100 results found for "substitution reasoning" in Class 10.
समीकरणों (x+2y=18) और (4x-y=9) को प्रतिस्थापन विधि से हल करने पर (y) का मान क्या है?
Solving (x+2y=18) and (4x-y=9) by substitution, what is the value of (y)?
#pair-linear-equations-substitution-simple
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=18-2y). Substituting in the second gives (72-8y-y=9), so (y=7).
Step 2
Why this answer is correct
The correct answer is B. (7). From the first equation, (x=18-2y). Substituting in the second gives (72-8y-y=9), so (y=7).
Step 3
Exam Tip
पहले से (x=18-2y)। दूसरे में रखने पर (72-8y-y=9), इसलिए (y=7)।
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यदि (4x-y=11) और (2x+3y=29), तो प्रतिस्थापन विधि से (y) का मान क्या होगा?
If (4x-y=11) and (2x+3y=29), what is the value of (y) by substitution?
#pair-linear-equations-substitution-expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (y=4x-11). Substitution must be checked in both equations before selecting an option.
Step 2
Why this answer is correct
The correct answer is C. (5). From the first equation, (y=4x-11). Substitution must be checked in both equations before selecting an option.
Step 3
Exam Tip
पहले समीकरण से (y=4x-11)। इसे दूसरे में रखने पर (14x=62) नहीं बल्कि (14x=62), इसलिए \(x=\frac{31}{7}\) नहीं; सरल विकल्पों से बचने के लिए पुनः जांच करें।
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दो संख्याओं का योग (23) है और उनका अंतर (7) है। प्रतिस्थापन विधि से बड़ी संख्या क्या होगी?
The sum of two numbers is (23) and their difference is (7). By substitution, what is the greater number?
#word-problem
#numbers
#substitution
A (14)
B (15)
C (16)
D (17)
Explanation opens after your attempt
Step 1
Concept
Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 2
Why this answer is correct
The correct answer is B. (15). Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 3
Exam Tip
यदि संख्याएं (x,y) हों तो (x+y=23) और (x-y=7)। जोड़ने पर (2x=30), इसलिए बड़ी संख्या (15) है।
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यदि (3x-2y=4) और (x+y=11), तो प्रतिस्थापन विधि से (y) का मान क्या होगा?
If (3x-2y=4) and (x+y=11), what is the value of (y) by substitution?
#pair-linear-equations
#substitution
#expert
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=11-y) carefully in the first equation; incorrect simplification changes the answer. Always check the obtained values in both equations.
Step 2
Why this answer is correct
The correct answer is D. (7). Substitute (x=11-y) carefully in the first equation; incorrect simplification changes the answer. Always check the obtained values in both equations.
Step 3
Exam Tip
दूसरे समीकरण से (x=11-y) रखकर (33-5y=4) नहीं बल्कि (33-3y-2y=4) मिलता है, इसलिए \(y=\frac{29}{5}\) नहीं होगा; सही जांच जरूरी है।
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यदि (2x-3y=-7) और (4x+y=19), तो प्रतिस्थापन विधि से (y) का मान क्या है?
If (2x-3y=-7) and (4x+y=19), what is the value of (y) by substitution?
#pair-linear-equations
#substitution
#expert
A (y=3)
B (y=4)
C (y=5)
D (y=2)
Explanation opens after your attempt
Step 1
Concept
From the second equation, put (y=19-4x), giving (x=4) and (y=3). In exams, isolate the easier variable first.
Step 2
Why this answer is correct
The correct answer is A. (y=3). From the second equation, put (y=19-4x), giving (x=4) and (y=3). In exams, isolate the easier variable first.
Step 3
Exam Tip
दूसरे समीकरण से (y=19-4x) रखकर हल करने पर (x=4) और (y=3) मिलता है। परीक्षा में पहले सरल चर को अलग करें।
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प्रतिस्थापन विधि से (y=2x+1) और (x+y=10) को हल करें।
Solve (y=2x+1) and (x+y=10) by substitution.
#linear equations
#substitution
#direct expression
#medium
#class 10
A ( (2,8) )
B ( (4,6) )
C ( (3,7) )
D ( (5,5) )
Explanation opens after your attempt
Correct Answer
C. ( (3,7) )
Step 1
Concept
Putting (y=2x+1) gives (3x+1=10), so (x=3) and (y=7). If (y=) form is given, substitute directly.
Step 2
Why this answer is correct
The correct answer is C. ( (3,7) ). Putting (y=2x+1) gives (3x+1=10), so (x=3) and (y=7). If (y=) form is given, substitute directly.
Step 3
Exam Tip
(y=2x+1) रखने पर (3x+1=10), इसलिए (x=3) और (y=7)। दिए गए रूप (y=) में हो तो सीधे रखें।
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प्रतिस्थापन विधि से (2x+y=11) और (x-y=1) को हल करें।
Solve (2x+y=11) and (x-y=1) by substitution.
#linear equations
#substitution
#medium
#class 10
A ( (3,5) )
B ( (4,3) )
C ( (5,1) )
D ( (2,7) )
Explanation opens after your attempt
Correct Answer
B. ( (4,3) )
Step 1
Concept
From (x-y=1), (y=x-1), so (2x+x-1=11) and the solution is ( (4,3) ). In exams, isolate the easier variable first.
Step 2
Why this answer is correct
The correct answer is B. ( (4,3) ). From (x-y=1), (y=x-1), so (2x+x-1=11) and the solution is ( (4,3) ). In exams, isolate the easier variable first.
Step 3
Exam Tip
(x-y=1) से (y=x-1), इसलिए (2x+x-1=11) और हल ( (4,3) ) है। परीक्षा में पहले आसान चर अलग करें।
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प्रतिस्थापन विधि से (x+y=17) और (y=x+3) का हल ज्ञात करें।
Find the solution of (x+y=17) and (y=x+3) by substitution.
#linear equations
#substitution
#one variable equation
#easy
#class 10
A ( (6,11) )
B ( (8,9) )
C ( (7,10) )
D ( (5,12) )
Explanation opens after your attempt
Correct Answer
C. ( (7,10) )
Step 1
Concept
Putting (y=x+3) gives (2x+3=17), so (x=7) and (y=10). Solve the one-variable equation formed after substitution.
Step 2
Why this answer is correct
The correct answer is C. ( (7,10) ). Putting (y=x+3) gives (2x+3=17), so (x=7) and (y=10). Solve the one-variable equation formed after substitution.
Step 3
Exam Tip
(y=x+3) रखने पर (2x+3=17), इसलिए (x=7) और (y=10)। प्रतिस्थापन के बाद बने एक चर के समीकरण को हल करें।
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प्रतिस्थापन विधि से (2x+y=16) और (x-y=2) को हल करें।
Solve (2x+y=16) and (x-y=2) by substitution.
#linear equations
#substitution
#two equations
#easy
#class 10
A ( (5,6) )
B ( (6,4) )
C ( (4,8) )
D ( (7,2) )
Explanation opens after your attempt
Correct Answer
B. ( (6,4) )
Step 1
Concept
From (x-y=2), (y=x-2), so (2x+x-2=16) and (x=6). Then (y=4).
Step 2
Why this answer is correct
The correct answer is B. ( (6,4) ). From (x-y=2), (y=x-2), so (2x+x-2=16) and (x=6). Then (y=4).
Step 3
Exam Tip
(x-y=2) से (y=x-2), इसलिए (2x+x-2=16) और (x=6)। फिर (y=4) मिलेगा।
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प्रतिस्थापन विधि से (3x+y=10) में (x=2) रखने पर (y) क्या होगा?
Using substitution in (3x+y=10), if (x=2), what is (y)?
#linear equations
#substitution
#simple calculation
#easy
#class 10
A (y=4)
B (y=3)
C (y=2)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
(3(2)+y=10), so (6+y=10) and (y=4). Multiply first and then subtract.
Step 2
Why this answer is correct
The correct answer is A. (y=4). (3(2)+y=10), so (6+y=10) and (y=4). Multiply first and then subtract.
Step 3
Exam Tip
(3(2)+y=10), इसलिए (6+y=10) और (y=4)। गुणा पहले और घटाव बाद में करें।
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प्रतिस्थापन विधि से हल करें: (x+y=7) और (x-y=1)। ((x,y)) क्या है?
Solve by substitution: (x+y=7) and (x-y=1). What is ((x,y))?
#linear equations
#substitution
#elimination
#easy
#class 10
A ( (4,3) )
B ( (3,4) )
C ( (5,2) )
D ( (2,5) )
Explanation opens after your attempt
Correct Answer
A. ( (4,3) )
Step 1
Concept
Adding both equations gives (2x=8), so (x=4) and (y=3). In exams, first eliminate the easy variable.
Step 2
Why this answer is correct
The correct answer is A. ( (4,3) ). Adding both equations gives (2x=8), so (x=4) and (y=3). In exams, first eliminate the easy variable.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=8), इसलिए (x=4) और (y=3)। परीक्षा में पहले जोड़कर आसान चर निकालें।
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कौन सा विकल्प \(\sqrt{3}\) की सिद्धि में (p=3k) रखने के बाद सही आगे का तर्क देता है?
Which option gives the correct further reasoning after substituting (p=3k) in the proof of \(\sqrt{3}\)?
#sqrt3 proof
#substitution reasoning
#hard
A \(9k^2=3q^2\), इसलिए \(q^2=3k^2\), अतः (q) (3) से विभाज्य है / \(9k^2=3q^2\), so \(q^2=3k^2\), hence (q) is divisible by (3)
B \(3k^2=3q^2\), इसलिए (q=k), अतः प्रमाण पूरा / \(3k^2=3q^2\), so (q=k), hence proof complete
C (p=q), इसलिए विरोधाभास / (p=q), so contradiction
D (q=0), इसलिए भिन्न अमान्य / (q=0), so fraction invalid
Explanation opens after your attempt
Correct Answer
A. \(9k^2=3q^2\), इसलिए \(q^2=3k^2\), अतः (q) (3) से विभाज्य है / \(9k^2=3q^2\), so \(q^2=3k^2\), hence (q) is divisible by (3)
Step 1
Concept
If (p=3k), then \(p^2=9k^2\).
Step 2
Why this answer is correct
From \(9k^2=3q^2\), we get \(q^2=3k^2\).
Step 3
Exam Tip
By the prime rule, (q) is divisible by (3). चरण 1: (p=3k) रखने पर \(p^2=9k^2\) होगा। चरण 2: \(9k^2=3q^2\) से \(q^2=3k^2\) मिलता है। चरण 3: अभाज्य नियम से (q) (3) से विभाज्य होता है।
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समीकरण (y=x+1) और (x+y=7) को हल करें।
Solve the equations (y=x+1) and (x+y=7).
#linear equations
#substitution
#expression substitution
#easy
#class 10
A ( (3,4) )
B ( (4,3) )
C ( (2,5) )
D ( (5,2) )
Explanation opens after your attempt
Correct Answer
A. ( (3,4) )
Step 1
Concept
Substituting (y=x+1) gives (x+x+1=7), so (x=3) and (y=4). Put the given expression into the other equation first.
Step 2
Why this answer is correct
The correct answer is A. ( (3,4) ). Substituting (y=x+1) gives (x+x+1=7), so (x=3) and (y=4). Put the given expression into the other equation first.
Step 3
Exam Tip
(y=x+1) को रखने पर (x+x+1=7), इसलिए (x=3) और (y=4)। पहले दिए गए चर को दूसरे समीकरण में रखें।
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कौन सा विकल्प \(\sqrt{5}\) की सिद्धि में सही और पूर्ण तर्क देता है?
