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1253 questions tagged with linear_equations.
Which condition gives a unique solution for ((y+1)x+2y=3) and (5x+(y-2)y=4)?
B. \(y^2-y-12\neq0\)
सारणिक (D=(y+1)(y-2)-10=y-2-y-12) है। अद्वितीय हल के लिए \(D\neq0\) चाहिए। / The determinant is (D=(y+1)(y-2)-10=y-2-y-12). For a unique solution, \(D\neq0\) is required.
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What is the value of (t) for infinitely many solutions of (tx+9y=6) and (20x+15y=10)?
C. (t=12)
तीनों अनुपात \(\frac{3}{5}\) होने चाहिए। इसलिए \(\frac{t}{20}=\frac{3}{5}\) से (t=12)। / All three ratios must be \(\frac{3}{5}\). Therefore, \(\frac{t}{20}=\frac{3}{5}\) gives (t=12).
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What is (s) for no solution in (sx+4y=12) and (21x+12y=40)?
C. (s=7)
गुणांक अनुपात समान करने पर \(\frac{s}{21}=\frac{4}{12}\) से (s=7) है। स्थिर पद अनुपात समान नहीं है। / Equating coefficient ratios, \(\frac{s}{21}=\frac{4}{12}\) gives (s=7). The constant ratio is not equal.
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When will (rx+2y=5) and (9x+3y=8) have a unique solution?
B. \(r\neq6\)
अद्वितीय हल के लिए \(\frac{r}{9}\neq\frac{2}{3}\) चाहिए। इसलिए \(r\neq6\) होगा। / For a unique solution, \(\frac{r}{9}\neq\frac{2}{3}\) is required. Hence \(r\neq6\).
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What is the value of (q) for infinitely many solutions of (qx+11y=22) and (18x+33y=66)?
C. (q=6)
अनंत हलों में \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\) होता है। इसलिए (q=6) सही मान है। / For infinitely many solutions, \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\). Therefore, (q=6) is correct.
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What is (p) for no solution in (px-5y=7) and (12x-15y=19)?
A. (p=4)
गुणांक अनुपात समान करने पर \(\frac{p}{12}=\frac{-5}{-15}\) से (p=4) है। स्थिर अनुपात अलग है। / Equating coefficient ratios, \(\frac{p}{12}=\frac{-5}{-15}\) gives (p=4). The constant ratio is different.
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For infinitely many solutions of (3x+ny=18) and (5x+10y=30), what is (n)?
C. (n=6)
अनंत हलों के लिए \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) चाहिए। इससे (n=6) मिलता है। / For infinitely many solutions, \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) is needed. This gives (n=6).
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When will (mx+7y=13) and (16x+14y=26) have a unique solution?
B. \(m\neq8\)
अद्वितीय हल के लिए \(\frac{m}{16}\neq\frac{7}{14}\) होना चाहिए। इसलिए \(m\neq8\)। / For a unique solution, \(\frac{m}{16}\neq\frac{7}{14}\) must hold. Therefore, \(m\neq8\).
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What is the value of (k) for no solution in (2x+3y=4) and (kx+6y=11)?
C. (k=4)
गुणांक अनुपात समान करने पर \(\frac{2}{k}=\frac{3}{6}\) से (k=4) है। स्थिर पद अनुपात अलग है। / Equating coefficient ratios, \(\frac{2}{k}=\frac{3}{6}\) gives (k=4). The constant ratio is different.
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For infinitely many solutions of (jx+5y=10) and (14x+7y=14), what is (j)?
C. (j=10)
तीनों अनुपात \(\frac{5}{7}\) होने चाहिए। इसलिए \(\frac{j}{14}=\frac{5}{7}\) से (j=10)। / All three ratios must be \(\frac{5}{7}\). Therefore, \(\frac{j}{14}=\frac{5}{7}\) gives (j=10).
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What is the value of (i) for no solution in (6x+iy=12) and (18x+27y=50)?
D. (i=9)
गुणांक अनुपात समान करने पर \(\frac{6}{18}=\frac{i}{27}\) से (i=9) आता है। स्थिर पद अनुपात समान नहीं है। / Equating coefficient ratios, \(\frac{6}{18}=\frac{i}{27}\) gives (i=9). The constant ratio is not equal.
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When will (hx+12y=6) and (10x+15y=20) have a unique solution?
B. \(h\neq8\)
अद्वितीय हल के लिए \(\frac{h}{10}\neq\frac{12}{15}\) होना चाहिए। इसलिए \(h\neq8\) सही है। / For a unique solution, \(\frac{h}{10}\neq\frac{12}{15}\) must hold. Hence \(h\neq8\) is correct.
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For infinitely many solutions of ((g-1)x+10y=15) and (8x+20y=30), what is (g)?
B. (g=5)
अनंत हलों के लिए \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) होना चाहिए। इससे (g=5) मिलता है। / For infinitely many solutions, \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) must hold. This gives (g=5).
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What is (f) for no solution in (7x+fy=2) and (28x+20y=13)?
B. (f=5)
गुणांक अनुपात \(\frac{1}{4}\) बनाने के लिए (f=5) चाहिए। स्थिर पद अनुपात अलग होने से कोई हल नहीं होगा। / To make the coefficient ratio \(\frac{1}{4}\), (f=5) is required. The different constant ratio gives no solution.
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When will (ex-4y=9) and (18x-12y=27) have a unique solution?
B. \(e\neq6\)
अद्वितीय हल के लिए \(\frac{e}{18}\neq\frac{-4}{-12}\) चाहिए। अतः \(e\neq6\)। / For a unique solution, \(\frac{e}{18}\neq\frac{-4}{-12}\) is needed. Hence \(e\neq6\).
