transformed equations se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
11 questions tagged with transformed equations.
What is the value of (x-y) from \(\frac{x+4y}{5}=10\) and \(\frac{3x-y}{4}=7\)?
B. \(x-y=\frac{40}{13}\)
दिए समीकरण (x+4y=50) और (3x-y=28) बनते हैं। हल से \(x-y=\frac{40}{13}\)। / The equations become (x+4y=50) and (3x-y=28). Solving gives \(x-y=\frac{40}{13}\).
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What is the value of (x) from \(\frac{2x-y}{5}=4\) and \(\frac{x+3y}{4}=8\)?
C. \(x=\frac{92}{7}\)
दिए समीकरण (2x-y=20) और (x+3y=32) बनते हैं। प्रतिस्थापन से \(x=\frac{92}{7}\)। / The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
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If \(\frac{x+y}{4}=6\) and \(\frac{x-y}{5}=2\), what are the values of (x) and (y)?
C. (x=17,\ y=7)
दिए समीकरण (x+y=24) और (x-y=10) बनते हैं। जोड़ने पर (x=17) और (y=7)। / The given equations become (x+y=24) and (x-y=10). Adding gives (x=17) and (y=7).
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What is the solution of (3(x+y)=57) and (4(x-y)=28)?
B. (x=13,\ y=6)
दिए समीकरण (x+y=19) और (x-y=7) बनते हैं। जोड़ने पर (x=13) और फिर (y=6)। / The equations become (x+y=19) and (x-y=7). Adding gives (x=13), then (y=6).
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What is the value of (x-y) from \(\frac{x+3y}{4}=9\) and \(\frac{2x-y}{3}=5\)?
D. (3)
दिए समीकरण (x+3y=36) और (2x-y=15) बनते हैं। हल \(x=\frac{81}{7},\ y=\frac{57}{7}\), इसलिए \(x-y=\frac{24}{7}\), अतः विकल्पों में कोई सही नहीं है। / The equations become (x+3y=36) and (2x-y=15). The solution is \(x=\frac{81}{7},\ y=\frac{57}{7}\), so \(x-y=\frac{24}{7}\), hence no option is correct.
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What is the value of (x) from \(\frac{3x-y}{4}=5\) and \(\frac{x+2y}{3}=7\)?
A. \(x=\frac{61}{7}\)
दिए समीकरण (3x-y=20) और (x+2y=21) बनते हैं। प्रतिस्थापन से \(x=\frac{61}{7}\) मिलता है। / The equations become (3x-y=20) and (x+2y=21). Substitution gives \(x=\frac{61}{7}\).
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If \(\frac{x+y}{3}=7\) and \(\frac{x-y}{4}=2\), what is the value of (x-y)?
C. (8)
दूसरा समीकरण सीधे (x-y=8) देता है। परीक्षा में कभी-कभी पूछे गए व्यंजक का मान सीधे मिल जाता है। / The second equation directly gives (x-y=8). In exams, the asked expression is sometimes obtained directly.
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What is the solution of (2(x+y)=34) and (3(x-y)=15)?
C. (x=11,\ y=6)
दिए समीकरण (x+y=17) और (x-y=5) बनते हैं। जोड़ने पर (x=11) और फिर (y=6)। / The equations become (x+y=17) and (x-y=5). Adding gives (x=11), then (y=6).
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What is the value of (x-y) from \(\frac{x+2y}{3}=8\) and \(\frac{2x-y}{5}=3\)?
D. \(\frac{21}{5}\)
दिए समीकरण (x+2y=24) और (2x-y=15) बनते हैं। हल \(x=\frac{54}{5},\ y=\frac{33}{5}\), इसलिए \(x-y=\frac{21}{5}\)। / The equations become (x+2y=24) and (2x-y=15). The solution is \(x=\frac{54}{5},\ y=\frac{33}{5}\), so \(x-y=\frac{21}{5}\).
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What is the value of (y) from \(\frac{2x-3y}{5}=1\) and \(\frac{x+y}{2}=6\)?
B. \(y=\frac{19}{5}\)
दिए समीकरण (2x-3y=5) और (x+y=12) बनते हैं। प्रतिस्थापन से \(y=\frac{19}{5}\) मिलता है। / The equations become (2x-3y=5) and (x+y=12). Substitution gives \(y=\frac{19}{5}\).
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If \(\frac{x+y}{2}=9\) and \(\frac{x-y}{3}=2\), what are the values of (x) and (y)?
A. (x=12,\ y=6)
दिए समीकरण (x+y=18) और (x-y=6) बनते हैं। जोड़ने पर (x=12) और फिर (y=6)। / The given equations become (x+y=18) and (x-y=6). Adding gives (x=12), then (y=6).
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