समांतर श्रेणी \(40,36,32,\ldots\) के पहले (8) पदों का योग ज्ञात कीजिए।
Find the sum of the first (8) terms of the arithmetic progression \(40,36,32,\ldots\).
#decreasing_ap
#sum
#negative_difference
A (208)
B (216)
C (224)
D (232)
Explanation opens after your attempt
Step 1
Concept
The eighth term is (12), so (S_8=\frac{8}{2}(40+12)=208). In a decreasing progression, take the difference as negative.
Step 2
Why this answer is correct
The correct answer is A. (208). The eighth term is (12), so (S_8=\frac{8}{2}(40+12)=208). In a decreasing progression, take the difference as negative.
Step 3
Exam Tip
आठवाँ पद (12) है, इसलिए (S_8=\frac{8}{2}(40+12)=208)। घटती श्रेणी में अंतर ऋणात्मक लें।
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पहले (15) विषम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।
Find the sum of the first (15) odd natural numbers.
#odd_numbers
#sum
#ap
A (215)
B (220)
C (225)
D (230)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) odd numbers is \(n^2\), so \(15^2=225\). This short formula saves time in exams.
Step 2
Why this answer is correct
The correct answer is C. (225). The sum of the first (n) odd numbers is \(n^2\), so \(15^2=225\). This short formula saves time in exams.
Step 3
Exam Tip
पहले (n) विषम संख्याओं का योग \(n^2\) होता है, इसलिए \(15^2=225\)। यह छोटा सूत्र परीक्षा में समय बचाता है।
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समांतर श्रेणी \(15,19,23,\ldots\) के पहले (10) पदों का योग क्या है?
What is the sum of the first (10) terms of the arithmetic progression \(15,19,23,\ldots\)?
#ap
#sum
#last_term
A (310)
B (320)
C (330)
D (340)
Explanation opens after your attempt
Step 1
Concept
The tenth term is (51), so (S_{10}=\frac{10}{2}(15+51)=330). Finding the last term first is an easy method.
Step 2
Why this answer is correct
The correct answer is C. (330). The tenth term is (51), so (S_{10}=\frac{10}{2}(15+51)=330). Finding the last term first is an easy method.
Step 3
Exam Tip
दसवाँ पद (51) है, इसलिए (S_{10}=\frac{10}{2}(15+51)=330)। अंतिम पद निकालकर योग लेना आसान तरीका है।
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यदि किसी समांतर श्रेणी में पहला पद (4), अंतर (5) और पदों की संख्या (13) है, तो पहले (13) पदों का योग कितना होगा?
If an arithmetic progression has first term (4), common difference (5), and (13) terms, what is the sum of the first (13) terms?
#ap
#sum
#formula
A (422)
B (432)
C (442)
D (452)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get \(S_{13}=442\). Write ((n-1)d) carefully in the formula.
Step 2
Why this answer is correct
The correct answer is C. (442). Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get \(S_{13}=442\). Write ((n-1)d) carefully in the formula.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) से \(S_{13}=442\) मिलता है। सूत्र में ((n-1)d) ध्यान से लिखें।
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समांतर श्रेणी \(6,9,12,\ldots\) के पहले (14) पदों का योग ज्ञात कीजिए।
Find the sum of the first (14) terms of the arithmetic progression \(6,9,12,\ldots\).
#ap
#sum
#first_n_terms
A (347)
B (357)
C (367)
D (377)
Explanation opens after your attempt
Step 1
Concept
Here (a=6), (d=3), and (n=14), so \(S_{14}=357\). First identify (a), (d), and (n).
Step 2
Why this answer is correct
The correct answer is B. (357). Here (a=6), (d=3), and (n=14), so \(S_{14}=357\). First identify (a), (d), and (n).
Step 3
Exam Tip
यहाँ (a=6), (d=3), (n=14) है, इसलिए \(S_{14}=357\)। पहले (a), (d), (n) पहचानना सबसे जरूरी है।
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समांतर श्रेढ़ी \(17,23,29,\ldots\) के पहले (8) पदों का योग ज्ञात कीजिए।
Find the sum of the first (8) terms of the arithmetic progression \(17,23,29,\ldots\).
