Concept-wise Practice

square roots MCQ Questions for Class 10

square roots se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

27 questions tagged with square roots.

यदि (m) पूर्णांक है और \(m<\sqrt{145}<m+1\), तो (m) का मान क्या है?

If (m) is an integer and \(m<\sqrt{145}<m+1\), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

Since (144<145<169), \(12<\sqrt{145}<13\). Perfect squares give (m) quickly.

Step 2

Why this answer is correct

The correct answer is B. (12). Since (144<145<169), \(12<\sqrt{145}<13\). Perfect squares give (m) quickly.

Step 3

Exam Tip

क्योंकि (144<145<169), इसलिए \(12<\sqrt{145}<13\)। पूर्ण वर्गों से (m) तुरंत मिलता है।

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संख्या रेखा पर \( \sqrt{65} \) का सबसे अच्छा एक दशमलव स्थान तक अनुमान कौन सा है?

What is the best estimate of \( \sqrt{65} \) to one decimal place on the number line?

Explanation opens after your attempt
Correct Answer

B. (8.1)

Step 1

Concept

\(8^2=64\) and \(8.1^2=65.61\), so \( \sqrt{65}\approx8.1 \). Estimate using nearby squares.

Step 2

Why this answer is correct

The correct answer is B. (8.1). \(8^2=64\) and \(8.1^2=65.61\), so \( \sqrt{65}\approx8.1 \). Estimate using nearby squares.

Step 3

Exam Tip

\(8^2=64\) और \(8.1^2=65.61\), इसलिए \( \sqrt{65}\approx8.1 \)। निकट वर्ग से अनुमान लगाएँ।

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संख्या रेखा पर \( \sqrt{52} \) किस दो लगातार पूर्णांकों के बीच स्थित है?

Between which two consecutive integers is \( \sqrt{52} \) located on the number line?

Explanation opens after your attempt
Correct Answer

B. (7) और (8)(7) and (8)

Step 1

Concept

Since (49<52<64), \(7<\sqrt{52}<8\). First identify the nearest perfect squares.

Step 2

Why this answer is correct

The correct answer is B. (7) और (8) / (7) and (8). Since (49<52<64), \(7<\sqrt{52}<8\). First identify the nearest perfect squares.

Step 3

Exam Tip

क्योंकि (49<52<64), इसलिए \(7<\sqrt{52}<8\)। पहले निकटतम पूर्ण वर्गों को पहचानें।

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यदि (m) ऐसा पूर्णांक है कि \(m<\sqrt{57}<m+1\), तो (m) का मान क्या है?

If (m) is an integer such that \(m<\sqrt{57}<m+1\), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

Since (49<57<64), \(7<\sqrt{57}<8\). Therefore (m=7).

Step 2

Why this answer is correct

The correct answer is A. (7). Since (49<57<64), \(7<\sqrt{57}<8\). Therefore (m=7).

Step 3

Exam Tip

क्योंकि (49<57<64), इसलिए \(7<\sqrt{57}<8\)। अतः (m=7) होगा।

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यदि (x) संख्या रेखा पर \( \sqrt{72} \) है, तो (x) के लिए सही सरल रूप कौन सा है?

If (x) is \( \sqrt{72} \) on the number line, what is the correct simplified form of (x)?

Explanation opens after your attempt
Correct Answer

A. \(6\sqrt{2}\)

Step 1

Concept

\( \sqrt{72}=\sqrt{36\cdot2}=6\sqrt{2}\). To simplify a root, factor out the largest perfect square.

Step 2

Why this answer is correct

The correct answer is A. \(6\sqrt{2}\). \( \sqrt{72}=\sqrt{36\cdot2}=6\sqrt{2}\). To simplify a root, factor out the largest perfect square.

Step 3

Exam Tip

\( \sqrt{72}=\sqrt{36\cdot2}=6\sqrt{2}\)। मूल सरल करने के लिए सबसे बड़ा पूर्ण वर्ग निकालें।

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किस विकल्प में \( \sqrt{15} \) की संख्या रेखा पर स्थिति सबसे सही बताई गई है?

