Concept-wise Practice

irrational root MCQ Questions for Class 10

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Practice Questions

18 questions tagged with irrational root.

यदि \(x=1-\sqrt{5}\), तो \(x^2-2x-4\) का मान क्या है?

If \(x=1-\sqrt{5}\), what is the value of \(x^2-2x-4\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Since \(x-1=-\sqrt{5}\), ((x-1)2=5), so \(x^2-2x-4=0\). Isolate the irrational part and square in exams.

Step 2

Why this answer is correct

The correct answer is A. (0). Since \(x-1=-\sqrt{5}\), ((x-1)2=5), so \(x^2-2x-4=0\). Isolate the irrational part and square in exams.

Step 3

Exam Tip

\(x-1=-\sqrt{5}\), इसलिए ((x-1)2=5) से \(x^2-2x-4=0\) मिलता है। परीक्षा में अपरिमेय भाग अलग करके वर्ग करें।

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यदि \(x=3-\sqrt{2}\), तो \(x^2-6x+7\) का मान क्या है?

If \(x=3-\sqrt{2}\), what is the value of \(x^2-6x+7\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

Step 2

Why this answer is correct

The correct answer is A. (0). Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.

Step 3

Exam Tip

\(x-3=-\sqrt{2}\), इसलिए ((x-3)2=2) से \(x^2-6x+7=0\) है। परीक्षा में \(a-\sqrt{b}\) को भी इसी विधि से संभालें।

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यदि (n) धनात्मक पूर्णांक है और \(\sqrt{n}\) अपरिमेय है, तो \(\sqrt{4n}\) कब परिमेय होगी?

If (n) is a positive integer and \(\sqrt{n}\) is irrational, when will \(\sqrt{4n}\) be rational?

Explanation opens after your attempt
Correct Answer

A. कभी नहींNever

Step 1

Concept

\(\sqrt{4n}=2\sqrt{n}\). Multiplying an irrational number by a non zero rational keeps it irrational.

Step 2

Why this answer is correct

The correct answer is A. कभी नहीं / Never. \(\sqrt{4n}=2\sqrt{n}\). Multiplying an irrational number by a non zero rational keeps it irrational.

Step 3

Exam Tip

\(\sqrt{4n}=2\sqrt{n}\) है। गैर शून्य परिमेय से अपरिमेय को गुणा करने पर संख्या अपरिमेय रहती है।

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यदि \(\sqrt{k}\) अपरिमेय है और (k) धनात्मक पूर्णांक है तो कौन सा (k) हो सकता है?

If \(\sqrt{k}\) is irrational and (k) is a positive integer, which (k) can be correct?

Explanation opens after your attempt
Correct Answer

A. (k=123)

Step 1

Concept

(123) is not a perfect square so \(\sqrt{123}\) is irrational. Roots of perfect squares are rational.

Step 2

Why this answer is correct

The correct answer is A. (k=123). (123) is not a perfect square so \(\sqrt{123}\) is irrational. Roots of perfect squares are rational.

Step 3

Exam Tip

(123) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{123}\) अपरिमेय है। पूर्ण वर्गों की जड़ परिमेय होती है।

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कौन सा कथन \(\sqrt{a}\) के लिए सही है जब (a) धनात्मक पूर्णांक है?

Which statement is correct for \(\sqrt{a}\) when (a) is a positive integer?

Explanation opens after your attempt
Correct Answer

A. यदि (a) पूर्ण वर्ग नहीं है तो \(\sqrt{a}\) अपरिमेय हैIf (a) is not a perfect square then \(\sqrt{a}\) is irrational

Step 1

Concept

The square root of a positive integer is rational only when the number is a perfect square. So a non perfect square gives an irrational root.

Step 2

Why this answer is correct

The correct answer is A. यदि (a) पूर्ण वर्ग नहीं है तो \(\sqrt{a}\) अपरिमेय है / If (a) is not a perfect square then \(\sqrt{a}\) is irrational. The square root of a positive integer is rational only when the number is a perfect square. So a non perfect square gives an irrational root.

Step 3

Exam Tip

धनात्मक पूर्णांक की वर्गमूल परिमेय तभी होती है जब संख्या पूर्ण वर्ग हो। इसलिए पूर्ण वर्ग न हो तो जड़ अपरिमेय होगी।

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यदि \(\sqrt{k}\) अपरिमेय है और (k) धनात्मक पूर्णांक है तो (k) के बारे में सही कथन क्या है?

If \(\sqrt{k}\) is irrational and (k) is a positive integer, what is correct about (k)?

