Concept-wise Practice

sum MCQ Questions for Class 10

sum se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

93 questions tagged with sum.

एक विद्यालय में पहले सप्ताह (35) पौधे लगाए गए और हर अगले सप्ताह (8) पौधे अधिक लगाए गए। (16) सप्ताहों में कुल कितने पौधे लगेंगे?

In a school (35) plants were planted in the first week and (8) more plants were planted each next week. How many plants will be planted in (16) weeks?

Explanation opens after your attempt
Correct Answer

B. (1520)

Step 1

Concept

Total plants are (S_{16}=8[70+15(8)]=1520). Exam tip: treat the weekly increase as the common difference.

Step 2

Why this answer is correct

The correct answer is B. (1520). Total plants are (S_{16}=8[70+15(8)]=1520). Exam tip: treat the weekly increase as the common difference.

Step 3

Exam Tip

कुल पौधे (S_{16}=8[70+15(8)]=1520) हैं। परीक्षा में साप्ताहिक वृद्धि को सार्व अंतर मानें।

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एक समान्तर श्रेणी के पहले (12) पदों का योग (516) है और (12)वाँ पद (75) है। प्रथम पद क्या है?

The sum of the first (12) terms of an arithmetic progression is (516) and the (12)th term is (75). What is the first term?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

Using (S_n=\frac{n}{2}(a+l)), (516=6(a+75)), so (a=11). Exam tip: when the last term is given, use the (a+l) form.

Step 2

Why this answer is correct

The correct answer is C. (11). Using (S_n=\frac{n}{2}(a+l)), (516=6(a+75)), so (a=11). Exam tip: when the last term is given, use the (a+l) form.

Step 3

Exam Tip

सूत्र (S_n=\frac{n}{2}(a+l)) से (516=6(a+75)) इसलिए (a=11)। परीक्षा में अंतिम पद दिया हो तो (a+l) वाला सूत्र तेज होता है।

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किसी समान्तर श्रेणी में प्रथम पद (7) और सार्व अंतर (5) है। यदि पहले (n) पदों का योग (1470) है तो (n) का मान क्या होगा?

In an arithmetic progression the first term is (7) and the common difference is (5). If the sum of the first (n) terms is (1470) then what is (n)?

Explanation opens after your attempt
Correct Answer

B. (24)

Step 1

Concept

Using (S_n=\frac{n}{2}[2a+(n-1)d]) gives (n=24). Exam tip: first reduce the equation to a simple quadratic.

Step 2

Why this answer is correct

The correct answer is B. (24). Using (S_n=\frac{n}{2}[2a+(n-1)d]) gives (n=24). Exam tip: first reduce the equation to a simple quadratic.

Step 3

Exam Tip

सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) लगाने पर (n=24) मिलता है। परीक्षा में पहले समीकरण को सरल वर्ग समीकरण में बदलें।

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किसी समांतर श्रेढ़ी का (n)वाँ पद \(a_n=7n-4\) है। पहले (80) पदों का योग ज्ञात कीजिए।

The (n)th term of an AP is \(a_n=7n-4\). Find the sum of the first (80) terms.

Explanation opens after your attempt
Correct Answer

C. (22360)

Step 1

Concept

The first term is (3), and the (80)th term is (556), so the sum is (22360). Finding the first and last terms from \(a_n\) is an easy method.

Step 2

Why this answer is correct

The correct answer is C. (22360). The first term is (3), and the (80)th term is (556), so the sum is (22360). Finding the first and last terms from \(a_n\) is an easy method.

Step 3

Exam Tip

पहला पद (3) और (80)वाँ पद (556) है, इसलिए योग (22360) है। \(a_n\) से पहला और अंतिम पद निकालना आसान तरीका है।

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समांतर श्रेढ़ी \(250,238,226,\ldots\) के पहले (30) पदों का योग ज्ञात कीजिए।

Find the sum of the first (30) terms of the AP \(250,238,226,\ldots\).

