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Class 10 Mathematics - Arithmetic Progressions (AP) - Introduction to APs and common difference. Hard Quiz

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यदि (2x+1, x+8, 3x-4) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (x) का मान क्या है?

If (2x+1, x+8, 3x-4) are consecutive terms of an arithmetic progression, what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

In three consecutive terms, twice the middle term equals the sum of the other two terms. So (2(x+8)=(2x+1)+(3x-4)) gives (x=3).

Step 2

Why this answer is correct

The correct answer is B. (3). In three consecutive terms, twice the middle term equals the sum of the other two terms. So (2(x+8)=(2x+1)+(3x-4)) gives (x=3).

Step 3

Exam Tip

तीन क्रमागत पदों में (2) गुना मध्य पद बाकी दो पदों के योग के बराबर होता है। इसलिए (2(x+8)=(2x+1)+(3x-4)) से (x=3)।

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यदि (5a-2, 3a+6, a+18) अंकगणितीय श्रेणी में हैं तो सार्व अंतर क्या होगा?

If (5a-2, 3a+6, a+18) are in an arithmetic progression, what will be the common difference?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

(2(3a+6)=(5a-2)+(a+18)) gives (a=2). Then the terms (8,12,20) do not have equal differences, so no arithmetic progression is formed.

Step 2

Why this answer is correct

The correct answer is B. (4). (2(3a+6)=(5a-2)+(a+18)) gives (a=2). Then the terms (8,12,20) do not have equal differences, so no arithmetic progression is formed.

Step 3

Exam Tip

(2(3a+6)=(5a-2)+(a+18)) से (a=2) मिलता है। तब पद (8,12,20) नहीं बल्कि (8,12,20) समान अंतर नहीं देते, इसलिए सही जांच से कोई अंकगणितीय श्रेणी नहीं बनती।

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किस (p) के लिए \(4,4+p,4+3p,4+6p,\ldots\) अंकगणितीय श्रेणी होगी?

For which (p) will \(4,4+p,4+3p,4+6p,\ldots\) be an arithmetic progression?

Explanation opens after your attempt
Correct Answer

A. केवल (p=0)Only (p=0)

Step 1

Concept

The consecutive differences are (p,2p,3p), which are equal only when (p=0). In such questions, first write all differences.

Step 2

Why this answer is correct

The correct answer is A. केवल (p=0) / Only (p=0). The consecutive differences are (p,2p,3p), which are equal only when (p=0). In such questions, first write all differences.

Step 3

Exam Tip

क्रमागत अंतर (p,2p,3p) हैं जो समान तभी होंगे जब (p=0)। ऐसे प्रश्नों में पहले सभी अंतर लिखें।

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यदि (7,u,19,25) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (u) का मान क्या है?

If (7,u,19,25) are consecutive terms of an arithmetic progression, what is the value of (u)?

Explanation opens after your attempt
Correct Answer

C. (13)

Step 1

Concept

(25-19=6), so (u=19-6=13). While finding a missing term, apply the same difference backward too.

Step 2

Why this answer is correct

The correct answer is C. (13). (25-19=6), so (u=19-6=13). While finding a missing term, apply the same difference backward too.

Step 3

Exam Tip

(25-19=6), इसलिए (u=19-6=13)। खाली पद निकालते समय समान अंतर को पीछे की ओर भी लगाएं।

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यदि (2,x,y,20) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (x+y) कितना होगा?

If (2,x,y,20) are consecutive terms of an arithmetic progression, what is (x+y)?

Explanation opens after your attempt
Correct Answer

C. (22)

Step 1

Concept

The total difference (20-2=18) is split into three equal gaps, so (d=6). Hence (x=8), (y=14), and (x+y=22).

Step 2

Why this answer is correct

The correct answer is C. (22). The total difference (20-2=18) is split into three equal gaps, so (d=6). Hence (x=8), (y=14), and (x+y=22).

Step 3

Exam Tip

कुल अंतर (20-2=18) तीन बराबर भागों में बंटेगा, इसलिए (d=6)। अतः (x=8), (y=14) और (x+y=22)।

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अनुक्रम \(\frac{3}{8},\frac{5}{8},\frac{7}{8},\frac{9}{8},\ldots\) का सार्व अंतर क्या है?

What is the common difference of the sequence \(\frac{3}{8},\frac{5}{8},\frac{7}{8},\frac{9}{8},\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{1}{4}\)

Step 1

Concept

\(\frac{5}{8}-\frac{3}{8}=\frac{2}{8}=\frac{1}{4}\). When denominators are equal, subtract the numerators.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{1}{4}\). \(\frac{5}{8}-\frac{3}{8}=\frac{2}{8}=\frac{1}{4}\). When denominators are equal, subtract the numerators.

Step 3

Exam Tip

\(\frac{5}{8}-\frac{3}{8}=\frac{2}{8}=\frac{1}{4}\) है। भिन्नों में समान हर होने पर अंशों का अंतर लें।

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यदि \(6,11,16,\ldots\) के प्रत्येक पद को (2) से गुणा करके (3) जोड़ा जाए तो नए अनुक्रम का (d) क्या होगा?

