What is the (16)th term of the AP (6,17,28,39,\ldots)?
Answer and explanation
Correct answer: 171
The first term of the AP is 6 and the common difference is \(17-6=11\). Using \(a_n=a+(n-1)d\), \(a_{16}=6+(16-1)\times11=6+165=171\). Hence, 171 is correct. A value such as 169 would result from using an incorrect common difference or term count. Exam tip: for the \(n\)th term, add \(n-1\) common differences, not \(n\).
Frequently asked questions
What is the correct answer to this question?
171
Why is this the correct answer?
The first term of the AP is 6 and the common difference is \(17-6=11\). Using \(a_n=a+(n-1)d\), \(a_{16}=6+(16-1)\times11=6+165=171\). Hence, 171 is correct. A value such as 169 would result from using an incorrect common difference or term count. Exam tip: for the \(n\)th term, add \(n-1\) common differences, not \(n\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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