Explanation opens after your attempt
Correct Answer

D. (2280)

Step 1

Concept

The last term is (-98), and \(S_{30}=2280\). Once the last term is found, (S_n=\frac{n}{2}(a+l)) is faster.

Step 2

Why this answer is correct

The correct answer is D. (2280). The last term is (-98), and \(S_{30}=2280\). Once the last term is found, (S_n=\frac{n}{2}(a+l)) is faster.

Step 3

Exam Tip

अंतिम पद (-98) है और \(S_{30}=2280\) है। अंतिम पद मिल जाए तो (S_n=\frac{n}{2}(a+l)) तेज रहता है।

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समांतर श्रेढ़ी \(300,287,274,\ldots\) के पहले (35) पदों का योग ज्ञात कीजिए।

Find the sum of the first (35) terms of the AP \(300,287,274,\ldots\).

Explanation opens after your attempt
Correct Answer

D. (2765)

Step 1

Concept

Here (d=-13), and \(S_{35}=2765\). Do not forget the negative sign of the common difference in a decreasing AP.

Step 2

Why this answer is correct

The correct answer is D. (2765). Here (d=-13), and \(S_{35}=2765\). Do not forget the negative sign of the common difference in a decreasing AP.

Step 3

Exam Tip

यहाँ (d=-13) है और \(S_{35}=2765\) आता है। घटती श्रेढ़ी में सार्व अंतर का ऋणात्मक चिह्न न भूलें।

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किसी समांतर श्रेढ़ी में पहले (30) पदों का योग (3000) है और (30)वाँ पद (150) है। पहला पद ज्ञात कीजिए।

In an AP, the sum of the first (30) terms is (3000), and the (30)th term is (150). Find the first term.

Explanation opens after your attempt
Correct Answer

B. (50)

Step 1

Concept

From (3000=15(a+150)), (a=50). Treat the (n)th term as the last term of the first (n) terms.

Step 2

Why this answer is correct

The correct answer is B. (50). From (3000=15(a+150)), (a=50). Treat the (n)th term as the last term of the first (n) terms.

Step 3

Exam Tip

(3000=15(a+150)) से (a=50) मिलता है। (n)वें पद को पहले (n) पदों का अंतिम पद मानें।

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एक समांतर श्रेढ़ी का पहला पद (x) और सार्व अंतर (3x-2) है। यदि पहले (12) पदों का योग (1128) है, तो (x) का मान क्या है?

The first term of an AP is (x), and the common difference is (3x-2). If the sum of the first (12) terms is (1128), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From (1128=6[2x+11(3x-2)]), (x=6). In variable-based questions, write (a) and (d) clearly first.

Step 2

Why this answer is correct

The correct answer is B. (6). From (1128=6[2x+11(3x-2)]), (x=6). In variable-based questions, write (a) and (d) clearly first.

Step 3

Exam Tip

(1128=6[2x+11(3x-2)]) से (x=6) मिलता है। चर वाले प्रश्न में पहले (a) और (d) स्पष्ट लिखें।

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किसी समांतर श्रेढ़ी का (n)वाँ पद \(a_n=5n-2\) है। पहले (70) पदों का योग ज्ञात कीजिए।

The (n)th term of an AP is \(a_n=5n-2\). Find the sum of the first (70) terms.

Explanation opens after your attempt
Correct Answer

D. (12285)

Step 1

Concept

The first term is (3), and the (70)th term is (348), so the sum is (12285). Finding the first and last terms from \(a_n\) is an easy method.

Step 2

Why this answer is correct

The correct answer is D. (12285). The first term is (3), and the (70)th term is (348), so the sum is (12285). Finding the first and last terms from \(a_n\) is an easy method.

Step 3

Exam Tip

पहला पद (3) और (70)वाँ पद (348) है, इसलिए योग (12285) है। \(a_n\) से पहले और अंतिम पद निकालना आसान तरीका है।

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समांतर श्रेढ़ी \(140,132,124,\ldots\) के पहले (25) पदों का योग ज्ञात कीजिए।

Find the sum of the first (25) terms of the AP \(140,132,124,\ldots\).