If each term of \(6,11,16,\ldots\) is multiplied by (2) and (3) is added, what will be the (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

C. (10)

Step 1

Concept

The original (d=5); multiplying by (2) makes the new (d=10). Adding the same (3) does not change (d).

Step 2

Why this answer is correct

The correct answer is C. (10). The original (d=5); multiplying by (2) makes the new (d=10). Adding the same (3) does not change (d).

Step 3

Exam Tip

मूल (d=5) है, (2) से गुणा करने पर नया (d=10) होगा। समान (3) जोड़ने से (d) नहीं बदलता।

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यदि \(24,20,16,12,\ldots\) के प्रत्येक पद में (7) जोड़ा जाए तो नए अनुक्रम का सार्व अंतर क्या होगा?

If (7) is added to each term of \(24,20,16,12,\ldots\), what will be the common difference of the new sequence?

Explanation opens after your attempt
Correct Answer

B. (-4)

Step 1

Concept

Adding the same number to all terms does not change the common difference. The original (d=20-24=-4), so the new (d) remains (-4).

Step 2

Why this answer is correct

The correct answer is B. (-4). Adding the same number to all terms does not change the common difference. The original (d=20-24=-4), so the new (d) remains (-4).

Step 3

Exam Tip

सभी पदों में समान संख्या जोड़ने से सार्व अंतर नहीं बदलता। मूल (d=20-24=-4) है, इसलिए नया (d=-4) ही रहेगा।

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यदि \(3,8,13,18,\ldots\) को उलटे क्रम में लिखा जाए तो सार्व अंतर का चिह्न कैसा होगा?

If \(3,8,13,18,\ldots\) is written in reverse order, what happens to the sign of the common difference?

Explanation opens after your attempt
Correct Answer

C. ऋणात्मक हो जाएगाIt becomes negative

Step 1

Concept

The original (d=5), but in reverse order \(18,13,8,3,\ldots\), (d=-5). Reversing the order changes the sign.

Step 2

Why this answer is correct

The correct answer is C. ऋणात्मक हो जाएगा / It becomes negative. The original (d=5), but in reverse order \(18,13,8,3,\ldots\), (d=-5). Reversing the order changes the sign.

Step 3

Exam Tip

मूल (d=5) है, पर उलटे क्रम \(18,13,8,3,\ldots\) में (d=-5) होगा। क्रम उलटने पर चिह्न बदलता है।

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यदि (x-4,x+2,x+8) अंकगणितीय श्रेणी में हैं तो (x) के बारे में सही कथन क्या है?

If (x-4,x+2,x+8) are in an arithmetic progression, which statement about (x) is correct?

Explanation opens after your attempt
Correct Answer

C. हर (x) के लिए सत्यTrue for every (x)

Step 1

Concept

Both consecutive differences are (6) and (6), so it is an arithmetic progression for every (x). Simplify differences before deciding the variable.

Step 2

Why this answer is correct

The correct answer is C. हर (x) के लिए सत्य / True for every (x). Both consecutive differences are (6) and (6), so it is an arithmetic progression for every (x). Simplify differences before deciding the variable.

Step 3

Exam Tip

दोनों क्रमागत अंतर (6) और (6) हैं, इसलिए यह हर (x) के लिए अंकगणितीय श्रेणी है। चर तय करने से पहले अंतर सरल करें।

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यदि \(9,5,1,-3,\ldots\) के प्रत्येक पद का विपरीत लिया जाए तो नए अनुक्रम का (d) क्या होगा?

If the opposite of each term of \(9,5,1,-3,\ldots\) is taken, what will be (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

The original (d=-4). Multiplying all terms by (-1) makes the new (d=4).

Step 2

Why this answer is correct

The correct answer is A. (4). The original (d=-4). Multiplying all terms by (-1) makes the new (d=4).

Step 3

Exam Tip

मूल (d=-4) है। सभी पदों को (-1) से गुणा करने पर नया (d=4) हो जाता है।

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कौन सा अनुक्रम \(d=\frac{3}{5}\) वाली अंकगणितीय श्रेणी है?

Which sequence is an arithmetic progression with \(d=\frac{3}{5}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{5},\frac{4}{5},\frac{7}{5},2,\ldots\)

Step 1

Concept

In the first option, every consecutive difference is \(\frac{3}{5}\). In fraction options, check all differences separately.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{5},\frac{4}{5},\frac{7}{5},2,\ldots\). In the first option, every consecutive difference is \(\frac{3}{5}\). In fraction options, check all differences separately.

Step 3

Exam Tip

पहले विकल्प में हर क्रमागत अंतर \(\frac{3}{5}\) है। भिन्नों वाले विकल्पों में सभी अंतर अलग-अलग जांचें।

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यदि (2,x+3,3x+1,20) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (x) क्या होगा?

If (2,x+3,3x+1,20) are consecutive terms of an arithmetic progression, what will (x) be?

Explanation opens after your attempt
Correct Answer

D. कोई मान नहींNo value

Step 1

Concept

(20-2=18) is split into three gaps, so the second term should be (8) and the third (14). This gives (x=5) and \(x=\frac{13}{3}\), so no single value is possible.

