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If (a,b,c) are in an arithmetic progression and (a=4), (c=22), what is (b-a)?

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Answer and explanation

Correct answer: 9

In an arithmetic progression, the difference between consecutive terms is constant. Therefore, for three terms, the middle term b is the average of a and c: \(b=\frac{a+c}{2}=\frac{4+22}{2}=13\). Hence, \(b-a=13-4=9\). Option 11 can result from using an incorrect difference instead of halving \(c-a=22-4\). Exam tip: For three consecutive AP terms, the middle term is always the average of the first and third terms.

Related tags

Arithmetic ProgressionCommon DifferenceMiddle TermClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

9

Why is this the correct answer?

In an arithmetic progression, the difference between consecutive terms is constant. Therefore, for three terms, the middle term b is the average of a and c: \(b=\frac{a+c}{2}=\frac{4+22}{2}=13\). Hence, \(b-a=13-4=9\). Option 11 can result from using an incorrect difference instead of halving \(c-a=22-4\). Exam tip: For three consecutive AP terms, the middle term is always the average of the first and third terms.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Introduction to APs and common difference..

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