Class 10 product MCQ Questions

Question 1/74 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (5x+3y=28) और (2x-y=1), तो (xy) का मान क्या है?

If (5x+3y=28) and (2x-y=1), what is the value of (xy)?

Explanation opens after your attempt

Correct Answer

C. (15)

Step 1

Concept

From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).

Step 2

Why this answer is correct

The correct answer is C. (15). From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).

Step 3

Exam Tip

दूसरे समीकरण से (y=2x-1)। रखने पर (11x=31) नहीं, सही रूप (5x+6x-3=28) से \(x=\frac{31}{11}\) आता है, इसलिए विकल्प जांचकर हल करें।

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Question 2/74 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (7x+2y=53) और (9x-4y=27), तो (xy) का मान क्या होगा?

If (7x+2y=53) and (9x-4y=27), what will be the value of (xy)?

Explanation opens after your attempt

Correct Answer

B. (28)

Step 1

Concept

Elimination gives (x=7), (y=2), so (xy=14). In exams, verify the solution before matching options.

Step 2

Why this answer is correct

The correct answer is B. (28). Elimination gives (x=7), (y=2), so (xy=14). In exams, verify the solution before matching options.

Step 3

Exam Tip

उन्मूलन से (x=7) और (y=2) नहीं, बल्कि (x=5), (y=9) नहीं मिलता; सही हल (x=7), (y=2) है और (xy=14) है। परीक्षा में विकल्पों से पहले हल की जाँच करें।

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Question 3/74 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (5x+3y=44) और (2x-y=3), तो (xy) का मान ज्ञात कीजिए।

If (5x+3y=44) and (2x-y=3), find the value of (xy).

Explanation opens after your attempt

Correct Answer

B. (35)

Step 1

Concept

From the second equation, put (y=2x-3), giving (x=5) and (y=7). In exams, recheck both values before finding (xy).

Step 2

Why this answer is correct

The correct answer is B. (35). From the second equation, put (y=2x-3), giving (x=5) and (y=7). In exams, recheck both values before finding (xy).

Step 3

Exam Tip

दूसरे समीकरण से (y=2x-3) रखकर (x=5) और (y=7) मिलता है। परीक्षा में (xy) निकालते समय दोनों मान फिर से जाँचें।

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Question 4/74 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x^-2+bx+16) के शून्यक परस्पर व्युत्क्रम हैं, तो (b) के बारे में क्या कहा जा सकता है?

If the zeroes of (p(x)=x^-2+bx+16) are reciprocals of each other, what can be said about (b)?

Explanation opens after your attempt

Correct Answer

A. ऐसा संभव नहीं हैIt is not possible

Step 1

Concept

Reciprocal zeroes must have product (1). Here the product is (16), so it is not possible.

Step 2

Why this answer is correct

The correct answer is A. ऐसा संभव नहीं है / It is not possible. Reciprocal zeroes must have product (1). Here the product is (16), so it is not possible.

Step 3

Exam Tip

परस्पर व्युत्क्रम शून्यकों का गुणनफल (1) होना चाहिए। यहाँ गुणनफल (16) है, इसलिए यह संभव नहीं है।

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Question 5/74 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 47

(p(x)=x^-3-3x^-2-4x+12) में (p(2)) और (p(-2)) का गुणनफल क्या है?

What is the product of (p(2)) and (p(-2)) for (p(x)=x^-3-3x^-2-4x+12)?

Explanation opens after your attempt

Correct Answer

B. (0)

Step 1

Concept

(p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).

Step 2

Why this answer is correct

The correct answer is B. (0). (p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).

Step 3

Exam Tip

(p(2)=8-12-8+12=0), इसलिए गुणनफल (0) होगा। एक मान (0) हो तो पूरा गुणनफल (0) होता है।

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Question 6/74 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 47

यदि अशून्य बहुपद (p(x)) की घात (6) और (q(x)) की घात (3) है, तो (p(x)q(x)) की घात क्या होगी?

If non-zero polynomial (p(x)) has degree (6) and (q(x)) has degree (3), what will be the degree of (p(x)q(x))?

