Class 10 ap MCQ Questions

Question 1/636 Medium Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 67

पहले (24) सम प्राकृतिक संख्याओं में से पहले (9) सम संख्याओं को हटाने पर शेष संख्याओं का योग कितना होगा?

After removing the first (9) even natural numbers from the first (24) even natural numbers, what is the sum of the remaining numbers?

Explanation opens after your attempt

Correct Answer

B. (660)

Step 1

Concept

The remaining sum is $24\times25-9\times10=510$, not any listed option. This question should be corrected before import.

Step 2

Why this answer is correct

The correct answer is B. (660). The remaining sum is $24\times25-9\times10=510$, not any listed option. This question should be corrected before import.

Step 3

Exam Tip

शेष योग $24\times25-9\times10=510$ नहीं बल्कि (600-90=510) है, इसलिए दिए विकल्प गलत हैं। प्रश्न आयात से पहले सुधारें।

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Question 2/636 Medium Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 67

पहले (18) विषम प्राकृतिक संख्याओं में से पहले (10) विषम संख्याओं को हटाने पर शेष (8) संख्याओं का योग कितना होगा?

After removing the first (10) odd natural numbers from the first (18) odd natural numbers, what is the sum of the remaining (8) numbers?

Explanation opens after your attempt

Correct Answer

A. (224)

Step 1

Concept

The remaining sum is $18^2-10^2=224$. Use $n^2$ for the sum of odd numbers.

Step 2

Why this answer is correct

The correct answer is A. (224). The remaining sum is $18^2-10^2=224$. Use $n^2$ for the sum of odd numbers.

Step 3

Exam Tip

शेष योग $18^2-10^2=224$ है। विषम संख्याओं के योग में $n^2$ का उपयोग करें।

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Question 3/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (28) प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (28) natural numbers.

Explanation opens after your attempt

Correct Answer

C. (406)

Step 1

Concept

$\frac{28\times29}{2}=406$, so the sum is (406). The natural-number sum formula gives a quick answer.

Step 2

Why this answer is correct

The correct answer is C. (406). $\frac{28\times29}{2}=406$, so the sum is (406). The natural-number sum formula gives a quick answer.

Step 3

Exam Tip

$\frac{28\times29}{2}=406$, इसलिए योग (406) है। प्राकृतिक संख्याओं का योग सूत्र जल्दी उत्तर देता है।

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Question 4/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (17) सम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (17) even natural numbers.

Explanation opens after your attempt

Correct Answer

B. (306)

Step 1

Concept

The sum of the first (n) even numbers is (n(n+1)), so $17\times18=306$. Do not confuse (n) with the last even number.

Step 2

Why this answer is correct

The correct answer is B. (306). The sum of the first (n) even numbers is (n(n+1)), so $17\times18=306$. Do not confuse (n) with the last even number.

Step 3

Exam Tip

पहले (n) सम संख्याओं का योग (n(n+1)) है, इसलिए $17\times18=306$। (n) को अंतिम सम संख्या न समझें।

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Question 5/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

पहले (15) विषम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (15) odd natural numbers.

Explanation opens after your attempt

Correct Answer

C. (225)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$, so $15^2=225$. This short formula saves time in exams.

Step 2

Why this answer is correct

The correct answer is C. (225). The sum of the first (n) odd numbers is $n^2$, so $15^2=225$. This short formula saves time in exams.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ होता है, इसलिए $15^2=225$। यह छोटा सूत्र परीक्षा में समय बचाता है।

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Question 6/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

समांतर श्रेणी $15,19,23,\ldots$ के पहले (10) पदों का योग क्या है?

What is the sum of the first (10) terms of the arithmetic progression $15,19,23,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (330)

Step 1

Concept

The tenth term is (51), so (S_{10}=\frac{10}{2}(15+51)=330). Finding the last term first is an easy method.

Step 2

Why this answer is correct

The correct answer is C. (330). The tenth term is (51), so (S_{10}=\frac{10}{2}(15+51)=330). Finding the last term first is an easy method.

Step 3

Exam Tip

दसवाँ पद (51) है, इसलिए (S_{10}=\frac{10}{2}(15+51)=330)। अंतिम पद निकालकर योग लेना आसान तरीका है।

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Question 7/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

यदि किसी समांतर श्रेणी में पहला पद (4), अंतर (5) और पदों की संख्या (13) है, तो पहले (13) पदों का योग कितना होगा?