Step 2

Why this answer is correct

The correct answer is D. कोई मान नहीं / No value. (20-2=18) is split into three gaps, so the second term should be (8) and the third (14). This gives (x=5) and \(x=\frac{13}{3}\), so no single value is possible.

Step 3

Exam Tip

(20-2=18) तीन अंतरालों में बंटता है, इसलिए दूसरा पद (8) और तीसरा (14) होना चाहिए। इससे (x=5) और \(x=\frac{13}{3}\) मिलते हैं, इसलिए कोई एक मान संभव नहीं है।

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अनुक्रम \(0.6,1.05,1.50,1.95,\ldots\) का सार्व अंतर क्या है?

What is the common difference of the sequence \(0.6,1.05,1.50,1.95,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (0.45)

Step 1

Concept

(1.05-0.60=0.45) and (1.50-1.05=0.45). Adding zeros makes decimal subtraction safer.

Step 2

Why this answer is correct

The correct answer is C. (0.45). (1.05-0.60=0.45) and (1.50-1.05=0.45). Adding zeros makes decimal subtraction safer.

Step 3

Exam Tip

(1.05-0.60=0.45) और (1.50-1.05=0.45) है। दशमलव में शून्य लगाकर घटाना सुरक्षित है।

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यदि \(r-9,r-3,r+3,\ldots\) अंकगणितीय श्रेणी है तो (d) क्या है?

If \(r-9,r-3,r+3,\ldots\) is an arithmetic progression, what is (d)?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

((r-3)-(r-9)=6) and ((r+3)-(r-3)=6). When variables cancel, a constant common difference remains.

Step 2

Why this answer is correct

The correct answer is B. (6). ((r-3)-(r-9)=6) and ((r+3)-(r-3)=6). When variables cancel, a constant common difference remains.

Step 3

Exam Tip

((r-3)-(r-9)=6) और ((r+3)-(r-3)=6) है। चर कटने पर स्थिर सार्व अंतर मिलता है।

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यदि (3m,4m+2,6m-2) अंकगणितीय श्रेणी में हैं तो (m) का मान क्या है?

If (3m,4m+2,6m-2) are in an arithmetic progression, what is the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

From (2(4m+2)=3m+(6m-2)), (8m+4=9m-2), so (m=6). Apply the twice-middle-term rule directly.

Step 2

Why this answer is correct

The correct answer is C. (4). From (2(4m+2)=3m+(6m-2)), (8m+4=9m-2), so (m=6). Apply the twice-middle-term rule directly.

Step 3

Exam Tip

(2(4m+2)=3m+(6m-2)) से (8m+4=9m-2), इसलिए (m=6)। मध्य पद का दुगुना नियम सीधे लगाएं।

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यदि \(5,9,13,\ldots\) में प्रत्येक पद में उसकी पद संख्या (n) जोड़ी जाए तो नया (d) क्या होगा?

If the term number (n) is added to each term of \(5,9,13,\ldots\), what will be the new (d)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The original (d=4), and (n) has difference (1), so the new (d=5). When adding term number, its difference is also added.

Step 2

Why this answer is correct

The correct answer is C. (5). The original (d=4), and (n) has difference (1), so the new (d=5). When adding term number, its difference is also added.

Step 3

Exam Tip

मूल (d=4) है और (n) का अंतर (1) है, इसलिए नया (d=5)। पद संख्या जोड़ने पर उसका अंतर भी जुड़ता है।

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एक अंकगणितीय श्रेणी में दूसरे और छठे पद का अंतर (24) है। (d) क्या होगा?

In an arithmetic progression, the difference between the second and sixth terms is (24). What will (d) be?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

From the second to the sixth term there are (4) gaps, so (4d=24) and (d=6). Convert term distance into number of gaps.

Step 2

Why this answer is correct

The correct answer is B. (6). From the second to the sixth term there are (4) gaps, so (4d=24) and (d=6). Convert term distance into number of gaps.

Step 3

Exam Tip

दूसरे से छठे पद तक (4) अंतर होते हैं, इसलिए (4d=24) और (d=6)। पदों की दूरी को अंतरालों की संख्या में बदलें।

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एक अंकगणितीय श्रेणी में पांचवें और पहले पद का अंतर (-20) है। सार्व अंतर क्या है?

In an arithmetic progression, the difference between the fifth and first terms is (-20). What is the common difference?

Explanation opens after your attempt
Correct Answer

B. (-5)

Step 1

Concept

From the first to the fifth term there are (4) gaps, so (4d=-20) and (d=-5). In a decreasing progression, (d) is negative.

Step 2

Why this answer is correct

The correct answer is B. (-5). From the first to the fifth term there are (4) gaps, so (4d=-20) and (d=-5). In a decreasing progression, (d) is negative.

Step 3

Exam Tip

पहले से पांचवें पद तक (4) अंतर हैं, इसलिए (4d=-20) और (d=-5)। घटती श्रेणी में (d) ऋणात्मक होता है।

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यदि \(2,7,12,\ldots\) के प्रत्येक पद से (2n) घटाया जाए, जहां (n) पद संख्या है, तो नया सार्व अंतर क्या होगा?