Explanation opens after your attempt

Correct Answer

C. (9)

Step 1

Concept

In the product of two non-zero polynomials, degrees add, so (6+3=9). In multiplication, look at the highest-power terms.

Step 2

Why this answer is correct

The correct answer is C. (9). In the product of two non-zero polynomials, degrees add, so (6+3=9). In multiplication, look at the highest-power terms.

Step 3

Exam Tip

दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (6+3=9)। गुणन में उच्चतम घातों का गुणन देखें।

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Question 7/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 48

(p(x)=x^-3-2x^-2-3x+4) में (p(1)) और (p(-1)) का गुणनफल क्या है?

What is the product of (p(1)) and (p(-1)) for (p(x)=x^-3-2x^-2-3x+4)?

Explanation opens after your attempt

Correct Answer

B. (0)

Step 1

Concept

(p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.

Step 2

Why this answer is correct

The correct answer is B. (0). (p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.

Step 3

Exam Tip

(p(1)=1-2-3+4=0) और (p(-1)=-1-2+3+4=4), इसलिए गुणनफल (0) है। पहले दोनों मान निकालें।

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Question 8/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)) की घात (5) और (q(x)) की घात (2) है, तो अशून्य (p(x)q(x)) की घात क्या होगी?

If the degree of (p(x)) is (5) and the degree of (q(x)) is (2), what is the degree of non-zero (p(x)q(x))?

Explanation opens after your attempt

Correct Answer

C. (7)

Step 1

Concept

In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.

Step 2

Why this answer is correct

The correct answer is C. (7). In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.

Step 3

Exam Tip

दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (5+2=7)। गुणन में घातों का योग याद रखें।

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Question 9/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि \(x^2-10x+q\) के शून्यक (2r) और (3r) हैं, तो (q) का मान क्या है?

If the zeroes of \(x^2-10x+q\) are (2r) and (3r), what is (q)?

Explanation opens after your attempt

Correct Answer

A. (24)

Step 1

Concept

From the sum (5r=10), (r=2). The product is \(2r\cdot3r=6r^2=24\).

Step 2

Why this answer is correct

The correct answer is A. (24). From the sum (5r=10), (r=2). The product is \(2r\cdot3r=6r^2=24\).

Step 3

Exam Tip

योग (5r=10) से (r=2) है। गुणनफल \(2r\cdot3r=6r^2=24\) है।

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Question 10/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

द्विघात बहुपद \(2x^2-7x+3\) के शून्यकों का गुणनफल क्या है?

What is the product of the zeroes of the quadratic polynomial \(2x^2-7x+3\)?

Explanation opens after your attempt

Correct Answer

B. \(\frac{3}{2}\)

Step 1

Concept

For \(ax^2+bx+c\), the product is \(\frac{c}{a}\). Here, \(\frac{3}{2}\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{3}{2}\). For \(ax^2+bx+c\), the product is \(\frac{c}{a}\). Here, \(\frac{3}{2}\) is correct.

Step 3

Exam Tip

द्विघात \(ax^2+bx+c\) में गुणनफल \(\frac{c}{a}\) होता है। यहां \(\frac{3}{2}\) सही है।

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Question 11/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 47

(p(x)=2x^-3+x^-2-5x+2) में (p(1)) और (p(-1)) का गुणनफल क्या है?

What is the product of (p(1)) and (p(-1)) for (p(x)=2x^-3+x^-2-5x+2)?

Explanation opens after your attempt

Correct Answer

A. (-12)

Step 1

Concept

(p(1)=2+1-5+2=0), and (p(-1)=-2+1+5+2=6), so the product is (0). The correct option is (0).

Step 2

Why this answer is correct

The correct answer is A. (-12). (p(1)=2+1-5+2=0), and (p(-1)=-2+1+5+2=6), so the product is (0). The correct option is (0).

Step 3

Exam Tip

(p(1)=0) नहीं बल्कि (2+1-5+2=0), और (p(-1)=-2+1+5+2=6), इसलिए गुणनफल (0) है। सही विकल्प (0) है।

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Question 12/74 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 47

यदि (p(x)) की घात (4) और (q(x)) की घात (3) है, तो सामान्यतः (p(x)q(x)) की घात क्या होगी?

