B. (36). The (12)th term is (4d) after the (8)th term, so (44+4(-2)=36). Add the negative difference carefully.

Step 3

Exam Tip

(12)वाँ पद (8)वें पद से (4d) आगे है इसलिए (44+4(-2)=36)। ऋणात्मक अंतर को ध्यान से जोड़ें।

Open Question Page

Question 24/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $7,16,25,34,\ldots$ का (21)वाँ पद क्या होगा?

What is the (21)st term of the AP $7,16,25,34,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (187)

Step 1

Concept

Here (d=9), so $a_{21}=7+20\times9=187$. Up to the (21)st term, (20) differences are added.

Step 2

Why this answer is correct

The correct answer is B. (187). Here (d=9), so $a_{21}=7+20\times9=187$. Up to the (21)st term, (20) differences are added.

Step 3

Exam Tip

यहाँ (d=9) है इसलिए $a_{21}=7+20\times9=187$। (21)वें पद तक (20) अंतर जुड़ते हैं।

Open Question Page

Question 25/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि किसी एपी में (a=2.5), (d=2.5) और (n=10) है तो $a_n$ क्या होगा?

If an AP has (a=2.5), (d=2.5), and (n=10), what is $a_n$?

Explanation opens after your attempt

Correct Answer

B. (25.0)

Step 1

Concept

$a_{10}=2.5+9\times2.5=25.0$. Treat decimals like ordinary numbers.

Step 2

Why this answer is correct

The correct answer is B. (25.0). $a_{10}=2.5+9\times2.5=25.0$. Treat decimals like ordinary numbers.

Step 3

Exam Tip

$a_{10}=2.5+9\times2.5=25.0$। दशमलव को सामान्य संख्या की तरह रखें।

Open Question Page

Question 26/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $48,42,36,30,\ldots$ का (11)वाँ पद ज्ञात करें।

Find the (11)th term of the AP $48,42,36,30,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (-12)

Step 1

Concept

Here (d=-6), so (a_{11}=48+10(-6)=-12). For the (11)th term, add (10d).

Step 2

Why this answer is correct

The correct answer is B. (-12). Here (d=-6), so (a_{11}=48+10(-6)=-12). For the (11)th term, add (10d).

Step 3

Exam Tip

यहाँ (d=-6) है इसलिए (a_{11}=48+10(-6)=-12)। (11)वें पद के लिए (10d) जोड़ें।

Open Question Page

Question 27/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि $a_2=12$ और (d=9) है तो (7)वाँ पद क्या होगा?

If $a_2=12$ and (d=9), what is the (7)th term?

Explanation opens after your attempt

Correct Answer

B. (57)

Step 1

Concept

The (7)th term is (5d) after the (2)nd term, so (12+45=57). Solve by moving forward from the given term.

Step 2

Why this answer is correct

The correct answer is B. (57). The (7)th term is (5d) after the (2)nd term, so (12+45=57). Solve by moving forward from the given term.

Step 3

Exam Tip

(7)वाँ पद (2)रे पद से (5d) आगे है इसलिए (12+45=57)। दिए पद से आगे बढ़कर हल करें।

Open Question Page

Question 28/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $18,28,38,48,\ldots$ का (9)वाँ पद क्या है?

What is the (9)th term of the AP $18,28,38,48,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (98)

Step 1

Concept

Here (d=10), so $a_9=18+8\times10=98$. Up to the (9)th term, (8) differences are added.

Step 2

Why this answer is correct

The correct answer is C. (98). Here (d=10), so $a_9=18+8\times10=98$. Up to the (9)th term, (8) differences are added.

Step 3

Exam Tip

यहाँ (d=10) है इसलिए $a_9=18+8\times10=98$। (9)वें पद तक (8) अंतर जुड़ते हैं।

Open Question Page

Question 29/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि (a=5) और (d=-1) है तो (30)वाँ पद क्या होगा?

If (a=5) and (d=-1), what is the (30)th term?

Explanation opens after your attempt

Correct Answer

C. (-24)

Step 1

Concept

(a_{30}=5+29(-1)=-24). For the (30)th term, add (29d).

Step 2

Why this answer is correct

The correct answer is C. (-24). (a_{30}=5+29(-1)=-24). For the (30)th term, add (29d).

Step 3

Exam Tip

(a_{30}=5+29(-1)=-24)। (30)वें पद के लिए (29d) जोड़ना है।

Open Question Page

Question 30/1038 Easy Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

एपी $31,34,37,40,\ldots$ का (22)वाँ पद क्या होगा?

What is the (22)nd term of the AP $31,34,37,40,\ldots$?

Explanation opens after your attempt

Correct Answer

D. (94)

Step 1

Concept

Here (d=3), so $a_{22}=31+21\times3=94$. The (22)nd term includes (21) differences.

Step 2

Why this answer is correct

The correct answer is D. (94). Here (d=3), so $a_{22}=31+21\times3=94$. The (22)nd term includes (21) differences.

Step 3

Exam Tip

यहाँ (d=3) है इसलिए $a_{22}=31+21\times3=94$। (22)वें पद में (21) अंतर जुड़ते हैं।

Open Question Page

easy MCQ Questions for Class 10

Practice Questions

समांतर श्रेणी \(22,25,28,\ldots\) के पहले (14) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

पहले (16) विषम प्राकृतिक संख्याओं का योग कितना है?

Concept

Why this answer is correct

Exam Tip

यदि (S_n=\frac{n}{2}(a+l)), (a=14), (l=84), और (n=15) है, तो योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

यदि किसी समांतर श्रेणी में \(S_5=65\) और \(S_{11}=242\) है, तो छठे से ग्यारहवें पदों का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समांतर श्रेणी \(2,9,16,\ldots\) के पहले (13) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

यदि किसी समांतर श्रेणी में (a=20), (d=-3), और (n=7) है, तो पहले (7) पदों का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

पहले (19) सम प्राकृतिक संख्याओं का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

पहले (22) प्राकृतिक संख्याओं का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(2,5,8,\ldots\) के पहले (14) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(14,17,20,\ldots\) के पहले (10) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(9,13,17,\ldots\) के पहले (15) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

किसी समांतर श्रेढ़ी के पहले (9) पदों का औसत (25) है। इन (9) पदों का योग कितना है?

Concept

Why this answer is correct

Exam Tip

एपी \(\frac{4}{5},\frac{9}{5},\frac{14}{5},\frac{19}{5},\ldots\) का (6)वाँ पद ज्ञात करें।

Concept

Why this answer is correct

Exam Tip

एपी \(14,14,14,14,\ldots\) का (40)वाँ पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

यदि \(a_9=70\) और (d=3) है तो (15)वाँ पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

एपी \(9,15,21,27,\ldots\) का (28)वाँ पद क्या है?

Concept

Why this answer is correct

Exam Tip

यदि \(a_1=22\) और (d=13) है तो (5)वाँ पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

एपी \(33,29,25,21,\ldots\) का (14)वाँ पद ज्ञात करें।

Concept

Why this answer is correct

Exam Tip

एपी \(6,17,28,39,\ldots\) का (16)वाँ पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

यदि (a=120), (d=-9) और (n=13) है तो \(a_n\) ज्ञात करें।

Concept