Explanation opens after your attempt
Correct Answer

D. (1100)

Step 1

Concept

The last term is (-52), and \(S_{25}=1100\). Even in a decreasing AP, (S_n=\frac{n}{2}(a+l)) is useful.

Step 2

Why this answer is correct

The correct answer is D. (1100). The last term is (-52), and \(S_{25}=1100\). Even in a decreasing AP, (S_n=\frac{n}{2}(a+l)) is useful.

Step 3

Exam Tip

अंतिम पद (-52) है और \(S_{25}=1100\) है। घटती श्रेढ़ी में भी (S_n=\frac{n}{2}(a+l)) उपयोगी है।

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समांतर श्रेढ़ी \(160,151,142,\ldots\) के पहले (22) पदों का योग ज्ञात कीजिए।

Find the sum of the first (22) terms of the AP \(160,151,142,\ldots\).

Explanation opens after your attempt
Correct Answer

D. (1441)

Step 1

Concept

Here (d=-9), and the formula gives \(S_{22}=1441\). In a decreasing AP, write the common difference as negative.

Step 2

Why this answer is correct

The correct answer is D. (1441). Here (d=-9), and the formula gives \(S_{22}=1441\). In a decreasing AP, write the common difference as negative.

Step 3

Exam Tip

यहाँ (d=-9) है और सूत्र से \(S_{22}=1441\) मिलता है। घटती श्रेढ़ी में सार्व अंतर ऋणात्मक लिखें।

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समांतर श्रेढ़ी \(-12,-5,2,\ldots,184\) का योग ज्ञात कीजिए।

Find the sum of the AP \(-12,-5,2,\ldots,184\).

Explanation opens after your attempt
Correct Answer

D. (2494)

Step 1

Concept

First, (184=-12+(n-1)7) gives (n=29), and the sum is (2494). When the last term is given, find (n) first.

Step 2

Why this answer is correct

The correct answer is D. (2494). First, (184=-12+(n-1)7) gives (n=29), and the sum is (2494). When the last term is given, find (n) first.

Step 3

Exam Tip

पहले (184=-12+(n-1)7) से (n=29) मिलता है और योग (2494) है। अंतिम पद दिया हो तो पहले (n) निकालें।

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किसी समांतर श्रेढ़ी में पहले (25) पदों का योग (1625) है और (25)वाँ पद (113) है। पहला पद ज्ञात कीजिए।

In an AP, the sum of the first (25) terms is (1625), and the (25)th term is (113). Find the first term.

Explanation opens after your attempt
Correct Answer

A. (17)

Step 1

Concept

From (1625=\frac{25}{2}(a+113)), (a=17). Treat the (n)th term as the last term of the first (n) terms.

Step 2

Why this answer is correct

The correct answer is A. (17). From (1625=\frac{25}{2}(a+113)), (a=17). Treat the (n)th term as the last term of the first (n) terms.

Step 3

Exam Tip

(1625=\frac{25}{2}(a+113)) से (a=17) मिलता है। (n)वें पद को पहले (n) पदों का अंतिम पद मानें।

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एक समांतर श्रेढ़ी का पहला पद (x) और सार्व अंतर (2x+1) है। यदि पहले (10) पदों का योग (445) है, तो (x) का मान क्या है?

The first term of an AP is (x), and the common difference is (2x+1). If the sum of the first (10) terms is (445), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

D. (4)

Step 1

Concept

From (445=5[2x+9(2x+1)]), (x=4). In variable-based questions, write (a) and (d) clearly first.

Step 2

Why this answer is correct

The correct answer is D. (4). From (445=5[2x+9(2x+1)]), (x=4). In variable-based questions, write (a) and (d) clearly first.

