In the proof that (\sqrt{2}) is irrational, what conclusion is obtained after putting (p=2k)?
Answer and explanation
Correct answer: (q^2=2k^2), so (q) is even
Step 1: From (p^2=2q^2) and (p=2k), we get (4k^2=2q^2). Step 2: Simplifying gives (q^2=2k^2), so (q^2) and (q) are even. Step 3: This second evenness completes the contradiction.
Frequently asked questions
What is the correct answer to this question?
(q^2=2k^2), so (q) is even
Why is this the correct answer?
Step 1: From (p^2=2q^2) and (p=2k), we get (4k^2=2q^2). Step 2: Simplifying gives (q^2=2k^2), so (q^2) and (q) are even. Step 3: This second evenness completes the contradiction.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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