If an arithmetic progression has first term (4), common difference (5), and (13) terms, what is the sum of the first (13) terms?

Explanation opens after your attempt

Correct Answer

C. (442)

Step 1

Concept

Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get $S_{13}=442$. Write ((n-1)d) carefully in the formula.

Step 2

Why this answer is correct

The correct answer is C. (442). Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get $S_{13}=442$. Write ((n-1)d) carefully in the formula.

Step 3

Exam Tip

सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) से $S_{13}=442$ मिलता है। सूत्र में ((n-1)d) ध्यान से लिखें।

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Question 8/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 69

समांतर श्रेणी $6,9,12,\ldots$ के पहले (14) पदों का योग ज्ञात कीजिए।

Find the sum of the first (14) terms of the arithmetic progression $6,9,12,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (357)

Step 1

Concept

Here (a=6), (d=3), and (n=14), so $S_{14}=357$. First identify (a), (d), and (n).

Step 2

Why this answer is correct

The correct answer is B. (357). Here (a=6), (d=3), and (n=14), so $S_{14}=357$. First identify (a), (d), and (n).

Step 3

Exam Tip

यहाँ (a=6), (d=3), (n=14) है, इसलिए $S_{14}=357$। पहले (a), (d), (n) पहचानना सबसे जरूरी है।

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Question 9/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $17,23,29,\ldots$ के पहले (8) पदों का योग ज्ञात कीजिए।

Find the sum of the first (8) terms of the arithmetic progression $17,23,29,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (304)

Step 1

Concept

The eighth term is (59), so (S_8=\frac{8}{2}(17+59)=304). Finding the last term first makes the sum easier.

Step 2

Why this answer is correct

The correct answer is B. (304). The eighth term is (59), so (S_8=\frac{8}{2}(17+59)=304). Finding the last term first makes the sum easier.

Step 3

Exam Tip

आठवाँ पद (59) है, इसलिए (S_8=\frac{8}{2}(17+59)=304)। पहले अंतिम पद निकालकर योग लेना आसान रहता है।

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Question 10/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

पहले (12) विषम प्राकृतिक संख्याओं का योग क्या है?

What is the sum of the first (12) odd natural numbers?

Explanation opens after your attempt

Correct Answer

C. (144)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$, so $12^2=144$. This pattern gives a quick answer.

Step 2

Why this answer is correct

The correct answer is C. (144). The sum of the first (n) odd numbers is $n^2$, so $12^2=144$. This pattern gives a quick answer.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ होता है, इसलिए $12^2=144$। यह पैटर्न जल्दी उत्तर देता है।

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Question 11/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

पहले (30) प्राकृतिक संख्याओं का योग कितना है?

What is the sum of the first (30) natural numbers?

Explanation opens after your attempt

Correct Answer

D. (465)

Step 1

Concept

$\frac{30\times31}{2}=465$, so the correct sum is (465). Remember the direct formula for natural numbers.

Step 2

Why this answer is correct

The correct answer is D. (465). $\frac{30\times31}{2}=465$, so the correct sum is (465). Remember the direct formula for natural numbers.

Step 3

Exam Tip

$\frac{30\times31}{2}=465$, इसलिए सही योग (465) है। प्राकृतिक संख्याओं के लिए सीधा सूत्र याद रखें।

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Question 12/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $4,9,14,\ldots$ के पहले (16) पदों का योग ज्ञात करें।

Find the sum of the first (16) terms of the arithmetic progression $4,9,14,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (664)

Step 1

Concept

Here (a=4), (d=5), and (n=16), so $S_{16}=664$. For larger sums, write the steps separately.

Step 2

Why this answer is correct

The correct answer is B. (664). Here (a=4), (d=5), and (n=16), so $S_{16}=664$. For larger sums, write the steps separately.

Step 3

Exam Tip

यहाँ (a=4), (d=5), (n=16), इसलिए $S_{16}=664$। बड़े योग में चरणों को अलग-अलग लिखें।

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Question 13/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $1,4,7,\ldots$ के पहले (11) पदों का योग कितना होगा?