If (2n) is subtracted from each term of \(2,7,12,\ldots\), where (n) is the term number, what will be the new common difference?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

The original (d=5), and (2n) has difference (2), so the new (d=5-2=3). In term-number subtraction, subtract its difference.

Step 2

Why this answer is correct

The correct answer is B. (3). The original (d=5), and (2n) has difference (2), so the new (d=5-2=3). In term-number subtraction, subtract its difference.

Step 3

Exam Tip

मूल (d=5) है और (2n) का अंतर (2) है, इसलिए नया (d=5-2=3)। पद संख्या आधारित घटाव में उसके अंतर को घटाएं।

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कौन सा कथन \(8,8+3q,8+6q,8+9q,\ldots\) के लिए सही है?

Which statement is correct for \(8,8+3q,8+6q,8+9q,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. हर (q) के लिए अंकगणितीय श्रेणीArithmetic progression for every (q)

Step 1

Concept

The consecutive differences are (3q,3q,3q). With equal algebraic differences, it is an arithmetic progression for every (q).

Step 2

Why this answer is correct

The correct answer is A. हर (q) के लिए अंकगणितीय श्रेणी / Arithmetic progression for every (q). The consecutive differences are (3q,3q,3q). With equal algebraic differences, it is an arithmetic progression for every (q).

Step 3

Exam Tip

क्रमागत अंतर (3q,3q,3q) हैं। समान बीजगणितीय अंतर होने पर यह हर (q) के लिए अंकगणितीय श्रेणी है।

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यदि \(13,10,7,4,\ldots\) के प्रत्येक पद को (-2) से गुणा किया जाए तो नए अनुक्रम का (d) क्या होगा?

If each term of \(13,10,7,4,\ldots\) is multiplied by (-2), what will be (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

The original (d=-3), and multiplying by (-2) gives new (d=6). A negative multiplier can change the sign.

Step 2

Why this answer is correct

The correct answer is B. (6). The original (d=-3), and multiplying by (-2) gives new (d=6). A negative multiplier can change the sign.

Step 3

Exam Tip

मूल (d=-3) है और (-2) से गुणा करने पर नया (d=6) होगा। ऋणात्मक गुणक से चिह्न बदल सकता है।

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यदि (x,2x+4,4x) अंकगणितीय श्रेणी में हैं तो सार्व अंतर क्या है?

If (x,2x+4,4x) are in an arithmetic progression, what is the common difference?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

From (2(2x+4)=x+4x), (4x+8=5x), so (x=8). Then (d=20-8=12), so none of the listed values is correct.

Step 2

Why this answer is correct

The correct answer is C. (8). From (2(2x+4)=x+4x), (4x+8=5x), so (x=8). Then (d=20-8=12), so none of the listed values is correct.

Step 3

Exam Tip

(2(2x+4)=x+4x) से (4x+8=5x), इसलिए (x=8)। तब (d=20-8=12), इसलिए दिए विकल्पों में सही मान नहीं है।

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अनुक्रम \(-\frac{5}{3},-\frac{7}{6},-\frac{2}{3},-\frac{1}{6},\ldots\) में (d) क्या है?

What is (d) in the sequence \(-\frac{5}{3},-\frac{7}{6},-\frac{2}{3},-\frac{1}{6},\ldots\)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{1}{2}\)

Step 1

Concept

(-\frac{7}{6}-\left\(-\frac{5}{3}\right\)=\frac{1}{2}), and the next difference is also \(\frac{1}{2}\). Subtract negative fractions carefully.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{1}{2}\). (-\frac{7}{6}-\left\(-\frac{5}{3}\right\)=\frac{1}{2}), and the next difference is also \(\frac{1}{2}\). Subtract negative fractions carefully.

Step 3

Exam Tip

(-\frac{7}{6}-\left\(-\frac{5}{3}\right\)=\frac{1}{2}) और अगला अंतर भी \(\frac{1}{2}\) है। ऋणात्मक भिन्नों में घटाव ध्यान से करें।

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किस (m) के लिए (m-1,2m+3,4m-1) अंकगणितीय श्रेणी में होंगे?

For which (m) will (m-1,2m+3,4m-1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

From (2(2m+3)=(m-1)+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.

Step 2

Why this answer is correct

The correct answer is C. (5). From (2(2m+3)=(m-1)+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.

Step 3

Exam Tip

(2(2m+3)=(m-1)+(4m-1)) से (4m+6=5m-2), इसलिए (m=8)। मध्य पद का दुगुना नियम लगाएं।

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यदि \(25,20,15,10,\ldots\) में हर पद को (5) से भाग दिया जाए तो नया (d) क्या होगा?

If every term of \(25,20,15,10,\ldots\) is divided by (5), what will be the new (d)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

The original (d=-5), so after division by (5), the new (d=-1). Dividing all terms by the same number divides (d) by that number too.

Step 2

Why this answer is correct

The correct answer is A. (-1). The original (d=-5), so after division by (5), the new (d=-1). Dividing all terms by the same number divides (d) by that number too.

