समीकरणों (4x-9y=31) और (8x+9y=65) के हल में (y) का मान क्या होगा?
For (4x-9y=31) and (8x+9y=65), what is the value of (y) in the solution?
#pair-linear-equations
#elimination
#fraction
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=96), so (x=8). Substituting in the first equation gives (32-9y=31), so \(y=\frac{1}{9}\).
Step 2
Why this answer is correct
The correct answer is A. (1). Adding gives (12x=96), so (x=8). Substituting in the first equation gives (32-9y=31), so \(y=\frac{1}{9}\).
Step 3
Exam Tip
जोड़ने पर (12x=96), इसलिए (x=8)। पहले समीकरण में रखने पर (32-9y=31), इसलिए \(y=\frac{1}{9}\)।
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यदि (6x+11y=9) और (12x-11y=63), तो (x-y) का मान क्या है?
If (6x+11y=9) and (12x-11y=63), what is the value of (x-y)?
#pair-linear-equations
#fraction
#negative-values
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Adding gives (18x=72), so (x=4). Then \(y=-\frac{15}{11}\), hence \(x-y=\frac{59}{11}\).
Step 2
Why this answer is correct
The correct answer is A. (6). Adding gives (18x=72), so (x=4). Then \(y=-\frac{15}{11}\), hence \(x-y=\frac{59}{11}\).
Step 3
Exam Tip
जोड़ने पर (18x=72), इसलिए (x=4)। फिर \(y=-\frac{15}{11}\), इसलिए \(x-y=\frac{59}{11}\)।
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समीकरणों (2x-y=9) और (5x+2y=12) को हल करने पर (x) का मान क्या है?
Solving (2x-y=9) and (5x+2y=12), what is the value of (x)?
#pair-linear-equations
#substitution
#fraction
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 2
Why this answer is correct
The correct answer is B. (3). From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 3
Exam Tip
पहले से (y=2x-9)। दूसरे में रखने पर (5x+4x-18=12), इसलिए \(x=\frac{10}{3}\), सरलीकरण ध्यान से करें।
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यदि (7x-3y=20) और (14x+3y=64), तो (2x+y) का मान क्या है?
If (7x-3y=20) and (14x+3y=64), what is the value of (2x+y)?
#pair-linear-equations
#expression
#fraction
A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
Adding gives (21x=84), so (x=4). From the first equation \(y=\frac{8}{3}\), hence \(2x+y=\frac{32}{3}\).
Step 2
Why this answer is correct
The correct answer is D. (15). Adding gives (21x=84), so (x=4). From the first equation \(y=\frac{8}{3}\), hence \(2x+y=\frac{32}{3}\).
Step 3
Exam Tip
जोड़ने पर (21x=84), इसलिए (x=4)। पहले समीकरण से \(y=\frac{8}{3}\), इसलिए \(2x+y=\frac{32}{3}\)।
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समीकरणों (3x+5y=34) और (6x-y=27) को हल करने पर (x+y) क्या होगा?
Solving (3x+5y=34) and (6x-y=27), what is (x+y)?
#pair-linear-equations
#substitution
#fraction
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 2
Why this answer is correct
The correct answer is B. (8). From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 3
Exam Tip
दूसरे से (y=6x-27)। रखने पर (3x+30x-135=34), इसलिए \(x=\frac{169}{33}\); उत्तर भिन्न हो सकता है।
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समीकरणों (12x-5y=19) और (6x+5y=35) को हल करने पर (3x-y) का मान क्या है?
Solving (12x-5y=19) and (6x+5y=35), what is the value of (3x-y)?
#pair-linear-equations
#expression
#fraction
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Adding gives (18x=54), so (x=3) and \(y=\frac{17}{5}\). Hence \(3x-y=\frac{28}{5}\); do not guess from options.
Step 2
Why this answer is correct
The correct answer is C. (7). Adding gives (18x=54), so (x=3) and \(y=\frac{17}{5}\). Hence \(3x-y=\frac{28}{5}\); do not guess from options.
