polynomial-value se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
28 questions tagged with polynomial-value.
If (p(x)=ax-3+bx-2+cx+d) and (p(0)=-7), what is the value of (d)?
B. (-7)
Putting (x=0) gives (p(0)=d). Therefore (d=-7).
The correct answer is B. (-7). Putting (x=0) gives (p(0)=d). Therefore (d=-7).
(x=0) रखने पर (p(0)=d) मिलता है। इसलिए (d=-7) है।
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If (p(x)=2x-2+3x+4), what is the difference (p(-1)-p(0))?
A. (-1)
(p(-1)=3) and (p(0)=4). Therefore (p(-1)-p(0)=-1).
The correct answer is A. (-1). (p(-1)=3) and (p(0)=4). Therefore (p(-1)-p(0)=-1).
(p(-1)=3) और (p(0)=4) है। इसलिए (p(-1)-p(0)=-1) है।
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If (p(x)=3x-2+2x-1), what is the value of (p\left\(\frac{1}{3}\right\))?
A. (0)
(p\left\(\frac{1}{3}\right\)=3\left\(\frac{1}{3}\right\)2+2\left\(\frac{1}{3}\right\)-1=0). Use brackets while substituting fractions.
The correct answer is A. (0). (p\left\(\frac{1}{3}\right\)=3\left\(\frac{1}{3}\right\)2+2\left\(\frac{1}{3}\right\)-1=0). Use brackets while substituting fractions.
(p\left\(\frac{1}{3}\right\)=3\left\(\frac{1}{3}\right\)2+2\left\(\frac{1}{3}\right\)-1=0) है। भिन्न रखते समय कोष्ठक लगाएँ।
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If (p(x)=x-2-2x+3), what is the value of (p(2)+p(-1))?
B. (9)
(p(2)=3) and (p(-1)=6). Therefore the sum is (9).
The correct answer is B. (9). (p(2)=3) and (p(-1)=6). Therefore the sum is (9).
(p(2)=3) और (p(-1)=6) है। इसलिए योग (9) है।
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If the constant term in (p(x)=x-2+5x+c) is (-6), what will (p(0)) be?
B. (-6)
(p(0)) is always equal to the constant term. Here the constant term is (-6).
The correct answer is B. (-6). (p(0)) is always equal to the constant term. Here the constant term is (-6).
(p(0)) हमेशा नियत पद के बराबर होता है। यहाँ नियत पद (-6) है।
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If (p(x)=2x-2+bx-10) and (p(2)=4), what is the value of (b)?
C. (3)
(p(2)=8+2b-10=4) gives (2b-2=4). Therefore (b=3).
The correct answer is C. (3). (p(2)=8+2b-10=4) gives (2b-2=4). Therefore (b=3).
(p(2)=8+2b-10=4) से (2b-2=4) मिलता है। इसलिए (b=3) है।
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If (p(x)=5x-2-3x+2), what is the value of (p(0)+p(1))?
C. (6)
(p(0)=2) and (p(1)=4). Therefore the sum is (6).
The correct answer is C. (6). (p(0)=2) and (p(1)=4). Therefore the sum is (6).
(p(0)=2) और (p(1)=4) है। इसलिए योग (6) है।
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If (p(x)=x-2+ax+a) and (p(1)=5), what is the value of (a)?
B. (2)
(p(1)=1+a+a=5) gives (1+2a=5). Therefore (a=2).
The correct answer is B. (2). (p(1)=1+a+a=5) gives (1+2a=5). Therefore (a=2).
(p(1)=1+a+a=5) से (1+2a=5) मिलता है। इसलिए (a=2) है।
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If (p(x)=3x-2-2x+1), what is the value of (p(2)-p(1))?
B. (6)
(p(2)=9) and (p(1)=3). Therefore (p(2)-p(1)=6).
The correct answer is B. (6). (p(2)=9) and (p(1)=3). Therefore (p(2)-p(1)=6).
(p(2)=9) और (p(1)=3) है। इसलिए (p(2)-p(1)=6) है।
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If (h(x)=x-2+2x), what is the value of (h(-2))?
A. (0)
(h(-2)=(-2)2+2(-2)=4-4=0). Use brackets and check signs when substituting a negative value.
The correct answer is A. (0). (h(-2)=(-2)2+2(-2)=4-4=0). Use brackets and check signs when substituting a negative value.
(h(-2)=(-2)2+2(-2)=4-4=0) है। ऋणात्मक मान रखते समय कोष्ठक और चिह्नों का ध्यान रखें।
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If (g(x)=3x-2-x), what is the value of (g(1))?
