यदि \(x=3-\sqrt{2}\), तो \(x^2-6x+7\) का मान क्या है?
If \(x=3-\sqrt{2}\), what is the value of \(x^2-6x+7\)?
Explanation opens after your attempt
Correct Answer
A. (0)
Concept
Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.
Why this answer is correct
The correct answer is A. (0). Since \(x-3=-\sqrt{2}\), ((x-3)2=2), hence \(x^2-6x+7=0\). Handle \(a-\sqrt{b}\) the same way in exams.
Exam Tip
\(x-3=-\sqrt{2}\), इसलिए ((x-3)2=2) से \(x^2-6x+7=0\) है। परीक्षा में \(a-\sqrt{b}\) को भी इसी विधि से संभालें।
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