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fraction-value MCQ Questions for Class 10

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21 questions tagged with fraction-value.

Question 1/21 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (x=5y-8) और (4x+3y=61), तो (y) का मान क्या है?

If (x=5y-8) and (4x+3y=61), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{93}{23}\)

Step 1

Concept

Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{93}{23}\). Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).

Step 3

Exam Tip

(x=5y-8) को दूसरे समीकरण में रखें। (20y-32+3y=61), इसलिए \(y=\frac{93}{23}\)।

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Question 2/21 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (6x+9y=117) और (8x-3y=37) से (y) का मान क्या है?

What is the value of (y) from (6x+9y=117) and (8x-3y=37)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{119}{15}\)

Step 1

Concept

Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{119}{15}\). Multiply the second equation by (3) and add it to the first. Solving gives \(y=\frac{119}{15}\).

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा कर पहले में जोड़ें। हल करने पर \(y=\frac{119}{15}\) मिलता है।

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Question 3/21 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (11x+4y=91) और (5x-4y=21) से (y) का मान क्या है?

What is the value of (y) from (11x+4y=91) and (5x-4y=21)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{7}{2}\)

Step 1

Concept

Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{7}{2}\). Adding both equations gives (16x=112), so (x=7). The first equation gives \(y=\frac{7}{2}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (16x=112), इसलिए (x=7)। पहले समीकरण से \(y=\frac{7}{2}\)।

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Question 4/21 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (7x+4y=58) और (3x-4y=22) को हल करने पर (y) का मान क्या है?

On solving (7x+4y=58) and (3x-4y=22), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

A. \(y=\frac{1}{2}\)

Step 1

Concept

Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(y=\frac{1}{2}\). Adding both equations gives (10x=80), so (x=8). The first equation gives \(y=\frac{1}{2}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (10x=80), इसलिए (x=8)। पहले समीकरण से \(y=\frac{1}{2}\)।

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Question 5/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (x=4y-7) और (3x+2y=59), तो (y) का मान क्या है?

If (x=4y-7) and (3x+2y=59), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{80}{14}\)

Step 1

Concept

Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{80}{14}\). Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).

Step 3

Exam Tip

(x=4y-7) को दूसरे समीकरण में रखिए। (12y-21+2y=59), इसलिए \(y=\frac{40}{7}\)।

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Question 6/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (5x+8y=86) और (7x-4y=38) से (y) का मान क्या है?

What is the value of (y) from (5x+8y=86) and (7x-4y=38)?

Explanation opens after your attempt
Correct Answer

D. \(y=\frac{102}{17}\)

Step 1

Concept

Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{162}{19}\) and \(y=\frac{103}{19}\), so none of the given options is correct.

Step 2

Why this answer is correct

The correct answer is D. \(y=\frac{102}{17}\). Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{162}{19}\) and \(y=\frac{103}{19}\), so none of the given options is correct.

Step 3

Exam Tip

दूसरे समीकरण को (2) से गुणा कर पहले में जोड़ें। \(x=\frac{162}{19}\) और \(y=\frac{103}{19}\) मिलता है, इसलिए दिए विकल्पों में कोई सही नहीं है।

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Question 7/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (9x-4y=52) और (3x+4y=20) को हल करने पर (y) कितना होगा?

On solving (9x-4y=52) and (3x+4y=20), what is (y)?

Explanation opens after your attempt
Correct Answer

A. \(y=-\frac{1}{2}\)

Step 1

Concept

Adding both equations gives (12x=72), so (x=6). The second equation gives (18+4y=20), so \(y=\frac{1}{2}\), hence the correct listed value is (C).

Step 2

Why this answer is correct

The correct answer is A. \(y=-\frac{1}{2}\). Adding both equations gives (12x=72), so (x=6). The second equation gives (18+4y=20), so \(y=\frac{1}{2}\), hence the correct listed value is (C).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (12x=72), इसलिए (x=6)। दूसरे समीकरण से (18+4y=20), इसलिए \(y=\frac{1}{2}\), इसलिए विकल्पों में सही मान (C) होता।

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Question 8/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (9x+5y=97) और (4x-5y=-12) से (y) का मान क्या है?

What is the value of (y) from (9x+5y=97) and (4x-5y=-12)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{93}{13}\)

Step 1

Concept

Adding both equations gives (13x=85). Substituting \(x=\frac{85}{13}\) gives \(y=\frac{93}{13}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{93}{13}\). Adding both equations gives (13x=85). Substituting \(x=\frac{85}{13}\) gives \(y=\frac{93}{13}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (13x=85) मिलता है। \(x=\frac{85}{13}\) रखकर \(y=\frac{93}{13}\) मिलता है।

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Question 9/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (5x+4y=73) और (3x-2y=19) को हल करने पर (y) का मान क्या है?