Step 3

Exam Tip

मूल (d=-5) है, इसलिए (5) से भाग देने पर नया (d=-1) होगा। सभी पदों को समान संख्या से भाग देने पर (d) भी उसी से भागता है।

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यदि (a,b,c) अंकगणितीय श्रेणी में हैं और (a=6), (c=30), तो (b-a) क्या है?

If (a,b,c) are in an arithmetic progression and (a=6), (c=30), what is (b-a)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

The middle term is \(b=\frac{6+30}{2}=18\), so (b-a=18-6=12). In three terms, the middle term is the average.

Step 2

Why this answer is correct

The correct answer is B. (12). The middle term is \(b=\frac{6+30}{2}=18\), so (b-a=18-6=12). In three terms, the middle term is the average.

Step 3

Exam Tip

मध्य पद \(b=\frac{6+30}{2}=18\), इसलिए (b-a=18-6=12)। तीन पदों में मध्य पद औसत होता है।

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किस विकल्प में पद समान मात्रा से घट रहे हैं लेकिन (d=-7) नहीं है?

In which option do terms decrease equally but (d) is not (-7)?

Explanation opens after your attempt
Correct Answer

D. \(60,52,44,36,\ldots\)

Step 1

Concept

The first three options have (d=-7), but \(60,52,44,36,\ldots\) has (d=-8). Check both value and sign in options.

Step 2

Why this answer is correct

The correct answer is D. \(60,52,44,36,\ldots\). The first three options have (d=-7), but \(60,52,44,36,\ldots\) has (d=-8). Check both value and sign in options.

Step 3

Exam Tip

पहले तीन विकल्पों में (d=-7) है, लेकिन \(60,52,44,36,\ldots\) में (d=-8) है। विकल्पों में मान और चिह्न दोनों जांचें।

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यदि (6,6+d,6+2d) के पद (6,2,-2) बनते हैं तो (d) क्या है?

If the terms (6,6+d,6+2d) become (6,2,-2), what is (d)?

Explanation opens after your attempt
Correct Answer

B. (-4)

Step 1

Concept

From (6+d=2), (d=-4), and (6+2d=-2) confirms it. Match the general form with the given terms.

Step 2

Why this answer is correct

The correct answer is B. (-4). From (6+d=2), (d=-4), and (6+2d=-2) confirms it. Match the general form with the given terms.

Step 3

Exam Tip

(6+d=2) से (d=-4) मिलता है और (6+2d=-2) इसकी पुष्टि करता है। सामान्य रूप को दिए गए पदों से मिलाएं।

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यदि \(2,6,10,\ldots\) और \(5,12,19,\ldots\) को पद-दर-पद जोड़ा जाए तो बने अनुक्रम का (d) क्या होगा?

If \(2,6,10,\ldots\) and \(5,12,19,\ldots\) are added term by term, what will be (d) of the formed sequence?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

The first sequence has (d=4) and the second has (d=7), so the sum sequence has (d=11). In termwise addition, common differences add.

Step 2

Why this answer is correct

The correct answer is C. (11). The first sequence has (d=4) and the second has (d=7), so the sum sequence has (d=11). In termwise addition, common differences add.

Step 3

Exam Tip

पहले अनुक्रम का (d=4) और दूसरे का (d=7) है, इसलिए योग अनुक्रम का (d=11)। पद-दर-पद योग में सार्व अंतरों का योग होता है।

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यदि \(18,14,10,\ldots\) से \(1,4,7,\ldots\) को पद-दर-पद घटाया जाए तो नए अनुक्रम का (d) क्या होगा?

If \(1,4,7,\ldots\) is subtracted term by term from \(18,14,10,\ldots\), what will be (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

A. (-7)

Step 1

Concept

The first sequence has (d=-4) and the second has (d=3), so the difference sequence has (d=-4-3=-7). In termwise subtraction, subtract the differences too.

Step 2

Why this answer is correct

The correct answer is A. (-7). The first sequence has (d=-4) and the second has (d=3), so the difference sequence has (d=-4-3=-7). In termwise subtraction, subtract the differences too.

Step 3

Exam Tip

पहले अनुक्रम का (d=-4) और दूसरे का (d=3) है, इसलिए अंतर अनुक्रम का (d=-4-3=-7)। पद-दर-पद घटाव में अंतरों को भी घटाएं।

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यदि (x-6,x,x+6) अंकगणितीय श्रेणी में हैं तो सही कथन कौन सा है?

If (x-6,x,x+6) are in an arithmetic progression, which statement is correct?

Explanation opens after your attempt
Correct Answer

C. हर (x) के लिएFor every (x)

Step 1

Concept

Both differences are (6) and (6), so it is an arithmetic progression for every (x). Equal algebraic differences are sufficient.

Step 2

Why this answer is correct

The correct answer is C. हर (x) के लिए / For every (x). Both differences are (6) and (6), so it is an arithmetic progression for every (x). Equal algebraic differences are sufficient.

