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If the constant term of the polynomial \(p(x)=x^2+5x+c\) is \(-6\), what is the value of \(p(0)\)?

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Answer and explanation

Correct answer: -6

For a polynomial, \(p(0)\) equals its constant term because \(p(0)=0^2+5(0)+c=c\). Here, the constant term is \(c=-6\), so \(p(0)=-6\). The value 5 is the coefficient of \(x\), not the constant term. Exam tip: To find \(p(0)\), substitute \(x=0\) in the polynomial.

Related tags

PolynomialsConstant-TermPolynomial-ValueP-Of-Zero

Frequently asked questions

What is the correct answer to this question?

-6

Why is this the correct answer?

For a polynomial, \(p(0)\) equals its constant term because \(p(0)=0^2+5(0)+c=c\). Here, the constant term is \(c=-6\), so \(p(0)=-6\). The value 5 is the coefficient of \(x\), not the constant term. Exam tip: To find \(p(0)\), substitute \(x=0\) in the polynomial.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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