Which option gives a correct and complete reasoning in the proof of \(\sqrt{5}\)?
#sqrt5 proof
#complete reasoning
#hard
#class 10
A \(p^2=5q^2\) से (p=5k), फिर (q=5r), इसलिए सहअभाज्य शर्त से विरोधाभास / From \(p^2=5q^2\), (p=5k), then (q=5r), so contradiction with coprime condition
B \(p^2=5q^2\) से (p=5q), इसलिए प्रमाण पूरा / From \(p^2=5q^2\), (p=5q), so proof complete
C \(\sqrt{5}=5\), इसलिए अपरिमेय / \(\sqrt{5}=5\), so irrational
D (q=0), इसलिए विरोधाभास / (q=0), so contradiction
Explanation opens after your attempt
Correct Answer
A. \(p^2=5q^2\) से (p=5k), फिर (q=5r), इसलिए सहअभाज्य शर्त से विरोधाभास / From \(p^2=5q^2\), (p=5k), then (q=5r), so contradiction with coprime condition
Step 1
Concept
From \(p^2=5q^2\), (p) is divisible by (5), so (p=5k).
Step 2
Why this answer is correct
Substitution gives (q) also divisible by (5), so (q=5r).
Step 3
Exam Tip
Common factor (5) contradicts the coprime condition. चरण 1: \(p^2=5q^2\) से (p) (5) से विभाज्य है और (p=5k)। चरण 2: रखने पर (q) भी (5) से विभाज्य मिलता है, यानी (q=5r)। चरण 3: दोनों में (5) साझा होना सहअभाज्य शर्त से विरोधाभास है।
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\(\sqrt{5}\) की सिद्धि में कौन सा कथन गलत तर्क है?
Which statement is a wrong reasoning in the proof of \(\sqrt{5}\)?
#sqrt5 proof
#wrong reasoning
#class 10
A \(p^2=5q^2\) से \(p^2\) (5) से विभाज्य है / From \(p^2=5q^2\), \(p^2\) is divisible by (5)
B \(p^2\) (5) से विभाज्य है, इसलिए (p) (5) से विभाज्य है / Since \(p^2\) is divisible by (5), (p) is divisible by (5)
C (p=5k) रखने पर \(p^2=25k^2\) / If (p=5k), then \(p^2=25k^2\)
D \(p^2=5q^2\) से (p=5q) सीधे मिलेगा / From \(p^2=5q^2\), we directly get (p=5q)
Explanation opens after your attempt
Correct Answer
D. \(p^2=5q^2\) से (p=5q) सीधे मिलेगा / From \(p^2=5q^2\), we directly get (p=5q)
Step 1
Concept
\(p^2=5q^2\) tells us divisibility of \(p^2\).
Step 2
Why this answer is correct
By the prime rule, (p) is divisible by (5), but (p=5q) does not follow directly.
Step 3
Exam Tip
In exams, writing (p=5k) is correct. चरण 1: \(p^2=5q^2\) से \(p^2\) की विभाज्यता पता चलती है। चरण 2: अभाज्य नियम से (p) (5) से विभाज्य है, लेकिन सीधे (p=5q) नहीं मिलता। चरण 3: परीक्षा में (p=5k) लिखना सही है।
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आयात प्रतिस्थापन नीति का संतुलित विशेषज्ञ मूल्यांकन क्या होगा?
What is a balanced expert evaluation of import substitution policy?
#import-substitution
#expert-evaluation
#industry
A यह आत्मनिर्भर उद्योग बढ़ा सकती थी लेकिन संरक्षणवाद से दक्षता समस्या आ सकती थी / It could grow self reliant industry but protectionism could create efficiency problems
B यह केवल सैन्य गठबंधन था / It was only a military alliance
C यह घरेलू उद्योग से असंबंधित थी / It was unrelated to domestic industry
D यह हर देश में बिना सीमा सफल हुई / It succeeded everywhere without limits
Explanation opens after your attempt
Correct Answer
A. यह आत्मनिर्भर उद्योग बढ़ा सकती थी लेकिन संरक्षणवाद से दक्षता समस्या आ सकती थी / It could grow self reliant industry but protectionism could create efficiency problems
Step 1
Concept
Understand both aims and limits of import substitution. For exams write benefits and criticism together.
Step 2
Why this answer is correct
The correct answer is A. यह आत्मनिर्भर उद्योग बढ़ा सकती थी लेकिन संरक्षणवाद से दक्षता समस्या आ सकती थी / It could grow self reliant industry but protectionism could create efficiency problems. Understand both aims and limits of import substitution. For exams write benefits and criticism together.
Step 3
Exam Tip
आयात प्रतिस्थापन के उद्देश्य और सीमाएं दोनों समझें। परीक्षा में लाभ और आलोचना साथ लिखें।
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आयात प्रतिस्थापन और निर्यातोन्मुख विकास की तुलना में मुख्य नीति अंतर क्या है?
What is the main policy difference between import substitution and export oriented development?
#import-substitution
#export-oriented-development
#economic-policy
A आयात प्रतिस्थापन घरेलू बाजार सुरक्षा पर और निर्यातोन्मुख विकास वैश्विक बाजार प्रतिस्पर्धा पर जोर देता है / Import substitution stresses domestic market protection while export oriented development stresses global market competition
B दोनों केवल सैन्य नीति हैं / Both are only military policies
C दोनों का उद्योग से कोई संबंध नहीं / Both have no relation with industry
D दोनों केवल भाषा नीति हैं / Both are only language policies
Explanation opens after your attempt
Correct Answer
A. आयात प्रतिस्थापन घरेलू बाजार सुरक्षा पर और निर्यातोन्मुख विकास वैश्विक बाजार प्रतिस्पर्धा पर जोर देता है / Import substitution stresses domestic market protection while export oriented development stresses global market competition
Step 1
Concept
Both development strategies show different economic paths. For exams understand benefits and limits of both.
Step 2
Why this answer is correct
The correct answer is A. आयात प्रतिस्थापन घरेलू बाजार सुरक्षा पर और निर्यातोन्मुख विकास वैश्विक बाजार प्रतिस्पर्धा पर जोर देता है / Import substitution stresses domestic market protection while export oriented development stresses global market competition. Both development strategies show different economic paths. For exams understand benefits and limits of both.
Step 3
Exam Tip
दोनों विकास रणनीतियां अलग आर्थिक रास्ते दिखाती हैं। परीक्षा में लाभ और सीमा दोनों समझें।
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आयात प्रतिस्थापन नीति की विशेषज्ञ स्तर की आलोचना किस बात पर केंद्रित होगी?
What would an expert level criticism of import substitution focus on?
#import-substitution
#criticism
#economic-policy
A संरक्षण से घरेलू उद्योग बचता है पर दक्षता और प्रतिस्पर्धा की समस्या आ सकती है / Protection saves domestic industry but can create efficiency and competition problems
B यह कभी किसी देश ने अपनाई नहीं / No country ever adopted it
C यह घरेलू उद्योग से असंबंधित है / It is unrelated to domestic industry
D यह हमेशा तुरंत पूर्ण सफलता देती है / It always gives immediate complete success
Explanation opens after your attempt
Correct Answer
A. संरक्षण से घरेलू उद्योग बचता है पर दक्षता और प्रतिस्पर्धा की समस्या आ सकती है / Protection saves domestic industry but can create efficiency and competition problems
Step 1
Concept
It is necessary to understand both benefits and limits of import substitution. For exams make a balanced evaluation.
Step 2
Why this answer is correct
The correct answer is A. संरक्षण से घरेलू उद्योग बचता है पर दक्षता और प्रतिस्पर्धा की समस्या आ सकती है / Protection saves domestic industry but can create efficiency and competition problems. It is necessary to understand both benefits and limits of import substitution. For exams make a balanced evaluation.
Step 3
Exam Tip
आयात प्रतिस्थापन के लाभ और सीमाएं दोनों समझना जरूरी है। परीक्षा में संतुलित मूल्यांकन करें।
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आयात प्रतिस्थापन नीति की सीमा समझना क्यों जरूरी है?
Why is it necessary to understand the limitation of import substitution policy?
#import-substitution
#limitations
#self-reliance
A क्योंकि संरक्षण से दक्षता और प्रतिस्पर्धा की समस्या पैदा हो सकती थी / Because protection could create problems of efficiency and competition
B क्योंकि यह कभी अपनाई ही नहीं गई / Because it was never adopted
C क्योंकि इसका उद्योग से कोई संबंध नहीं था / Because it had no relation with industry
D क्योंकि यह हमेशा तुरंत पूर्ण सफलता देती थी / Because it always gave immediate complete success
Explanation opens after your attempt
Correct Answer
A. क्योंकि संरक्षण से दक्षता और प्रतिस्पर्धा की समस्या पैदा हो सकती थी / Because protection could create problems of efficiency and competition
Step 1
Concept
Import substitution aimed at self reliance but also had limits. For exams write both benefits and criticism.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि संरक्षण से दक्षता और प्रतिस्पर्धा की समस्या पैदा हो सकती थी / Because protection could create problems of efficiency and competition. Import substitution aimed at self reliance but also had limits. For exams write both benefits and criticism.
Step 3
Exam Tip
आयात प्रतिस्थापन आत्मनिर्भरता के लिए था लेकिन उसकी सीमाएं भी थीं। परीक्षा में लाभ और आलोचना दोनों लिखें।
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आयात प्रतिस्थापन नीति की आलोचना किस आधार पर की जा सकती है?
On what basis can import substitution policy be criticized?
#import-substitution
#criticism
#economic-policy
A संरक्षण से दक्षता और वैश्विक प्रतिस्पर्धा की समस्या आ सकती थी / Protection could create problems of efficiency and global competition
B यह घरेलू उद्योग से असंबंधित थी / It was unrelated to domestic industry
C यह विदेशी निर्भरता बढ़ाने के लिए ही थी / It was only for increasing foreign dependence
D यह कभी किसी देश ने अपनाई ही नहीं / No country ever adopted it
Explanation opens after your attempt
Correct Answer
A. संरक्षण से दक्षता और वैश्विक प्रतिस्पर्धा की समस्या आ सकती थी / Protection could create problems of efficiency and global competition
Step 1
Concept
Import substitution aimed at self reliance but also had limits. For exams write both benefits and criticism.
Step 2
Why this answer is correct
The correct answer is A. संरक्षण से दक्षता और वैश्विक प्रतिस्पर्धा की समस्या आ सकती थी / Protection could create problems of efficiency and global competition. Import substitution aimed at self reliance but also had limits. For exams write both benefits and criticism.
Step 3
Exam Tip
आयात प्रतिस्थापन आत्मनिर्भरता के लिए था पर उसकी सीमाएं भी थीं। परीक्षा में लाभ और आलोचना दोनों लिखें।
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आयात प्रतिस्थापन नीति औपनिवेशिक अनुभव की किस सीख पर आधारित थी?
Import substitution policy was based on which lesson of colonial experience?
#import-substitution
#self-reliance
#industry
A विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness
B घरेलू उद्योग हमेशा अनावश्यक होते हैं / Domestic industries are always unnecessary
C विदेशी माल पर निर्भरता पूर्ण स्वतंत्रता देती है / Dependence on foreign goods gives complete freedom
D व्यापार और विकास असंबंधित हैं / Trade and development are unrelated
Explanation opens after your attempt
Correct Answer
A. विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness
Step 1
Concept
Import substitution was a policy of domestic industry and self reliance. For exams write both benefits and limits.
Step 2
Why this answer is correct
The correct answer is A. विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness. Import substitution was a policy of domestic industry and self reliance. For exams write both benefits and limits.