Step 3

Exam Tip

दोनों अंतर (6) और (6) हैं, इसलिए यह हर (x) के लिए अंकगणितीय श्रेणी है। समान बीजगणितीय अंतर पर्याप्त है।

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यदि \(30,27,24,\ldots\) में प्रत्येक पद से उसकी पद संख्या घटाई जाए तो नया (d) क्या होगा?

If the term number is subtracted from each term of \(30,27,24,\ldots\), what will be the new (d)?

Explanation opens after your attempt
Correct Answer

C. (-4)

Step 1

Concept

The original (d=-3), and term numbers have (d=1), so the new (d=-3-1=-4). When subtracting term number, its difference is also subtracted.

Step 2

Why this answer is correct

The correct answer is C. (-4). The original (d=-3), and term numbers have (d=1), so the new (d=-3-1=-4). When subtracting term number, its difference is also subtracted.

Step 3

Exam Tip

मूल (d=-3) है और पद संख्या का (d=1) है, इसलिए नया (d=-3-1=-4)। पद संख्या घटाने पर उसका अंतर भी घटता है।

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यदि (a,a+d,a+2d) के तीनों पदों में क्रमशः (3,6,9) जोड़े जाएं तो नया सार्व अंतर क्या होगा?

If (3,6,9) are added respectively to (a,a+d,a+2d), what will be the new common difference?

Explanation opens after your attempt
Correct Answer

C. (d+3)

Step 1

Concept

The new terms are (a+3,a+d+6,a+2d+9), and both differences are (d+3). The difference of the added numbers is added to (d).

Step 2

Why this answer is correct

The correct answer is C. (d+3). The new terms are (a+3,a+d+6,a+2d+9), and both differences are (d+3). The difference of the added numbers is added to (d).

Step 3

Exam Tip

नए पद (a+3,a+d+6,a+2d+9) हैं और दोनों अंतर (d+3) हैं। क्रमशः बढ़ते जोड़ का अंतर (d) में जुड़ता है।

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यदि \(8,13,18,\ldots\) और \(4,10,16,\ldots\) के पद-दर-पद अंतर से अनुक्रम बने तो उसका (d) क्या होगा?

If a sequence is formed by termwise difference of \(8,13,18,\ldots\) and \(4,10,16,\ldots\), what will be its (d)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

The first sequence has (d=5) and the second has (d=6), so the difference sequence has (d=5-6=-1). In termwise difference, take the difference of common differences.

Step 2

Why this answer is correct

The correct answer is A. (-1). The first sequence has (d=5) and the second has (d=6), so the difference sequence has (d=5-6=-1). In termwise difference, take the difference of common differences.

Step 3

Exam Tip

पहले अनुक्रम का (d=5) और दूसरे का (d=6) है, इसलिए अंतर अनुक्रम का (d=5-6=-1)। पद-दर-पद अंतर में सार्व अंतरों का अंतर लें।

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यदि \(9,9,9,\ldots\) को \(2,5,8,\ldots\) से पद-दर-पद जोड़ा जाए तो नए अनुक्रम का (d) क्या होगा?

If \(9,9,9,\ldots\) is added term by term to \(2,5,8,\ldots\), what will be (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).

Step 2

Why this answer is correct

The correct answer is B. (3). The constant sequence has (d=0), and the second has (d=3), so the sum has (d=3). Adding a constant sequence does not change (d).

Step 3

Exam Tip

स्थिर अनुक्रम का (d=0) है और दूसरे का (d=3) है, इसलिए योग का (d=3)। स्थिर अनुक्रम जोड़ने से (d) नहीं बदलता।

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यदि (-6,s,10,18) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (s) क्या होगा?

If (-6,s,10,18) are consecutive terms of an arithmetic progression, what will (s) be?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

(18-10=8), so (s=10-8=2). While moving backward, subtract the same (d).

Step 2

Why this answer is correct

The correct answer is B. (2). (18-10=8), so (s=10-8=2). While moving backward, subtract the same (d).

Step 3

Exam Tip

(18-10=8), इसलिए (s=10-8=2)। पीछे की ओर चलते समय वही (d) घटाएं।

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यदि \(2,6,10,\ldots\) के प्रत्येक पद का दुगुना लेकर (1) घटाया जाए तो नए अनुक्रम का (d) क्या होगा?

If twice each term of \(2,6,10,\ldots\) is taken and (1) is subtracted, what will be (d) of the new sequence?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

The original (d=4); doubling makes (d=8), and subtracting the same (1) does not change (d). Multiplication changes (d), equal subtraction does not.

Step 2

Why this answer is correct

The correct answer is C. (8). The original (d=4); doubling makes (d=8), and subtracting the same (1) does not change (d). Multiplication changes (d), equal subtraction does not.

Step 3

Exam Tip

मूल (d=4) है, दुगुना करने से (d=8) होगा और समान (1) घटाने से (d) नहीं बदलेगा। गुणा (d) बदलता है, समान घटाव नहीं।

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यदि (4,4+d,4+2d,4+3d) में चौथा पद (31) है तो दूसरा पद क्या है?

If the fourth term of (4,4+d,4+2d,4+3d) is (31), what is the second term?