#ap
#sum
#first_n_terms
A (296)
B (304)
C (312)
D (320)
Explanation opens after your attempt
Step 1
Concept
The eighth term is (59), so (S_8=\frac{8}{2}(17+59)=304). Finding the last term first makes the sum easier.
Step 2
Why this answer is correct
The correct answer is B. (304). The eighth term is (59), so (S_8=\frac{8}{2}(17+59)=304). Finding the last term first makes the sum easier.
Step 3
Exam Tip
आठवाँ पद (59) है, इसलिए (S_8=\frac{8}{2}(17+59)=304)। पहले अंतिम पद निकालकर योग लेना आसान रहता है।
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समांतर श्रेढ़ी \(40,37,34,\ldots\) के पहले (10) पदों का योग ज्ञात कीजिए।
Find the sum of the first (10) terms of the arithmetic progression \(40,37,34,\ldots\).
#decreasing_ap
#sum
#ten_terms
A (265)
B (275)
C (285)
D (295)
Explanation opens after your attempt
Step 1
Concept
The tenth term is (13), so (S_{10}=\frac{10}{2}(40+13)=265). In a decreasing progression, the last term is smaller.
Step 2
Why this answer is correct
The correct answer is A. (265). The tenth term is (13), so (S_{10}=\frac{10}{2}(40+13)=265). In a decreasing progression, the last term is smaller.
Step 3
Exam Tip
दसवाँ पद (13) है, इसलिए (S_{10}=\frac{10}{2}(40+13)=265)। घटती श्रेढ़ी में अंतिम पद कम होता है।
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समांतर श्रेढ़ी \(50,45,40,\ldots\) के पहले (9) पदों का योग कितना है?
What is the sum of the first (9) terms of the arithmetic progression \(50,45,40,\ldots\)?
#decreasing_ap
#sum
#nine_terms
A (260)
B (270)
C (280)
D (290)
Explanation opens after your attempt
Step 1
Concept
The ninth term is (10), so (S_9=\frac{9}{2}(50+10)=270). Because the difference is negative, the last term will be smaller.
Step 2
Why this answer is correct
The correct answer is B. (270). The ninth term is (10), so (S_9=\frac{9}{2}(50+10)=270). Because the difference is negative, the last term will be smaller.
Step 3
Exam Tip
नौवाँ पद (10) है, इसलिए (S_9=\frac{9}{2}(50+10)=270)। ऋणात्मक अंतर के कारण अंतिम पद कम होगा।
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पहले (12) विषम प्राकृतिक संख्याओं का योग क्या है?
What is the sum of the first (12) odd natural numbers?
#odd_numbers
#sum
#ap
A (121)
B (132)
C (144)
D (156)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) odd numbers is \(n^2\), so \(12^2=144\). This pattern gives a quick answer.
Step 2
Why this answer is correct
The correct answer is C. (144). The sum of the first (n) odd numbers is \(n^2\), so \(12^2=144\). This pattern gives a quick answer.
Step 3
Exam Tip
पहले (n) विषम संख्याओं का योग \(n^2\) होता है, इसलिए \(12^2=144\)। यह पैटर्न जल्दी उत्तर देता है।
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पहले (30) प्राकृतिक संख्याओं का योग कितना है?
What is the sum of the first (30) natural numbers?
#natural_numbers
#sum
#ap
A (435)
B (445)
C (455)
D (465)
Explanation opens after your attempt
Step 1
Concept
\(\frac{30\times31}{2}=465\), so the correct sum is (465). Remember the direct formula for natural numbers.
Step 2
Why this answer is correct
The correct answer is D. (465). \(\frac{30\times31}{2}=465\), so the correct sum is (465). Remember the direct formula for natural numbers.
Step 3
Exam Tip
\(\frac{30\times31}{2}=465\), इसलिए सही योग (465) है। प्राकृतिक संख्याओं के लिए सीधा सूत्र याद रखें।
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समांतर श्रेढ़ी \(4,9,14,\ldots\) के पहले (16) पदों का योग ज्ञात करें।
Find the sum of the first (16) terms of the arithmetic progression \(4,9,14,\ldots\).