Explanation opens after your attempt
Correct Answer

A. (k) पूर्ण वर्ग नहीं है(k) is not a perfect square

Step 1

Concept

If a positive integer is not a perfect square its square root is irrational. So (k) is not a perfect square.

Step 2

Why this answer is correct

The correct answer is A. (k) पूर्ण वर्ग नहीं है / (k) is not a perfect square. If a positive integer is not a perfect square its square root is irrational. So (k) is not a perfect square.

Step 3

Exam Tip

धनात्मक पूर्णांक पूर्ण वर्ग न हो तो उसकी वर्गमूल अपरिमेय होती है। इसलिए (k) पूर्ण वर्ग नहीं होगा।

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कौन सी संख्या \(\frac{p}{q}\) रूप में नहीं लिखी जा सकती जहाँ \(q\neq0\)?

Which number cannot be written in the form \(\frac{p}{q}\) where \(q\neq0\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{14}\)

Step 1

Concept

\(\sqrt{14}\) is irrational because (14) is not a perfect square. The other options can be written in rational form.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{14}\). \(\sqrt{14}\) is irrational because (14) is not a perfect square. The other options can be written in rational form.

Step 3

Exam Tip

\(\sqrt{14}\) अपरिमेय है क्योंकि (14) पूर्ण वर्ग नहीं है। बाकी विकल्प परिमेय रूप में लिखे जा सकते हैं।

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यदि (n) एक धनात्मक पूर्णांक है और \(\sqrt{n}\) अपरिमेय है तो (n) के बारे में क्या कहा जा सकता है?

If (n) is a positive integer and \(\sqrt{n}\) is irrational then what can be said about (n)?

Explanation opens after your attempt
Correct Answer

A. (n) पूर्ण वर्ग नहीं है(n) is not a perfect square

Step 1

Concept

The square root of a positive integer is irrational when it is not a perfect square. Remember this simple rule.

Step 2

Why this answer is correct

The correct answer is A. (n) पूर्ण वर्ग नहीं है / (n) is not a perfect square. The square root of a positive integer is irrational when it is not a perfect square. Remember this simple rule.

Step 3

Exam Tip

धनात्मक पूर्णांक की वर्गमूल अपरिमेय तब होती है जब वह पूर्ण वर्ग नहीं होता। यह सरल नियम याद रखें।

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\(\sqrt{43}\) के बारे में सही कथन कौन सा है?

Which statement is correct about \(\sqrt{43}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(43) is not a perfect square so \(\sqrt{43}\) is irrational. Watch the root when the number is not a perfect square.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (43) is not a perfect square so \(\sqrt{43}\) is irrational. Watch the root when the number is not a perfect square.

Step 3

Exam Tip

(43) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{43}\) अपरिमेय है। पूर्ण वर्ग न होने पर जड़ पर ध्यान दें।

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कौन सी संख्या परिमेय संख्या नहीं है?

Which number is not a rational number?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{34}\)

Step 1

Concept

\(\sqrt{34}\) cannot be written in \(\frac{p}{q}\) form. The other options are rational.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{34}\). \(\sqrt{34}\) cannot be written in \(\frac{p}{q}\) form. The other options are rational.

Step 3

Exam Tip

\(\sqrt{34}\) को \(\frac{p}{q}\) रूप में नहीं लिखा जा सकता। बाकी विकल्प परिमेय हैं।

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कौन सा विकल्प परिमेय संख्या नहीं है?

Which option is not a rational number?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{29}\)

Step 1

Concept

\(\sqrt{29}\) is irrational because (29) is not a perfect square. All others can be written in rational form.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{29}\). \(\sqrt{29}\) is irrational because (29) is not a perfect square. All others can be written in rational form.

Step 3

Exam Tip

\(\sqrt{29}\) अपरिमेय है क्योंकि (29) पूर्ण वर्ग नहीं है। बाकी सभी परिमेय रूप में लिखे जा सकते हैं।

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\(\sqrt{37}\) के बारे में कौन सा कथन सही है?

Which statement is correct about \(\sqrt{37}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(37) is not a perfect square so \(\sqrt{37}\) is irrational. Remember the list of perfect squares.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (37) is not a perfect square so \(\sqrt{37}\) is irrational. Remember the list of perfect squares.

Step 3

Exam Tip

(37) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{37}\) अपरिमेय है। पूर्ण वर्गों की सूची याद रखें।

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कौन सा निष्कर्ष सही है यदि संख्या \(\sqrt{n}\) में (n) पूर्ण वर्ग नहीं है?