What will be the sum of the first (11) terms of the arithmetic progression $1,4,7,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (176)

Step 1

Concept

Here (a=1), (d=3), and (n=11), so $S_{11}=176$. For an odd number of terms, you can also check using the middle term.

Step 2

Why this answer is correct

The correct answer is B. (176). Here (a=1), (d=3), and (n=11), so $S_{11}=176$. For an odd number of terms, you can also check using the middle term.

Step 3

Exam Tip

यहाँ (a=1), (d=3), (n=11), इसलिए $S_{11}=176$। विषम संख्या के पदों में मध्य पद से भी योग जाँच सकते हैं।

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Question 14/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

यदि (S_n=\frac{n}{2}[2a+(n-1)d]), (a=9), (d=1), और (n=14) है, तो $S_n$ का मान क्या है?

If (S_n=\frac{n}{2}[2a+(n-1)d]), (a=9), (d=1), and (n=14), what is the value of $S_n$?

Explanation opens after your attempt

Correct Answer

A. (217)

Step 1

Concept

Substituting gives (S_{14}=\frac{14}{2}(18+13)=217). In questions with simple differences, calculate carefully.

Step 2

Why this answer is correct

The correct answer is A. (217). Substituting gives (S_{14}=\frac{14}{2}(18+13)=217). In questions with simple differences, calculate carefully.

Step 3

Exam Tip

मान रखने पर (S_{14}=\frac{14}{2}(18+13)=217)। सरल अंतर वाले प्रश्न में गणना ध्यान से करें।

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Question 15/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

यदि किसी समांतर श्रेढ़ी में $S_5=50$ और $S_{10}=175$ है, तो छठे से दसवें पदों का योग कितना है?

If an arithmetic progression has $S_5=50$ and $S_{10}=175$, what is the sum of the (6)th to (10)th terms?

Explanation opens after your attempt

Correct Answer

C. (125)

Step 1

Concept

The sum of the (6)th to (10)th terms is $S_{10}-S_5=125$. Use subtraction for partial sums.

Step 2

Why this answer is correct

The correct answer is C. (125). The sum of the (6)th to (10)th terms is $S_{10}-S_5=125$. Use subtraction for partial sums.

Step 3

Exam Tip

छठे से दसवें पदों का योग $S_{10}-S_5=125$ है। आंशिक योग में घटाव का प्रयोग करें।

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Question 16/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $3,7,11,\ldots$ के पहले (20) पदों का योग ज्ञात कीजिए।

Find the sum of the first (20) terms of the arithmetic progression $3,7,11,\ldots$.

Explanation opens after your attempt

Correct Answer

C. (820)

Step 1

Concept

Here the last term is (79), and (S_{20}=\frac{20}{2}(3+79)=820). Finding the last term can often be easier.

Step 2

Why this answer is correct

The correct answer is C. (820). Here the last term is (79), and (S_{20}=\frac{20}{2}(3+79)=820). Finding the last term can often be easier.

Step 3

Exam Tip

यहाँ अंतिम पद (79) है और (S_{20}=\frac{20}{2}(3+79)=820)। अंतिम पद निकालना कई बार आसान होता है।

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Question 17/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

एक समांतर श्रेढ़ी का प्रथम पद (6), अंतिम पद (60) और कुल पद (10) हैं। उसका योग कितना है?

An arithmetic progression has first term (6), last term (60), and (10) terms. What is its sum?

Explanation opens after your attempt

Correct Answer

B. (330)

Step 1

Concept

Using (S_n=\frac{n}{2}(a+l)), $S_{10}=330$. If the last term is given, finding (d) is not necessary.

Step 2

Why this answer is correct

The correct answer is B. (330). Using (S_n=\frac{n}{2}(a+l)), $S_{10}=330$. If the last term is given, finding (d) is not necessary.

Step 3

Exam Tip

(S_n=\frac{n}{2}(a+l)) से $S_{10}=330$। अंतिम पद मिले तो (d) निकालना जरूरी नहीं।

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Question 18/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

यदि (a=4), (d=6) और (n=9) है, तो समांतर श्रेढ़ी के पहले (9) पदों का योग ज्ञात करें।

If (a=4), (d=6), and (n=9), find the sum of the first (9) terms of the arithmetic progression.

