Concept-wise Practice

constant-term MCQ Questions for Class 10

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Practice Questions

6 questions tagged with constant-term.

Question 1/6 Expert Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि (p(x)=x-2-2x-3\sqrt{2}) है, तो स्थिर पद का शून्यकों से संबंध क्या बताता है?

If (p(x)=x-2-2x-3\sqrt{2}), what does the constant term tell about the zeroes?

Explanation opens after your attempt
Correct Answer

A. शून्यकों का गुणनफल \(-3\sqrt{2}\) हैThe product of zeroes is \(-3\sqrt{2}\)

Step 1

Concept

In a monic quadratic, the constant term is the product of zeroes. Here \(\alpha\beta=-3\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. शून्यकों का गुणनफल \(-3\sqrt{2}\) है / The product of zeroes is \(-3\sqrt{2}\). In a monic quadratic, the constant term is the product of zeroes. Here \(\alpha\beta=-3\sqrt{2}\).

Step 3

Exam Tip

एकक द्विघात में स्थिर पद शून्यकों का गुणनफल होता है। यहाँ \(\alpha\beta=-3\sqrt{2}\) है।

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Question 2/6 Expert Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि \(x^2-2x+m\) के शून्यक \(1+\sqrt{6}\) और \(1-\sqrt{6}\) हैं, तो (m) क्या है?

If the zeroes of \(x^2-2x+m\) are \(1+\sqrt{6}\) and \(1-\sqrt{6}\), what is (m)?

Explanation opens after your attempt
Correct Answer

A. (-5)

Step 1

Concept

The product is (1-6=-5), so (m=-5). In a monic polynomial, the constant term is the product of zeroes.

Step 2

Why this answer is correct

The correct answer is A. (-5). The product is (1-6=-5), so (m=-5). In a monic polynomial, the constant term is the product of zeroes.

Step 3

Exam Tip

गुणनफल (1-6=-5) है, इसलिए (m=-5)। एकक बहुपद में स्थिर पद शून्यकों का गुणनफल होता है।

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Question 3/6 Expert Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि किसी एकक द्विघात बहुपद के शून्यक \(4+\sqrt{11}\) और \(4-\sqrt{11}\) हैं, तो स्थिर पद क्या होगा?

If the zeroes of a monic quadratic polynomial are \(4+\sqrt{11}\) and \(4-\sqrt{11}\), what will be the constant term?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.

Step 2

Why this answer is correct

The correct answer is A. (5). The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.

Step 3

Exam Tip

स्थिर पद गुणनफल है और (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5)। संयुग्मी गुणनफल में बीच का अपरिमेय भाग हट जाता है।

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Question 4/6 Hard Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 27

यदि \(x^2+bx+12\) के शून्यक \(2+\sqrt{7}\) और \(2-\sqrt{7}\) हैं, तो त्रुटि क्या है?

If the zeroes of \(x^2+bx+12\) are \(2+\sqrt{7}\) and \(2-\sqrt{7}\), what is the error?

Explanation opens after your attempt
Correct Answer

B. गुणनफल (-3) है, इसलिए स्थिर पद (12) नहीं हो सकताProduct is (-3), so constant term cannot be (12)

Step 1

Concept

The product of these zeroes is (4-7=-3). In a monic polynomial, the constant term must equal the product.

Step 2

Why this answer is correct

The correct answer is B. गुणनफल (-3) है, इसलिए स्थिर पद (12) नहीं हो सकता / Product is (-3), so constant term cannot be (12). The product of these zeroes is (4-7=-3). In a monic polynomial, the constant term must equal the product.

Step 3

Exam Tip

इन शून्यकों का गुणनफल (4-7=-3) है। एकक बहुपद में स्थिर पद गुणनफल के बराबर होना चाहिए।

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Question 5/6 Hard Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 27

यदि \(a+\sqrt{b}\) और \(a-\sqrt{b}\) किसी एकक द्विघात बहुपद के शून्यक हैं, तो स्थिर पद क्या होगा?

If \(a+\sqrt{b}\) and \(a-\sqrt{b}\) are zeroes of a monic quadratic polynomial, what is the constant term?

Explanation opens after your attempt
Correct Answer

A. \(a^2-b\)

Step 1

Concept

In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2-b).

Step 2

Why this answer is correct

The correct answer is A. \(a^2-b\). In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2-b).

Step 3

Exam Tip

एकक बहुपद में स्थिर पद शून्यकों का गुणनफल होता है। यहाँ गुणनफल (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2-b) है।

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Question 6/6 Hard Mathematics Chapter 2: Polynomials Irrational numbers and real numbers Class 10 Level 26

यदि शून्यक \(2\sqrt{2}\) और \(3\sqrt{2}\) हैं, तो बहुपद का स्थिर पद क्या होगा यदि अग्र गुणांक (1) है?

If the zeroes are \(2\sqrt{2}\) and \(3\sqrt{2}\), what is the constant term if the leading coefficient is (1)?

Explanation opens after your attempt
Correct Answer

A. (12)

Step 1

Concept

The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).

Step 2

Why this answer is correct

The correct answer is A. (12). The constant term equals the product of the zeroes. (\(2\sqrt{2}\)\(3\sqrt{2}\)=12).

Step 3

Exam Tip

स्थिर पद शून्यकों के गुणनफल के बराबर है। (\(2\sqrt{2}\)\(3\sqrt{2}\)=12) है।

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