किसी समांतर श्रेढ़ी में \(S_n=2n^2+5n\) है। पहले (8) पदों का योग क्या होगा?
In an AP, \(S_n=2n^2+5n\). What is the sum of the first (8) terms?
#sum formula
#given sn
#substitution
A (168)
B (160)
C (172)
D (176)
Explanation opens after your attempt
Step 1
Concept
(S_8=2(8)2 +5(8)=168). Put (n=8) directly in the given \(S_n\).
Step 2
Why this answer is correct
The correct answer is A. (168). (S_8=2(8)2 +5(8)=168). Put (n=8) directly in the given \(S_n\).
Step 3
Exam Tip
(S_8=2(8)2 +5(8)=168)। दिए गए \(S_n\) में सीधे (n=8) रखें।
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यदि \(S_n=3n^2+2n\), तो पहले (12) पदों का योग क्या है?
If \(S_n=3n^2+2n\), what is the sum of the first (12) terms?
#sum expression
#substitution
#ap
A (452)
B (456)
C (460)
D (468)
Explanation opens after your attempt
Step 1
Concept
Putting (n=12), (S_{12}=3(12)2 +2(12)=456). Substitute the given value of (n) directly in the sum formula.
Step 2
Why this answer is correct
The correct answer is B. (456). Putting (n=12), (S_{12}=3(12)2 +2(12)=456). Substitute the given value of (n) directly in the sum formula.
Step 3
Exam Tip
(n=12) रखने पर (S_{12}=3(12)2 +2(12)=456)। दिए गए योग सूत्र में सीधे (n) का मान रखें।
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यदि (5(2x-y)-3(x+y)=11) और (2(2x-y)+4(x+y)=50), तो (y) का मान क्या है?
If (5(2x-y)-3(x+y)=11) and (2(2x-y)+4(x+y)=50), what is the value of (y)?
#pair-linear-equations
#linear-combination
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. (3). Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (5u-3v=11), (2u+4v=50) से (u=7,v=9), इसलिए \(y=\frac{11}{3}\)।
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राम की वर्तमान आयु श्याम की आयु से (4) वर्ष अधिक है। (5) वर्ष बाद उनकी आयुओं का योग (44) होगा। राम की वर्तमान आयु क्या है?
Ram is (4) years older than Shyam. After (5) years, the sum of their ages will be (44). What is Ram's present age?
#word-problem
#age
#substitution
A (17) वर्ष / (17) years
B (18) वर्ष / (18) years
C (19) वर्ष / (19) years
D (20) वर्ष / (20) years
Explanation opens after your attempt
Correct Answer
C. (19) वर्ष / (19) years
Step 1
Concept
Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 2
Why this answer is correct
The correct answer is C. (19) वर्ष / (19) years. Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 3
Exam Tip
यदि राम की आयु (r) और श्याम की (s) हो तो (r-s=4) और (r+s+10=44)। हल करने पर (r=19) मिलता है।
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यदि (2x+3y=13) और (mx-3y=17) का हल (x=5) है, तो (m) का मान क्या है?
If (2x+3y=13) and (mx-3y=17) have solution (x=5), what is (m)?
#pair-linear-equations
#parameter
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 3
Exam Tip
पहले समीकरण में (x=5) रखने पर (10+3y=13), इसलिए (y=1)। दूसरे में (5m-3=17), इसलिए (m=4)।
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यदि (4x+ky=26) और (4x-3y=2) का हल (y=4) है, तो (k) का मान क्या है?
If (4x+ky=26) and (4x-3y=2) have solution (y=4), what is (k)?
#pair-linear-equations
#parameter
#substitution
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 2
Why this answer is correct
The correct answer is B. (3). Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 3
Exam Tip
दूसरे समीकरण में (y=4) रखने पर (4x-12=2), इसलिए \(x=\frac{7}{2}\)। पहले में (14+4k=26), इसलिए (k=3)।
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यदि (ax+2y=17) और (3x-2y=7) का हल (x=4) है, तो (a) का मान क्या है?
If the solution of (ax+2y=17) and (3x-2y=7) has (x=4), what is the value of (a)?