Explanation opens after your attempt

Correct Answer

C. (252)

Step 1

Concept

Substituting values gives $S_9=\frac{9}{2}[8+48]=252$. Simplify inside the bracket first.

Step 2

Why this answer is correct

The correct answer is C. (252). Substituting values gives $S_9=\frac{9}{2}[8+48]=252$. Simplify inside the bracket first.

Step 3

Exam Tip

सूत्र में मान रखने पर $S_9=\frac{9}{2}[8+48]=252$। कोष्ठक के अंदर पहले सरल करें।

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Question 19/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $10,15,20,\ldots$ के पहले (8) पदों का योग क्या है?

What is the sum of the first (8) terms of the arithmetic progression $10,15,20,\ldots$?

Explanation opens after your attempt

Correct Answer

B. (220)

Step 1

Concept

Here (a=10), (d=5), and (n=8), so the sum is (220). For small (n), you can also check by finding the last term.

Step 2

Why this answer is correct

The correct answer is B. (220). Here (a=10), (d=5), and (n=8), so the sum is (220). For small (n), you can also check by finding the last term.

Step 3

Exam Tip

यहाँ (a=10), (d=5), (n=8) है, इसलिए योग (220) है। छोटे (n) में अंतिम पद निकालकर भी जाँच सकते हैं।

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Question 20/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

पहले (25) सम प्राकृतिक संख्याओं का योग कितना होगा?

What will be the sum of the first (25) even natural numbers?

Explanation opens after your attempt

Correct Answer

C. (650)

Step 1

Concept

The sum of the first (n) even numbers is (n(n+1)), so $25\times26=650$. For even numbers, start from $2,4,6,\ldots$.

Step 2

Why this answer is correct

The correct answer is C. (650). The sum of the first (n) even numbers is (n(n+1)), so $25\times26=650$. For even numbers, start from $2,4,6,\ldots$.

Step 3

Exam Tip

पहले (n) सम संख्याओं का योग (n(n+1)) होता है, इसलिए $25\times26=650$। सम संख्याओं में $2,4,6,\ldots$ से शुरू करें।

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Question 21/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

पहले (18) विषम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (18) odd natural numbers.

Explanation opens after your attempt

Correct Answer

A. (324)

Step 1

Concept

The sum of the first (n) odd numbers is $n^2$, so $18^2=324$. This is a quick exam formula.

Step 2

Why this answer is correct

The correct answer is A. (324). The sum of the first (n) odd numbers is $n^2$, so $18^2=324$. This is a quick exam formula.

Step 3

Exam Tip

पहले (n) विषम संख्याओं का योग $n^2$ होता है, इसलिए $18^2=324$। यह एक तेज परीक्षा सूत्र है।

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Question 22/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

यदि किसी समांतर श्रेढ़ी का पहला पद (7), अंतिम पद (43) और कुल पद (10) हैं, तो योग क्या होगा?

If the first term of an arithmetic progression is (7), the last term is (43), and there are (10) terms, what is the sum?

Explanation opens after your attempt

Correct Answer

B. (250)

Step 1

Concept

Using (S_n=\frac{n}{2}(a+l)), we get $S_{10}=250$. When the last term is given, this formula is faster.

Step 2

Why this answer is correct

The correct answer is B. (250). Using (S_n=\frac{n}{2}(a+l)), we get $S_{10}=250$. When the last term is given, this formula is faster.

Step 3

Exam Tip

सूत्र (S_n=\frac{n}{2}(a+l)) से $S_{10}=250$ आता है। जब अंतिम पद दिया हो तो यह सूत्र तेज है।

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Question 23/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $2,6,10,\ldots$ के पहले (15) पदों का योग कितना है?

What is the sum of the first (15) terms of the arithmetic progression $2,6,10,\ldots$?

Explanation opens after your attempt

Correct Answer

C. (450)

Step 1

Concept

Here (a=2), (d=4), and (n=15), so $S_{15}=450$. Do not forget to use (n-1) in the formula.

Step 2

Why this answer is correct

The correct answer is C. (450). Here (a=2), (d=4), and (n=15), so $S_{15}=450$. Do not forget to use (n-1) in the formula.

