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If p(x) = x² − 2√2x + 2, which is the correct factorized form of p(x)?

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Answer and explanation

Correct answer: (x − √2)²

Use the perfect-square identity (x − a)² = x² − 2ax + a². Taking a = √2 gives (x − √2)² = x² − 2√2x + (√2)² = x² − 2√2x + 2, which is exactly the given polynomial. Therefore option A is correct. Option B expands to x² + 2√2x + 2, so its middle-term sign is wrong. Option C expands to x² − 4x + 4 and has different coefficients. Option D uses the difference-of-squares identity and gives x² − 2, which lacks the required middle term. The factorization also shows that √2 is a repeated zero, because the same linear factor occurs twice.

Related tags

FactorisationPerfect SquareIrrational ZeroPolynomial IdentitiesPolynomialsPolynomials In One VariableMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

(x − √2)²

Why is this the correct answer?

Use the perfect-square identity (x − a)² = x² − 2ax + a². Taking a = √2 gives (x − √2)² = x² − 2√2x + (√2)² = x² − 2√2x + 2, which is exactly the given polynomial. Therefore option A is correct. Option B expands to x² + 2√2x + 2, so its middle-term sign is wrong. Option C expands to x² − 4x + 4 and has different coefficients. Option D uses the difference-of-squares identity and gives x² − 2, which lacks the required middle term. The factorization also shows that √2 is a repeated zero, because the same linear factor occurs twice.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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