Concept-wise Practice

even numbers MCQ Questions for Class 10

even numbers se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with even numbers.

Question 1/5 Hard Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 18

\(\sqrt{2}\) के अपरिमेय होने के प्रमाण में (p=2k) रखने के बाद कौन-सा निष्कर्ष मिलता है?

In the proof that \(\sqrt{2}\) is irrational, what conclusion is obtained after putting (p=2k)?

Explanation opens after your attempt
Correct Answer

A. \(q^2=2k^2\), इसलिए (q) सम है\(q^2=2k^2\), so (q) is even

Step 1

Concept

From \(p^2=2q^2\) and (p=2k), we get \(4k^2=2q^2\).

Step 2

Why this answer is correct

Simplifying gives \(q^2=2k^2\), so \(q^2\) and (q) are even.

Step 3

Exam Tip

This second evenness completes the contradiction. चरण 1: \(p^2=2q^2\) और (p=2k) रखने पर \(4k^2=2q^2\) मिलता है। चरण 2: सरल करने पर \(q^2=2k^2\), इसलिए \(q^2\) सम और (q) सम है। चरण 3: यही दूसरा समपन विरोधाभास पूरा करता है।

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Question 2/5 Medium Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 17

\(\sqrt{2}\) की सिद्धि में (p) और (q) दोनों सम मिलते हैं। इसे विरोधाभास क्यों कहा जाता है?

In the proof of \(\sqrt{2}\), both (p) and (q) are found even. Why is this called a contradiction?

Explanation opens after your attempt
Correct Answer

A. क्योंकि दोनों में (2) साझा गुणनखंड है, जबकि वे सहअभाज्य माने गए थेBecause both have common factor (2), while they were assumed coprime

Step 1

Concept

An even number is divisible by (2).

Step 2

Why this answer is correct

If both are even, (2) is a common factor.

Step 3

Exam Tip

Coprime numbers cannot have such a common factor. चरण 1: सम संख्या (2) से विभाज्य होती है। चरण 2: दोनों सम होने पर (2) साझा गुणनखंड है। चरण 3: सहअभाज्य संख्याओं में ऐसा साझा गुणनखंड नहीं हो सकता।

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Question 3/5 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 18

यदि (p) और (q) दोनों सम मिलते हैं, तो वे सहअभाज्य क्यों नहीं हो सकते?

If both (p) and (q) are found even, why can they not be coprime?

Explanation opens after your attempt
Correct Answer

A. क्योंकि दोनों में (2) साझा गुणनखंड हैBecause both have (2) as a common factor

Step 1

Concept

An even number is divisible by (2).

Step 2

Why this answer is correct

If both (p) and (q) are even, both have (2) as a common factor.

Step 3

Exam Tip

Coprime numbers have no common factor except (1). चरण 1: सम संख्या (2) से विभाज्य होती है। चरण 2: यदि (p) और (q) दोनों सम हैं, तो दोनों में (2) साझा गुणनखंड है। चरण 3: सहअभाज्य संख्याओं में (1) के अलावा साझा गुणनखंड नहीं होता।

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Question 4/5 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

किस प्रमाण में (p) और (q) दोनों सम मिलते हैं?

In which proof are both (p) and (q) found even?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\) के प्रमाण मेंIn the proof of \(\sqrt{2}\)

Step 1

Concept

In the proof of \(\sqrt{2}\), we get \(p^2=2q^2\).

Step 2

Why this answer is correct

This makes both (p) and (q) even.

Step 3

Exam Tip

The common factor (2) creates the contradiction. चरण 1: \(\sqrt{2}\) के प्रमाण में समीकरण \(p^2=2q^2\) मिलता है। चरण 2: इससे (p) और (q) दोनों सम मिलते हैं। चरण 3: (2) वाला साझा गुणनखंड ही विरोधाभास बनाता है।

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Question 5/5 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

यदि (p) और (q) दोनों सम हों, तो वे सहअभाज्य क्यों नहीं हो सकते?

If (p) and (q) are both even, why can they not be coprime?

Explanation opens after your attempt
Correct Answer

A. क्योंकि दोनों में (2) साझा गुणनखंड होगाBecause both will have (2) as a common factor

Step 1

Concept

An even number is divisible by (2).

Step 2

Why this answer is correct

If both (p) and (q) are even, both have (2) as a common factor.

Step 3

Exam Tip

Coprime numbers do not have a common factor other than (1). चरण 1: सम संख्या (2) से विभाज्य होती है। चरण 2: यदि (p) और (q) दोनों सम हैं, तो दोनों में (2) साझा गुणनखंड है। चरण 3: सहअभाज्य संख्याओं में साझा गुणनखंड (1) के अलावा नहीं होता।

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