Step 3

Exam Tip

(445=5[2x+9(2x+1)]) से (x=4) मिलता है। चर वाले प्रश्न में पहले (a) और (d) स्पष्ट लिखें।

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किसी समांतर श्रेढ़ी का (n)वाँ पद \(a_n=6n+5\) है। पहले (60) पदों का योग ज्ञात कीजिए।

The (n)th term of an AP is \(a_n=6n+5\). Find the sum of the first (60) terms.

Explanation opens after your attempt
Correct Answer

A. (11280)

Step 1

Concept

The first term is (11), and the (60)th term is (365), so the sum is (11280). Finding the first and last terms from \(a_n\) is an easy method.

Step 2

Why this answer is correct

The correct answer is A. (11280). The first term is (11), and the (60)th term is (365), so the sum is (11280). Finding the first and last terms from \(a_n\) is an easy method.

Step 3

Exam Tip

पहला पद (11) और (60)वाँ पद (365) है, इसलिए योग (11280) है। \(a_n\) से पहले और अंतिम पद निकालना आसान तरीका है।

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समांतर श्रेढ़ी \(95,89,83,\ldots\) के पहले (20) पदों का योग ज्ञात कीजिए।

Find the sum of the first (20) terms of the AP \(95,89,83,\ldots\).

Explanation opens after your attempt
Correct Answer

B. (760)

Step 1

Concept

The last term is (-19), and \(S_{20}=760\). Even in a decreasing AP, (S_n=\frac{n}{2}(a+l)) is useful.

Step 2

Why this answer is correct

The correct answer is B. (760). The last term is (-19), and \(S_{20}=760\). Even in a decreasing AP, (S_n=\frac{n}{2}(a+l)) is useful.

Step 3

Exam Tip

अंतिम पद (-19) है और \(S_{20}=760\) है। घटती श्रेढ़ी में भी (S_n=\frac{n}{2}(a+l)) उपयोगी है।

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समांतर श्रेढ़ी \(120,113,106,\ldots\) के पहले (25) पदों का योग ज्ञात कीजिए।

Find the sum of the first (25) terms of the AP \(120,113,106,\ldots\).

Explanation opens after your attempt
Correct Answer

C. (900)

Step 1

Concept

Here (d=-7), and the formula gives \(S_{25}=900\). In a decreasing AP, write the common difference as negative.

Step 2

Why this answer is correct

The correct answer is C. (900). Here (d=-7), and the formula gives \(S_{25}=900\). In a decreasing AP, write the common difference as negative.

Step 3

Exam Tip

यहाँ (d=-7) है और सूत्र से \(S_{25}=900\) मिलता है। घटती श्रेढ़ी में सार्व अंतर ऋणात्मक लिखें।

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समांतर श्रेढ़ी \(-6,1,8,\ldots,169\) का योग ज्ञात कीजिए।

Find the sum of the AP \(-6,1,8,\ldots,169\).

Explanation opens after your attempt
Correct Answer

C. (2119)

Step 1

Concept

First, (169=-6+(n-1)7) gives (n=26), and the sum is (2119). When the last term is given, find (n) first.

Step 2

Why this answer is correct

The correct answer is C. (2119). First, (169=-6+(n-1)7) gives (n=26), and the sum is (2119). When the last term is given, find (n) first.

Step 3

Exam Tip

पहले (169=-6+(n-1)7) से (n=26) मिलता है और योग (2119) है। अंतिम पद दिया हो तो पहले (n) निकालें।

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किसी समांतर श्रेढ़ी में पहले (20) पदों का योग (740) है और (20)वाँ पद (60) है। पहला पद ज्ञात कीजिए।

In an AP, the sum of the first (20) terms is (740), and the (20)th term is (60). Find the first term.

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.

Step 2

Why this answer is correct

The correct answer is B. (14). From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.

Step 3

Exam Tip

(740=10(a+60)) से (a=14) मिलता है। जब (n)वाँ पद दिया हो तो उसे अंतिम पद की तरह इस्तेमाल करें।

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एक समांतर श्रेढ़ी का पहला पद (x) और सार्व अंतर (x+2) है। यदि पहले (10) पदों का योग (365) है, तो (x) का मान क्या है?