Which conclusion is correct if (n) is not a perfect square in the number \(\sqrt{n}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{n}\) अपरिमेय होगी\(\sqrt{n}\) will be irrational

Step 1

Concept

If positive integer (n) is not a perfect square then \(\sqrt{n}\) is irrational. This is an easy exam rule.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{n}\) अपरिमेय होगी / \(\sqrt{n}\) will be irrational. If positive integer (n) is not a perfect square then \(\sqrt{n}\) is irrational. This is an easy exam rule.

Step 3

Exam Tip

धनात्मक पूर्णांक (n) पूर्ण वर्ग न हो तो \(\sqrt{n}\) अपरिमेय होती है। यह आसान परीक्षा नियम है।

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\(\sqrt{64}\) और \(\sqrt{65}\) में कौन सा कथन सही है?

Which statement is correct about \(\sqrt{64}\) and \(\sqrt{65}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{64}\) परिमेय है और \(\sqrt{65}\) अपरिमेय है\(\sqrt{64}\) is rational and \(\sqrt{65}\) is irrational

Step 1

Concept

(64) is a perfect square but (65) is not. So their square roots are of different types.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{64}\) परिमेय है और \(\sqrt{65}\) अपरिमेय है / \(\sqrt{64}\) is rational and \(\sqrt{65}\) is irrational. (64) is a perfect square but (65) is not. So their square roots are of different types.

Step 3

Exam Tip

(64) पूर्ण वर्ग है लेकिन (65) नहीं है। इसलिए उनकी वर्गमूल की प्रकृति अलग है।

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\(\sqrt{11}\) के बारे में सही कथन कौन सा है?

Which statement is correct about \(\sqrt{11}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(11) is not a perfect square so \(\sqrt{11}\) is irrational. Identify such roots in simplest form.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (11) is not a perfect square so \(\sqrt{11}\) is irrational. Identify such roots in simplest form.

Step 3

Exam Tip

(11) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{11}\) अपरिमेय है। ऐसी जड़ों को सरल रूप में पहचानें।

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यदि \(x=\sqrt{a}\) अपरिमेय है और (a<50) धनात्मक पूर्णांक है, तो कौन-सा (a) उपयुक्त नहीं है?

If \(x=\sqrt{a}\) is irrational and (a<50) is a positive integer, which (a) is not suitable?

Explanation opens after your attempt
Correct Answer

C. (36)

Step 1

Concept

\(\sqrt{a}\) is irrational only when (a) is not a perfect square.

Step 2

Why this answer is correct

(36) is a perfect square and \(\sqrt{36}=6\), so it is not suitable.

Step 3

Exam Tip

Quickly identify perfect squares among the options. चरण 1: \(\sqrt{a}\) अपरिमेय तभी होगा जब (a) पूर्ण वर्ग न हो। चरण 2: (36) पूर्ण वर्ग है और \(\sqrt{36}=6\), इसलिए यह उपयुक्त नहीं है। चरण 3: विकल्पों में पूर्ण वर्ग को तुरंत पहचानें।

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किस विकल्प में \(\sqrt{a}\) अपरिमेय है?

In which option is \(\sqrt{a}\) irrational?

Explanation opens after your attempt
Correct Answer

C. (a=90)

Step 1

Concept

(49), (81), and (121) are perfect squares.

Step 2

Why this answer is correct

(90) is not a perfect square, so \(\sqrt{90}\) is irrational.

Step 3

Exam Tip

To decide the nature of a square root, first check perfect squares. चरण 1: (49), (81) और (121) पूर्ण वर्ग हैं। चरण 2: (90) पूर्ण वर्ग नहीं है, इसलिए \(\sqrt{90}\) अपरिमेय है। चरण 3: वर्गमूल की प्रकृति जानने के लिए सबसे पहले पूर्ण वर्ग जाँचें।

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यदि (x) अपरिमेय है और \(x^2=7\), तो (x) का संभावित मान कौन-सा है?

If (x) is irrational and \(x^2=7\), which can be the value of (x)?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{7}\)

Step 1

Concept

From \(x^2=7\), \(x=\sqrt{7}\) or \(x=-\sqrt{7}\).

Step 2

Why this answer is correct

Among the options, \(\sqrt{7}\) is present and it is irrational.

Step 3

Exam Tip

Remember both positive and negative roots, then match the given options. चरण 1: \(x^2=7\) से \(x=\sqrt{7}\) या \(x=-\sqrt{7}\) हो सकता है। चरण 2: दिए गए विकल्पों में \(\sqrt{7}\) है, जो अपरिमेय है। चरण 3: वर्ग समीकरण में धन और ऋण दोनों मूल याद रखें, पर विकल्प के अनुसार चुनें।

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