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middle-term MCQ Questions for Class 10

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15 questions tagged with middle-term.

Question 1/15 Expert Mathematics Arithmetic Progressions (AP) Finding the sum of the first $n$ terms of an AP Class 10 Level 68

एक समान्तर श्रेणी में \(S_{11}=385\) है। (6)वाँ पद क्या होगा?

In an arithmetic progression \(S_{11}=385\). What is the (6)th term?

Explanation opens after your attempt
Correct Answer

C. (35)

Step 1

Concept

In (11) terms, the (6)th term is the middle term, so \(t_6=\frac{385}{11}=35\). Exam tip: use the middle term for an odd number of terms.

Step 2

Why this answer is correct

The correct answer is C. (35). In (11) terms, the (6)th term is the middle term, so \(t_6=\frac{385}{11}=35\). Exam tip: use the middle term for an odd number of terms.

Step 3

Exam Tip

(11) पदों में (6)वाँ पद मध्य पद है इसलिए \(t_6=\frac{385}{11}=35\)। परीक्षा में विषम पदों की श्रेणी में मध्य पद का उपयोग करें।

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Question 2/15 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (6,h,24) अंकगणितीय श्रेणी में हैं तो (h-6) क्या है?

If (6,h,24) are in an arithmetic progression, what is (h-6)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

The middle term is \(h=\frac{6+24}{2}=15\), so (h-6=9). In three terms, the middle term is found by the average.

Step 2

Why this answer is correct

The correct answer is B. (9). The middle term is \(h=\frac{6+24}{2}=15\), so (h-6=9). In three terms, the middle term is found by the average.

Step 3

Exam Tip

मध्य पद \(h=\frac{6+24}{2}=15\), इसलिए (h-6=9)। तीन पदों में मध्य पद औसत से मिलता है।

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Question 3/15 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (a,b,c) अंकगणितीय श्रेणी में हैं और (a=6), (c=30), तो (b-a) क्या है?

If (a,b,c) are in an arithmetic progression and (a=6), (c=30), what is (b-a)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

The middle term is \(b=\frac{6+30}{2}=18\), so (b-a=18-6=12). In three terms, the middle term is the average.

Step 2

Why this answer is correct

The correct answer is B. (12). The middle term is \(b=\frac{6+30}{2}=18\), so (b-a=18-6=12). In three terms, the middle term is the average.

Step 3

Exam Tip

मध्य पद \(b=\frac{6+30}{2}=18\), इसलिए (b-a=18-6=12)। तीन पदों में मध्य पद औसत होता है।

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Question 4/15 Expert Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (a,b,c) अंकगणितीय श्रेणी में हैं और (a=-6), (c=18), तो (b-a) कितना है?

If (a,b,c) are in an arithmetic progression and (a=-6), (c=18), what is (b-a)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The middle term is \(b=\frac{-6+18}{2}=6\), so (b-a=6-(-6)=12). In three terms, the middle term is the average.

Step 2

Why this answer is correct

The correct answer is C. (12). The middle term is \(b=\frac{-6+18}{2}=6\), so (b-a=6-(-6)=12). In three terms, the middle term is the average.

Step 3

Exam Tip

मध्य पद \(b=\frac{-6+18}{2}=6\), इसलिए (b-a=6-(-6)=12)। तीन पदों में मध्य पद औसत होता है।

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Question 5/15 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 62

यदि (4, h, 20) अंकगणितीय श्रेणी में हैं और (h) मध्य पद है, तो (h-4) क्या है?

If (4, h, 20) are in an arithmetic progression and (h) is the middle term, what is (h-4)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

\(h=\frac{4+20}{2}=12\), so (h-4=8). Finding the middle term also gives the common difference.

Step 2

Why this answer is correct

The correct answer is B. (8). \(h=\frac{4+20}{2}=12\), so (h-4=8). Finding the middle term also gives the common difference.

Step 3

Exam Tip

\(h=\frac{4+20}{2}=12\), इसलिए (h-4=8)। मध्य पद निकालकर सार्व अंतर भी मिल जाता है।

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Question 6/15 Hard Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 62

यदि (a,b,c) अंकगणितीय श्रेणी में हैं और (a=4), (c=22), तो (b-a) क्या है?

If (a,b,c) are in an arithmetic progression and (a=4), (c=22), what is (b-a)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

For three terms, \(b=\frac{4+22}{2}=13\), so (b-a=13-4=9). Find the middle term using the average.

Step 2

Why this answer is correct

The correct answer is B. (9). For three terms, \(b=\frac{4+22}{2}=13\), so (b-a=13-4=9). Find the middle term using the average.

Step 3

Exam Tip

तीन पदों में \(b=\frac{4+22}{2}=13\), इसलिए (b-a=13-4=9)। मध्य पद को औसत से निकालें।

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Question 7/15 Medium Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 63

यदि (13,b,31) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (b) का मान क्या है?

If (13,b,31) are consecutive terms of an arithmetic progression, what is the value of (b)?

