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find parameter MCQ Questions for Class 10

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6 questions tagged with find parameter.

Question 1/6 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

किस (k) के लिए (k-2,k+5,2k+1) अंकगणितीय श्रेणी में होंगे?

For which (k) will (k-2,k+5,2k+1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

D. (9)

Step 1

Concept

From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.

Step 2

Why this answer is correct

The correct answer is D. (9). From (2(k+5)=(k-2)+(2k+1)), (2k+10=3k-1), so (k=11). Identify the middle term while forming the equation.

Step 3

Exam Tip

(2(k+5)=(k-2)+(2k+1)) से (2k+10=3k-1), इसलिए (k=11)। समीकरण बनाते समय मध्य पद को पहचानें।

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Question 2/6 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

किस (m) के लिए (m-1,2m+3,4m-1) अंकगणितीय श्रेणी में होंगे?

For which (m) will (m-1,2m+3,4m-1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

From (2(2m+3)=(m-1)+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.

Step 2

Why this answer is correct

The correct answer is C. (5). From (2(2m+3)=(m-1)+(4m-1)), (4m+6=5m-2), so (m=8). Use the twice-middle-term rule.

Step 3

Exam Tip

(2(2m+3)=(m-1)+(4m-1)) से (4m+6=5m-2), इसलिए (m=8)। मध्य पद का दुगुना नियम लगाएं।

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Question 3/6 Expert Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (k+1, 2k+4, 4k-2) अंकगणितीय श्रेणी में हैं, तो (k) का मान क्या होगा?

If (k+1, 2k+4, 4k-2) are in an arithmetic progression, what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

D. (6)

Step 1

Concept

From (2(2k+4)=(k+1)+(4k-2)), (4k+8=5k-1), so (k=9). Identify the middle term correctly while forming the equation.

Step 2

Why this answer is correct

The correct answer is D. (6). From (2(2k+4)=(k+1)+(4k-2)), (4k+8=5k-1), so (k=9). Identify the middle term correctly while forming the equation.

Step 3

Exam Tip

(2(2k+4)=(k+1)+(4k-2)) से (4k+8=5k-1), इसलिए (k=9)। समीकरण बनाते समय मध्य पद को सही पहचानें।

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Question 4/6 Expert Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (q-3, 2q+1, 4q-1) अंकगणितीय श्रेणी में हैं, तो (q) क्या होगा?

If (q-3, 2q+1, 4q-1) are in an arithmetic progression, what will (q) be?

Explanation opens after your attempt
Correct Answer

D. (5)

Step 1

Concept

From (2(2q+1)=(q-3)+(4q-1)), (4q+2=5q-4), so (q=6). Watch signs while applying the twice-middle-term rule.

Step 2

Why this answer is correct

The correct answer is D. (5). From (2(2q+1)=(q-3)+(4q-1)), (4q+2=5q-4), so (q=6). Watch signs while applying the twice-middle-term rule.

Step 3

Exam Tip

(2(2q+1)=(q-3)+(4q-1)) से (4q+2=5q-4), इसलिए (q=6)। मध्य पद का दुगुना नियम लगाते समय संकेतों पर ध्यान दें।

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Question 5/6 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 62

किस (k) के लिए (k-3, k+2, 2k+1) अंकगणितीय श्रेणी में होंगे?

For which (k) will (k-3, k+2, 2k+1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

From (2(k+2)=(k-3)+(2k+1)), (2k+4=3k-2), so (k=6). Identify the middle term while forming the equation.

Step 2

Why this answer is correct

The correct answer is B. (5). From (2(k+2)=(k-3)+(2k+1)), (2k+4=3k-2), so (k=6). Identify the middle term while forming the equation.

Step 3

Exam Tip

(2(k+2)=(k-3)+(2k+1)) से (2k+4=3k-2), इसलिए (k=6)। समीकरण बनाते समय मध्य पद को पहचानें।

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Question 6/6 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 62

किस (m) के लिए (m+2, 2m+5, 4m+1) अंकगणितीय श्रेणी में होंगे?

For which (m) will (m+2, 2m+5, 4m+1) be in an arithmetic progression?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

From (2(2m+5)=(m+2)+(4m+1)), (4m+10=5m+3), so (m=7). Use the twice-middle-term rule for three terms.

Step 2

Why this answer is correct

The correct answer is A. (4). From (2(2m+5)=(m+2)+(4m+1)), (4m+10=5m+3), so (m=7). Use the twice-middle-term rule for three terms.

Step 3

Exam Tip

(2(2m+5)=(m+2)+(4m+1)) से (4m+10=5m+3), इसलिए (m=7)। तीन पदों में मध्य पद का दुगुना नियम लगाएं।

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