#ap
#sum
#sixteen_terms
A (656)
B (664)
C (672)
D (680)
Explanation opens after your attempt
Step 1
Concept
Here (a=4), (d=5), and (n=16), so \(S_{16}=664\). For larger sums, write the steps separately.
Step 2
Why this answer is correct
The correct answer is B. (664). Here (a=4), (d=5), and (n=16), so \(S_{16}=664\). For larger sums, write the steps separately.
Step 3
Exam Tip
यहाँ (a=4), (d=5), (n=16), इसलिए \(S_{16}=664\)। बड़े योग में चरणों को अलग-अलग लिखें।
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समांतर श्रेढ़ी \(30,25,20,\ldots\) के पहले (5) पदों का योग क्या है?
What is the sum of the first (5) terms of the arithmetic progression \(30,25,20,\ldots\)?
#decreasing_ap
#sum
#five_terms
A (90)
B (95)
C (100)
D (105)
Explanation opens after your attempt
Step 1
Concept
The first (5) terms are (30,25,20,15,10), so the sum is (100). In easy questions, writing the terms can also verify the answer.
Step 2
Why this answer is correct
The correct answer is C. (100). The first (5) terms are (30,25,20,15,10), so the sum is (100). In easy questions, writing the terms can also verify the answer.
Step 3
Exam Tip
पहले (5) पद (30,25,20,15,10) हैं, इसलिए योग (100) है। आसान प्रश्न में पद लिखकर भी जाँच सकते हैं।
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समांतर श्रेढ़ी \(1,4,7,\ldots\) के पहले (11) पदों का योग कितना होगा?
What will be the sum of the first (11) terms of the arithmetic progression \(1,4,7,\ldots\)?
#ap
#sum
#eleven_terms
A (171)
B (176)
C (181)
D (186)
Explanation opens after your attempt
Step 1
Concept
Here (a=1), (d=3), and (n=11), so \(S_{11}=176\). For an odd number of terms, you can also check using the middle term.
Step 2
Why this answer is correct
The correct answer is B. (176). Here (a=1), (d=3), and (n=11), so \(S_{11}=176\). For an odd number of terms, you can also check using the middle term.
Step 3
Exam Tip
यहाँ (a=1), (d=3), (n=11), इसलिए \(S_{11}=176\)। विषम संख्या के पदों में मध्य पद से भी योग जाँच सकते हैं।
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यदि (S_n=\frac{n}{2}[2a+(n-1)d]), (a=9), (d=1), और (n=14) है, तो \(S_n\) का मान क्या है?
If (S_n=\frac{n}{2}[2a+(n-1)d]), (a=9), (d=1), and (n=14), what is the value of \(S_n\)?
#ap
#sum
#formula_value
A (217)
B (343)
C (224)
D (231)
Explanation opens after your attempt
Step 1
Concept
Substituting gives (S_{14}=\frac{14}{2}(18+13)=217). In questions with simple differences, calculate carefully.
Step 2
Why this answer is correct
The correct answer is A. (217). Substituting gives (S_{14}=\frac{14}{2}(18+13)=217). In questions with simple differences, calculate carefully.
Step 3
Exam Tip
मान रखने पर (S_{14}=\frac{14}{2}(18+13)=217)। सरल अंतर वाले प्रश्न में गणना ध्यान से करें।
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समांतर श्रेढ़ी \(20,18,16,\ldots\) के पहले (6) पदों का योग क्या होगा?
What will be the sum of the first (6) terms of the arithmetic progression \(20,18,16,\ldots\)?
#decreasing_ap
#sum
#average
A (80)
B (85)
C (90)
D (95)
Explanation opens after your attempt
Step 1
Concept
The first (6) terms go from (20) to (10), and the average is (15), so the sum is (90). The average of equally spaced terms is useful.
Step 2
Why this answer is correct
The correct answer is C. (90). The first (6) terms go from (20) to (10), and the average is (15), so the sum is (90). The average of equally spaced terms is useful.