Explanation opens after your attempt
Correct Answer

C. (22)

Step 1

Concept

The middle term is \(b=\frac{13+31}{2}=22\). In three consecutive terms the middle term is the average.

Step 2

Why this answer is correct

The correct answer is C. (22). The middle term is \(b=\frac{13+31}{2}=22\). In three consecutive terms the middle term is the average.

Step 3

Exam Tip

मध्य पद \(b=\frac{13+31}{2}=22\) है। तीन क्रमागत पदों में बीच वाला पद औसत होता है।

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Question 8/15 Medium Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 63

यदि (8,m,20) किसी अंकगणितीय श्रेणी के क्रमागत तीन पद हैं तो (m) क्या है?

If (8,m,20) are three consecutive terms of an arithmetic progression, what is (m)?

Explanation opens after your attempt
Correct Answer

C. (14)

Step 1

Concept

The middle term is \(m=\frac{8+20}{2}=14\). In three consecutive terms the middle term is the average.

Step 2

Why this answer is correct

The correct answer is C. (14). The middle term is \(m=\frac{8+20}{2}=14\). In three consecutive terms the middle term is the average.

Step 3

Exam Tip

मध्य पद \(m=\frac{8+20}{2}=14\) है। तीन क्रमागत पदों में बीच वाला पद औसत होता है।

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Question 9/15 Medium Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (9,b,21) अंकगणितीय श्रेणी के क्रमागत पद हैं तो (b) का मान क्या है?

If (9,b,21) are consecutive terms of an arithmetic progression, what is the value of (b)?

Explanation opens after your attempt
Correct Answer

C. (15)

Step 1

Concept

The middle term is \(b=\frac{9+21}{2}=15\). In three consecutive terms the middle term is the average.

Step 2

Why this answer is correct

The correct answer is C. (15). The middle term is \(b=\frac{9+21}{2}=15\). In three consecutive terms the middle term is the average.

Step 3

Exam Tip

मध्य पद \(b=\frac{9+21}{2}=15\) है। तीन क्रमागत पदों में बीच वाला पद औसत होता है।

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Question 10/15 Medium Mathematics Arithmetic Progressions (AP) Introduction to APs and common difference. Class 10 Level 61

यदि (3,m,11) किसी अंकगणितीय श्रेणी के क्रमागत तीन पद हैं तो (m) क्या है?

If (3,m,11) are three consecutive terms of an arithmetic progression, what is (m)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

The middle term is the average of (3) and (11), so \(m=\frac{3+11}{2}=7\). In three consecutive terms the middle term is the average.

Step 2

Why this answer is correct

The correct answer is A. (7). The middle term is the average of (3) and (11), so \(m=\frac{3+11}{2}=7\). In three consecutive terms the middle term is the average.

Step 3

Exam Tip

बीच का पद (3) और (11) का औसत है इसलिए \(m=\frac{3+11}{2}=7\)। तीन क्रमागत पदों में मध्य पद औसत होता है।

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Question 11/15 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(3x^2-11x+6=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(3x^2-11x+6=0\)?

Explanation opens after your attempt
Correct Answer

A. ((3x-2)(x-3))

Step 1

Concept

(3x-2-11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).

Step 2

Why this answer is correct

The correct answer is A. ((3x-2)(x-3)). (3x-2-11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).

Step 3

Exam Tip

(3x-2-11x+6=(3x-2)(x-3)) है। परीक्षा में विस्तार करके (-11x) वापस जांचें।

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Question 12/15 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

मध्य पद विभाजन में \(4x^2+13x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(4x^2+13x+3=0\), what is the value of (ac)?

Explanation opens after your attempt
Correct Answer

A. (12)

Step 1

Concept

Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (12). Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=4) और (c=3), इसलिए (ac=12) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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Question 13/15 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(2x^2-7x+5=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(2x^2-7x+5=0\)?

Explanation opens after your attempt
Correct Answer

A. ((2x-5)(x-1))

Step 1

Concept

(2x-2-7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).

Step 2

Why this answer is correct

The correct answer is A. ((2x-5)(x-1)). (2x-2-7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).

Step 3

Exam Tip

(2x-2-7x+5=(2x-5)(x-1)) है। परीक्षा में विस्तार करके (-7x) वापस जांचें।

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Question 14/15 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

मध्य पद विभाजन में \(3x^2+10x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(3x^2+10x+3=0\), what is the value of (ac)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (9). Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=3) और (c=3), इसलिए (ac=9) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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Question 15/15 Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(2x^2-5x+3=0\) के गुणनखंड कौनसे हैं?

What are the factors of \(2x^2-5x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. ((2x-3)(x-1))

Step 1

Concept

(2x-2-5x+3=(2x-3)(x-1)). In exams, multiply back to check the middle term (-5x).

Step 2

Why this answer is correct

The correct answer is A. ((2x-3)(x-1)). (2x-2-5x+3=(2x-3)(x-1)). In exams, multiply back to check the middle term (-5x).

Step 3

Exam Tip

(2x-2-5x+3=(2x-3)(x-1)) है। परीक्षा में गुणा करके मध्य पद (-5x) वापस जांचें।

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