Step 3
Exam Tip
आयात प्रतिस्थापन घरेलू उद्योग और आत्मनिर्भरता की नीति थी। परीक्षा में इसके लाभ और सीमा दोनों लिखें।
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आयात प्रतिस्थापन नीति के पीछे औपनिवेशिक अनुभव का कौन सा सबक था?
Which lesson from colonial experience was behind import substitution policy?
#import-substitution
#self-reliance
#colonial-experience
A विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness
B विदेशी वस्तुओं पर निर्भरता हमेशा लाभकारी होती है / Dependence on foreign goods is always beneficial
C घरेलू उद्योग का विकास अनावश्यक है / Development of domestic industry is unnecessary
D व्यापार और विकास असंबंधित हैं / Trade and development are unrelated
Explanation opens after your attempt
Correct Answer
A. विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness
Step 1
Concept
Import substitution was an attempt to increase domestic industry and self reliance. For exams write both benefits and limits.
Step 2
Why this answer is correct
The correct answer is A. विदेशी उद्योगों पर निर्भरता आर्थिक कमजोरी पैदा कर सकती है / Dependence on foreign industries can create economic weakness. Import substitution was an attempt to increase domestic industry and self reliance. For exams write both benefits and limits.
Step 3
Exam Tip
आयात प्रतिस्थापन घरेलू उद्योग और आत्मनिर्भरता बढ़ाने का प्रयास था। परीक्षा में लाभ और सीमा दोनों लिखें।
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आयात प्रतिस्थापन नीति के पीछे उपनिवेशवादी अनुभव का कौन सा प्रभाव था?
Which effect of colonial experience was behind import substitution policy?
#import-substitution
#colonial-experience
#industry
A विदेशी उद्योगों पर निर्भरता घटाने की इच्छा / Desire to reduce dependence on foreign industries
B विदेशी वस्तुओं पर निर्भरता बढ़ाने की इच्छा / Desire to increase dependence on foreign goods
C स्थानीय उद्योगों को बंद करने की इच्छा / Desire to close local industries
D उपनिवेशवाद लौटाने की इच्छा / Desire to bring colonialism back
Explanation opens after your attempt
Correct Answer
A. विदेशी उद्योगों पर निर्भरता घटाने की इच्छा / Desire to reduce dependence on foreign industries
Step 1
Concept
Import substitution was a policy to strengthen domestic industry. For exams connect it with economic self reliance.
Step 2
Why this answer is correct
The correct answer is A. विदेशी उद्योगों पर निर्भरता घटाने की इच्छा / Desire to reduce dependence on foreign industries. Import substitution was a policy to strengthen domestic industry. For exams connect it with economic self reliance.
Step 3
Exam Tip
आयात प्रतिस्थापन घरेलू उद्योग को मजबूत करने की नीति थी। परीक्षा में इसे आर्थिक आत्मनिर्भरता से जोड़ें।
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आयात प्रतिस्थापन नीति की सीमा क्या हो सकती थी?
What could be a limitation of import substitution policy?
#import-substitution
#limitations
#economic-policy
A घरेलू उद्योग संरक्षण के साथ प्रतिस्पर्धा और दक्षता की समस्या आ सकती थी / Along with protection domestic industry could face competition and efficiency problems
B यह हमेशा बिना किसी समस्या के सफल होती थी / It always succeeded without any problem
C यह सभी विदेशी निर्भरता तुरंत खत्म कर देती थी / It immediately ended all foreign dependence
D इसका उद्योग से कोई संबंध नहीं था / It had no relation with industry
Explanation opens after your attempt
Correct Answer
A. घरेलू उद्योग संरक्षण के साथ प्रतिस्पर्धा और दक्षता की समस्या आ सकती थी / Along with protection domestic industry could face competition and efficiency problems
Step 1
Concept
Import substitution aimed at self reliance but had limits too. For exams understand both benefits and limits of policy.
Step 2
Why this answer is correct
The correct answer is A. घरेलू उद्योग संरक्षण के साथ प्रतिस्पर्धा और दक्षता की समस्या आ सकती थी / Along with protection domestic industry could face competition and efficiency problems. Import substitution aimed at self reliance but had limits too. For exams understand both benefits and limits of policy.
Step 3
Exam Tip
आयात प्रतिस्थापन आत्मनिर्भरता के लिए था लेकिन इसकी सीमाएं भी थीं। परीक्षा में नीति के लाभ और सीमा दोनों समझें।
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आयात प्रतिस्थापन और आर्थिक आत्मनिर्भरता में क्या संबंध था?
What was the relation between import substitution and economic self reliance?
#import-substitution
#self-reliance
#domestic-industry
A घरेलू उद्योग बढ़ाकर विदेशी वस्तुओं पर निर्भरता घटाना / Reducing dependence on foreign goods by increasing domestic industry
B विदेशी वस्तुओं की निर्भरता बढ़ाना / Increasing dependence on foreign goods
C सभी उद्योग बंद करना / Closing all industries
D दास व्यापार वापस लाना / Bringing back slave trade
Explanation opens after your attempt
Correct Answer
A. घरेलू उद्योग बढ़ाकर विदेशी वस्तुओं पर निर्भरता घटाना / Reducing dependence on foreign goods by increasing domestic industry
Step 1
Concept
Import substitution was linked with self reliant development policy. For exams connect it with post independence planning.
Step 2
Why this answer is correct
The correct answer is A. घरेलू उद्योग बढ़ाकर विदेशी वस्तुओं पर निर्भरता घटाना / Reducing dependence on foreign goods by increasing domestic industry. Import substitution was linked with self reliant development policy. For exams connect it with post independence planning.
Step 3
Exam Tip
आयात प्रतिस्थापन आत्मनिर्भर विकास की नीति से जुड़ा था। परीक्षा में इसे स्वतंत्रता बाद आर्थिक योजना से जोड़ें।
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आयात प्रतिस्थापन नीति को नवस्वतंत्र देशों ने किस समस्या के समाधान के रूप में देखा?
Newly independent countries saw import substitution policy as a solution to which problem?
#import-substitution
#domestic-industry
#self-reliance
A विदेशी औद्योगिक वस्तुओं पर निर्भरता / Dependence on foreign industrial goods
B सभी घरेलू उद्योगों की अधिकता / Excess of all domestic industries
C किसी भी बाजार का अभाव / Absence of any market
D राजनीतिक नागरिकता का अंत / End of political citizenship
Explanation opens after your attempt
Correct Answer
A. विदेशी औद्योगिक वस्तुओं पर निर्भरता / Dependence on foreign industrial goods
Step 1
Concept
Import substitution was a policy to build domestic industry. For exams connect it with economic self reliance.
Step 2
Why this answer is correct
The correct answer is A. विदेशी औद्योगिक वस्तुओं पर निर्भरता / Dependence on foreign industrial goods. Import substitution was a policy to build domestic industry. For exams connect it with economic self reliance.
Step 3
Exam Tip
आयात प्रतिस्थापन घरेलू उद्योग बनाने की नीति थी। परीक्षा में इसे आर्थिक आत्मनिर्भरता से जोड़ें।
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आयात प्रतिस्थापन नीति नए स्वतंत्र देशों में क्यों अपनाई गई?
Why was import substitution policy adopted in newly independent countries?
#import-substitution
#domestic-industry
#economic-policy
A घरेलू उद्योग विकसित कर विदेशी वस्तुओं पर निर्भरता घटाने के लिए / To develop domestic industry and reduce dependence on foreign goods
B सभी उद्योग बंद करने के लिए / To close all industries
C उपनिवेशी व्यापार बढ़ाने के लिए / To increase colonial trade
D दासता फिर शुरू करने के लिए / To restart slavery
Explanation opens after your attempt
Correct Answer
A. घरेलू उद्योग विकसित कर विदेशी वस्तुओं पर निर्भरता घटाने के लिए / To develop domestic industry and reduce dependence on foreign goods
Step 1
Concept
The aim of import substitution was to increase domestic production. For exams connect it with post independence economic policy.
Step 2
Why this answer is correct
The correct answer is A. घरेलू उद्योग विकसित कर विदेशी वस्तुओं पर निर्भरता घटाने के लिए / To develop domestic industry and reduce dependence on foreign goods. The aim of import substitution was to increase domestic production. For exams connect it with post independence economic policy.
Step 3
Exam Tip
आयात प्रतिस्थापन का उद्देश्य घरेलू उत्पादन को बढ़ाना था। परीक्षा में इसे स्वतंत्रता बाद आर्थिक नीति से जोड़ें।
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आयात प्रतिस्थापन नीति का सरल उद्देश्य क्या था?
What was the simple aim of import substitution policy?
#import-substitution
#industry
#development
A विदेशी वस्तुओं की जगह घरेलू उत्पादन बढ़ाना / Increasing domestic production instead of foreign goods
B सभी उद्योग बंद करना / Closing all industries
C दास व्यापार बढ़ाना / Increasing slave trade
D विदेशी शासन लागू करना / Applying foreign rule
Explanation opens after your attempt
Correct Answer
A. विदेशी वस्तुओं की जगह घरेलू उत्पादन बढ़ाना / Increasing domestic production instead of foreign goods
Step 1
Concept
Through import substitution countries wanted to develop domestic industries. For exams connect it with post independence economic policy.
Step 2
Why this answer is correct
The correct answer is A. विदेशी वस्तुओं की जगह घरेलू उत्पादन बढ़ाना / Increasing domestic production instead of foreign goods. Through import substitution countries wanted to develop domestic industries. For exams connect it with post independence economic policy.
Step 3
Exam Tip
आयात प्रतिस्थापन से देश घरेलू उद्योग विकसित करना चाहते थे। परीक्षा में इसे स्वतंत्रता बाद आर्थिक नीति से जोड़ें।
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यदि (y=2x+3) और (5x-2y=1), तो (x) का मान क्या है?
If (y=2x+3) and (5x-2y=1), what is the value of (x)?
#pair-linear-equations-substitution-brackets
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=2x+3) gives (5x-2(2x+3)=1). This gives (x=7); handle the negative sign outside brackets carefully.
Step 2
Why this answer is correct
The correct answer is C. (7). Substituting (y=2x+3) gives (5x-2(2x+3)=1). This gives (x=7); handle the negative sign outside brackets carefully.
Step 3
Exam Tip
(y=2x+3) रखने पर (5x-2(2x+3)=1)। इससे (x=7) मिलता है, कोष्ठक खोलते समय चिन्ह ध्यान रखें।
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यदि \(\frac{3}{x}+\frac{2}{y}=13\) और \(\frac{2}{x}-\frac{1}{y}=3\), तो \(\frac{1}{x}\) का मान क्या है?
If \(\frac{3}{x}+\frac{2}{y}=13\) and \(\frac{2}{x}-\frac{1}{y}=3\), what is the value of \(\frac{1}{x}\)?
#pair-linear-equations-reciprocal-substitution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solve (3u+2v=13), (2u-v=3) carefully before choosing.
Step 2
Why this answer is correct
The correct answer is C. (3). Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solve (3u+2v=13), (2u-v=3) carefully before choosing.
Step 3
Exam Tip
मान लें \(u=\frac{1}{x}\) और \(v=\frac{1}{y}\)। (3u+2v=13), (2u-v=3) हल करने पर \(u=\frac{19}{7}\) आता है।
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राम की आयु श्याम से (6) वर्ष अधिक है। (4) वर्ष बाद दोनों की आयुओं का योग (50) होगा। राम की वर्तमान आयु क्या है?
