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If \(p(x)=ax^3+bx^2+cx+d\) and \(p(0)=-7\), what is the value of \(d\)?
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Answer and explanation
Correct answer: -7
Substituting \(x=0\) gives \(p(0)=a(0)^3+b(0)^2+c(0)+d=d\). Since \(p(0)=-7\), the constant term is \(d=-7\). Option A has the incorrect sign. Exam tip: For any polynomial, \(p(0)\) equals its constant term.
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What is the correct answer to this question?
-7
Why is this the correct answer?
Substituting \(x=0\) gives \(p(0)=a(0)^3+b(0)^2+c(0)+d=d\). Since \(p(0)=-7\), the constant term is \(d=-7\). Option A has the incorrect sign. Exam tip: For any polynomial, \(p(0)\) equals its constant term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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