Step 3
Exam Tip
जोड़ने पर (18x=54), इसलिए (x=3) और \(y=\frac{17}{5}\)। अतः \(3x-y=\frac{28}{5}\), विकल्प देखकर अनुमान न लगाएं।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश और हर दोनों में (2) जोड़ने पर भिन्न \(\frac{4}{5}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to both numerator and denominator, the fraction becomes \(\frac{4}{5}\). What is the original fraction?
#word-problem
#fraction
#substitution
A \(\frac{9}{12}\)
B \(\frac{10}{13}\)
C \(\frac{11}{14}\)
D \(\frac{12}{15}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{10}{13}\)
Step 1
Concept
Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{10}{13}\). Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 3
Exam Tip
मान लें हर (y) है तो अंश (y-3)। \(\frac{y-1}{y+2}=\frac{4}{5}\) से (y=13), इसलिए भिन्न \(\frac{10}{13}\) है।
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समीकरणों (8x-3y=13) और (2x+3y=17) का हल क्या है?
What is the solution of (8x-3y=13) and (2x+3y=17)?
#pair-linear-equations
#elimination
#fraction
A \(x=3,\ y=\frac{11}{3}\)
B (x=4,\ y=3)
C \(x=2,\ y=\frac{13}{3}\)
D (x=5,\ y=1)
Explanation opens after your attempt
Correct Answer
A. \(x=3,\ y=\frac{11}{3}\)
Step 1
Concept
Adding gives (10x=30), so (x=3). Then (2x+3y=17) gives \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\ y=\frac{11}{3}\). Adding gives (10x=30), so (x=3). Then (2x+3y=17) gives \(y=\frac{11}{3}\).
Step 3
Exam Tip
जोड़ने पर (10x=30), इसलिए (x=3)। फिर (2x+3y=17) से \(y=\frac{11}{3}\) मिलता है।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश में (2) और हर में (1) जोड़ने पर भिन्न \(\frac{3}{4}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to the numerator and (1) to the denominator, the fraction becomes \(\frac{3}{4}\). What is the original fraction?
#linear equations
#fraction
#substitution
#class 10
A \(\frac{5}{8}\)
B \(\frac{6}{9}\)
C \(\frac{7}{10}\)
D \(\frac{8}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{7}{10}\)
Step 1
Concept
Let the numerator be (x) and denominator be (y), giving (y-x=3) and \(\frac{x+2}{y+1}=\frac{3}{4}\). In exams, solve the simple linear equations after cross multiplication.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{7}{10}\). Let the numerator be (x) and denominator be (y), giving (y-x=3) and \(\frac{x+2}{y+1}=\frac{3}{4}\). In exams, solve the simple linear equations after cross multiplication.
Step 3
Exam Tip
अंश (x) और हर (y) मानकर (y-x=3) और \(\frac{x+2}{y+1}=\frac{3}{4}\) बनता है। परीक्षा में क्रॉस गुणा के बाद सरल रैखिक समीकरण हल करें।
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एक भिन्न में हर अंश से (5) अधिक है। यदि अंश और हर दोनों में (1) जोड़ने पर भिन्न \(\frac{2}{3}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the denominator is (5) more than the numerator. If (1) is added to both numerator and denominator, the fraction becomes \(\frac{2}{3}\). What is the original fraction?
#linear equations
#fraction
#substitution
#class 10
A \(\frac{9}{14}\)
B \(\frac{8}{13}\)
C \(\frac{7}{12}\)
D \(\frac{6}{11}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{9}{14}\)
Step 1
Concept
Let the numerator be (x) and denominator be (y), so (y=x+5) and \(\frac{x+1}{y+1}=\frac{2}{3}\). In exams, cross multiply when converting a fraction into an equation.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9}{14}\). Let the numerator be (x) and denominator be (y), so (y=x+5) and \(\frac{x+1}{y+1}=\frac{2}{3}\). In exams, cross multiply when converting a fraction into an equation.
Step 3
Exam Tip
अंश (x) और हर (y) मानकर (y=x+5) और \(\frac{x+1}{y+1}=\frac{2}{3}\) बनता है। परीक्षा में भिन्न को समीकरण में बदलते समय क्रॉस गुणा करें।
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समीकरण \(\frac{x}{2}+\frac{y}{4}=5\) और (x-y=4) को हल करें।
Solve \(\frac{x}{2}+\frac{y}{4}=5\) and (x-y=4).