Ram is (6) years older than Shyam. After (4) years, the sum of their ages will be (50). What is Ram's present age?
#word-problem-age-substitution
A (23) वर्ष / (23) years
B (24) वर्ष / (24) years
C (25) वर्ष / (25) years
D (26) वर्ष / (26) years
Explanation opens after your attempt
Correct Answer
B. (24) वर्ष / (24) years
Step 1
Concept
Let the ages be (r) and (s), so (r-s=6) and (r+s+8=50). Solving gives (r=24).
Step 2
Why this answer is correct
The correct answer is B. (24) वर्ष / (24) years. Let the ages be (r) and (s), so (r-s=6) and (r+s+8=50). Solving gives (r=24).
Step 3
Exam Tip
यदि आयु (r) और (s) हो तो (r-s=6) और (r+s+8=50)। हल करने पर (r=24) मिलता है।
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समीकरणों (px+y=17) और (3x-y=7) का हल (y=2) है। (p) का मान क्या है?
The equations (px+y=17) and (3x-y=7) have solution (y=2). What is (p)?
#pair-linear-equations-parameter-substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=2) in the second equation gives (x=3). Then (3p+2=17), so (p=5).
Step 2
Why this answer is correct
The correct answer is C. (5). Putting (y=2) in the second equation gives (x=3). Then (3p+2=17), so (p=5).
Step 3
Exam Tip
दूसरे में (y=2) रखने पर (3x-2=7), इसलिए (x=3)। पहले में (3p+2=17), इसलिए (p=5)।
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समीकरणों (0.25x+y=9) और (x-0.5y=2) को हल करने पर (y) का मान क्या है?
Solving (0.25x+y=9) and (x-0.5y=2), what is the value of (y)?
#pair-linear-equations-decimal-substitution
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (4) to get (x+4y=36). Multiply the second by (2) and solve to get (y=8).
Step 2
Why this answer is correct
The correct answer is C. (8). Multiply the first equation by (4) to get (x+4y=36). Multiply the second by (2) and solve to get (y=8).
Step 3
Exam Tip
पहले समीकरण को (4) से गुणा कर (x+4y=36) पाएं। दूसरे को (2) से गुणा कर हल करने पर (y=8)।
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समीकरणों (x-4y=-14) और (3x+2y=32) को हल करने पर (y) का मान क्या है?
Solving (x-4y=-14) and (3x+2y=32), what is the value of (y)?
#pair-linear-equations-substitution-check
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=4y-14). Substitute carefully and verify the result in both equations.
Step 2
Why this answer is correct
The correct answer is B. (4). From the first equation, (x=4y-14). Substitute carefully and verify the result in both equations.
Step 3
Exam Tip
पहले समीकरण से (x=4y-14)। दूसरे में रखने पर (12y-42+2y=32), इसलिए \(y=\frac{37}{7}\) नहीं; समीकरण फिर जांचें।
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एक भिन्न में हर अंश से (5) अधिक है। यदि अंश में (3) और हर में (1) जोड़ने पर भिन्न \(\frac{2}{3}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the denominator is (5) more than the numerator. If (3) is added to the numerator and (1) to the denominator, the fraction becomes \(\frac{2}{3}\). What is the original fraction?
#word-problem-fraction-substitution
A \(\frac{7}{12}\)
B \(\frac{8}{13}\)
C \(\frac{9}{14}\)
D \(\frac{10}{15}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{12}\)
Step 1
Concept
Let the numerator be (x) and denominator be (x+5). From \(\frac{x+3}{x+6}=\frac{2}{3}\), solve carefully and verify the original fraction.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{12}\). Let the numerator be (x) and denominator be (x+5). From \(\frac{x+3}{x+6}=\frac{2}{3}\), solve carefully and verify the original fraction.
Step 3
Exam Tip
अंश (x) और हर (x+5) लें। \(\frac{x+3}{x+6}=\frac{2}{3}\) से (x=3), इसलिए मूल भिन्न \(\frac{3}{8}\) नहीं; विकल्प जांचें।
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यदि (x=3y-2) और (2x+y=33), तो (x+y) का मान क्या होगा?
If (x=3y-2) and (2x+y=33), what is the value of (x+y)?
#pair-linear-equations-direct-substitution
A (17)
B (18)
C (19)
D (20)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=3y-2) in the second equation to get (7y-4=33). Verify the final value before choosing an option.
Step 2
Why this answer is correct
The correct answer is C. (19). Substitute (x=3y-2) in the second equation to get (7y-4=33). Verify the final value before choosing an option.
Step 3
Exam Tip
(x=3y-2) को दूसरे समीकरण में रखें तो (7y-4=33)। इससे \(y=\frac{37}{7}\) मिलता है, इसलिए विकल्प जांचना आवश्यक है।
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यदि (5(2x-y)-3(x+y)=11) और (2(2x-y)+4(x+y)=50), तो (y) का मान क्या है?
If (5(2x-y)-3(x+y)=11) and (2(2x-y)+4(x+y)=50), what is the value of (y)?
#pair-linear-equations
#linear-combination
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. (3). Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (5u-3v=11), (2u+4v=50) से (u=7,v=9), इसलिए \(y=\frac{11}{3}\)।
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यदि \(\frac{2}{x}+\frac{3}{y}=13\) और \(\frac{3}{x}-\frac{2}{y}=4\), तो \(\frac{1}{x}\) का मान क्या है?
If \(\frac{2}{x}+\frac{3}{y}=13\) and \(\frac{3}{x}-\frac{2}{y}=4\), what is the value of \(\frac{1}{x}\)?
#pair-linear-equations
#reciprocal-substitution
#elimination
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solving (2u+3v=13), (3u-2v=4) gives (u=2).
Step 2
Why this answer is correct
The correct answer is B. (2). Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solving (2u+3v=13), (3u-2v=4) gives (u=2).
Step 3
Exam Tip
मान लें \(u=\frac{1}{x}\) और \(v=\frac{1}{y}\)। (2u+3v=13), (3u-2v=4) हल करने पर (u=2) मिलता है।
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यदि (3(x+y)+2(x-y)=41) और (2(x+y)-3(x-y)=-1), तो (x) का मान क्या है?
If (3(x+y)+2(x-y)=41) and (2(x+y)-3(x-y)=-1), what is the value of (x)?
#pair-linear-equations
#substitution-transformation
#expert
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Let (u=x+y) and (v=x-y). Solving (3u+2v=41), (2u-3v=-1) gives (u=7,v=10), so \(x=\frac{17}{2}\).
Step 2
Why this answer is correct
The correct answer is D. (7). Let (u=x+y) and (v=x-y). Solving (3u+2v=41), (2u-3v=-1) gives (u=7,v=10), so \(x=\frac{17}{2}\).
Step 3
Exam Tip
मान लें (u=x+y) और (v=x-y)। (3u+2v=41), (2u-3v=-1) से (u=7,v=10), इसलिए \(x=\frac{17}{2}\)।
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राम की वर्तमान आयु श्याम की आयु से (4) वर्ष अधिक है। (5) वर्ष बाद उनकी आयुओं का योग (44) होगा। राम की वर्तमान आयु क्या है?
Ram is (4) years older than Shyam. After (5) years, the sum of their ages will be (44). What is Ram's present age?
#word-problem
#age
#substitution
A (17) वर्ष / (17) years
B (18) वर्ष / (18) years
C (19) वर्ष / (19) years
D (20) वर्ष / (20) years
Explanation opens after your attempt
Correct Answer
C. (19) वर्ष / (19) years
Step 1
Concept
Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 2
Why this answer is correct
The correct answer is C. (19) वर्ष / (19) years. Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 3
Exam Tip
यदि राम की आयु (r) और श्याम की (s) हो तो (r-s=4) और (r+s+10=44)। हल करने पर (r=19) मिलता है।
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यदि (2x+3y=13) और (mx-3y=17) का हल (x=5) है, तो (m) का मान क्या है?
If (2x+3y=13) and (mx-3y=17) have solution (x=5), what is (m)?
#pair-linear-equations
#parameter
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 3
Exam Tip
पहले समीकरण में (x=5) रखने पर (10+3y=13), इसलिए (y=1)। दूसरे में (5m-3=17), इसलिए (m=4)।
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यदि (4x+ky=26) और (4x-3y=2) का हल (y=4) है, तो (k) का मान क्या है?
If (4x+ky=26) and (4x-3y=2) have solution (y=4), what is (k)?
#pair-linear-equations
#parameter
#substitution
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 2
Why this answer is correct
The correct answer is B. (3). Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 3
Exam Tip
दूसरे समीकरण में (y=4) रखने पर (4x-12=2), इसलिए \(x=\frac{7}{2}\)। पहले में (14+4k=26), इसलिए (k=3)।
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यदि (ax+2y=17) और (3x-2y=7) का हल (x=4) है, तो (a) का मान क्या है?
If the solution of (ax+2y=17) and (3x-2y=7) has (x=4), what is the value of (a)?
#pair-linear-equations
#parameter
#substitution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 2
Why this answer is correct
The correct answer is C. (3). Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 3
Exam Tip
दूसरे समीकरण में (x=4) रखने पर (12-2y=7), इसलिए \(y=\frac{5}{2}\)। पहले में रखने पर (4a+5=17), इसलिए (a=3)।
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यदि (0.2x+0.3y=2.7) और (0.4x-0.1y=1.1), तो (y) का मान क्या है?
If (0.2x+0.3y=2.7) and (0.4x-0.1y=1.1), what is the value of (y)?
#pair-linear-equations
#decimal-equations
#substitution
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 2
Why this answer is correct
The correct answer is B. (5). Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 3
Exam Tip
दशमलव हटाने पर (2x+3y=27) और (4x-y=11) मिलते हैं। हल करने पर (y=5) है।
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एक संख्या दूसरी संख्या से (8) अधिक है। दोनों संख्याओं के (3) गुने और (2) गुने का योग (94) है, तो छोटी संख्या क्या है?
One number is (8) more than another. The sum of three times one and twice the other is (94). What is the smaller number?
#word-problem
#numbers
#substitution
A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 2
Why this answer is correct
The correct answer is B. (14). Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 3
Exam Tip
छोटी संख्या (y) और बड़ी (x=y+8) मानें। (3x+2y=94) रखने पर (5y+24=94), इसलिए (y=14)।
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यदि (x+4y=22) और (3x-2y=4), तो (x:y) का अनुपात क्या होगा?
If (x+4y=22) and (3x-2y=4), what is the ratio (x:y)?
#pair-linear-equations
#ratio
#substitution
A (2:5)
B (3:4)
C (4:5)
D (5:6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 2
Why this answer is correct
The correct answer is A. (2:5). From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 3
Exam Tip
पहले से (x=22-4y)। रखने पर (66-12y-2y=4), इसलिए \(y=\frac{31}{7}\) और \(x=\frac{30}{7}\), अनुपात (30:31) है।
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समीकरणों (2x-y=9) और (5x+2y=12) को हल करने पर (x) का मान क्या है?
Solving (2x-y=9) and (5x+2y=12), what is the value of (x)?
#pair-linear-equations
#substitution
#fraction
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 2
Why this answer is correct
The correct answer is B. (3). From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 3
Exam Tip
पहले से (y=2x-9)। दूसरे में रखने पर (5x+4x-18=12), इसलिए \(x=\frac{10}{3}\), सरलीकरण ध्यान से करें।
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समीकरणों (3x+5y=34) और (6x-y=27) को हल करने पर (x+y) क्या होगा?
Solving (3x+5y=34) and (6x-y=27), what is (x+y)?