The first term of an AP is (x), and the common difference is (x+2). If the sum of the first (10) terms is (365), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

From (365=5[2x+9(x+2)]), (x=5). In variable-based questions, write (a) and (d) clearly first.

Step 2

Why this answer is correct

The correct answer is A. (5). From (365=5[2x+9(x+2)]), (x=5). In variable-based questions, write (a) and (d) clearly first.

Step 3

Exam Tip

(365=5[2x+9(x+2)]) से (x=5) मिलता है। चर वाले प्रश्न में पहले (a) और (d) को साफ लिखें।

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किसी समांतर श्रेढ़ी का (n)वाँ पद \(a_n=4n-1\) है। पहले (50) पदों का योग ज्ञात कीजिए।

The (n)th term of an AP is \(a_n=4n-1\). Find the sum of the first (50) terms.

Explanation opens after your attempt
Correct Answer

A. (5050)

Step 1

Concept

The first term is (3), and the (50)th term is (199), so the sum is (5050). Finding the first and last terms from \(a_n\) is an easy method.

Step 2

Why this answer is correct

The correct answer is A. (5050). The first term is (3), and the (50)th term is (199), so the sum is (5050). Finding the first and last terms from \(a_n\) is an easy method.

Step 3

Exam Tip

पहला पद (3) और (50)वाँ पद (199) है, इसलिए योग (5050) है। \(a_n\) से पहले और अंतिम पद निकालना आसान तरीका है।

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समांतर श्रेढ़ी \(12,18,24,\ldots,192\) का योग ज्ञात कीजिए।

Find the sum of the AP \(12,18,24,\ldots,192\).

Explanation opens after your attempt
Correct Answer

C. (3162)

Step 1

Concept

First, (192=12+(n-1)6) gives (n=31), and the sum is (3162). When the last term is given, find the number of terms first.

Step 2

Why this answer is correct

The correct answer is C. (3162). First, (192=12+(n-1)6) gives (n=31), and the sum is (3162). When the last term is given, find the number of terms first.

Step 3

Exam Tip

पहले (192=12+(n-1)6) से (n=31) मिलता है और योग (3162) है। अंतिम पद हो तो पहले पदों की संख्या निकालें।

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समांतर श्रेढ़ी \(8,13,18,\ldots,83\) का योग ज्ञात कीजिए।

Find the sum of the AP \(8,13,18,\ldots,83\).

Explanation opens after your attempt
Correct Answer

B. (728)

Step 1

Concept

First find (n): (83=8+(n-1)5), so (n=16) and the sum is (728). When the last term is given, find the number of terms first.

Step 2

Why this answer is correct

The correct answer is B. (728). First find (n): (83=8+(n-1)5), so (n=16) and the sum is (728). When the last term is given, find the number of terms first.

Step 3

Exam Tip

पहले (n) निकालें: (83=8+(n-1)5), इसलिए (n=16) और योग (728) है। अंतिम पद होने पर पहले पदों की संख्या निकालें।

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यदि पहले (n) प्राकृतिक संख्याओं का योग (465) है, तो (n) क्या होगा?

If the sum of the first (n) natural numbers is (465), what is (n)?

Explanation opens after your attempt
Correct Answer

C. (30)

Step 1

Concept

From (\frac{n(n+1)}{2}=465), (n=30). The sum of natural numbers is a special case of AP.

Step 2

Why this answer is correct

The correct answer is C. (30). From (\frac{n(n+1)}{2}=465), (n=30). The sum of natural numbers is a special case of AP.

Step 3

Exam Tip

(\frac{n(n+1)}{2}=465) से (n=30) आता है। प्राकृतिक संख्याओं का योग भी समांतर श्रेढ़ी का विशेष रूप है।

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समांतर श्रेढ़ी \(100,95,90,\ldots\) के पहले (12) पदों का योग ज्ञात कीजिए।

Find the sum of the first (12) terms of the AP \(100,95,90,\ldots\).