On solving (5x+4y=73) and (3x-2y=19), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{23}{11}\)

Step 1

Concept

Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{111}{11}\) and then \(y=\frac{23}{11}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{23}{11}\). Multiply the second equation by (2) and add it to the first. This gives \(x=\frac{111}{11}\) and then \(y=\frac{23}{11}\).

Step 3

Exam Tip

दूसरे समीकरण को (2) से गुणा कर पहले में जोड़ें। \(x=\frac{111}{11}\) और फिर \(y=\frac{23}{11}\) मिलता है।

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Question 10/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (11x-5y=13) और (7x+10y=74), तो (x+2y) का मान क्या है?

If (11x-5y=13) and (7x+10y=74), what is the value of (x+2y)?

Explanation opens after your attempt
Correct Answer

C. (13)

Step 1

Concept

Multiply the first equation by (2) and add it to the second to get (x=4), \(y=\frac{9}{2}\). In exams, substitute fractional values carefully in the expression.

Step 2

Why this answer is correct

The correct answer is C. (13). Multiply the first equation by (2) and add it to the second to get (x=4), \(y=\frac{9}{2}\). In exams, substitute fractional values carefully in the expression.

Step 3

Exam Tip

पहले समीकरण को (2) से गुणा करके दूसरे में जोड़ें और (x=4), \(y=\frac{9}{2}\) पाएँ। परीक्षा में भिन्न मानों को व्यंजक में सावधानी से रखें।

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Question 11/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (x=3y-4) और (2x+5y=37), तो (y) का मान क्या है?

If (x=3y-4) and (2x+5y=37), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{45}{11}\)

Step 1

Concept

Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{45}{11}\). Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).

Step 3

Exam Tip

(x=3y-4) को दूसरे समीकरण में रखें। (6y-8+5y=37), इसलिए \(y=\frac{45}{11}\)।

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Question 12/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (4x+9y=71) और (5x-3y=8) से (y) का मान क्या है?

What is the value of (y) from (4x+9y=71) and (5x-3y=8)?

Explanation opens after your attempt
Correct Answer

B. \(y=\frac{17}{3}\)

Step 1

Concept

Multiply the second equation by (3) and add the first. (x=5), then (4(5)+9y=71) gives \(y=\frac{17}{3}\).

Step 2

Why this answer is correct

The correct answer is B. \(y=\frac{17}{3}\). Multiply the second equation by (3) and add the first. (x=5), then (4(5)+9y=71) gives \(y=\frac{17}{3}\).

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा कर पहले से जोड़ें। (x=5), फिर (4(5)+9y=71) से \(y=\frac{17}{3}\)।

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Question 13/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (8x-3y=31) और (2x+3y=29) को हल करने पर (y) कितना होगा?

On solving (8x-3y=31) and (2x+3y=29), what is (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{17}{3}\)

Step 1

Concept

Adding both equations gives (10x=60), so (x=6). From the second equation, \(y=\frac{17}{3}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{17}{3}\). Adding both equations gives (10x=60), so (x=6). From the second equation, \(y=\frac{17}{3}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (10x=60), इसलिए (x=6)। दूसरे समीकरण से \(y=\frac{17}{3}\)।

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Question 14/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (7x+2y=32) और (3x-4y=-6) से (y) का मान क्या है?

What is the value of (y) from (7x+2y=32) and (3x-4y=-6)?

Explanation opens after your attempt
Correct Answer

A. \(y=\frac{69}{17}\)

Step 1

Concept

Multiply the first equation by (2) and add the second. \(x=\frac{58}{17}\) and \(y=\frac{69}{17}\).

Step 2

Why this answer is correct

The correct answer is A. \(y=\frac{69}{17}\). Multiply the first equation by (2) and add the second. \(x=\frac{58}{17}\) and \(y=\frac{69}{17}\).

Step 3

Exam Tip

पहले समीकरण को (2) से गुणा कर दूसरे से जोड़ें। \(x=\frac{58}{17}\) और \(y=\frac{69}{17}\)।

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Question 15/21 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (4x+3y=50) और (2x-5y=-6) को हल करने पर (y) का मान क्या है?

On solving (4x+3y=50) and (2x-5y=-6), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

D. \(y=\frac{62}{13}\)

Step 1

Concept

Use \(x=\frac{5y-6}{2}\) from the second equation. Substitution gives (13y=62), so \(y=\frac{62}{13}\).

