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If \(p(x)=2x^2+bx-10\) and \(p(2)=4\), what is the value of \(b\)?
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Answer and explanation
Correct answer: 3
Substitute \(x=2\) into the polynomial: \(p(2)=2(2)^2+2b-10=4\). Thus, \(8+2b-10=4\), so \(2b-2=4\) and \(b=3\). Therefore, option C is correct. Exam tip: when a value such as \(p(a)\) is given, substitute \(x=a\) directly in the polynomial.
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
Substitute \(x=2\) into the polynomial: \(p(2)=2(2)^2+2b-10=4\). Thus, \(8+2b-10=4\), so \(2b-2=4\) and \(b=3\). Therefore, option C is correct. Exam tip: when a value such as \(p(a)\) is given, substitute \(x=a\) directly in the polynomial.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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