#pair-linear-equations
#parameter
#substitution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 2
Why this answer is correct
The correct answer is C. (3). Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 3
Exam Tip
दूसरे समीकरण में (x=4) रखने पर (12-2y=7), इसलिए \(y=\frac{5}{2}\)। पहले में रखने पर (4a+5=17), इसलिए (a=3)।
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यदि (0.2x+0.3y=2.7) और (0.4x-0.1y=1.1), तो (y) का मान क्या है?
If (0.2x+0.3y=2.7) and (0.4x-0.1y=1.1), what is the value of (y)?
#pair-linear-equations
#decimal-equations
#substitution
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 2
Why this answer is correct
The correct answer is B. (5). Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 3
Exam Tip
दशमलव हटाने पर (2x+3y=27) और (4x-y=11) मिलते हैं। हल करने पर (y=5) है।
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एक संख्या दूसरी संख्या से (8) अधिक है। दोनों संख्याओं के (3) गुने और (2) गुने का योग (94) है, तो छोटी संख्या क्या है?
One number is (8) more than another. The sum of three times one and twice the other is (94). What is the smaller number?
#word-problem
#numbers
#substitution
A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 2
Why this answer is correct
The correct answer is B. (14). Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 3
Exam Tip
छोटी संख्या (y) और बड़ी (x=y+8) मानें। (3x+2y=94) रखने पर (5y+24=94), इसलिए (y=14)।
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यदि (x+4y=22) और (3x-2y=4), तो (x:y) का अनुपात क्या होगा?
If (x+4y=22) and (3x-2y=4), what is the ratio (x:y)?
#pair-linear-equations
#ratio
#substitution
A (2:5)
B (3:4)
C (4:5)
D (5:6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 2
Why this answer is correct
The correct answer is A. (2:5). From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 3
Exam Tip
पहले से (x=22-4y)। रखने पर (66-12y-2y=4), इसलिए \(y=\frac{31}{7}\) और \(x=\frac{30}{7}\), अनुपात (30:31) है।
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समीकरणों (2x-y=9) और (5x+2y=12) को हल करने पर (x) का मान क्या है?
Solving (2x-y=9) and (5x+2y=12), what is the value of (x)?
#pair-linear-equations
#substitution
#fraction
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 2
Why this answer is correct
The correct answer is B. (3). From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 3
Exam Tip
पहले से (y=2x-9)। दूसरे में रखने पर (5x+4x-18=12), इसलिए \(x=\frac{10}{3}\), सरलीकरण ध्यान से करें।
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समीकरणों (3x+5y=34) और (6x-y=27) को हल करने पर (x+y) क्या होगा?
Solving (3x+5y=34) and (6x-y=27), what is (x+y)?
#pair-linear-equations
#substitution
#fraction
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 2
Why this answer is correct
The correct answer is B. (8). From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 3
Exam Tip
दूसरे से (y=6x-27)। रखने पर (3x+30x-135=34), इसलिए \(x=\frac{169}{33}\); उत्तर भिन्न हो सकता है।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश और हर दोनों में (2) जोड़ने पर भिन्न \(\frac{4}{5}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to both numerator and denominator, the fraction becomes \(\frac{4}{5}\). What is the original fraction?
#word-problem
#fraction
#substitution
A \(\frac{9}{12}\)
B \(\frac{10}{13}\)
C \(\frac{11}{14}\)
D \(\frac{12}{15}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{10}{13}\)
Step 1
Concept
Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{10}{13}\). Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 3
Exam Tip
मान लें हर (y) है तो अंश (y-3)। \(\frac{y-1}{y+2}=\frac{4}{5}\) से (y=13), इसलिए भिन्न \(\frac{10}{13}\) है।
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दो संख्याओं का योग (23) है और उनका अंतर (7) है। प्रतिस्थापन विधि से बड़ी संख्या क्या होगी?
The sum of two numbers is (23) and their difference is (7). By substitution, what is the greater number?