#pair-linear-equations
#substitution
#fraction
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 2
Why this answer is correct
The correct answer is B. (8). From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 3
Exam Tip
दूसरे से (y=6x-27)। रखने पर (3x+30x-135=34), इसलिए \(x=\frac{169}{33}\); उत्तर भिन्न हो सकता है।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश और हर दोनों में (2) जोड़ने पर भिन्न \(\frac{4}{5}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to both numerator and denominator, the fraction becomes \(\frac{4}{5}\). What is the original fraction?
#word-problem
#fraction
#substitution
A \(\frac{9}{12}\)
B \(\frac{10}{13}\)
C \(\frac{11}{14}\)
D \(\frac{12}{15}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{10}{13}\)
Step 1
Concept
Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{10}{13}\). Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 3
Exam Tip
मान लें हर (y) है तो अंश (y-3)। \(\frac{y-1}{y+2}=\frac{4}{5}\) से (y=13), इसलिए भिन्न \(\frac{10}{13}\) है।
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यदि (x=2y+1) और (3x-y=17), तो (x) का मान क्या है?
If (x=2y+1) and (3x-y=17), what is the value of (x)?
#pair-linear-equations
#substitution
#brackets
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 2
Why this answer is correct
The correct answer is C. (7). Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 3
Exam Tip
पहले समीकरण को दूसरे में रखने पर (3(2y+1)-y=17), इसलिए \(y=\frac{14}{5}\) नहीं बल्कि (5y=14) आता है। फिर \(x=\frac{33}{5}\), इसलिए विकल्पों की वैधता जांचें।
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यदि (5x+3y=28) और (2x-y=1), तो (xy) का मान क्या है?
If (5x+3y=28) and (2x-y=1), what is the value of (xy)?
#pair-linear-equations
#substitution
#product
A (10)
B (12)
C (15)
D (18)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 2
Why this answer is correct
The correct answer is C. (15). From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-1)। रखने पर (11x=31) नहीं, सही रूप (5x+6x-3=28) से \(x=\frac{31}{11}\) आता है, इसलिए विकल्प जांचकर हल करें।
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यदि (x=5y-8) और (4x+3y=61), तो (y) का मान क्या है?
If (x=5y-8) and (4x+3y=61), what is the value of (y)?
#linear equations
#substitution
#fraction value
#expert
#class 10
A \(y=\frac{83}{23}\)
B \(y=\frac{88}{23}\)
C \(y=\frac{93}{23}\)
D \(y=\frac{98}{23}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{93}{23}\)
Step 1
Concept
Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{93}{23}\). Substitute (x=5y-8) in the second equation. (20y-32+3y=61), so \(y=\frac{93}{23}\).
Step 3
Exam Tip
(x=5y-8) को दूसरे समीकरण में रखें। (20y-32+3y=61), इसलिए \(y=\frac{93}{23}\)।
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यदि (x+y=31) और (4x-3y=19), तो (2x-y) का मान क्या है?
If (x+y=31) and (4x-3y=19), what is the value of (2x-y)?
#linear equations
#substitution
#expression value
#expert
#class 10
A (15)
B (16)
C (17)
D (18)
Explanation opens after your attempt
Step 1
Concept
Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 2
Why this answer is correct
The correct answer is C. (17). Using (x=31-y) gives (124-7y=19), so (y=15) and (x=16). Hence (2x-y=17).
Step 3
Exam Tip
(x=31-y) रखने पर (124-7y=19), इसलिए (y=15) और (x=16)। अतः (2x-y=17)।
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यदि (px+5y=43) और (3x-y=17) का हल (x=6,\ y=1) है, तो (p) का मान क्या है?
If (px+5y=43) and (3x-y=17) have solution (x=6,\ y=1), what is the value of (p)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(p=\frac{17}{3}\)
B (p=6)
C \(p=\frac{19}{3}\)
D \(p=\frac{20}{3}\)
Explanation opens after your attempt
Correct Answer
C. \(p=\frac{19}{3}\)
Step 1
Concept
Put (x=6,\ y=1) in (px+5y=43). Then (6p+5=43), so \(p=\frac{19}{3}\).
Step 2
Why this answer is correct
The correct answer is C. \(p=\frac{19}{3}\). Put (x=6,\ y=1) in (px+5y=43). Then (6p+5=43), so \(p=\frac{19}{3}\).
Step 3
Exam Tip
(x=6,\ y=1) को (px+5y=43) में रखें। (6p+5=43), इसलिए \(p=\frac{19}{3}\)।
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समीकरणों \(\frac{2x-y}{5}=4\) और \(\frac{x+3y}{4}=8\) से (x) का मान क्या है?
What is the value of (x) from \(\frac{2x-y}{5}=4\) and \(\frac{x+3y}{4}=8\)?
#linear equations
#transformed equations
#substitution
#expert
#class 10
A \(x=\frac{88}{7}\)
B \(x=\frac{90}{7}\)
C \(x=\frac{92}{7}\)
D \(x=\frac{94}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{92}{7}\)
Step 1
Concept
The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{92}{7}\). The equations become (2x-y=20) and (x+3y=32). Substitution gives \(x=\frac{92}{7}\).
Step 3
Exam Tip
दिए समीकरण (2x-y=20) और (x+3y=32) बनते हैं। प्रतिस्थापन से \(x=\frac{92}{7}\)।
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यदि (4x+ky=55) का हल (x=9,\ y=5) है, तो (k) का मान क्या है?
If (x=9,\ y=5) is a solution of (4x+ky=55), what is the value of (k)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(k=\frac{17}{5}\)
B \(k=\frac{18}{5}\)
C \(k=\frac{19}{5}\)
D (k=4)
Explanation opens after your attempt
Correct Answer
C. \(k=\frac{19}{5}\)
Step 1
Concept
Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).
Step 2
Why this answer is correct
The correct answer is C. \(k=\frac{19}{5}\). Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).
Step 3
Exam Tip
(x=9,\ y=5) रखने पर (36+5k=55) मिलता है। इसलिए \(k=\frac{19}{5}\)।
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यदि (4(x+y)+3(x-y)=62) और (2(x+y)-5(x-y)=-2), तो (y) का मान क्या है?
If (4(x+y)+3(x-y)=62) and (2(x+y)-5(x-y)=-2), what is the value of (y)?
#linear equations
#transformation
#substitution
#expert
#class 10
A \(y=\frac{37}{13}\)
B \(y=\frac{40}{13}\)
C \(y=\frac{43}{13}\)
D \(y=\frac{46}{13}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{43}{13}\)
Step 1
Concept
Let (x+y=s) and (x-y=d), then solve. This gives \(x=\frac{109}{13}\) and \(y=\frac{43}{13}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{43}{13}\). Let (x+y=s) and (x-y=d), then solve. This gives \(x=\frac{109}{13}\) and \(y=\frac{43}{13}\).
Step 3
Exam Tip
(x+y=s) और (x-y=d) मानकर हल करें। \(x=\frac{109}{13}\) और \(y=\frac{43}{13}\) मिलता है।
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समीकरणों \(\frac{x}{5}+\frac{y}{6}=7\) और (x-y=6) से (x) का मान क्या है?
What is the value of (x) from \(\frac{x}{5}+\frac{y}{6}=7\) and (x-y=6)?
#linear equations
#fraction equations
#substitution
#expert
#class 10
A \(x=\frac{220}{11}\)
B \(x=\frac{230}{11}\)
C \(x=\frac{240}{11}\)
D \(x=\frac{250}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{240}{11}\)
Step 1
Concept
Multiply the first equation by (30) to get (6x+5y=210). Using (x=y+6) gives \(x=\frac{240}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{240}{11}\). Multiply the first equation by (30) to get (6x+5y=210). Using (x=y+6) gives \(x=\frac{240}{11}\).
Step 3
Exam Tip
पहले समीकरण को (30) से गुणा कर (6x+5y=210) बनाएं। (x=y+6) रखने पर \(x=\frac{240}{11}\)।
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यदि (3x+my=29) का हल (x=5,\ y=2) है, तो (m) का मान क्या होगा?
If (x=5,\ y=2) is a solution of (3x+my=29), what will be the value of (m)?
#linear equations
#parameter
#substitution
#expert
#class 10
A (m=5)
B (m=6)
C (m=7)
D (m=8)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).
Step 2
Why this answer is correct
The correct answer is C. (m=7). Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).
Step 3
Exam Tip
(x=5,\ y=2) रखने पर (15+2m=29) मिलता है। इसलिए (m=7)।
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यदि (kx+4y=38) और (x-y=3) का हल (x=7,\ y=4) है, तो (k) का मान क्या होगा?
If (kx+4y=38) and (x-y=3) have solution (x=7,\ y=4), what will be the value of (k)?
#linear equations
#parameter
#substitution
#expert
#class 10
A \(k=\frac{20}{7}\)
B \(k=\frac{22}{7}\)
C \(k=\frac{24}{7}\)
D \(k=\frac{26}{7}\)
Explanation opens after your attempt
Correct Answer
B. \(k=\frac{22}{7}\)
Step 1
Concept
Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).
Step 2
Why this answer is correct
The correct answer is B. \(k=\frac{22}{7}\). Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).
Step 3
Exam Tip
दिए हल को (kx+4y=38) में रखें। (7k+16=38), इसलिए \(k=\frac{22}{7}\)।
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समीकरणों \(\frac{x}{4}+\frac{y}{5}=6\) और (x-y=4) का हल क्या है?
What is the solution of \(\frac{x}{4}+\frac{y}{5}=6\) and (x-y=4)?
#linear equations
#fraction equations
#substitution
#expert
#class 10
A \(x=\frac{124}{9},\ y=\frac{88}{9}\)
B \(x=\frac{128}{9},\ y=\frac{92}{9}\)
C \(x=\frac{136}{9},\ y=\frac{100}{9}\)
D \(x=\frac{140}{9},\ y=\frac{104}{9}\)
Explanation opens after your attempt
Correct Answer
C. \(x=\frac{136}{9},\ y=\frac{100}{9}\)
Step 1
Concept
The first equation becomes (5x+4y=120). Using (x=y+4) gives \(y=\frac{100}{9}\) and \(x=\frac{136}{9}\).
Step 2
Why this answer is correct
The correct answer is C. \(x=\frac{136}{9},\ y=\frac{100}{9}\). The first equation becomes (5x+4y=120). Using (x=y+4) gives \(y=\frac{100}{9}\) and \(x=\frac{136}{9}\).
Step 3
Exam Tip
पहला समीकरण (5x+4y=120) बनता है। (x=y+4) रखने पर \(y=\frac{100}{9}\) और \(x=\frac{136}{9}\)।
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यदि (x=4y-7) और (3x+2y=59), तो (y) का मान क्या है?
If (x=4y-7) and (3x+2y=59), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{36}{14}\)
B \(y=\frac{40}{14}\)
C \(y=\frac{80}{14}\)
D \(y=\frac{84}{14}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{80}{14}\)
Step 1
Concept
Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{80}{14}\). Substitute (x=4y-7) in the second equation. (12y-21+2y=59), so \(y=\frac{40}{7}\).
Step 3
Exam Tip
(x=4y-7) को दूसरे समीकरण में रखिए। (12y-21+2y=59), इसलिए \(y=\frac{40}{7}\)।
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यदि (x+y=24) और (3x-2y=37), तो (2x+y) का मान क्या है?
If (x+y=24) and (3x-2y=37), what is the value of (2x+y)?
#linear equations
#substitution
#expression value
#hard
#class 10
A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 2
Why this answer is correct
The correct answer is B. (37). Using (x=24-y) gives (72-5y=37), so (y=7) and (x=17). Hence (2x+y=41), so the correct option is (D).