Step 3
Exam Tip
पहले (6) पद (20) से (10) तक हैं और औसत (15) है, इसलिए योग (90) है। समान दूरी वाले पदों का औसत उपयोगी होता है।
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यदि किसी समांतर श्रेढ़ी में \(S_5=50\) और \(S_{10}=175\) है, तो छठे से दसवें पदों का योग कितना है?
If an arithmetic progression has \(S_5=50\) and \(S_{10}=175\), what is the sum of the (6)th to (10)th terms?
#partial_sum
#ap
#sum
A (115)
B (120)
C (125)
D (130)
Explanation opens after your attempt
Step 1
Concept
The sum of the (6)th to (10)th terms is \(S_{10}-S_5=125\). Use subtraction for partial sums.
Step 2
Why this answer is correct
The correct answer is C. (125). The sum of the (6)th to (10)th terms is \(S_{10}-S_5=125\). Use subtraction for partial sums.
Step 3
Exam Tip
छठे से दसवें पदों का योग \(S_{10}-S_5=125\) है। आंशिक योग में घटाव का प्रयोग करें।
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समांतर श्रेढ़ी \(3,7,11,\ldots\) के पहले (20) पदों का योग ज्ञात कीजिए।
Find the sum of the first (20) terms of the arithmetic progression \(3,7,11,\ldots\).
#ap
#sum
#twenty_terms
A (800)
B (810)
C (820)
D (830)
Explanation opens after your attempt
Step 1
Concept
Here the last term is (79), and (S_{20}=\frac{20}{2}(3+79)=820). Finding the last term can often be easier.
Step 2
Why this answer is correct
The correct answer is C. (820). Here the last term is (79), and (S_{20}=\frac{20}{2}(3+79)=820). Finding the last term can often be easier.
Step 3
Exam Tip
यहाँ अंतिम पद (79) है और (S_{20}=\frac{20}{2}(3+79)=820)। अंतिम पद निकालना कई बार आसान होता है।
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एक समांतर श्रेढ़ी का प्रथम पद (6), अंतिम पद (60) और कुल पद (10) हैं। उसका योग कितना है?
An arithmetic progression has first term (6), last term (60), and (10) terms. What is its sum?
#ap
#sum
#first_last
A (320)
B (330)
C (340)
D (350)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=330\). If the last term is given, finding (d) is not necessary.
Step 2
Why this answer is correct
The correct answer is B. (330). Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=330\). If the last term is given, finding (d) is not necessary.
Step 3
Exam Tip
(S_n=\frac{n}{2}(a+l)) से \(S_{10}=330\)। अंतिम पद मिले तो (d) निकालना जरूरी नहीं।
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समांतर श्रेढ़ी \(12,10,8,\ldots\) के पहले (7) पदों का योग कितना है?
What is the sum of the first (7) terms of the arithmetic progression \(12,10,8,\ldots\)?
#decreasing_ap
#sum
#negative_difference
A (40)
B (42)
C (44)
D (46)
Explanation opens after your attempt
Step 1
Concept
This is a decreasing progression with (d=-2), so \(S_7=42\). In a decreasing progression, take the common difference as negative.
Step 2
Why this answer is correct
The correct answer is B. (42). This is a decreasing progression with (d=-2), so \(S_7=42\). In a decreasing progression, take the common difference as negative.
Step 3
Exam Tip
यह घटती हुई श्रेढ़ी है जहाँ (d=-2), इसलिए \(S_7=42\)। घटती श्रेढ़ी में अंतर ऋणात्मक लें।
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यदि (a=4), (d=6) और (n=9) है, तो समांतर श्रेढ़ी के पहले (9) पदों का योग ज्ञात करें।
If (a=4), (d=6), and (n=9), find the sum of the first (9) terms of the arithmetic progression.
#ap
#sum
#formula
A (248)
B (250)
C (252)
D (256)
Explanation opens after your attempt
Step 1
Concept
Substituting values gives \(S_9=\frac{9}{2}[8+48]=252\). Simplify inside the bracket first.