#linear equations
#fraction
#elimination
#medium
#class 10
A ( (8,4) )
B ( (6,2) )
C ( (10,6) )
D ( (4,8) )
Explanation opens after your attempt
Correct Answer
A. ( (8,4) )
Step 1
Concept
Multiplying the first equation by (4) gives (2x+y=20). Solving it with (x-y=4) gives (x=8) and (y=4).
Step 2
Why this answer is correct
The correct answer is A. ( (8,4) ). Multiplying the first equation by (4) gives (2x+y=20). Solving it with (x-y=4) gives (x=8) and (y=4).
Step 3
Exam Tip
पहले समीकरण को (4) से गुणा करने पर (2x+y=20) मिलता है। इसे (x-y=4) के साथ हल करने पर (x=8) और (y=4)।
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समीकरण \(\frac{x}{3}+y=6\) और (x-y=6) का हल क्या है?
What is the solution of \(\frac{x}{3}+y=6\) and (x-y=6)?
#linear equations
#substitution
#fraction
#medium
#class 10
A ( (6,0) )
B ( (9,3) )
C ( (12,6) )
D ( (3,9) )
Explanation opens after your attempt
Correct Answer
B. ( (9,3) )
Step 1
Concept
Putting (x=y+6) gives \(\frac{y+6}{3}+y=6\), so (y=3) and (x=9). Matching denominators reduces mistakes in fractions.
Step 2
Why this answer is correct
The correct answer is B. ( (9,3) ). Putting (x=y+6) gives \(\frac{y+6}{3}+y=6\), so (y=3) and (x=9). Matching denominators reduces mistakes in fractions.
Step 3
Exam Tip
(x=y+6) रखने पर \(\frac{y+6}{3}+y=6\), इसलिए (y=3) और (x=9)। भिन्न में हर समान करने से गलती कम होती है।
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समीकरण \(\frac{x}{2}+y=7\) और (x-y=2) को हल करें।
Solve \(\frac{x}{2}+y=7\) and (x-y=2).
#linear equations
#substitution
#fraction
#medium
#class 10
A ( (6,4) )
B ( (4,6) )
C ( (8,3) )
D ( (5,5) )
Explanation opens after your attempt
Correct Answer
A. ( (6,4) )
Step 1
Concept
From (x-y=2), (x=y+2), so \(\frac{y+2}{2}+y=7\) and (y=4). In fraction questions, try to clear denominators first.
Step 2
Why this answer is correct
The correct answer is A. ( (6,4) ). From (x-y=2), (x=y+2), so \(\frac{y+2}{2}+y=7\) and (y=4). In fraction questions, try to clear denominators first.
Step 3
Exam Tip
(x-y=2) से (x=y+2), इसलिए \(\frac{y+2}{2}+y=7\) और (y=4)। भिन्न वाले प्रश्न में पहले हर हटाने की कोशिश करें।
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समीकरण (4x-y=9) और (2x+3y=23) का ग्राफीय हल कौन-सा है?
Which is the graphical solution of (4x-y=9) and (2x+3y=23)?
#substitution
#graphical solution
#fraction
A बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{37}{7}\right\))
B बिंदु (\left\(\frac{37}{7},\frac{25}{7}\right\)) / Point (\left\(\frac{37}{7},\frac{25}{7}\right\))
C बिंदु (\left\(5,3\right\)) / Point (\left\(5,3\right\))
D बिंदु (\left\(3,5\right\)) / Point (\left\(3,5\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{37}{7}\right\))
Step 1
Concept
Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{37}{7}\right\)). Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 3
Exam Tip
(4x-y=9) से (y=4x-9) रखकर \(x=\frac{25}{7}\) मिलता है। फिर \(y=\frac{37}{7}\) है।
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समीकरण (3x-2y=4) और (x+5y=23) का ग्राफीय हल कौन-सा है?
Which is the graphical solution of (3x-2y=4) and (x+5y=23)?