B. (2)
(g(1)=3(1)2-1=2). Substitute (1) for each (x) and simplify.
The correct answer is B. (2). (g(1)=3(1)2-1=2). Substitute (1) for each (x) and simplify.
(g(1)=3(1)2-1=2) है। प्रत्येक (x) की जगह (1) रखकर सरल करें।
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If (p(x)=2x+1), what is the value of (p(3)-p(1))?
B. (4)
(p(3)=7) and (p(1)=3), so the difference is (4). Find both values separately first.
The correct answer is B. (4). (p(3)=7) and (p(1)=3), so the difference is (4). Find both values separately first.
(p(3)=7) और (p(1)=3), इसलिए अंतर (4) है। पहले दोनों मान अलग-अलग निकालें।
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If (p(x)=3x-5), what is (p(2))?
A. (1)
(p(2)=3(2)-5=1). Use direct substitution in a simple linear polynomial.
The correct answer is A. (1). (p(2)=3(2)-5=1). Use direct substitution in a simple linear polynomial.
(p(2)=3(2)-5=1) है। सरल रैखिक बहुपद में सीधे प्रतिस्थापन करें।
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For (p(x)=x-2-5x+6), what is the value of (p(2))?
A. (0)
(p(2)=22-5(2)+6=0). In exams, keep the sign of the negative term carefully.
The correct answer is A. (0). (p(2)=22-5(2)+6=0). In exams, keep the sign of the negative term carefully.
(p(2)=22-5(2)+6=0)। परीक्षा में ऋणात्मक पद का चिह्न ध्यान से रखें।
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If (p(x)=4x-2-5x+2), what is the value of (p(3))?
B. (23)
(p(3)=4(3)2-5(3)+2=36-15+2=23). Evaluate powers first while substituting.
The correct answer is B. (23). (p(3)=4(3)2-5(3)+2=36-15+2=23). Evaluate powers first while substituting.
(p(3)=4(3)2-5(3)+2=36-15+2=23)। प्रतिस्थापन में पहले घात निकालें।
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If (p(x)=3x-2-2x+4), what is the value of (p(2))?
C. (12)
(p(2)=3(2)2-2(2)+4=12-4+4=12). Evaluate powers first while substituting.
The correct answer is C. (12). (p(2)=3(2)2-2(2)+4=12-4+4=12). Evaluate powers first while substituting.
(p(2)=3(2)2-2(2)+4=12-4+4=12)। प्रतिस्थापन में पहले घात निकालें।
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If (p(x)=2x-2-3x+1), what is the value of (p(2))?
B. (3)
(p(2)=2(2)2-3(2)+1=8-6+1=3). Evaluate powers first while substituting.
The correct answer is B. (3). (p(2)=2(2)2-3(2)+1=8-6+1=3). Evaluate powers first while substituting.
(p(2)=2(2)2-3(2)+1=8-6+1=3)। प्रतिस्थापन में पहले घात निकालें।
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If (p(x)=x-2-4), what is (p(2))?
A. (0)
(p(2)=22-4=0). So (2) is a zero of this polynomial.
The correct answer is A. (0). (p(2)=22-4=0). So (2) is a zero of this polynomial.
(p(2)=22-4=0) है। इसलिए (2) इस बहुपद का शून्यक है।
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If (p(x)=x-2-1), what is (p(1))?
A. (0)
(p(1)=12-1=0). When (p(a)=0), (a) is called a zero.
The correct answer is A. (0). (p(1)=12-1=0). When (p(a)=0), (a) is called a zero.
(p(1)=12-1=0) है। जब (p(a)=0) हो तो (a) शून्यक कहलाता है।
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If \(x=1-\sqrt{5}\), what is the value of \(x^2-2x-4\)?
A. (0)
Since \(x-1=-\sqrt{5}\), ((x-1)2=5), so \(x^2-2x-4=0\). Isolate the irrational part and square in exams.
The correct answer is A. (0). Since \(x-1=-\sqrt{5}\), ((x-1)2=5), so \(x^2-2x-4=0\). Isolate the irrational part and square in exams.
\(x-1=-\sqrt{5}\), इसलिए ((x-1)2=5) से \(x^2-2x-4=0\) मिलता है। परीक्षा में अपरिमेय भाग अलग करके वर्ग करें।
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If \(x=\sqrt{3}\), what is the value of \(2x^2-x-6\)?
A. \(-\sqrt{3}\)
\(2x^2-x-6=2\cdot3-\sqrt{3}-6=-\sqrt{3}\). Simplify \(x^2\) first in exams.