Step 2
Why this answer is correct
The correct answer is C. (252). Substituting values gives \(S_9=\frac{9}{2}[8+48]=252\). Simplify inside the bracket first.
Step 3
Exam Tip
सूत्र में मान रखने पर \(S_9=\frac{9}{2}[8+48]=252\)। कोष्ठक के अंदर पहले सरल करें।
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समांतर श्रेढ़ी \(10,15,20,\ldots\) के पहले (8) पदों का योग क्या है?
What is the sum of the first (8) terms of the arithmetic progression \(10,15,20,\ldots\)?
#ap
#sum
#common_difference
A (210)
B (220)
C (230)
D (240)
Explanation opens after your attempt
Step 1
Concept
Here (a=10), (d=5), and (n=8), so the sum is (220). For small (n), you can also check by finding the last term.
Step 2
Why this answer is correct
The correct answer is B. (220). Here (a=10), (d=5), and (n=8), so the sum is (220). For small (n), you can also check by finding the last term.
Step 3
Exam Tip
यहाँ (a=10), (d=5), (n=8) है, इसलिए योग (220) है। छोटे (n) में अंतिम पद निकालकर भी जाँच सकते हैं।
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पहले (25) सम प्राकृतिक संख्याओं का योग कितना होगा?
What will be the sum of the first (25) even natural numbers?
#even_numbers
#ap
#sum
A (600)
B (625)
C (650)
D (675)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) even numbers is (n(n+1)), so \(25\times26=650\). For even numbers, start from \(2,4,6,\ldots\).
Step 2
Why this answer is correct
The correct answer is C. (650). The sum of the first (n) even numbers is (n(n+1)), so \(25\times26=650\). For even numbers, start from \(2,4,6,\ldots\).
Step 3
Exam Tip
पहले (n) सम संख्याओं का योग (n(n+1)) होता है, इसलिए \(25\times26=650\)। सम संख्याओं में \(2,4,6,\ldots\) से शुरू करें।
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पहले (18) विषम प्राकृतिक संख्याओं का योग ज्ञात कीजिए।
Find the sum of the first (18) odd natural numbers.
#odd_numbers
#ap
#sum
A (324)
B (342)
C (360)
D (378)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) odd numbers is \(n^2\), so \(18^2=324\). This is a quick exam formula.
Step 2
Why this answer is correct
The correct answer is A. (324). The sum of the first (n) odd numbers is \(n^2\), so \(18^2=324\). This is a quick exam formula.
Step 3
Exam Tip
पहले (n) विषम संख्याओं का योग \(n^2\) होता है, इसलिए \(18^2=324\)। यह एक तेज परीक्षा सूत्र है।
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यदि किसी समांतर श्रेढ़ी का पहला पद (7), अंतिम पद (43) और कुल पद (10) हैं, तो योग क्या होगा?
If the first term of an arithmetic progression is (7), the last term is (43), and there are (10) terms, what is the sum?
#ap
#sum
#last_term
A (240)
B (250)
C (260)
D (270)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), we get \(S_{10}=250\). When the last term is given, this formula is faster.
Step 2
Why this answer is correct
The correct answer is B. (250). Using (S_n=\frac{n}{2}(a+l)), we get \(S_{10}=250\). When the last term is given, this formula is faster.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}(a+l)) से \(S_{10}=250\) आता है। जब अंतिम पद दिया हो तो यह सूत्र तेज है।
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समांतर श्रेढ़ी \(2,6,10,\ldots\) के पहले (15) पदों का योग कितना है?
What is the sum of the first (15) terms of the arithmetic progression \(2,6,10,\ldots\)?
#ap
#sum
#easy_mcq
A (420)
B (430)
C (450)
D (460)
Explanation opens after your attempt
Step 1
Concept
Here (a=2), (d=4), and (n=15), so \(S_{15}=450\). Do not forget to use (n-1) in the formula.
Step 2
Why this answer is correct
The correct answer is C. (450). Here (a=2), (d=4), and (n=15), so \(S_{15}=450\). Do not forget to use (n-1) in the formula.
