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In which proof are both (p) and (q) found even?

Answer and explanation

Correct answer: In the proof of (\sqrt{2})

Step 1: In the proof of (\sqrt{2}), we get (p^2=2q^2). Step 2: This makes both (p) and (q) even. Step 3: The common factor (2) creates the contradiction.

Related tags

Sqrt2 ProofEven NumbersClass 10Proof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematicsClass 10 Mcq

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