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Which is the correct factorised form of the equation \(3x^2-11x+6=0\)?
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Answer and explanation
Correct answer: \((3x-2)(x-3)=0\)
Expanding \((3x-2)(x-3)\) gives \(3x^2-9x-2x+6=3x^2-11x+6\), so option A is correct. Option C expands to \(3x^2-9x+6\), whose coefficient of \(x\) is incorrect. In an exam, expand the factors to check both the middle term and the constant term.
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What is the correct answer to this question?
\((3x-2)(x-3)=0\)
Why is this the correct answer?
Expanding \((3x-2)(x-3)\) gives \(3x^2-9x-2x+6=3x^2-11x+6\), so option A is correct. Option C expands to \(3x^2-9x+6\), whose coefficient of \(x\) is incorrect. In an exam, expand the factors to check both the middle term and the constant term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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