#substitution
#graphical solution
#fraction
A बिंदु (\left\(\frac{65}{17},\frac{65}{17}\right\)) / Point (\left\(\frac{65}{17},\frac{65}{17}\right\))
B बिंदु (\left\(\frac{67}{17},\frac{65}{17}\right\)) / Point (\left\(\frac{67}{17},\frac{65}{17}\right\))
C बिंदु (\left\(\frac{65}{17},\frac{67}{17}\right\)) / Point (\left\(\frac{65}{17},\frac{67}{17}\right\))
D बिंदु (\left\(4,3\right\)) / Point (\left\(4,3\right\))
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(\frac{65}{17},\frac{65}{17}\right\)) / Point (\left\(\frac{65}{17},\frac{65}{17}\right\))
Step 1
Concept
Using (x=23-5y) from (x+5y=23) gives \(y=\frac{65}{17}\). Then \(x=\frac{65}{17}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{65}{17},\frac{65}{17}\right\)) / Point (\left\(\frac{65}{17},\frac{65}{17}\right\)). Using (x=23-5y) from (x+5y=23) gives \(y=\frac{65}{17}\). Then \(x=\frac{65}{17}\).
Step 3
Exam Tip
(x+5y=23) से (x=23-5y) रखकर \(y=\frac{65}{17}\) मिलता है। फिर \(x=\frac{65}{17}\) है।
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यदि ग्राफ में प्रतिच्छेद बिंदु (\left\(4.5,1.5\right\)) पढ़ा गया है, तो इसे भिन्न में कैसे लिखेंगे?
If the intersection point is read as (\left\(4.5,1.5\right\)) on a graph, how will it be written in fractions?
#decimal coordinates
#fraction
#graph reading
A (\left\(\frac{9}{2},\frac{3}{2}\right\))
B (\left\(\frac{3}{2},\frac{9}{2}\right\))
C (\left\(\frac{45}{100},\frac{15}{100}\right\))
D (\left\(\frac{4}{5},\frac{1}{5}\right\))
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{9}{2},\frac{3}{2}\right\))
Step 1
Concept
\(4.5=\frac{9}{2}\) and \(1.5=\frac{3}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{9}{2},\frac{3}{2}\right\)). \(4.5=\frac{9}{2}\) and \(1.5=\frac{3}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 3
Exam Tip
\(4.5=\frac{9}{2}\) और \(1.5=\frac{3}{2}\)। ग्राफ से मिले दशमलव निर्देशांक को सरल भिन्न में लिखें।
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यदि ग्राफ में प्रतिच्छेद बिंदु ( \left\(3.5,2.5\right\) ) पढ़ा गया है, तो इसे भिन्न में कैसे लिखेंगे?
If the intersection point is read as ( \left\(3.5,2.5\right\) ) on a graph, how will it be written in fractions?
#decimal coordinates
#fraction
#graph reading
A ( \left\(\frac{7}{2},\frac{5}{2}\right\) )
B ( \left\(\frac{5}{2},\frac{7}{2}\right\) )
C ( \left\(\frac{35}{100},\frac{25}{100}\right\) )
D ( \left\(\frac{3}{5},\frac{2}{5}\right\) )
Explanation opens after your attempt
Correct Answer
A. ( \left\(\frac{7}{2},\frac{5}{2}\right\) )
Step 1
Concept
\(3.5=\frac{7}{2}\) and \(2.5=\frac{5}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. ( \left\(\frac{7}{2},\frac{5}{2}\right\) ). \(3.5=\frac{7}{2}\) and \(2.5=\frac{5}{2}\). Write decimal coordinates read from a graph as simplified fractions.
Step 3
Exam Tip
\(3.5=\frac{7}{2}\) और \(2.5=\frac{5}{2}\)। ग्राफ से मिले दशमलव निर्देशांक को सरल भिन्न में लिखें।
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यदि ग्राफ में प्रतिच्छेद बिंदु ( \left\(2.5,1.5\right\) ) पढ़ा गया है, तो हल को भिन्न में कैसे लिखेंगे?
If the intersection point is read as ( \left\(2.5,1.5\right\) ) on a graph, how will the solution be written in fractions?