#word-problem
#numbers
#substitution
A (14)
B (15)
C (16)
D (17)
Explanation opens after your attempt
Step 1
Concept
Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 2
Why this answer is correct
The correct answer is B. (15). Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 3
Exam Tip
यदि संख्याएं (x,y) हों तो (x+y=23) और (x-y=7)। जोड़ने पर (2x=30), इसलिए बड़ी संख्या (15) है।
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यदि (x=2y+1) और (3x-y=17), तो (x) का मान क्या है?
If (x=2y+1) and (3x-y=17), what is the value of (x)?
#pair-linear-equations
#substitution
#brackets
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 2
Why this answer is correct
The correct answer is C. (7). Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 3
Exam Tip
पहले समीकरण को दूसरे में रखने पर (3(2y+1)-y=17), इसलिए \(y=\frac{14}{5}\) नहीं बल्कि (5y=14) आता है। फिर \(x=\frac{33}{5}\), इसलिए विकल्पों की वैधता जांचें।
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यदि (5x+3y=28) और (2x-y=1), तो (xy) का मान क्या है?
If (5x+3y=28) and (2x-y=1), what is the value of (xy)?
#pair-linear-equations
#substitution
#product
A (10)
B (12)
C (15)
D (18)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 2
Why this answer is correct
The correct answer is C. (15). From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-1)। रखने पर (11x=31) नहीं, सही रूप (5x+6x-3=28) से \(x=\frac{31}{11}\) आता है, इसलिए विकल्प जांचकर हल करें।
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यदि (3x-2y=4) और (x+y=11), तो प्रतिस्थापन विधि से (y) का मान क्या होगा?
If (3x-2y=4) and (x+y=11), what is the value of (y) by substitution?
#pair-linear-equations
#substitution
#expert
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=11-y) carefully in the first equation; incorrect simplification changes the answer. Always check the obtained values in both equations.
Step 2
Why this answer is correct
The correct answer is D. (7). Substitute (x=11-y) carefully in the first equation; incorrect simplification changes the answer. Always check the obtained values in both equations.
Step 3
Exam Tip
दूसरे समीकरण से (x=11-y) रखकर (33-5y=4) नहीं बल्कि (33-3y-2y=4) मिलता है, इसलिए \(y=\frac{29}{5}\) नहीं होगा; सही जांच जरूरी है।
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यदि (2x-3y=-7) और (4x+y=19), तो प्रतिस्थापन विधि से (y) का मान क्या है?
If (2x-3y=-7) and (4x+y=19), what is the value of (y) by substitution?
#pair-linear-equations
#substitution
#expert
A (y=3)
B (y=4)
C (y=5)
D (y=2)
Explanation opens after your attempt
Step 1
Concept
From the second equation, put (y=19-4x), giving (x=4) and (y=3). In exams, isolate the easier variable first.
Step 2
Why this answer is correct
The correct answer is A. (y=3). From the second equation, put (y=19-4x), giving (x=4) and (y=3). In exams, isolate the easier variable first.
Step 3
Exam Tip
दूसरे समीकरण से (y=19-4x) रखकर हल करने पर (x=4) और (y=3) मिलता है। परीक्षा में पहले सरल चर को अलग करें।
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यदि (x=5y-8) और (4x+3y=61), तो (y) का मान क्या है?
If (x=5y-8) and (4x+3y=61), what is the value of (y)?
#linear equations
#substitution
#fraction value
#expert
#class 10
A \(y=\frac{83}{23}\)
B \(y=\frac{88}{23}\)
C \(y=\frac{93}{23}\)
D \(y=\frac{98}{23}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{93}{23}\)
Step 1
Concept
Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{93}{23}\). Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 3
Exam Tip
(x=5y-8) को दूसरे समीकरण में रखें। (20y-32+3y=61), इसलिए \(y=\frac{93}{23}\)।
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यदि (x+y=31) और (4x-3y=19), तो (2x-y) का मान क्या है?
If (x+y=31) and (4x-3y=19), what is the value of (2x-y)?