Explanation opens after your attempt
Correct Answer

A. (870)

Step 1

Concept

The last term is (45), so (S_{12}=\frac{12}{2}(100+45)=870). Once the last term is found, the sum is quick.

Step 2

Why this answer is correct

The correct answer is A. (870). The last term is (45), so (S_{12}=\frac{12}{2}(100+45)=870). Once the last term is found, the sum is quick.

Step 3

Exam Tip

अंतिम पद (45) है, इसलिए (S_{12}=\frac{12}{2}(100+45)=870)। अंतिम पद मिल जाए तो योग तेजी से निकलेगा।

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समांतर श्रेढ़ी \(31,28,25,\ldots\) के पहले (20) पदों का योग ज्ञात कीजिए।

Find the sum of the first (20) terms of the AP \(31,28,25,\ldots\).

Explanation opens after your attempt
Correct Answer

A. (50)

Step 1

Concept

Here the last term is (-26), and \(S_{20}=50\). In a decreasing AP, the sum can become quite small.

Step 2

Why this answer is correct

The correct answer is A. (50). Here the last term is (-26), and \(S_{20}=50\). In a decreasing AP, the sum can become quite small.

Step 3

Exam Tip

यहाँ अंतिम पद (-26) है और \(S_{20}=50\) मिलता है। घटती श्रेढ़ी में योग बहुत छोटा भी हो सकता है।

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यदि किसी समांतर श्रेढ़ी का पहला पद (11), अंतिम पद (71) और योग (574) है, तो पदों की संख्या क्या है?

If an AP has first term (11), last term (71), and sum (574), what is the number of terms?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.

Step 2

Why this answer is correct

The correct answer is C. (14). From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.

Step 3

Exam Tip

(\frac{n}{2}(11+71)=574) से (n=14) मिलता है। अंतिम पद दिए होने पर सार्व अंतर की जरूरत नहीं होती।

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समांतर श्रेणी \(90,84,78,\ldots\) के पहले (6) पदों का योग कितना होगा?

What will be the sum of the first (6) terms of the arithmetic progression \(90,84,78,\ldots\)?

Explanation opens after your attempt
Correct Answer

B. (450)

Step 1

Concept

The sixth term is (60), so (S_6=\frac{6}{2}(90+60)=450). In decreasing order, calculate the last term carefully.

Step 2

Why this answer is correct

The correct answer is B. (450). The sixth term is (60), so (S_6=\frac{6}{2}(90+60)=450). In decreasing order, calculate the last term carefully.

Step 3

Exam Tip

छठा पद (60) है, इसलिए (S_6=\frac{6}{2}(90+60)=450)। घटते क्रम में अंतिम पद की गणना ध्यान से करें।

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पहले (28) प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (28) natural numbers.

Explanation opens after your attempt
Correct Answer

C. (406)

Step 1

Concept

\(\frac{28\times29}{2}=406\), so the sum is (406). The natural-number sum formula gives a quick answer.

Step 2

Why this answer is correct

The correct answer is C. (406). \(\frac{28\times29}{2}=406\), so the sum is (406). The natural-number sum formula gives a quick answer.

Step 3

Exam Tip

\(\frac{28\times29}{2}=406\), इसलिए योग (406) है। प्राकृतिक संख्याओं का योग सूत्र जल्दी उत्तर देता है।

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पहले (17) सम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।

Find the sum of the first (17) even natural numbers.

Explanation opens after your attempt
Correct Answer

B. (306)

Step 1

Concept

The sum of the first (n) even numbers is (n(n+1)), so \(17\times18=306\). Do not confuse (n) with the last even number.

Step 2

Why this answer is correct

The correct answer is B. (306). The sum of the first (n) even numbers is (n(n+1)), so \(17\times18=306\). Do not confuse (n) with the last even number.

Step 3

Exam Tip

पहले (n) सम संख्याओं का योग (n(n+1)) है, इसलिए \(17\times18=306\)। (n) को अंतिम सम संख्या न समझें।

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