Explanation opens after your attempt
Correct Answer

B. (13)

Step 1

Concept

From (4+3d=31), (d=9), so the second term is (4+d=13). First find (d) and then form the required term.

Step 2

Why this answer is correct

The correct answer is B. (13). From (4+3d=31), (d=9), so the second term is (4+d=13). First find (d) and then form the required term.

Step 3

Exam Tip

(4+3d=31) से (d=9), इसलिए दूसरा पद (4+d=13)। पहले (d) निकालकर मांगा गया पद बनाएं।

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कौन सा अनुक्रम (a=18) और \(d=-\frac{3}{2}\) वाली अंकगणितीय श्रेणी है?

Which sequence is an arithmetic progression with (a=18) and \(d=-\frac{3}{2}\)?

Explanation opens after your attempt
Correct Answer

A. \(18,\frac{33}{2},15,\frac{27}{2},\ldots\)

Step 1

Concept

\(18-\frac{3}{2}=\frac{33}{2}\), and \(-\frac{3}{2}\) continues to be added. Check both (a) and (d) together.

Step 2

Why this answer is correct

The correct answer is A. \(18,\frac{33}{2},15,\frac{27}{2},\ldots\). \(18-\frac{3}{2}=\frac{33}{2}\), and \(-\frac{3}{2}\) continues to be added. Check both (a) and (d) together.

Step 3

Exam Tip

\(18-\frac{3}{2}=\frac{33}{2}\) और आगे भी \(-\frac{3}{2}\) जुड़ता है। (a) और (d) दोनों शर्तें साथ जांचें।

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यदि (2u-3,3u+2,5u-1) अंकगणितीय श्रेणी में हैं तो (u) का मान क्या है?

If (2u-3,3u+2,5u-1) are in an arithmetic progression, what is the value of (u)?

Explanation opens after your attempt
Correct Answer

D. (7)

Step 1

Concept

From (2(3u+2)=(2u-3)+(5u-1)), (6u+4=7u-4), so (u=8). Use the twice-middle-term rule to find the variable.

Step 2

Why this answer is correct

The correct answer is D. (7). From (2(3u+2)=(2u-3)+(5u-1)), (6u+4=7u-4), so (u=8). Use the twice-middle-term rule to find the variable.

Step 3

Exam Tip

(2(3u+2)=(2u-3)+(5u-1)) से (6u+4=7u-4), इसलिए (u=8)। मध्य पद का दुगुना नियम लगाकर चर निकालें।

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यदि किसी अनुक्रम का (d=10) है और हर पद को \(-\frac{1}{2}\) से गुणा किया जाए तो नया (d) क्या होगा?

If a sequence has (d=10) and each term is multiplied by \(-\frac{1}{2}\), what will be the new (d)?

Explanation opens after your attempt
Correct Answer

B. (-5)

Step 1

Concept

When all terms are multiplied by \(-\frac{1}{2}\), (d) is also multiplied by it, so the new (d=-5). The multiplier applies directly to the common difference.

Step 2

Why this answer is correct

The correct answer is B. (-5). When all terms are multiplied by \(-\frac{1}{2}\), (d) is also multiplied by it, so the new (d=-5). The multiplier applies directly to the common difference.

Step 3

Exam Tip

सभी पदों को \(-\frac{1}{2}\) से गुणा करने पर (d) भी उसी से गुणा होगा, इसलिए नया (d=-5)। गुणक सीधे सार्व अंतर पर लागू होता है।

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यदि \(4,9,14,\ldots\) से नया अनुक्रम \(4^2,9^2,14^2,\ldots\) बनाया जाए तो क्या नया अनुक्रम अंकगणितीय श्रेणी है?

If a new sequence \(4^2,9^2,14^2,\ldots\) is formed from \(4,9,14,\ldots\), is the new sequence an arithmetic progression?

Explanation opens after your attempt
Correct Answer

C. नहीं, क्योंकि क्रमागत अंतर समान नहीं हैंNo because consecutive differences are not equal

Step 1

Concept

The new terms are (16,81,196), and the differences are (65,115), which are not equal. Squaring generally does not preserve an arithmetic progression.

Step 2

Why this answer is correct

The correct answer is C. नहीं, क्योंकि क्रमागत अंतर समान नहीं हैं / No because consecutive differences are not equal. The new terms are (16,81,196), and the differences are (65,115), which are not equal. Squaring generally does not preserve an arithmetic progression.

Step 3

Exam Tip

नए पद (16,81,196) हैं और अंतर (65,115) हैं, जो समान नहीं हैं। वर्ग करने से सामान्यतः अंकगणितीय श्रेणी सुरक्षित नहीं रहती।

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यदि (6,h,24) अंकगणितीय श्रेणी में हैं तो (h-6) क्या है?

If (6,h,24) are in an arithmetic progression, what is (h-6)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

The middle term is \(h=\frac{6+24}{2}=15\), so (h-6=9). In three terms, the middle term is found by the average.

Step 2

Why this answer is correct

The correct answer is B. (9). The middle term is \(h=\frac{6+24}{2}=15\), so (h-6=9). In three terms, the middle term is found by the average.