#decimal coordinates
#fraction
#graph reading
A ( \left\(\frac{5}{2},\frac{3}{2}\right\) )
B ( \left\(\frac{3}{2},\frac{5}{2}\right\) )
C ( \left\(\frac{25}{10},\frac{15}{100}\right\) )
D ( \left\(\frac{2}{5},\frac{1}{5}\right\) )
Explanation opens after your attempt
Correct Answer
A. ( \left\(\frac{5}{2},\frac{3}{2}\right\) )
Step 1
Concept
\(2.5=\frac{5}{2}\) and \(1.5=\frac{3}{2}\). When reading decimals from a graph, write them as simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. ( \left\(\frac{5}{2},\frac{3}{2}\right\) ). \(2.5=\frac{5}{2}\) and \(1.5=\frac{3}{2}\). When reading decimals from a graph, write them as simplified fractions.
Step 3
Exam Tip
\(2.5=\frac{5}{2}\) और \(1.5=\frac{3}{2}\)। ग्राफ से दशमलव बिंदु पढ़ने पर सरल भिन्न में लिखें।
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यदि \(x=\frac{\sqrt{169}}{6}\), तो संख्या रेखा पर (x) किसके बराबर है?
If \(x=\frac{\sqrt{169}}{6}\), what is (x) equal to on the number line?
#number-line
#exact-root
#fraction
A \( \frac{13}{6} \)
B \( \frac{169}{6} \)
C \( \frac{6}{13} \)
D \( \frac{26}{6} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{13}{6} \)
Step 1
Concept
\( \sqrt{169}=13 \), so \(x=\frac{13}{6}\). Find the square root first and then divide.
Step 2
Why this answer is correct
The correct answer is A. \( \frac{13}{6} \). \( \sqrt{169}=13 \), so \(x=\frac{13}{6}\). Find the square root first and then divide.
Step 3
Exam Tip
\( \sqrt{169}=13 \), इसलिए \(x=\frac{13}{6}\) है। पहले वर्गमूल निकालें फिर भाग करें।
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यदि \(x=\frac{\sqrt{144}}{5}\), तो संख्या रेखा पर (x) किसके बराबर है?
If \(x=\frac{\sqrt{144}}{5}\), what is (x) equal to on the number line?
#number-line
#exact-root
#fraction
A \( \frac{12}{5} \)
B \( \frac{144}{5} \)
C \( \frac{5}{12} \)
D \( \frac{72}{5} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{12}{5} \)
Step 1
Concept
\( \sqrt{144}=12 \), so \(x=\frac{12}{5}\). Find the square root first and then divide.
Step 2
Why this answer is correct
The correct answer is A. \( \frac{12}{5} \). \( \sqrt{144}=12 \), so \(x=\frac{12}{5}\). Find the square root first and then divide.
Step 3
Exam Tip
\( \sqrt{144}=12 \), इसलिए \(x=\frac{12}{5}\) है। पहले वर्गमूल निकालें फिर भाग करें।
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संख्या रेखा पर \( \frac{2}{5} \) और \( \frac{3}{5} \) के ठीक बीच का बिंदु कौन सा है?
Which point is exactly midway between \( \frac{2}{5} \) and \( \frac{3}{5} \) on the number line?
#number-line
#midpoint
#fraction
A \( \frac{1}{2} \)
B \( \frac{5}{2} \)
C \( \frac{1}{5} \)
D \( \frac{4}{5} \)
Explanation opens after your attempt
Correct Answer
A. \( \frac{1}{2} \)
Step 1
Concept
The midpoint is \( \frac{\frac{2}{5}+\frac{3}{5}}{2}=\frac{1}{2} \). Use the average for the midpoint.
Step 2
Why this answer is correct
The correct answer is A. \( \frac{1}{2} \). The midpoint is \( \frac{\frac{2}{5}+\frac{3}{5}}{2}=\frac{1}{2} \). Use the average for the midpoint.
Step 3
Exam Tip
मध्य बिंदु \( \frac{\frac{2}{5}+\frac{3}{5}}{2}=\frac{1}{2} \) है। मध्य के लिए औसत लें।
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यदि (x) संख्या रेखा पर (1.25) है, तो (x) का भिन्न रूप कौन-सा है?
If (x) is (1.25) on the number line, which fractional form represents (x)?