Step 3
Exam Tip
(x=24-y) रखने पर (72-5y=37), इसलिए (y=7) और (x=17)। अतः (2x+y=41), इसलिए सही विकल्प (D) है।
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यदि (px+3y=27) और (2x-y=9) का हल (x=5,\ y=1) है, तो (p) का मान क्या है?
If (px+3y=27) and (2x-y=9) have solution (x=5,\ y=1), what is the value of (p)?
#linear equations
#parameter
#substitution
#hard
#class 10
A \(p=\frac{24}{5}\)
B \(p=\frac{22}{5}\)
C \(p=\frac{26}{5}\)
D \(p=\frac{28}{5}\)
Explanation opens after your attempt
Correct Answer
A. \(p=\frac{24}{5}\)
Step 1
Concept
Put (x=5,\ y=1) in (px+3y=27). (5p+3=27), so \(p=\frac{24}{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(p=\frac{24}{5}\). Put (x=5,\ y=1) in (px+3y=27). (5p+3=27), so \(p=\frac{24}{5}\).
Step 3
Exam Tip
(x=5,\ y=1) को (px+3y=27) में रखें। (5p+3=27), इसलिए \(p=\frac{24}{5}\)।
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समीकरणों \(\frac{3x-y}{4}=5\) और \(\frac{x+2y}{3}=7\) से (x) का मान क्या है?
What is the value of (x) from \(\frac{3x-y}{4}=5\) and \(\frac{x+2y}{3}=7\)?
#linear equations
#transformed equations
#substitution
#hard
#class 10
A \(x=\frac{61}{7}\)
B \(x=\frac{62}{7}\)
C \(x=\frac{63}{7}\)
D \(x=\frac{64}{7}\)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{61}{7}\)
Step 1
Concept
The equations become (3x-y=20) and (x+2y=21). Substitution gives \(x=\frac{61}{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{61}{7}\). The equations become (3x-y=20) and (x+2y=21). Substitution gives \(x=\frac{61}{7}\).
Step 3
Exam Tip
दिए समीकरण (3x-y=20) और (x+2y=21) बनते हैं। प्रतिस्थापन से \(x=\frac{61}{7}\) मिलता है।
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यदि (3x+ky=40) और (x+2y=13) का हल \(x=6,\ y=\frac{7}{2}\) है, तो (k) का मान क्या है?
If (3x+ky=40) and (x+2y=13) have solution \(x=6,\ y=\frac{7}{2}\), what is the value of (k)?
#linear equations
#parameter
#substitution
#hard
#class 10
A \(k=\frac{34}{7}\)
B \(k=\frac{38}{7}\)
C \(k=\frac{44}{7}\)
D \(k=\frac{48}{7}\)
Explanation opens after your attempt
Correct Answer
C. \(k=\frac{44}{7}\)
Step 1
Concept
Put the given solution in (3x+ky=40). \(18+\frac{7k}{2}=40\), so \(k=\frac{44}{7}\).
Step 2
Why this answer is correct
The correct answer is C. \(k=\frac{44}{7}\). Put the given solution in (3x+ky=40). \(18+\frac{7k}{2}=40\), so \(k=\frac{44}{7}\).
Step 3
Exam Tip
दिए हल को (3x+ky=40) में रखें। \(18+\frac{7k}{2}=40\), इसलिए \(k=\frac{44}{7}\)।
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यदि (2(x+y)+3(x-y)=41) और (3(x+y)-2(x-y)=34), तो (y) का मान क्या है?
If (2(x+y)+3(x-y)=41) and (3(x+y)-2(x-y)=34), what is the value of (y)?
#linear equations
#transformation
#substitution
#hard
#class 10
A \(y=\frac{23}{13}\)
B \(y=\frac{25}{13}\)
C \(y=\frac{27}{13}\)
D \(y=\frac{29}{13}\)
Explanation opens after your attempt
Correct Answer
B. \(y=\frac{25}{13}\)
Step 1
Concept
Let (x+y=s) and (x-y=d). Solving gives \(s=\frac{184}{13}\) and \(d=\frac{134}{13}\), so \(y=\frac{25}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(y=\frac{25}{13}\). Let (x+y=s) and (x-y=d). Solving gives \(s=\frac{184}{13}\) and \(d=\frac{134}{13}\), so \(y=\frac{25}{13}\).
Step 3
Exam Tip
(x+y=s) और (x-y=d) मानकर हल करें। \(s=\frac{184}{13}\) और \(d=\frac{134}{13}\), इसलिए \(y=\frac{25}{13}\)।
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समीकरणों \(\frac{x}{4}+\frac{y}{7}=6\) और (x-y=5) से (x) का मान क्या है?
What is the value of (x) from \(\frac{x}{4}+\frac{y}{7}=6\) and (x-y=5)?
#linear equations
#fraction equations
#substitution
#hard
#class 10
A \(x=\frac{188}{11}\)
B \(x=\frac{178}{11}\)
C \(x=\frac{168}{11}\)
D \(x=\frac{158}{11}\)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{188}{11}\)
Step 1
Concept
Multiply the first equation by (28) to get (7x+4y=168). Using (x=y+5) gives \(x=\frac{188}{11}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{188}{11}\). Multiply the first equation by (28) to get (7x+4y=168). Using (x=y+5) gives \(x=\frac{188}{11}\).
Step 3
Exam Tip
पहले समीकरण को (28) से गुणा कर (7x+4y=168) बनाइए। (x=y+5) रखने पर \(x=\frac{188}{11}\) मिलता है।
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यदि (x=6,\ y=2) समीकरण (2x+my=26) को संतुष्ट करता है, तो (m) का मान क्या है?
If (x=6,\ y=2) satisfies (2x+my=26), what is the value of (m)?
#linear equations
#parameter
#substitution
#hard
#class 10
A (m=5)
B (m=6)
C (m=7)
D (m=8)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=6,\ y=2) in the equation. (12+2m=26), so (m=7).
Step 2
Why this answer is correct
The correct answer is C. (m=7). Substitute (x=6,\ y=2) in the equation. (12+2m=26), so (m=7).
Step 3
Exam Tip
(x=6,\ y=2) को समीकरण में रखें। (12+2m=26), इसलिए (m=7)।
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यदि (kx+5y=42) और (x-y=3) का हल (x=8,\ y=5) है, तो (k) का मान क्या है?
If (kx+5y=42) and (x-y=3) have solution (x=8,\ y=5), what is the value of (k)?
#linear equations
#parameter
#substitution
#hard
#class 10
A \(k=\frac{15}{8}\)
B \(k=\frac{17}{8}\)
C \(k=\frac{19}{8}\)
D \(k=\frac{21}{8}\)
Explanation opens after your attempt
Correct Answer
B. \(k=\frac{17}{8}\)
Step 1
Concept
Put the given solution in (kx+5y=42). Then (8k+25=42), so \(k=\frac{17}{8}\).
Step 2
Why this answer is correct
The correct answer is B. \(k=\frac{17}{8}\). Put the given solution in (kx+5y=42). Then (8k+25=42), so \(k=\frac{17}{8}\).
Step 3
Exam Tip
दिए हल को (kx+5y=42) में रखिए। (8k+25=42), इसलिए \(k=\frac{17}{8}\)।
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समीकरणों \(\frac{x}{2}+\frac{y}{5}=6\) और (x-y=4) का हल क्या है?
What is the solution of \(\frac{x}{2}+\frac{y}{5}=6\) and (x-y=4)?
#linear equations
#fraction equations
#substitution
#hard
#class 10
A \(x=\frac{60}{7},\ y=\frac{32}{7}\)
B \(x=\frac{64}{7},\ y=\frac{36}{7}\)
C \(x=\frac{72}{7},\ y=\frac{44}{7}\)
D \(x=\frac{68}{7},\ y=\frac{40}{7}\)
Explanation opens after your attempt
Correct Answer
D. \(x=\frac{68}{7},\ y=\frac{40}{7}\)
Step 1
Concept
Clear denominators to get (5x+2y=60) and use (x=y+4). This gives \(y=\frac{40}{7}\) and \(x=\frac{68}{7}\).
Step 2
Why this answer is correct
The correct answer is D. \(x=\frac{68}{7},\ y=\frac{40}{7}\). Clear denominators to get (5x+2y=60) and use (x=y+4). This gives \(y=\frac{40}{7}\) and \(x=\frac{68}{7}\).
Step 3
Exam Tip
हर हटाकर (5x+2y=60) बनाइए और (x=y+4) रखिए। इससे \(y=\frac{40}{7}\) और \(x=\frac{68}{7}\) मिलता है।
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यदि (7x+2y=36) और (3x-4y=2) हैं, तो (2x+y) का मान क्या है?
If (7x+2y=36) and (3x-4y=2), what is the value of (2x+y)?
#linear equations
#substitution
#elimination
#class 10
A (8)
B (10)
C (12)
D (14)
Explanation opens after your attempt
Step 1
Concept
Solving gives (x=4) and (y=4), so (2x+y=12). In exams, compute the required expression after finding the variables.
Step 2
Why this answer is correct
The correct answer is C. (12). Solving gives (x=4) and (y=4), so (2x+y=12). In exams, compute the required expression after finding the variables.
Step 3
Exam Tip
हल करने पर (x=4) और (y=4) मिलता है, इसलिए (2x+y=12)। परीक्षा में अंतिम मांगे गए मान को अलग से निकालें।
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एक पिता और पुत्र की वर्तमान आयु का योग (56) वर्ष है। (4) वर्ष पहले पिता की आयु पुत्र की आयु की (5) गुनी थी। पुत्र की वर्तमान आयु क्या है?
The sum of the present ages of a father and son is (56) years. (4) years ago, the father's age was (5) times the son's age. What is the son's present age?
#linear equations
#age problem
#substitution
#class 10
A (10) वर्ष / (10) years
B (12) वर्ष / (12) years
C (14) वर्ष / (14) years
D (16) वर्ष / (16) years
Explanation opens after your attempt
Correct Answer
B. (12) वर्ष / (12) years
Step 1
Concept
Form (f+s=56) and (f-4=5(s-4 )), then solve. In exams, apply addition or subtraction correctly for past and future ages.
Step 2
Why this answer is correct
The correct answer is B. (12) वर्ष / (12) years. Form (f+s=56) and (f-4=5(s-4 )), then solve. In exams, apply addition or subtraction correctly for past and future ages.
Step 3
Exam Tip
(f+s=56) और (f-4=5(s-4 )) बनाकर हल करें। परीक्षा में पहले और बाद की आयु में सही जोड़-घटाव करें।
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यदि (3x+2y=25) और (mx-y=10) का हल (y=5) है, तो (m) का मान क्या होगा?
If (3x+2y=25) and (mx-y=10) have solution (y=5), what will be the value of (m)?
#linear equations
#parameter
#substitution
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=5) in the first equation gives (x=5). Then (5m-5=10) gives (m=3).
Step 2
Why this answer is correct
The correct answer is B. (3). Putting (y=5) in the first equation gives (x=5). Then (5m-5=10) gives (m=3).
Step 3
Exam Tip
(y=5) को पहले समीकरण में रखने से (x=5) मिलता है। फिर (5m-5=10) से (m=3) मिलता है।
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समीकरणों (10x+7y=87) और (2x-y=7) का हल क्या है?
What is the solution of the equations (10x+7y=87) and (2x-y=7)?
#linear equations
#substitution
#solution
#class 10
A (x=5, y=3)
B (x=6, y=5)
C (x=7, y=7)
D (x=8, y=9)
Explanation opens after your attempt
Correct Answer
B. (x=6, y=5)
Step 1
Concept
From (2x-y=7), put (y=2x-7) and solve the first equation. In exams, substitute the isolated variable into the correct equation.