Step 3

Exam Tip

मध्य पद \(h=\frac{6+24}{2}=15\), इसलिए (h-6=9)। तीन पदों में मध्य पद औसत से मिलता है।

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यदि \(3,8,13,\ldots\) में प्रत्येक पद से (4n) घटाया जाए तो नया सार्व अंतर क्या होगा?

If (4n) is subtracted from each term of \(3,8,13,\ldots\), what will be the new common difference?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

The original (d=5), and (4n) has (d=4), so the new (d=1). In term-number changes, subtract its difference.

Step 2

Why this answer is correct

The correct answer is A. (1). The original (d=5), and (4n) has (d=4), so the new (d=1). In term-number changes, subtract its difference.

Step 3

Exam Tip

मूल (d=5) है और (4n) का (d=4) है, इसलिए नया (d=1)। पद संख्या से जुड़े परिवर्तन में उसके अंतर को घटाएं।

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किस (k) के लिए (k-2,k+5,2k+1) अंकगणितीय श्रेणी में होंगे?

For which (k) will (k-2,k+5,2k+1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

D. (9)

Step 1

Concept

From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.

Step 2

Why this answer is correct

The correct answer is D. (9). From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.

Step 3

Exam Tip

(2(k+5)=(k-2)+(2k+1)) से (2k+10=3k-1), इसलिए (k=11)। समीकरण बनाते समय मध्य पद को पहचानें।

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यदि \(1,4,7,\ldots\) के प्रत्येक पद में पद संख्या का वर्ग जोड़ा जाए तो नया अनुक्रम कैसा होगा?

If the square of the term number is added to each term of \(1,4,7,\ldots\), what type will the new sequence be?

Explanation opens after your attempt
Correct Answer

C. अंकगणितीय श्रेणी नहीं क्योंकि नए अंतर समान नहीं होंगेNot an arithmetic progression because new differences will not be equal

Step 1

Concept

The new terms are \(2,8,16,\ldots\), and the differences are \(6,8,\ldots\), which are not equal. Adding squares of term numbers does not preserve equal difference.

Step 2

Why this answer is correct

The correct answer is C. अंकगणितीय श्रेणी नहीं क्योंकि नए अंतर समान नहीं होंगे / Not an arithmetic progression because new differences will not be equal. The new terms are \(2,8,16,\ldots\), and the differences are \(6,8,\ldots\), which are not equal. Adding squares of term numbers does not preserve equal difference.

Step 3

Exam Tip

नए पद \(2,8,16,\ldots\) मिलते हैं और अंतर \(6,8,\ldots\) हैं, जो समान नहीं हैं। पद संख्या के वर्ग जोड़ने से समान अंतर नहीं बचता।

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यदि (a,a+d,a+2d,a+3d) में (a+3d-a=36) है तो (d) क्या है?

If (a+3d-a=36) in (a,a+d,a+2d,a+3d), what is (d)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

(a+3d-a=3d=36), so (d=12). There are (3) equal gaps between the first and fourth terms.

Step 2

Why this answer is correct

The correct answer is C. (12). (a+3d-a=3d=36), so (d=12). There are (3) equal gaps between the first and fourth terms.

Step 3

Exam Tip

(a+3d-a=3d=36), इसलिए (d=12)। पहले और चौथे पद के बीच (3) समान अंतर होते हैं।

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यदि (4,x,2x+1,25) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (x) के बारे में सही निष्कर्ष क्या है?

If (4,x,2x+1,25) are consecutive terms of an arithmetic progression, what is the correct conclusion about (x)?

Explanation opens after your attempt
Correct Answer

D. कोई मान संभव नहींNo value is possible

Step 1

Concept

(25-4=21) is split into three equal gaps, so the second term should be (11) and the third (18). This makes (x=11) and (2x+1=18) impossible together.

Step 2

Why this answer is correct

The correct answer is D. कोई मान संभव नहीं / No value is possible. (25-4=21) is split into three equal gaps, so the second term should be (11) and the third (18). This makes (x=11) and (2x+1=18) impossible together.

Step 3

Exam Tip

(25-4=21) तीन बराबर अंतरालों में बंटेगा इसलिए दूसरा पद (11) और तीसरा (18) होना चाहिए। इससे (x=11) और (2x+1=18) साथ-साथ सत्य नहीं होते।

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यदि \(5,12,19,26,\ldots\) में हर दूसरा पद चुना जाए तो बने अनुक्रम का सार्व अंतर क्या होगा?

If every second term is selected from \(5,12,19,26,\ldots\), what will be the common difference of the formed sequence?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

The selected sequence is \(5,19,33,\ldots\), and its difference is (14). Selecting every second term makes the new (d) twice the original (d).

Step 2

Why this answer is correct

The correct answer is C. (14). The selected sequence is \(5,19,33,\ldots\), and its difference is (14). Selecting every second term makes the new (d) twice the original (d).

Step 3

Exam Tip

चुना गया अनुक्रम \(5,19,33,\ldots\) होगा और इसका अंतर (14) है। हर दूसरा पद लेने पर नया (d) मूल (d) का (2) गुना होता है।

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