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Class 10MathematicsPolynomialsPolynomials in one variableExpertLevel 47
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If \(p(x)=5x^2+bx+c\), \(p(0)=-4\), and \(p(1)=3\), what is the value of \(b\)?

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Answer and explanation

Correct answer: 2

Since \(p(0)=c\), we get \(c=-4\). Substituting \(x=1\) and \(p(1)=3\) gives \(5+b-4=3\), so \(b=2\). Option A is the value of \(5+c\), not the value of \(b\). Exam tip: use \(x=0\) first to determine the constant term, then apply the second condition.

Related tags

Polynomial EvaluationConstant TermUnknown CoefficientQuadratic Polynomial

Frequently asked questions

What is the correct answer to this question?

2

Why is this the correct answer?

Since \(p(0)=c\), we get \(c=-4\). Substituting \(x=1\) and \(p(1)=3\) gives \(5+b-4=3\), so \(b=2\). Option A is the value of \(5+c\), not the value of \(b\). Exam tip: use \(x=0\) first to determine the constant term, then apply the second condition.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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