If the degree of (p(x)) is (4) and the degree of (q(x)) is (3), what will generally be the degree of (p(x)q(x))?

Explanation opens after your attempt

Correct Answer

B. (7)

Step 1

Concept

In the product of two non-zero polynomials, degrees add, so (4+3=7). Remember degree addition in multiplication.

Step 2

Why this answer is correct

The correct answer is B. (7). In the product of two non-zero polynomials, degrees add, so (4+3=7). Remember degree addition in multiplication.

Step 3

Exam Tip

दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (4+3=7)। गुणन में घातों का योग याद रखें।

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Question 13/74 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(72\cdot68\) का मान पहचान से क्या है?

Using an identity, what is the value of \(72\cdot68\)?

Explanation opens after your attempt

Correct Answer

A. (4896)

Step 1

Concept

(72\cdot68=(70+2)(70-2)=70²-2²=4896). This uses the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. (4896). (72\cdot68=(70+2)(70-2)=70²-2²=4896). This uses the difference of squares identity.

Step 3

Exam Tip

(72\cdot68=(70+2)(70-2)=70²-2²=4896)। यह अंतर के वर्ग का उपयोग है।

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Question 14/74 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 44

\(64\cdot56\) का मान पहचान से क्या है?

Using an identity, what is the value of \(64\cdot56\)?

Explanation opens after your attempt

Correct Answer

A. (3584)

Step 1

Concept

(64\cdot56=(60+4)(60-4)=60²-4²=3584). This uses the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. (3584). (64\cdot56=(60+4)(60-4)=60²-4²=3584). This uses the difference of squares identity.

Step 3

Exam Tip

(64\cdot56=(60+4)(60-4)=60²-4²=3584)। यह अंतर के वर्ग का उपयोग है।

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Question 15/74 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 43

\(53\cdot47\) का मान पहचान से क्या है?

Using an identity, what is the value of \(53\cdot47\)?

Explanation opens after your attempt

Correct Answer

A. (2491)

Step 1

Concept

(53\cdot47=(50+3)(50-3)=50²-3²=2491). This uses the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. (2491). (53\cdot47=(50+3)(50-3)=50²-3²=2491). This uses the difference of squares identity.

Step 3

Exam Tip

(53\cdot47=(50+3)(50-3)=50²-3²=2491)। यह अंतर के वर्ग का उपयोग है।

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Question 16/74 Easy Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(6^2\cdot2^2\) का संक्षिप्त रूप क्या है?

What is the compact form of \(6^2\cdot2^2\)?

Explanation opens after your attempt

Correct Answer

B. \(12^2\)

Step 1

Concept

When exponents are equal, bases can be multiplied. Hence (6²\cdot2²=\(6\cdot2\)²=12²).

Step 2

Why this answer is correct

The correct answer is B. \(12^2\). When exponents are equal, bases can be multiplied. Hence (6²\cdot2²=\(6\cdot2\)²=12²).

Step 3

Exam Tip

समान घात होने पर आधारों का गुणा किया जा सकता है। इसलिए (6²\cdot2²=\(6\cdot2\)²=12²) है।

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Question 17/74 Easy Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 44

\(4^2\cdot5^2\) का संक्षिप्त रूप क्या है?

What is the compact form of \(4^2\cdot5^2\)?

Explanation opens after your attempt

Correct Answer

B. \(20^2\)

Step 1

Concept

When exponents are equal, bases can be multiplied. Hence (4²\cdot5²=\(4\cdot5\)²=20²).

Step 2

Why this answer is correct

The correct answer is B. \(20^2\). When exponents are equal, bases can be multiplied. Hence (4²\cdot5²=\(4\cdot5\)²=20²).

Step 3

Exam Tip

समान घात होने पर आधारों को गुणा कर सकते हैं। इसलिए (4²\cdot5²=\(4\cdot5\)²=20²) है।

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Question 18/74 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

किस धनात्मक संख्या में (7) जोड़ने पर प्राप्त संख्या और मूल संख्या का गुणनफल (330) होता है?

For which positive number does the product of the number and the number increased by (7) equal (330)?

Explanation opens after your attempt

Correct Answer

B. (15)

Step 1

Concept

Let the number be (x). Then (x(x+7)=330), and \(x^2+7x-330=0\) gives the positive root (x=15).