The correct answer is A. \(-\sqrt{3}\). \(2x^2-x-6=2\cdot3-\sqrt{3}-6=-\sqrt{3}\). Simplify \(x^2\) first in exams.
\(2x^2-x-6=2\cdot3-\sqrt{3}-6=-\sqrt{3}\) है। परीक्षा में \(x^2\) को पहले सरल करें।
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If \(x=\sqrt{11}\), what is the value of \(x^4-121\)?
A. (0)
Since \(x^2=11\), \(x^4=121\), so the value is (0). In exams reduce higher powers using \(x^2\).
The correct answer is A. (0). Since \(x^2=11\), \(x^4=121\), so the value is (0). In exams reduce higher powers using \(x^2\).
\(x^2=11\), इसलिए \(x^4=121\) और मान (0) है। परीक्षा में उच्च घात को \(x^2\) से सरल करें।
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If \(x=2+\sqrt{5}\), what is the value of \(x^2-4x-1\)?
A. (0)
Since \(x-2=\sqrt{5}\), squaring gives ((x-2)2=5), so \(x^2-4x-1=0\). In exams square to remove the radical.
The correct answer is A. (0). Since \(x-2=\sqrt{5}\), squaring gives ((x-2)2=5), so \(x^2-4x-1=0\). In exams square to remove the radical.
\(x-2=\sqrt{5}\), इसलिए ((x-2)2=5) से \(x^2-4x-1=0\) मिलता है। परीक्षा में वर्ग करके अपरिमेय हटाएं।
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If (p(x)=x-2-7), what is the form of (p\(\sqrt{7}+1\))?
A. \(1+2\sqrt{7}\)
(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.
The correct answer is A. \(1+2\sqrt{7}\). (\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}). Use ((a+b)2) carefully in exams.
(\(\sqrt{7}+1\)2-7=8+2\sqrt{7}-7=1+2\sqrt{7}) है। परीक्षा में ((a+b)2) सावधानी से लगाएं।
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If \(x=\sqrt{3}\), what is the value of \(x^2-3\)?
B. (0)
Since (\(\sqrt{3}\)2=3), \(x^2-3=0\). In exams the square of a square root gives the radicand.
The correct answer is B. (0). Since (\(\sqrt{3}\)2=3), \(x^2-3=0\). In exams the square of a square root gives the radicand.
क्योंकि (\(\sqrt{3}\)2=3), इसलिए \(x^2-3=0\) है। परीक्षा में वर्गमूल का वर्ग मूलांक देता है।
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If (p(x)=x-2-5x+6), what type of number is (p\(\sqrt{2}\))?
B. अपरिमेयIrrational
(p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), which is irrational. In exams substitute first and then simplify the radical.
The correct answer is B. अपरिमेय / Irrational. (p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), which is irrational. In exams substitute first and then simplify the radical.
(p\(\sqrt{2}\)=2-5\sqrt{2}+6=8-5\sqrt{2}), जो अपरिमेय है। परीक्षा में पहले प्रतिस्थापन करें फिर वर्गमूल को सरल करें।
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If (p\(\sqrt{5}\)=0) and (p(x)=x-2+ax-5), what is the value of (a)?
A. (0)
Substitution gives \(5+a\sqrt{5}-5=0\), so \(a\sqrt{5}=0\) and (a=0). Simplify like terms first while substituting.
The correct answer is A. (0). Substitution gives \(5+a\sqrt{5}-5=0\), so \(a\sqrt{5}=0\) and (a=0). Simplify like terms first while substituting.
रखने पर \(5+a\sqrt{5}-5=0\), इसलिए \(a\sqrt{5}=0\) और (a=0)। मान रखते समय समान पद पहले सरल करें।
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If (p\(\sqrt{3}\)=0) and (p(x)=x-2+ax+3), what is the value of (a)?
A. \(-2\sqrt{3}\)
From \(3+a\sqrt{3}+3=0\), \(a\sqrt{3}=-6\), so \(a=-2\sqrt{3}\). After substituting an irrational value, separate like terms carefully.
The correct answer is A. \(-2\sqrt{3}\). From \(3+a\sqrt{3}+3=0\), \(a\sqrt{3}=-6\), so \(a=-2\sqrt{3}\). After substituting an irrational value, separate like terms carefully.
\(3+a\sqrt{3}+3=0\) से \(a\sqrt{3}=-6\), इसलिए \(a=-2\sqrt{3}\) है। अपरिमेय मान रखने के बाद समान पद अलग करें।
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