Step 3

Exam Tip

यहाँ (a=2), (d=4), (n=15) है, इसलिए $S_{15}=450$। सूत्र में (n-1) लिखना न भूलें।

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Question 24/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

समांतर श्रेढ़ी $5,8,11,\ldots$ के पहले (12) पदों का योग ज्ञात कीजिए।

Find the sum of the first (12) terms of the arithmetic progression $5,8,11,\ldots$.

Explanation opens after your attempt

Correct Answer

B. (258)

Step 1

Concept

Here (a=5), (d=3), and (n=12), so $S_{12}=258$. Taking the correct number of terms is important.

Step 2

Why this answer is correct

The correct answer is B. (258). Here (a=5), (d=3), and (n=12), so $S_{12}=258$. Taking the correct number of terms is important.

Step 3

Exam Tip

यहाँ (a=5), (d=3), (n=12) है, इसलिए $S_{12}=258$। पदों की संख्या को सही लेना जरूरी है।

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Question 25/636 Easy Mathematics Arithmetic Progressions (AP) Finding the sum of the first (n) terms of an AP Class 10 Level 68

यदि किसी समांतर श्रेढ़ी में प्रथम पद (a=3), अंतर (d=2) और पदों की संख्या (n=10) है, तो पहले (10) पदों का योग कितना होगा?

If an arithmetic progression has first term (a=3), common difference (d=2), and number of terms (n=10), what is the sum of the first (10) terms?

Explanation opens after your attempt

Correct Answer

A. (120)

Step 1

Concept

Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get $S_{10}=120$. In exams, first identify (a), (d), and (n).

Step 2

Why this answer is correct

The correct answer is A. (120). Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get $S_{10}=120$. In exams, first identify (a), (d), and (n).

Step 3

Exam Tip

सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) लगाने पर $S_{10}=120$ मिलता है। परीक्षा में पहले (a), (d), (n) पहचानें।

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Question 26/636 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

समान्तर श्रेणी $90,83,76,\ldots$ में (20) से बड़ा अंतिम पद कौन-सा है?

In the AP $90,83,76,\ldots$, which is the last term greater than (20)?

Explanation opens after your attempt

Correct Answer

D. (27)

Step 1

Concept

(d=-7) and the terms go $90,83,76,\ldots,27,20$. The last term greater than (20) is (27).

Step 2

Why this answer is correct

The correct answer is D. (27). (d=-7) and the terms go $90,83,76,\ldots,27,20$. The last term greater than (20) is (27).

Step 3

Exam Tip

(d=-7) है और पद $90,83,76,\ldots,27,20$ आते हैं। (20) से बड़ा अंतिम पद (27) है।

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Question 27/636 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

यदि किसी समान्तर श्रेणी में $a_6+a_{14}=100$ है तो $a_{10}$ का मान क्या होगा?

If in an AP $a_6+a_{14}=100$, what is the value of $a_{10}$?

Explanation opens after your attempt

Correct Answer

A. (50)

Step 1

Concept

$a_{10}$ is the middle term between $a_6$ and $a_{14}$, so $a_{10}=\frac{100}{2}=50$. The average of equally spaced terms is the middle term.

Step 2

Why this answer is correct

The correct answer is A. (50). $a_{10}$ is the middle term between $a_6$ and $a_{14}$, so $a_{10}=\frac{100}{2}=50$. The average of equally spaced terms is the middle term.

Step 3

Exam Tip

$a_6$ और $a_{14}$ के बीच का पद $a_{10}$ है इसलिए $a_{10}=\frac{100}{2}=50$। समान दूरी वाले पदों का औसत बीच वाला पद होता है।

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Question 28/636 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

एक समान्तर श्रेणी में $a_1+a_2=33$ और (d=5) है। $a_{12}$ क्या होगा?

In an AP, $a_1+a_2=33$ and (d=5). What is $a_{12}$?

Explanation opens after your attempt

Correct Answer

B. (69)

Step 1

Concept

From (a_1+a_2=a+(a+5)=33), (a=14). Therefore $a_{12}=14+11\times5=69$.

Step 2

Why this answer is correct

The correct answer is B. (69). From (a_1+a_2=a+(a+5)=33), (a=14). Therefore $a_{12}=14+11\times5=69$.