#polynomials
#number-line
#terminating-decimal
#fraction
A \(\frac{5}{4}\)
B \(\frac{4}{5}\)
C \(\frac{1}{25}\)
D \(\frac{25}{4}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{5}{4}\)
Step 1
Concept
\(1.25=\frac{125}{100}=\frac{5}{4}\). Convert terminating decimals using denominator \(10^n\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{5}{4}\). \(1.25=\frac{125}{100}=\frac{5}{4}\). Convert terminating decimals using denominator \(10^n\).
Step 3
Exam Tip
\(1.25=\frac{125}{100}=\frac{5}{4}\)। सांत दशमलव को हर \(10^n\) से भिन्न में बदलें।
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यदि (P) संख्या रेखा पर (-1) से दाईं ओर \(\frac{7}{3}\) इकाई है, तो (P) का मान क्या होगा?
If (P) is \(\frac{7}{3}\) units to the right of (-1) on the number line, what is the value of (P)?
#polynomials
#number-line
#direction
#fraction
A \(\frac{4}{3}\)
B \(-\frac{4}{3}\)
C \(\frac{10}{3}\)
D -\( \frac{10}{3} \)
Explanation opens after your attempt
Correct Answer
A. \(\frac{4}{3}\)
Step 1
Concept
Moving right means addition, so \(-1+\frac{7}{3}=\frac{4}{3}\). Decide addition or subtraction by direction.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{4}{3}\). Moving right means addition, so \(-1+\frac{7}{3}=\frac{4}{3}\). Decide addition or subtraction by direction.
Step 3
Exam Tip
दाईं ओर जाने पर जोड़ते हैं, इसलिए \(-1+\frac{7}{3}=\frac{4}{3}\)। दिशा के अनुसार जोड़ या घटाव तय करें।
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संख्या रेखा पर \(\frac{-11}{5}\) किस दो क्रमागत पूर्णांकों के बीच आएगा?
On the number line, between which two consecutive integers will \(\frac{-11}{5}\) lie?
#polynomials
#number-line
#negative-rational
#fraction
A (-3) और (-2) / (-3) and (-2)
B (-2) और (-1) / (-2) and (-1)
C (2) और (3) / (2) and (3)
D (-1) और (0) / (-1) and (0)
Explanation opens after your attempt
Correct Answer
A. (-3) और (-2) / (-3) and (-2)
Step 1
Concept
Since \(\frac{-11}{5}=-2.2\), it lies between (-3) and (-2). Be careful with position of negative decimals.
Step 2
Why this answer is correct
The correct answer is A. (-3) और (-2) / (-3) and (-2). Since \(\frac{-11}{5}=-2.2\), it lies between (-3) and (-2). Be careful with position of negative decimals.
Step 3
Exam Tip
\(\frac{-11}{5}=-2.2\), इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक दशमलव में स्थान का ध्यान रखें।
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संख्या रेखा पर \(\sqrt{\frac{1}{2}}\) का सबसे अच्छा दशमलव अनुमान कौन सा है?
What is the best decimal estimate of \(\sqrt{\frac{1}{2}}\) on the number line?
#number-line
#square-root
#fraction
#estimation
A (0.5)
B (0.707)
C (1.2)
D (2)
Explanation opens after your attempt
Correct Answer
B. (0.707)
Step 1
Concept
\(\sqrt{\frac{1}{2}}\approx0.707\). In estimation, you can square the options to check.
Step 2
Why this answer is correct
The correct answer is B. (0.707). \(\sqrt{\frac{1}{2}}\approx0.707\). In estimation, you can square the options to check.
Step 3
Exam Tip
\(\sqrt{\frac{1}{2}}\approx0.707\) होता है। अनुमान में वर्ग करके विकल्प जांच सकते हैं।
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संख्या रेखा पर \(0.333\ldots\) किस भिन्न के बराबर है?
On the number line, \(0.333\ldots\) is equal to which fraction?
#number-line
#recurring-decimal
#fraction
#rational-numbers
A \(\frac{1}{2}\)
B \(\frac{1}{3}\)
C \(\frac{3}{10}\)
D \(\frac{2}{3}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{1}{3}\)
Step 1
Concept
\(0.333\ldots=\frac{1}{3}\), so both are at the same point. Connect recurring decimals with fractions.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{1}{3}\). \(0.333\ldots=\frac{1}{3}\), so both are at the same point. Connect recurring decimals with fractions.