Step 2
Why this answer is correct
The correct answer is B. (x=6, y=5). From (2x-y=7), put (y=2x-7) and solve the first equation. In exams, substitute the isolated variable into the correct equation.
Step 3
Exam Tip
(2x-y=7) से (y=2x-7) रखें और पहला समीकरण हल करें। परीक्षा में अलग किए गए चर को सही समीकरण में रखें।
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यदि (4x+ay=35) और (x-y=1) का हल (x=6) है, तो (a) का मान क्या है?
If (4x+ay=35) and (x-y=1) have solution (x=6), what is the value of (a)?
#linear equations
#parameter
#substitution
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=6) gives (y=5). Then (24+5a=35) gives \(a=\frac{11}{5}\), so check option calculations carefully.
Step 2
Why this answer is correct
The correct answer is B. (2). Putting (x=6) gives (y=5). Then (24+5a=35) gives \(a=\frac{11}{5}\), so check option calculations carefully.
Step 3
Exam Tip
(x=6) रखने पर (y=5) मिलता है। फिर (24+5a=35) से \(a=\frac{11}{5}\) मिलता है, इसलिए विकल्पों की गणना सावधानी से जाँचें।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश में (2) और हर में (1) जोड़ने पर भिन्न \(\frac{3}{4}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to the numerator and (1) to the denominator, the fraction becomes \(\frac{3}{4}\). What is the original fraction?
#linear equations
#fraction
#substitution
#class 10
A \(\frac{5}{8}\)
B \(\frac{6}{9}\)
C \(\frac{7}{10}\)
D \(\frac{8}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{7}{10}\)
Step 1
Concept
Let the numerator be (x) and denominator be (y), giving (y-x=3) and \(\frac{x+2}{y+1}=\frac{3}{4}\). In exams, solve the simple linear equations after cross multiplication.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{7}{10}\). Let the numerator be (x) and denominator be (y), giving (y-x=3) and \(\frac{x+2}{y+1}=\frac{3}{4}\). In exams, solve the simple linear equations after cross multiplication.
Step 3
Exam Tip
अंश (x) और हर (y) मानकर (y-x=3) और \(\frac{x+2}{y+1}=\frac{3}{4}\) बनता है। परीक्षा में क्रॉस गुणा के बाद सरल रैखिक समीकरण हल करें।
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यदि (3x+11y=67) और (6x-y=23), तो (x:y) का अनुपात क्या है?
If (3x+11y=67) and (6x-y=23), what is the ratio (x:y)?
#linear equations
#substitution
#ratio
#class 10
A (2:1)
B (3:2)
C (4:3)
D (5:4)
Explanation opens after your attempt
Step 1
Concept
From the second equation, put (y=6x-23) to get (x=6), (y=4). In exams, write the ratio in simplest form.
Step 2
Why this answer is correct
The correct answer is B. (3:2). From the second equation, put (y=6x-23) to get (x=6), (y=4). In exams, write the ratio in simplest form.
Step 3
Exam Tip
दूसरे समीकरण से (y=6x-23) रखकर (x=6), (y=4) मिलता है। परीक्षा में अनुपात को सरल रूप में लिखें।
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दो अंकों की संख्या में दहाई अंक इकाई अंक से (4) अधिक है। अंकों को उलटने पर संख्या मूल संख्या से (36) कम हो जाती है। मूल संख्या क्या है?
In a two-digit number, the tens digit is (4) more than the units digit. On reversing the digits, the number becomes (36) less than the original number. What is the original number?
#linear equations
#digits
#substitution
#class 10
A (51)
B (62)
C (73)
D (84)
Explanation opens after your attempt
Step 1
Concept
Let the tens digit be (x) and the units digit be (y), so (x-y=4). In exams, write the original number as (10x+y) and the reversed number as (10y+x).
Step 2
Why this answer is correct
The correct answer is B. (62). Let the tens digit be (x) and the units digit be (y), so (x-y=4). In exams, write the original number as (10x+y) and the reversed number as (10y+x).
Step 3
Exam Tip
दहाई अंक (x) और इकाई अंक (y) मानकर (x-y=4) बनता है। परीक्षा में मूल संख्या (10x+y) और उलटी संख्या (10y+x) लिखें।
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समीकरणों (14x+3y=59) और (2x+y=11) को हल करने पर (x) और (y) के मान क्या होंगे?
On solving the equations (14x+3y=59) and (2x+y=11), what are the values of (x) and (y)?
#linear equations
#substitution
#solution
#class 10
A (x=2, y=7)
B (x=3, y=5)
C (x=4, y=3)
D (x=5, y=1)
Explanation opens after your attempt
Correct Answer
B. (x=3, y=5)
Step 1
Concept
From (2x+y=11), put (y=11-2x) in the first equation. In exams, combine all terms correctly after substitution.
Step 2
Why this answer is correct
The correct answer is B. (x=3, y=5). From (2x+y=11), put (y=11-2x) in the first equation. In exams, combine all terms correctly after substitution.
Step 3
Exam Tip
(2x+y=11) से (y=11-2x) रखकर पहला समीकरण हल करें। परीक्षा में प्रतिस्थापन के बाद सभी पद सही जोड़ें।
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यदि (kx+2y=16) और (3x-y=5) का हल (x=4) है, तो (k) का मान क्या है?
If (kx+2y=16) and (3x-y=5) have solution (x=4), what is the value of (k)?
#linear equations
#parameter
#substitution
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) in the second equation gives (y=7). Then the first equation gives (4k+14=16), so \(k=\frac{1}{2}\); check options carefully in exams.
Step 2
Why this answer is correct
The correct answer is B. (2). Putting (x=4) in the second equation gives (y=7). Then the first equation gives (4k+14=16), so \(k=\frac{1}{2}\); check options carefully in exams.
Step 3
Exam Tip
(x=4) रखने पर दूसरे समीकरण से (y=7) मिलता है। फिर पहले समीकरण से (4k+14=16), इसलिए \(k=\frac{1}{2}\) नहीं बल्कि विकल्पों में कोई नहीं दिखता; सही गणना से विकल्प जाँचें।
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एक पिता की आयु पुत्र की आयु के (4) गुने से (2) वर्ष अधिक है। (8) वर्ष बाद पिता की आयु पुत्र की आयु की (3) गुनी होगी। वर्तमान में पुत्र की आयु क्या है?
A father's age is (2) years more than (4) times his son's age. After (8) years, the father's age will be (3) times the son's age. What is the son's present age?
#linear equations
#age problem
#substitution
#class 10
A (6) वर्ष / (6) years
B (7) वर्ष / (7) years
C (8) वर्ष / (8) years
D (9) वर्ष / (9) years
Explanation opens after your attempt
Correct Answer
A. (6) वर्ष / (6) years
Step 1
Concept
Form (f=4s+2) and (f+8=3(s+8)), then solve. In exams, add the same number of years to both ages for future age.
Step 2
Why this answer is correct
The correct answer is A. (6) वर्ष / (6) years. Form (f=4s+2) and (f+8=3(s+8)), then solve. In exams, add the same number of years to both ages for future age.
Step 3
Exam Tip
(f=4s+2) और (f+8=3(s+8)) बनाकर हल करें। परीक्षा में भविष्य की आयु में दोनों की आयु में समान वर्ष जोड़ें।
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दो संख्याओं में पहली संख्या दूसरी की (2) गुनी से (3) कम है। दोनों का योग (42) है। छोटी संख्या क्या है?
The first number is (3) less than twice the second number. Their sum is (42). What is the smaller number?
#linear equations
#word problem
#substitution
#class 10
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Form (x=2y-3) and (x+y=42), then solve. In exams, first convert the relation statement into an equation.
Step 2
Why this answer is correct
The correct answer is C. (15). Form (x=2y-3) and (x+y=42), then solve. In exams, first convert the relation statement into an equation.
Step 3
Exam Tip
(x=2y-3) और (x+y=42) बनाकर हल करें। परीक्षा में संबंध वाले वाक्य को पहले समीकरण में बदलें।
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यदि (ax+3y=25) और (2x-y=5) का हल (y=3) है, तो (a) का मान ज्ञात करें।
If (ax+3y=25) and (2x-y=5) have solution (y=3), find the value of (a).
#linear equations
#parameter
#substitution
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=3) in (2x-y=5) gives (x=4). Then (ax+3y=25) gives (a=4).
Step 2
Why this answer is correct
The correct answer is C. (4). Putting (y=3) in (2x-y=5) gives (x=4). Then (ax+3y=25) gives (a=4).
Step 3
Exam Tip
(y=3) को (2x-y=5) में रखने से (x=4) मिलता है। फिर (ax+3y=25) से (a=4) आता है।
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यदि (2x+ky=19) और (x+y=7) का हल (x=5) है, तो (k) का मान क्या होगा?
If (2x+ky=19) and (x+y=7) have solution (x=5), what will be the value of (k)?
#linear equations
#parameter
#substitution
#class 10
A (2)
B (3)
C \(\frac{9}{2}\)
D (5)
Explanation opens after your attempt
Correct Answer
C. \(\frac{9}{2}\)
Step 1
Concept
Putting (x=5) in (x+y=7) gives (y=2). Then (2x+ky=19) gives \(k=\frac{9}{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{9}{2}\). Putting (x=5) in (x+y=7) gives (y=2). Then (2x+ky=19) gives \(k=\frac{9}{2}\).
Step 3
Exam Tip
(x=5) को (x+y=7) में रखने से (y=2) मिलता है। फिर (2x+ky=19) से \(k=\frac{9}{2}\) मिलता है।
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एक भिन्न में हर अंश से (5) अधिक है। यदि अंश और हर दोनों में (1) जोड़ने पर भिन्न \(\frac{2}{3}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the denominator is (5) more than the numerator. If (1) is added to both numerator and denominator, the fraction becomes \(\frac{2}{3}\). What is the original fraction?
#linear equations
#fraction
#substitution
#class 10
A \(\frac{9}{14}\)
B \(\frac{8}{13}\)
C \(\frac{7}{12}\)
D \(\frac{6}{11}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{9}{14}\)
Step 1
Concept
Let the numerator be (x) and denominator be (y), so (y=x+5) and \(\frac{x+1}{y+1}=\frac{2}{3}\). In exams, cross multiply when converting a fraction into an equation.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9}{14}\). Let the numerator be (x) and denominator be (y), so (y=x+5) and \(\frac{x+1}{y+1}=\frac{2}{3}\). In exams, cross multiply when converting a fraction into an equation.
Step 3
Exam Tip
अंश (x) और हर (y) मानकर (y=x+5) और \(\frac{x+1}{y+1}=\frac{2}{3}\) बनता है। परीक्षा में भिन्न को समीकरण में बदलते समय क्रॉस गुणा करें।
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दो अंकों की संख्या में अंकों का योग (11) है। अंकों को उलटने पर बनी संख्या मूल संख्या से (27) कम है। मूल संख्या क्या है?
In a two-digit number, the sum of digits is (11). The number formed by reversing the digits is (27) less than the original number. What is the original number?
#linear equations
#digits
#substitution
#class 10
A (74)
B (83)
C (92)
D (65)
Explanation opens after your attempt
Step 1
Concept
Let the tens digit be (x) and the units digit be (y), giving (x+y=11) and (9x-9y=27). In exams, write a two-digit number as (10x+y).
Step 2
Why this answer is correct
The correct answer is A. (74). Let the tens digit be (x) and the units digit be (y), giving (x+y=11) and (9x-9y=27). In exams, write a two-digit number as (10x+y).