Step 3
Exam Tip
यहाँ (a=2), (d=4), (n=15) है, इसलिए \(S_{15}=450\)। सूत्र में (n-1) लिखना न भूलें।
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समांतर श्रेढ़ी \(5,8,11,\ldots\) के पहले (12) पदों का योग ज्ञात कीजिए।
Find the sum of the first (12) terms of the arithmetic progression \(5,8,11,\ldots\).
#ap
#sum
#arithmetic_progression
A (246)
B (258)
C (266)
D (276)
Explanation opens after your attempt
Step 1
Concept
Here (a=5), (d=3), and (n=12), so \(S_{12}=258\). Taking the correct number of terms is important.
Step 2
Why this answer is correct
The correct answer is B. (258). Here (a=5), (d=3), and (n=12), so \(S_{12}=258\). Taking the correct number of terms is important.
Step 3
Exam Tip
यहाँ (a=5), (d=3), (n=12) है, इसलिए \(S_{12}=258\)। पदों की संख्या को सही लेना जरूरी है।
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यदि किसी समांतर श्रेढ़ी में प्रथम पद (a=3), अंतर (d=2) और पदों की संख्या (n=10) है, तो पहले (10) पदों का योग कितना होगा?
If an arithmetic progression has first term (a=3), common difference (d=2), and number of terms (n=10), what is the sum of the first (10) terms?
#ap
#sum
#n_terms
#class10
A (120)
B (110)
C (100)
D (90)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get \(S_{10}=120\). In exams, first identify (a), (d), and (n).
Step 2
Why this answer is correct
The correct answer is A. (120). Using (S_n=\frac{n}{2}[2a+(n-1)d]), we get \(S_{10}=120\). In exams, first identify (a), (d), and (n).
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) लगाने पर \(S_{10}=120\) मिलता है। परीक्षा में पहले (a), (d), (n) पहचानें।
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यदि \(9,9,9,\ldots\) को \(2,5,8,\ldots\) से पद-दर-पद जोड़ा जाए तो नए अनुक्रम का (d) क्या होगा?
If \(9,9,9,\ldots\) is added term by term to \(2,5,8,\ldots\), what will be (d) of the new sequence?
#ap
#constant sequence
#sum
#hard
A (0)
B (3)
C (9)
D (12)
Explanation opens after your attempt
Step 1
Concept
The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).
Step 2
Why this answer is correct
The correct answer is B. (3). The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).
Step 3
Exam Tip
स्थिर अनुक्रम का (d=0) है और दूसरे का (d=3) है, इसलिए योग का (d=3)। स्थिर अनुक्रम जोड़ने से (d) नहीं बदलता।
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यदि \(5, 5, 5,\ldots\) को \(2, 4, 6,\ldots\) से पद-दर-पद जोड़ा जाए, तो नए अनुक्रम का (d) क्या होगा?
If \(5, 5, 5,\ldots\) is added term by term to \(2, 4, 6,\ldots\), what will be (d) of the new sequence?
#ap
#constant sequence
#sum
#hard
A (0)
B (2)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
The first sequence has (d=0) and the second has (d=2), so the new (d=2). Adding a constant sequence does not change (d).
Step 2
Why this answer is correct
The correct answer is B. (2). The first sequence has (d=0) and the second has (d=2), so the new (d=2). Adding a constant sequence does not change (d).
Step 3
Exam Tip
पहले अनुक्रम का (d=0) और दूसरे का (d=2) है, इसलिए नया (d=2)। स्थिर अनुक्रम जोड़ने से (d) नहीं बदलता।
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यदि (p(x)=x-2 -(m+3)x+12) के शून्यक (3) और (4) हैं, तो (m) का मान क्या है?
If the zeroes of (p(x)=x-2 -(m+3)x+12) are (3) and (4), what is (m)?
#polynomials
#zeroes
#sum
#hard
A (3)
B (4)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
The sum of zeroes is (7), which equals (m+3). Therefore, (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). The sum of zeroes is (7), which equals (m+3). Therefore, (m=4).
Step 3
Exam Tip
शून्यकों का योग (7) है और यह (m+3) के बराबर है। इसलिए (m=4) मिलेगा।
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