Step 2

Why this answer is correct

The correct answer is D. \(y=\frac{62}{13}\). Use \(x=\frac{5y-6}{2}\) from the second equation. Substitution gives (13y=62), so \(y=\frac{62}{13}\).

Step 3

Exam Tip

दूसरे समीकरण से \(x=\frac{5y-6}{2}\) रखें। पहले में रखने पर (13y=62), इसलिए \(y=\frac{62}{13}\)।

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Question 16/21 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (8x-5y=29) और (3x+5y=26) से (y) का मान क्या है?

What is the value of (y) from (8x-5y=29) and (3x+5y=26)?

Explanation opens after your attempt
Correct Answer

D. \(y=\frac{11}{5}\)

Step 1

Concept

Adding both equations gives (11x=55), so (x=5). From the second equation (15+5y=26), hence \(y=\frac{11}{5}\).

Step 2

Why this answer is correct

The correct answer is D. \(y=\frac{11}{5}\). Adding both equations gives (11x=55), so (x=5). From the second equation (15+5y=26), hence \(y=\frac{11}{5}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (11x=55), इसलिए (x=5)। दूसरे समीकरण से (15+5y=26), अतः \(y=\frac{11}{5}\)।

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Question 17/21 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (2x+3y=27) और (4x-y=11), तो (x) का मान क्या होगा?

If (2x+3y=27) and (4x-y=11), what will be the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (x=4)

Step 1

Concept

Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).

Step 2

Why this answer is correct

The correct answer is B. (x=4). Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).

Step 3

Exam Tip

दूसरे समीकरण से (y=4x-11) रखें। पहले में रखने पर (14x-33=27), इसलिए \(x=\frac{30}{7}\) आता है।

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Question 18/21 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (4x+y=22) और (3x-2y=1), तो (y) का मान क्या होगा?

If (4x+y=22) and (3x-2y=1), what will be the value of (y)?

Explanation opens after your attempt
Correct Answer

C. (y=6)

Step 1

Concept

Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).

Step 2

Why this answer is correct

The correct answer is C. (y=6). Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).

Step 3

Exam Tip

पहले समीकरण से (y=22-4x) रखें। दूसरे में रखने पर (11x=45), फिर \(y=\frac{62}{11}\) मिलता है।

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Question 19/21 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

समीकरणों (8x-3y=25) और (2x+3y=17) से (x) का मान क्या है?

What is the value of (x) from (8x-3y=25) and (2x+3y=17)?

Explanation opens after your attempt
Correct Answer

B. (x=4)

Step 1

Concept

Adding both equations gives (10x=42). Therefore \(x=\frac{21}{5}\).

Step 2

Why this answer is correct

The correct answer is B. (x=4). Adding both equations gives (10x=42). Therefore \(x=\frac{21}{5}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (10x=42) मिलता है। इसलिए \(x=\frac{21}{5}\) है।

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Question 20/21 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

समीकरणों (7x+2y=33) और (x-2y=3) को हल करने पर (y) कितना होगा?

On solving (7x+2y=33) and (x-2y=3), what is (y)?

Explanation opens after your attempt
Correct Answer

B. (y=2)

Step 1

Concept

Adding both equations gives (8x=36), so \(x=\frac{9}{2}\). Then (x-2y=3) gives \(y=\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is B. (y=2). Adding both equations gives (8x=36), so \(x=\frac{9}{2}\). Then (x-2y=3) gives \(y=\frac{3}{4}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (8x=36), इसलिए \(x=\frac{9}{2}\)। फिर (x-2y=3) से \(y=\frac{3}{4}\) आता है।

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Question 21/21 Easy Mathematics Polynomials Polynomials in one variable Class 10 Level 47

यदि (r(x)=4x-2), तो (r\left\(\frac{1}{2}\right\)) क्या है?

If (r(x)=4x-2), what is (r\left\(\frac{1}{2}\right\))?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

(r\left\(\frac{1}{2}\right\)=4\left\(\frac{1}{2}\right\)2=1). Use brackets when substituting fractions.

Step 2

Why this answer is correct

The correct answer is A. (1). (r\left\(\frac{1}{2}\right\)=4\left\(\frac{1}{2}\right\)2=1). Use brackets when substituting fractions.

Step 3

Exam Tip

(r\left\(\frac{1}{2}\right\)=4\left\(\frac{1}{2}\right\)2=1) है। भिन्न रखते समय कोष्ठक का प्रयोग करें।

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