Step 2

Why this answer is correct

The correct answer is B. (15). Let the number be (x). Then (x(x+7)=330), and \(x^2+7x-330=0\) gives the positive root (x=15).

Step 3

Exam Tip

संख्या (x) हो तो (x(x+7)=330)। \(x^2+7x-330=0\) से धनात्मक हल (x=15) है।

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Question 19/74 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो क्रमागत विषम धनात्मक पूर्णांकों का गुणनफल (483) है। बड़ी संख्या क्या है?

The product of two consecutive positive odd integers is (483). What is the larger integer?

Explanation opens after your attempt

Correct Answer

B. (23)

Step 1

Concept

The integers are (x) and (x+2). From (x(x+2)=483), (x=21), so the larger integer is (23).

Step 2

Why this answer is correct

The correct answer is B. (23). The integers are (x) and (x+2). From (x(x+2)=483), (x=21), so the larger integer is (23).

Step 3

Exam Tip

संख्याएँ (x) और (x+2) हैं। (x(x+2)=483) से (x=21) मिलता है इसलिए बड़ी संख्या (23) है।

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Question 20/74 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो क्रमागत सम धनात्मक पूर्णांकों का गुणनफल (360) है। छोटी संख्या क्या है?

The product of two consecutive positive even integers is (360). What is the smaller integer?

Explanation opens after your attempt

Correct Answer

B. (18)

Step 1

Concept

Let the integers be (x) and (x+2). From (x(x+2)=360), \(x^2+2x-360=0\), so (x=18).

Step 2

Why this answer is correct

The correct answer is B. (18). Let the integers be (x) and (x+2). From (x(x+2)=360), \(x^2+2x-360=0\), so (x=18).

Step 3

Exam Tip

संख्याएँ (x) और (x+2) मानें। (x(x+2)=360) से \(x^2+2x-360=0\) और (x=18) मिलता है।

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Question 21/74 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक संख्या और उससे (4) अधिक संख्या का गुणनफल (221) है। छोटी संख्या क्या है?

The product of a number and the number (4) more than it is (221). What is the smaller number?

Explanation opens after your attempt

Correct Answer

C. (13)

Step 1

Concept

The equation is (x(x+4)=221). The positive solution is (x=13).

Step 2

Why this answer is correct

The correct answer is C. (13). The equation is (x(x+4)=221). The positive solution is (x=13).

Step 3

Exam Tip

समीकरण (x(x+4)=221) है। धनात्मक हल (x=13) है।

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Question 22/74 Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

दो धनात्मक संख्याओं में अंतर (6) है और उनका गुणनफल (216) है। छोटी संख्या क्या है?

Two positive numbers differ by (6) and their product is (216). What is the smaller number?

Explanation opens after your attempt

Correct Answer

C. (12)

Step 1

Concept

If the smaller number is (x), then (x(x+6)=216). The positive solution is (x=12).

Step 2

Why this answer is correct

The correct answer is C. (12). If the smaller number is (x), then (x(x+6)=216). The positive solution is (x=12).

Step 3

Exam Tip

छोटी संख्या (x) हो तो (x(x+6)=216)। धनात्मक हल (x=12) है।

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Question 23/74 Easy Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक संख्या को उसके (6) कम मान से गुणा करने पर (112) मिलता है। बड़ी संख्या क्या है?

A number multiplied by (6) less than itself gives (112). What is the larger number?

Explanation opens after your attempt

Correct Answer

B. (14)

Step 1

Concept

If the larger number is (x), then (x(x-6)=112), giving (x=14). Use (x-6) for less than the number.

Step 2

Why this answer is correct

The correct answer is B. (14). If the larger number is (x), then (x(x-6)=112), giving (x=14). Use (x-6) for less than the number.

Step 3

Exam Tip

बड़ी संख्या (x) हो तो (x(x-6)=112), जिससे (x=14) है। कम मान लिखते समय (x-6) का प्रयोग करें।

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Question 24/74 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि \(x^2-16x+q=0\) की जड़ें (5:3) के अनुपात में हैं, तो (q) का मान क्या होगा?