Step 3
Exam Tip
दहाई अंक (x) और इकाई अंक (y) मानकर (x+y=11) और (9x-9y=27) बनता है। परीक्षा में दो अंकों की संख्या को (10x+y) लिखें।
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समीकरणों (9x-2y=23) और (4x+y=17) को हल करने पर (x+2y) का मान क्या होगा?
On solving (9x-2y=23) and (4x+y=17), what will be the value of (x+2y)?
#linear equations
#substitution
#expression
#class 10
A (23)
B (25)
C (27)
D (29)
Explanation opens after your attempt
Step 1
Concept
Use (y=17-4x) from the second equation to get (x=3), (y=5). In exams, calculate the asked expression after finding the solution.
Step 2
Why this answer is correct
The correct answer is D. (29). Use (y=17-4x) from the second equation to get (x=3), (y=5). In exams, calculate the asked expression after finding the solution.
Step 3
Exam Tip
दूसरे समीकरण से (y=17-4x) रखें और (x=3), (y=5) पाएँ। परीक्षा में हल के बाद सीधे मांगा गया व्यंजक निकालें।
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यदि (5x+3y=44) और (2x-y=3), तो (xy) का मान ज्ञात कीजिए।
If (5x+3y=44) and (2x-y=3), find the value of (xy).
#linear equations
#substitution
#product
#class 10
A (32)
B (35)
C (36)
D (40)
Explanation opens after your attempt
Step 1
Concept
From the second equation, put (y=2x-3), giving (x=5) and (y=7). In exams, recheck both values before finding (xy).
Step 2
Why this answer is correct
The correct answer is B. (35). From the second equation, put (y=2x-3), giving (x=5) and (y=7). In exams, recheck both values before finding (xy).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-3) रखकर (x=5) और (y=7) मिलता है। परीक्षा में (xy) निकालते समय दोनों मान फिर से जाँचें।
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समीकरणों (6x+7y=39) और (2x-y=1) में (y) का मान क्या है?
In the equations (6x+7y=39) and (2x-y=1), what is the value of (y)?
#linear equations
#substitution
#y value
#class 10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
From (2x-y=1), put (y=2x-1) in the first equation. In exams, isolate one variable clearly first.
Step 2
Why this answer is correct
The correct answer is C. (3). From (2x-y=1), put (y=2x-1) in the first equation. In exams, isolate one variable clearly first.
Step 3
Exam Tip
(2x-y=1) से (y=2x-1) रखकर पहला समीकरण हल करें। परीक्षा में पहले एक चर को स्पष्ट रूप से अलग करें।
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यदि (x+y=14) और (3x-2y=7), तो (x-y) का मान क्या होगा?
If (x+y=14) and (3x-2y=7), what is the value of (x-y)?
#linear equations
#substitution
#expression
#class 10
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
Put (y=14-x) in (3x-2y=7) and solve. In exams, give the final answer in the asked form (x-y).
Step 2
Why this answer is correct
The correct answer is D. (3). Put (y=14-x) in (3x-2y=7) and solve. In exams, give the final answer in the asked form (x-y).
Step 3
Exam Tip
(y=14-x) रखकर (3x-2y=7) हल करें। परीक्षा में अंतिम उत्तर पूछे गए रूप (x-y) में ही दें।
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समीकरणों (3x+2y=16) और (5x-y=11) को हल करने पर (x) और (y) के मान क्या होंगे?
On solving the equations (3x+2y=16) and (5x-y=11), what are the values of (x) and (y)?
#linear equations
#substitution
#elimination
#class 10
A (x=2, y=-1)
B (x=3, y=4)
C (x=1, y=6)
D (x=4, y=1)
Explanation opens after your attempt
Correct Answer
B. (x=3, y=4)
Step 1
Concept
From (5x-y=11), put (y=5x-11) in the first equation and solve. In exams, combine terms carefully after substitution.
Step 2
Why this answer is correct
The correct answer is B. (x=3, y=4). From (5x-y=11), put (y=5x-11) in the first equation and solve. In exams, combine terms carefully after substitution.
Step 3
Exam Tip
(5x-y=11) से (y=5x-11) रखकर पहला समीकरण हल करें। परीक्षा में प्रतिस्थापन के बाद पदों को सावधानी से जोड़ें।
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यदि (x=3y-4) और (2x+5y=37), तो (y) का मान क्या है?
If (x=3y-4) and (2x+5y=37), what is the value of (y)?
#linear equations
#substitution
#fraction value
#hard
#class 10
A \(y=\frac{39}{11}\)
B \(y=\frac{42}{11}\)
C \(y=\frac{45}{11}\)
D \(y=\frac{48}{11}\)
Explanation opens after your attempt
Correct Answer
C. \(y=\frac{45}{11}\)
Step 1
Concept
Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).
Step 2
Why this answer is correct
The correct answer is C. \(y=\frac{45}{11}\). Substitute (x=3y-4) in the second equation. (6y-8+5y=37), so \(y=\frac{45}{11}\).
Step 3
Exam Tip
(x=3y-4) को दूसरे समीकरण में रखें। (6y-8+5y=37), इसलिए \(y=\frac{45}{11}\)।
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यदि (x+y=15) और (2x-3y=10), तो (3x+y) का मान क्या है?
If (x+y=15) and (2x-3y=10), what is the value of (3x+y)?
#linear equations
#substitution
#expression value
#hard
#class 10
A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
Using (x=15-y) gives (30-5y=10), so (y=4) and (x=11). Hence (3x+y=37).
Step 2
Why this answer is correct
The correct answer is B. (37). Using (x=15-y) gives (30-5y=10), so (y=4) and (x=11). Hence (3x+y=37).
Step 3
Exam Tip
(x=15-y) रखने पर (30-5y=10), इसलिए (y=4) और (x=11)। अतः (3x+y=37)।
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यदि (px+2y=18) और (3x-y=5) का हल (x=4,\ y=7) है, तो (p) का मान क्या है?
If (px+2y=18) and (3x-y=5) have solution (x=4,\ y=7), what is the value of (p)?
#linear equations
#parameter
#substitution
#hard
#class 10
A (p=1)
B (p=2)
C (p=3)
D (p=4)
Explanation opens after your attempt
Step 1
Concept
Put (x=4,\ y=7) in (px+2y=18). (4p+14=18), so (p=1).
Step 2
Why this answer is correct
The correct answer is A. (p=1). Put (x=4,\ y=7) in (px+2y=18). (4p+14=18), so (p=1).
Step 3
Exam Tip
(x=4,\ y=7) को (px+2y=18) में रखें। (4p+14=18), इसलिए (p=1)।
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समीकरणों \(\frac{2x-3y}{5}=1\) और \(\frac{x+y}{2}=6\) से (y) का मान क्या है?
What is the value of (y) from \(\frac{2x-3y}{5}=1\) and \(\frac{x+y}{2}=6\)?
#linear equations
#transformed equations
#substitution
#hard
#class 10
A \(y=\frac{16}{5}\)
B \(y=\frac{19}{5}\)
C \(y=\frac{21}{5}\)
D \(y=\frac{24}{5}\)
Explanation opens after your attempt
Correct Answer
B. \(y=\frac{19}{5}\)
Step 1
Concept
The equations become (2x-3y=5) and (x+y=12). Substitution gives \(y=\frac{19}{5}\).
Step 2
Why this answer is correct
The correct answer is B. \(y=\frac{19}{5}\). The equations become (2x-3y=5) and (x+y=12). Substitution gives \(y=\frac{19}{5}\).
Step 3
Exam Tip
दिए समीकरण (2x-3y=5) और (x+y=12) बनते हैं। प्रतिस्थापन से \(y=\frac{19}{5}\) मिलता है।
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यदि (2x+ky=15) और (x-2y=1) का हल (x=5,\ y=2) है, तो (k) का मान क्या है?
If (2x+ky=15) and (x-2y=1) have solution (x=5,\ y=2), what is the value of (k)?
#linear equations
#parameter
#substitution
#hard
#class 10
A (k=2)
B (k=3)
C \(k=\frac{5}{2}\)
D \(k=\frac{7}{2}\)
Explanation opens after your attempt
Correct Answer
C. \(k=\frac{5}{2}\)
Step 1
Concept
Put (x=5,\ y=2) in (2x+ky=15). (10+2k=15), so \(k=\frac{5}{2}\).
Step 2
Why this answer is correct
The correct answer is C. \(k=\frac{5}{2}\). Put (x=5,\ y=2) in (2x+ky=15). (10+2k=15), so \(k=\frac{5}{2}\).
Step 3
Exam Tip
(x=5,\ y=2) को (2x+ky=15) में रखें। (10+2k=15), इसलिए \(k=\frac{5}{2}\)।
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यदि (3(x+y)+2(x-y)=31) और (2(x+y)-(x-y)=13), तो (x) का मान क्या है?
If (3(x+y)+2(x-y)=31) and (2(x+y)-(x-y)=13), what is the value of (x)?
#linear equations
#transformation
#substitution
#hard
#class 10
A \(x=\frac{34}{7}\)
B \(x=\frac{40}{7}\)
C \(x=\frac{44}{7}\)
D \(x=\frac{47}{7}\)
Explanation opens after your attempt
Correct Answer
B. \(x=\frac{40}{7}\)
Step 1
Concept
Let (x+y=s) and (x-y=d). Solving gives \(s=\frac{57}{7}\) and \(d=\frac{23}{7}\), so \(x=\frac{40}{7}\).
Step 2
Why this answer is correct
The correct answer is B. \(x=\frac{40}{7}\). Let (x+y=s) and (x-y=d). Solving gives \(s=\frac{57}{7}\) and \(d=\frac{23}{7}\), so \(x=\frac{40}{7}\).
Step 3
Exam Tip
(x+y=s) और (x-y=d) मानें। हल करने पर \(s=\frac{57}{7}\) और \(d=\frac{23}{7}\), इसलिए \(x=\frac{40}{7}\)।
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समीकरणों \(\frac{x}{3}+\frac{y}{5}=4\) और (x-y=6) से (x) का मान क्या है?
What is the value of (x) from \(\frac{x}{3}+\frac{y}{5}=4\) and (x-y=6)?
#linear equations
#fraction equations
#substitution
#hard
#class 10
A \(x=\frac{39}{4}\)
B \(x=\frac{37}{4}\)
C \(x=\frac{41}{4}\)
D \(x=\frac{35}{4}\)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{39}{4}\)
Step 1
Concept
Multiply the first equation by (15) to get (5x+3y=60). Using (x=y+6) gives \(x=\frac{39}{4}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{39}{4}\). Multiply the first equation by (15) to get (5x+3y=60). Using (x=y+6) gives \(x=\frac{39}{4}\).
Step 3
Exam Tip
पहले समीकरण को (15) से गुणा कर (5x+3y=60) बनाएं। (x=y+6) रखने पर \(x=\frac{39}{4}\)।
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यदि (2x+my=34) का हल (x=7,\ y=4) है, तो (m) का मान क्या होगा?
If (x=7,\ y=4) is a solution of (2x+my=34), what will be the value of (m)?
#linear equations
#parameter
#substitution
#hard
#class 10
A (m=4)
B (m=5)
C (m=6)
D (m=7)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=7,\ y=4) in the equation. (14+4m=34), so (m=5).
Step 2
Why this answer is correct
The correct answer is B. (m=5). Substitute (x=7,\ y=4) in the equation. (14+4m=34), so (m=5).
Step 3
Exam Tip
(x=7,\ y=4) को समीकरण में रखें। (14+4m=34), इसलिए (m=5)।
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