Step 3
Exam Tip
\(0.333\ldots=\frac{1}{3}\), इसलिए दोनों एक ही बिंदु पर होंगे। आवर्ती दशमलव को भिन्न से जोड़कर याद रखें।
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यदि (0) और (1) के बीच का भाग (8) बराबर भागों में बांटा जाए तो \(\frac{5}{8}\) कौन सा बिंदु होगा?
If the part between (0) and (1) is divided into (8) equal parts, which point represents \(\frac{5}{8}\)?
#number-line
#fraction
#equal-parts
#rational-numbers
A (0) के बाद तीसरा बिंदु / Third point after (0)
B (0) के बाद चौथा बिंदु / Fourth point after (0)
C (0) के बाद पांचवां बिंदु / Fifth point after (0)
D (1) के बाद पांचवां बिंदु / Fifth point after (1)
Explanation opens after your attempt
Correct Answer
C. (0) के बाद पांचवां बिंदु / Fifth point after (0)
Step 1
Concept
\(\frac{5}{8}\) means (5) parts out of (8) equal parts. Treat the denominator as divisions and the numerator as count.
Step 2
Why this answer is correct
The correct answer is C. (0) के बाद पांचवां बिंदु / Fifth point after (0). \(\frac{5}{8}\) means (5) parts out of (8) equal parts. Treat the denominator as divisions and the numerator as count.
Step 3
Exam Tip
\(\frac{5}{8}\) का अर्थ (8) बराबर भागों में से (5) भाग है। हर को भागों की संख्या और अंश को गिनती मानें।
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संख्या रेखा पर (2.25) किस भिन्न के बराबर है?
Which fraction is equal to (2.25) on the number line?
#decimal
#fraction
#number-line
A \(\frac{9}{4}\)
B \(\frac{4}{9}\)
C \(\frac{5}{4}\)
D \(\frac{11}{4}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{9}{4}\)
Step 1
Concept
\(2.25=\frac{225}{100}=\frac{9}{4}\). Converting a decimal to simplest fraction gives the correct point.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9}{4}\). \(2.25=\frac{225}{100}=\frac{9}{4}\). Converting a decimal to simplest fraction gives the correct point.
Step 3
Exam Tip
\(2.25=\frac{225}{100}=\frac{9}{4}\)। दशमलव को सरल भिन्न में बदलना सही बिंदु देता है।
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संख्या रेखा पर (3.5) किस भिन्न के बराबर है?
Which fraction is equal to (3.5) on the number line?
#decimal
#fraction
#number-line
A \(\frac{7}{2}\)
B \(\frac{5}{3}\)
C \(\frac{3}{5}\)
D \(\frac{2}{7}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{2}\)
Step 1
Concept
\(3.5=\frac{35}{10}=\frac{7}{2}\). Convert the decimal to a simplest fraction to fix its position.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{2}\). \(3.5=\frac{35}{10}=\frac{7}{2}\). Convert the decimal to a simplest fraction to fix its position.
Step 3
Exam Tip
\(3.5=\frac{35}{10}=\frac{7}{2}\)। दशमलव को सरल भिन्न में बदलकर सही स्थान तय करें।
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संख्या रेखा पर \(\frac{5}{2}\) किस दो पूर्णांकों के बीच स्थित है?
Between which two integers does \(\frac{5}{2}\) lie on the number line?
#fraction
#decimal
#number-line
A (2) और (3) / (2) and (3)
B (1) और (2) / (1) and (2)
C (3) और (4) / (3) and (4)
D (0) और (1) / (0) and (1)
Explanation opens after your attempt
Correct Answer
A. (2) और (3) / (2) and (3)
Step 1
Concept
\( \frac{5}{2}=2.5\), so it lies between (2) and (3). Converting a fraction to decimal is an easy method.
Step 2
Why this answer is correct
The correct answer is A. (2) और (3) / (2) and (3). \( \frac{5}{2}=2.5\), so it lies between (2) and (3). Converting a fraction to decimal is an easy method.
Step 3
Exam Tip
\(\frac{5}{2}=2.5\), इसलिए यह (2) और (3) के बीच है। भिन्न को दशमलव रूप में बदलना आसान तरीका है।
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