If the roots of \(x^2-16x+q=0\) are in the ratio (5:3), what is the value of (q)?

Explanation opens after your attempt

Correct Answer

C. (60)

Step 1

Concept

Let the roots be (5r) and (3r). From (8r=16), (r=2), so the product is \(15r^2=60\).

Step 2

Why this answer is correct

The correct answer is C. (60). Let the roots be (5r) and (3r). From (8r=16), (r=2), so the product is \(15r^2=60\).

Step 3

Exam Tip

जड़ें (5r) और (3r) मानें। (8r=16) से (r=2), इसलिए गुणनफल \(15r^2=60\) है।

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Question 25/74 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(x^2-14x+q=0\) की जड़ें (3:4) के अनुपात में हैं, तो (q) का मान क्या होगा?

If the roots of \(x^2-14x+q=0\) are in the ratio (3:4), what is the value of (q)?

Explanation opens after your attempt

Correct Answer

C. (48)

Step 1

Concept

Let the roots be (3r) and (4r). From (7r=14), (r=2), so the product is \(12r^2=48\).

Step 2

Why this answer is correct

The correct answer is C. (48). Let the roots be (3r) and (4r). From (7r=14), (r=2), so the product is \(12r^2=48\).

Step 3

Exam Tip

जड़ें (3r) और (4r) मानें। (7r=14) से (r=2), इसलिए गुणनफल \(12r^2=48\) है।

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Question 26/74 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2-12x+q=0\) की जड़ें (2:3) के अनुपात में हैं, तो (q) का मान क्या होगा?

If the roots of \(x^2-12x+q=0\) are in the ratio (2:3), what is the value of (q)?

Explanation opens after your attempt

Correct Answer

A. \(\frac{864}{25}\)

Step 1

Concept

Let the roots be (2r) and (3r). From (5r=12), \(r=\frac{12}{5}\), so the product is \(6r^2=\frac{864}{25}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{864}{25}\). Let the roots be (2r) and (3r). From (5r=12), \(r=\frac{12}{5}\), so the product is \(6r^2=\frac{864}{25}\).

Step 3

Exam Tip

जड़ें (2r) और (3r) मानें। (5r=12) से \(r=\frac{12}{5}\), इसलिए गुणनफल \(6r^2=\frac{864}{25}\) है।

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Question 27/74 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2-2x+k=0\) की जड़ें \(\tan \theta\) और \(\cot \theta\) हैं, तो (k) का मान क्या है?

If the roots of \(x^2-2x+k=0\) are \(\tan \theta\) and \(\cot \theta\), what is the value of (k)?

Explanation opens after your attempt

Correct Answer

A. (1)

Step 1

Concept

We know \(\tan \theta\cdot\cot \theta=1\). The product of roots is (k), so (k=1).

Step 2

Why this answer is correct

The correct answer is A. (1). We know \(\tan \theta\cdot\cot \theta=1\). The product of roots is (k), so (k=1).

Step 3

Exam Tip

\(\tan \theta\cdot\cot \theta=1\) होता है। जड़ों का गुणनफल (k) है, इसलिए (k=1)।

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Question 28/74 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(x^2-10x+24=0\) के मूल \(\alpha\) और \(\beta\) हैं तो (\(\alpha-2\)) और (\(\beta-2\)) का गुणनफल क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-10x+24=0\), what is the product of (\(\alpha-2\)) and (\(\beta-2\))?

Explanation opens after your attempt

Correct Answer

A. (8)

Step 1

Concept

Here \(\alpha+\beta=10\) and \(\alpha\beta=24\). (\(\alpha-2\)\(\beta-2\)=24-20+4=8).

Step 2

Why this answer is correct

The correct answer is A. (8). Here \(\alpha+\beta=10\) and \(\alpha\beta=24\). (\(\alpha-2\)\(\beta-2\)=24-20+4=8).

Step 3

Exam Tip

यहां \(\alpha+\beta=10\) और \(\alpha\beta=24\) है। (\(\alpha-2\)\(\beta-2\)=24-20+4=8) है।

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Question 29/74 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि मूलों का योग (6) और उनके वर्गों का योग (52) है तो मूलों का गुणनफल क्या होगा?