#linear equations
#substitution
#expression value
#expert
#class 10
A (15)
B (16)
C (17)
D (18)
Explanation opens after your attempt
Step 1
Concept
Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 2
Why this answer is correct
The correct answer is C. (17). Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 3
Exam Tip
(x=31-y) रखने पर (124-7y=19), इसलिए (y=15) और (x=16)। अतः (2x-y=17)।
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यदि (px+5y=43) और (3x-y=17) का हल (x=6,\ y=1) है, तो (p) का मान क्या है?
If (px+5y=43) and (3x-y=17) have solution (x=6,\ y=1), what is the value of (p)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(p=\frac{17}{3}\)
B (p=6)
C \(p=\frac{19}{3}\)
D \(p=\frac{20}{3}\)
Explanation opens after your attempt
Correct Answer
C. \(p=\frac{19}{3}\)
Step 1
Concept
Put (x=6,\ y=1) in (px+5y=43). Then (6p+5=43), so \(p=\frac{19}{3}\).
Step 2
Why this answer is correct
The correct answer is C. \(p=\frac{19}{3}\). Put (x=6,\ y=1) in (px+5y=43). Then (6p+5=43), so \(p=\frac{19}{3}\).
Step 3
Exam Tip
(x=6,\ y=1) को (px+5y=43) में रखें। (6p+5=43), इसलिए \(p=\frac{19}{3}\)।
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समीकरणों \(\frac{2x-y}{5}=4\) और \(\frac{x+3y}{4}=8\) से (x) का मान क्या है?
What is the value of (x) from \(\frac{2x-y}{5}=4\) and \(\frac{x+3y}{4}=8\)?
#linear equations
#transformed equations
#substitution
#expert
#class 10
A \(x=\frac{88}{7}\)
B \(x=\frac{90}{7}\)
C \(x=\frac{92}{7}\)
D \(x=\frac{94}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{92}{7}\)
Step 1
Concept
The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{92}{7}\). The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
Step 3
Exam Tip
दिए समीकरण (2x-y=20) और (x+3y=32) बनते हैं। प्रतिस्थापन से \(x=\frac{92}{7}\)।
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यदि (4x+ky=55) का हल (x=9,\ y=5) है, तो (k) का मान क्या है?
If (x=9,\ y=5) is a solution of (4x+ky=55), what is the value of (k)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(k=\frac{17}{5}\)
B \(k=\frac{18}{5}\)
C \(k=\frac{19}{5}\)
D (k=4)
Explanation opens after your attempt
Correct Answer
C. \(k=\frac{19}{5}\)
Step 1
Concept
Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(k=\frac{19}{5}\). Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).
Step 3
Exam Tip
(x=9,\ y=5) रखने पर (36+5k=55) मिलता है। इसलिए \(k=\frac{19}{5}\)।
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यदि (4(x+y)+3(x-y)=62) और (2(x+y)-5(x-y)=-2), तो (y) का मान क्या है?
If (4(x+y)+3(x-y)=62) and (2(x+y)-5(x-y)=-2), what is the value of (y)?
#linear equations
#transformation
#substitution
#expert
#class 10
A \(y=\frac{37}{13}\)
B \(y=\frac{40}{13}\)
C \(y=\frac{43}{13}\)
D \(y=\frac{46}{13}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{43}{13}\)
Step 1
Concept
Let (x+y=s) and (x-y=d), then solve. This gives \(x=\frac{109}{13}\) and \(y=\frac{43}{13}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{43}{13}\). Let (x+y=s) and (x-y=d), then solve. This gives \(x=\frac{109}{13}\) and \(y=\frac{43}{13}\).
Step 3
Exam Tip
(x+y=s) और (x-y=d) मानकर हल करें। \(x=\frac{109}{13}\) और \(y=\frac{43}{13}\) मिलता है।
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समीकरणों \(\frac{x}{5}+\frac{y}{6}=7\) और (x-y=6) से (x) का मान क्या है?
What is the value of (x) from \(\frac{x}{5}+\frac{y}{6}=7\) and (x-y=6)?