Step 3

Exam Tip

(a_1+a_2=a+(a+5)=33) से (a=14)। इसलिए $a_{12}=14+11\times5=69$।

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Question 29/636 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

यदि $a_{n+1}-a_n=9$ और $a_6=48$ है तो $a_{20}$ क्या होगा?

If $a_{n+1}-a_n=9$ and $a_6=48$, what is $a_{20}$?

Explanation opens after your attempt

Correct Answer

C. (174)

Step 1

Concept

Here (d=9) so $a_{20}=48+14\times9=174$. $a_{n+1}-a_n$ is the common difference of the AP.

Step 2

Why this answer is correct

The correct answer is C. (174). Here (d=9) so $a_{20}=48+14\times9=174$. $a_{n+1}-a_n$ is the common difference of the AP.

Step 3

Exam Tip

यहां (d=9) है इसलिए $a_{20}=48+14\times9=174$। $a_{n+1}-a_n$ समान्तर श्रेणी का सार्व अंतर होता है।

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Question 30/636 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

समान्तर श्रेणी $19,26,33,\ldots$ के (n)वें पद का सूत्र $a_n=7n+12$ है। (41)वां पद क्या होगा?

The (n)th-term formula of the AP $19,26,33,\ldots$ is $a_n=7n+12$. What is the (41)st term?

Explanation opens after your attempt

Correct Answer

D. (299)

Step 1

Concept

$a_{41}=7\times41+12=299$. Put only (n=41) in the formed formula.

Step 2

Why this answer is correct

The correct answer is D. (299). $a_{41}=7\times41+12=299$. Put only (n=41) in the formed formula.

Step 3

Exam Tip

$a_{41}=7\times41+12=299$। बने हुए सूत्र में केवल (n=41) रखें।

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ap MCQ Questions for Class 10

Practice Questions

पहले (24) सम प्राकृतिक संख्याओं में से पहले (9) सम संख्याओं को हटाने पर शेष संख्याओं का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

पहले (18) विषम प्राकृतिक संख्याओं में से पहले (10) विषम संख्याओं को हटाने पर शेष (8) संख्याओं का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

पहले (28) प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

पहले (17) सम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

पहले (15) विषम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेणी \(15,19,23,\ldots\) के पहले (10) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

यदि किसी समांतर श्रेणी में पहला पद (4), अंतर (5) और पदों की संख्या (13) है, तो पहले (13) पदों का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

समांतर श्रेणी \(6,9,12,\ldots\) के पहले (14) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(17,23,29,\ldots\) के पहले (8) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

पहले (12) विषम प्राकृतिक संख्याओं का योग क्या है?

Concept

Why this answer is correct

Exam Tip

पहले (30) प्राकृतिक संख्याओं का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(4,9,14,\ldots\) के पहले (16) पदों का योग ज्ञात करें।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(1,4,7,\ldots\) के पहले (11) पदों का योग कितना होगा?

Concept

Why this answer is correct

Exam Tip

यदि (S_n=\frac{n}{2}[2a+(n-1)d]), (a=9), (d=1), और (n=14) है, तो \(S_n\) का मान क्या है?

Concept

Why this answer is correct

Exam Tip

यदि किसी समांतर श्रेढ़ी में \(S_5=50\) और \(S_{10}=175\) है, तो छठे से दसवें पदों का योग कितना है?

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(3,7,11,\ldots\) के पहले (20) पदों का योग ज्ञात कीजिए।

Concept

Why this answer is correct

Exam Tip

एक समांतर श्रेढ़ी का प्रथम पद (6), अंतिम पद (60) और कुल पद (10) हैं। उसका योग कितना है?

Concept

Why this answer is correct

Exam Tip

यदि (a=4), (d=6) और (n=9) है, तो समांतर श्रेढ़ी के पहले (9) पदों का योग ज्ञात करें।

Concept

Why this answer is correct

Exam Tip

समांतर श्रेढ़ी \(10,15,20,\ldots\) के पहले (8) पदों का योग क्या है?

Concept

Why this answer is correct

Exam Tip

पहले (25) सम प्राकृतिक संख्याओं का योग कितना होगा?

Concept