If the sum of roots is (6) and the sum of their squares is (52), what is the product of roots?

Explanation opens after your attempt

Correct Answer

A. (-8)

Step 1

Concept

(\alpha^-2+\beta^-2=\(\alpha+\beta\)²-2\alpha\beta). From \(52=36-2\alpha\beta\), we get \(\alpha\beta=-8\).

Step 2

Why this answer is correct

The correct answer is A. (-8). (\alpha^-2+\beta^-2=\(\alpha+\beta\)²-2\alpha\beta). From \(52=36-2\alpha\beta\), we get \(\alpha\beta=-8\).

Step 3

Exam Tip

(\alpha^-2+\beta^-2=\(\alpha+\beta\)²-2\alpha\beta) है। \(52=36-2\alpha\beta\) से \(\alpha\beta=-8\) मिलता है।

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Question 30/74 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2-6x-16=0\) के मूलों को (2) घटाने पर नए मूलों का गुणनफल क्या होगा?

If each root of \(x^2-6x-16=0\) is decreased by (2), what is the product of the new roots?

Explanation opens after your attempt

Correct Answer

A. (-24)

Step 1

Concept

The old roots are (8) and (-2). The new roots are (6) and (-4), so the product is (-24).

Step 2

Why this answer is correct

The correct answer is A. (-24). The old roots are (8) and (-2). The new roots are (6) and (-4), so the product is (-24).

Step 3

Exam Tip

पुराने मूल (8) और (-2) हैं। नए मूल (6) और (-4) होंगे इसलिए गुणनफल (-24) है।

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product MCQ Questions for Class 10

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यदि (5x+3y=28) और (2x-y=1), तो (xy) का मान क्या है?

Concept

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यदि (5x+3y=44) और (2x-y=3), तो (xy) का मान ज्ञात कीजिए।

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यदि (p(x)=x-2+bx+16) के शून्यक परस्पर व्युत्क्रम हैं, तो (b) के बारे में क्या कहा जा सकता है?

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(p(x)=x-3-3x-2-4x+12) में (p(2)) और (p(-2)) का गुणनफल क्या है?

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यदि अशून्य बहुपद (p(x)) की घात (6) और (q(x)) की घात (3) है, तो (p(x)q(x)) की घात क्या होगी?

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(p(x)=x-3-2x-2-3x+4) में (p(1)) और (p(-1)) का गुणनफल क्या है?

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यदि (p(x)) की घात (5) और (q(x)) की घात (2) है, तो अशून्य (p(x)q(x)) की घात क्या होगी?

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यदि \(x^2-10x+q\) के शून्यक (2r) और (3r) हैं, तो (q) का मान क्या है?

Concept

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द्विघात बहुपद \(2x^2-7x+3\) के शून्यकों का गुणनफल क्या है?

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(p(x)=2x-3+x-2-5x+2) में (p(1)) और (p(-1)) का गुणनफल क्या है?

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यदि (p(x)) की घात (4) और (q(x)) की घात (3) है, तो सामान्यतः (p(x)q(x)) की घात क्या होगी?

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\(53\cdot47\) का मान पहचान से क्या है?

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किस धनात्मक संख्या में (7) जोड़ने पर प्राप्त संख्या और मूल संख्या का गुणनफल (330) होता है?

Concept

Why this answer is correct

Exam Tip

दो क्रमागत विषम धनात्मक पूर्णांकों का गुणनफल (483) है। बड़ी संख्या क्या है?

Concept

Why this answer is correct

Exam Tip

दो क्रमागत सम धनात्मक पूर्णांकों का गुणनफल (360) है। छोटी संख्या क्या है?

Concept

यदि (p(x)=x^-2+bx+16) के शून्यक परस्पर व्युत्क्रम हैं, तो (b) के बारे में क्या कहा जा सकता है?

(p(x)=x^-3-3x^-2-4x+12) में (p(2)) और (p(-2)) का गुणनफल क्या है?

(p(x)=x^-3-2x^-2-3x+4) में (p(1)) और (p(-1)) का गुणनफल क्या है?

(p(x)=2x^-3+x^-2-5x+2) में (p(1)) और (p(-1)) का गुणनफल क्या है?