#linear equations
#fraction equations
#substitution
#expert
#class 10
A \(x=\frac{220}{11}\)
B \(x=\frac{230}{11}\)
C \(x=\frac{240}{11}\)
D \(x=\frac{250}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{240}{11}\)
Step 1
Concept
Multiply the first equation by (30) to get (6x+5y=210). Using (x=y+6) gives \(x=\frac{240}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{240}{11}\). Multiply the first equation by (30) to get (6x+5y=210). Using (x=y+6) gives \(x=\frac{240}{11}\).
Step 3
Exam Tip
पहले समीकरण को (30) से गुणा कर (6x+5y=210) बनाएं। (x=y+6) रखने पर \(x=\frac{240}{11}\)।
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यदि (3x+my=29) का हल (x=5,\ y=2) है, तो (m) का मान क्या होगा?
If (x=5,\ y=2) is a solution of (3x+my=29), what will be the value of (m)?
#linear equations
#parameter
#substitution
#expert
#class 10
A (m=5)
B (m=6)
C (m=7)
D (m=8)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).
Step 2
Why this answer is correct
The correct answer is C. (m=7). Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).
Step 3
Exam Tip
(x=5,\ y=2) रखने पर (15+2m=29) मिलता है। इसलिए (m=7)।
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यदि (kx+4y=38) और (x-y=3) का हल (x=7,\ y=4) है, तो (k) का मान क्या होगा?
If (kx+4y=38) and (x-y=3) have solution (x=7,\ y=4), what will be the value of (k)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(k=\frac{20}{7}\)
B \(k=\frac{22}{7}\)
C \(k=\frac{24}{7}\)
D \(k=\frac{26}{7}\)
Explanation opens after your attempt
Correct Answer
B. \(k=\frac{22}{7}\)
Step 1
Concept
Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).
Step 2
Why this answer is correct
The correct answer is B. \(k=\frac{22}{7}\). Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).
Step 3
Exam Tip
दिए हल को (kx+4y=38) में रखें। (7k+16=38), इसलिए \(k=\frac{22}{7}\)।
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समीकरणों \(\frac{x}{4}+\frac{y}{5}=6\) और (x-y=4) का हल क्या है?
What is the solution of \(\frac{x}{4}+\frac{y}{5}=6\) and (x-y=4)?
#linear equations
#fraction equations
#substitution
#expert
#class 10
A \(x=\frac{124}{9},\ y=\frac{88}{9}\)
B \(x=\frac{128}{9},\ y=\frac{92}{9}\)
C \(x=\frac{136}{9},\ y=\frac{100}{9}\)
D \(x=\frac{140}{9},\ y=\frac{104}{9}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{136}{9},\ y=\frac{100}{9}\)
Step 1
Concept
The first equation becomes (5x+4y=120). Using (x=y+4) gives \(y=\frac{100}{9}\) and \(x=\frac{136}{9}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{136}{9},\ y=\frac{100}{9}\). The first equation becomes (5x+4y=120). Using (x=y+4) gives \(y=\frac{100}{9}\) and \(x=\frac{136}{9}\).
Step 3
Exam Tip
पहला समीकरण (5x+4y=120) बनता है। (x=y+4) रखने पर \(y=\frac{100}{9}\) और \(x=\frac{136}{9}\)।
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यदि (x=4y-7) और (3x+2y=59), तो (y) का मान क्या है?
If (x=4y-7) and (3x+2y=59), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{36}{14}\)
B \(y=\frac{40}{14}\)
C \(y=\frac{80}{14}\)
D \(y=\frac{84}{14}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{80}{14}\)
Step 1
Concept
Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{80}{14}\). Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 3
Exam Tip
(x=4y-7) को दूसरे समीकरण में रखिए। (12y-21+2y=59), इसलिए \(y=\frac{40}{7}\)।
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यदि (x+y=24) और (3x-2y=37), तो (2x+y) का मान क्या है?
If (x+y=24) and (3x-2y=37), what is the value of (2x+y)?
#linear equations
#substitution
#expression value
#hard
#class 10
A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 2
Why this answer is correct
The correct answer is B. (37). Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 3
Exam Tip
(x=24-y) रखने पर (72-5y=37), इसलिए (y=7) और (x=17)। अतः (2x+y=41), इसलिए सही विकल्प (D) है।
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