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What is the value of (d) for infinitely many solutions of (4x+dy=7) and (12x+15y=21)?
C. (d=5)
अनंत हलों में \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) होना चाहिए। इसलिए (d=5) सही है। / For infinitely many solutions, \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) must hold. So (d=5) is correct.
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What is (c) for no solution in (cx+6y=5) and (9x+18y=10)?
B. (c=3)
गुणांक अनुपात समान करने पर \(\frac{c}{9}=\frac{6}{18}\) से (c=3) आता है। स्थिर अनुपात \(\frac{5}{10}\) अलग है। / Equating coefficient ratios, \(\frac{c}{9}=\frac{6}{18}\) gives (c=3). The constant ratio \(\frac{5}{10}\) is different.
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What is the value of (b) for infinitely many solutions of (2x+by=6) and (bx+8y=24)?
C. (b=4)
अनंत हलों के लिए \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) होना चाहिए। इससे (b=4) मिलता है। / For infinitely many solutions, \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) must hold. This gives (b=4).
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What is the condition for a unique solution of (ax+2y=3) and (4x+ay=9)?
B. \(a^2\neq8\)
सारणिक \(D=a^2-8\) है। अद्वितीय हल के लिए \(D\neq0\) यानी \(a^2\neq8\)। / The determinant is \(D=a^2-8\). For a unique solution, \(D\neq0\), so \(a^2\neq8\).
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For ((z+2)x+3y=5) and (6x+(z-1)y=7) to be non-unique, what are the possible values of (z)?
A. (z=4,-3)
अद्वितीय न होने के लिए ((z+2)(z-1)-18=0) होना चाहिए। इससे (z=4) या (z=-3) मिलता है। / For non-unique solutions, ((z+2)(z-1)-18=0) must hold. This gives (z=4) or (z=-3).
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If (D=0), \(D_x=0\), and \(D_y=0\), what happens in a pair of two linear equations?
C. अनंत हलInfinitely many solutions
तीनों सारणिक शून्य होने पर समीकरण आश्रित हो सकते हैं। कक्षा (10) में इसे अनंत हल की स्थिति से जोड़कर देखें। / When all three determinants are zero, the equations may be dependent. In Class (10), link this with infinitely many solutions.
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If \(a_1b_2-a_2b_1\neq0\), what is the correct statement about the pair?
C. युग्म का अद्वितीय हल हैThe pair has a unique solution
सारणिक शून्य नहीं होने पर रेखाएँ एक बिंदु पर कटती हैं। इसलिए अद्वितीय हल होता है। / When the determinant is non-zero, the lines intersect at one point. Hence there is a unique solution.
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If two lines are distinct and parallel, what is the correct ratio condition?
B. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\)
अलग समांतर रेखाओं में गुणांक अनुपात समान और स्थिर पद अनुपात अलग होता है। यही कोई हल नहीं की शर्त है। / For distinct parallel lines, coefficient ratios are equal and the constant ratio is different. This is the condition for no solution.
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C. अनंत हलInfinitely many solutions
समान ढाल और समान अवरोध का अर्थ एक ही रेखा है। इसलिए ऐसे युग्म में अनंत हल होते हैं। / Same slope and same intercept mean the same line. Therefore, such a pair has infinitely many solutions.
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If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), what is the solution status of the pair?
C. अनंत हलInfinitely many solutions
तीनों अनुपात समान होने पर रेखाएँ संपाती होती हैं। इसलिए अनंत हल मिलते हैं। / When all three ratios are equal, the lines are coincident. Therefore, infinitely many solutions occur.
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B. \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\)
अद्वितीय हल तब मिलता है जब रेखाएँ एक बिंदु पर कटती हैं। इसका अनुपात रूप \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\) है। / A unique solution occurs when the lines intersect at one point. Its ratio form is \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\).
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What is the value of \(\gamma\) for no solution in \(5x+\gamma y=1\) and (25x+15y=11)?
B. \(\gamma=3\)
गुणांक अनुपात समान करने पर \(\frac{5}{25}=\frac{\gamma}{15}\) से \(\gamma=3\) मिलता है। स्थिर अनुपात अलग है। / Equating coefficient ratios, \(\frac{5}{25}=\frac{\gamma}{15}\) gives \(\gamma=3\). The constant ratio is different.
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For infinitely many solutions of (9x+\(\beta+4\)y=15) and (27x+18y=45), what is \(\beta\)?
B. \(\beta=2\)
अनंत हलों में \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) होना चाहिए। इससे \(\beta=2\) मिलता है। / For infinitely many solutions, \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) must hold. This gives \(\beta=2\).
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When will (\(\alpha-1\)x+5y=2) and (8x+10y=6) have a unique solution?
B. \(\alpha\neq5\)
अद्वितीय हल के लिए \(\frac{\alpha-1}{8}\neq\frac{5}{10}\) चाहिए। इसलिए \(\alpha\neq5\) सही है। / For a unique solution, \(\frac{\alpha-1}{8}\neq\frac{5}{10}\) is required. Hence \(\alpha\neq5\) is correct.
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What is \(\mu\) for no solution in \(14x+\mu y=9\) and (21x+6y=20)?
B. \(\mu=4\)
\(\frac{14}{21}=\frac{2}{3}\) है। गुणांक अनुपात समान करने पर \(\frac{\mu}{6}=\frac{2}{3}\) से \(\mu=4\)। / \(\frac{14}{21}=\frac{2}{3}\). Equating coefficient ratios, \(\frac{\mu}{6}=\frac{2}{3}\) gives \(\mu=4\).
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