Which option states the position of \( \sqrt{15} \) on the number line most correctly?

Explanation opens after your attempt
Correct Answer

A. (3.8) और (3.9) के बीचBetween (3.8) and (3.9)

Step 1

Concept

\(3.8^2=14.44\) and \(3.9^2=15.21\), so \( \sqrt{15}\) lies between them. Check squares for decimal bounds.

Step 2

Why this answer is correct

The correct answer is A. (3.8) और (3.9) के बीच / Between (3.8) and (3.9). \(3.8^2=14.44\) and \(3.9^2=15.21\), so \( \sqrt{15}\) lies between them. Check squares for decimal bounds.

Step 3

Exam Tip

\(3.8^2=14.44\) और \(3.9^2=15.21\), इसलिए \( \sqrt{15}\) इनके बीच है। दशमलव सीमा के लिए वर्ग जाँचें।

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यदि \( \sqrt{n} \) संख्या रेखा पर (8) और (9) के बीच है, तो (n) के लिए कौन सा मान संभव है?

If \( \sqrt{n} \) lies between (8) and (9) on the number line, which value of (n) is possible?

Explanation opens after your attempt
Correct Answer

A. (70)

Step 1

Concept

From \(8<\sqrt{n}<9\), we get (64<n<81), so (70) is possible. Square positive bounds carefully.

Step 2

Why this answer is correct

The correct answer is A. (70). From \(8<\sqrt{n}<9\), we get (64<n<81), so (70) is possible. Square positive bounds carefully.

Step 3

Exam Tip

\(8<\sqrt{n}<9\) से (64<n<81), इसलिए (70) संभव है। असमानता को वर्ग करते समय धनात्मक सीमा का उपयोग करें।

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कौन सी संख्या \( \sqrt{8} \) और (3) के बीच संख्या रेखा पर स्थित है?

Which number lies between \( \sqrt{8} \) and (3) on the number line?

Explanation opens after your attempt
Correct Answer

A. (2.9)

Step 1

Concept

\( \sqrt{8}\approx2.828\), so (2.9) lies between it and (3). First estimate the irrational number.

Step 2

Why this answer is correct

The correct answer is A. (2.9). \( \sqrt{8}\approx2.828\), so (2.9) lies between it and (3). First estimate the irrational number.

Step 3

Exam Tip

\( \sqrt{8}\approx2.828\), इसलिए (2.9) उसके और (3) के बीच है। पहले अपरिमेय संख्या का अनुमान करें।

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संख्या रेखा पर \( \sqrt{99} \) का सबसे निकटतम पूर्णांक कौन सा है?

Which integer is closest to \( \sqrt{99} \) on the number line?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

(99) is very close to (100), so \( \sqrt{99}\) is about (10). The nearest perfect square gives a quick answer.

Step 2

Why this answer is correct

The correct answer is A. (10). (99) is very close to (100), so \( \sqrt{99}\) is about (10). The nearest perfect square gives a quick answer.

Step 3

Exam Tip

(99) संख्या (100) के बहुत निकट है, इसलिए \( \sqrt{99}\) लगभग (10) है। निकटतम पूर्ण वर्ग तेजी से उत्तर देता है।

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संख्या रेखा पर \( \sqrt{12}-1 \) किस दो पूर्णांकों के बीच आएगा?

Between which two integers will \( \sqrt{12}-1 \) lie on the number line?

Explanation opens after your attempt
Correct Answer

A. (2) और (3)(2) and (3)

Step 1

Concept

Since \(3<\sqrt{12}<4\), \(2<\sqrt{12}-1<3\). First find the root interval, then subtract.

Step 2

Why this answer is correct

The correct answer is A. (2) और (3) / (2) and (3). Since \(3<\sqrt{12}<4\), \(2<\sqrt{12}-1<3\). First find the root interval, then subtract.

Step 3

Exam Tip

\(3<\sqrt{12}<4\), इसलिए \(2<\sqrt{12}-1<3\)। पहले मूल का अंतराल निकालें, फिर घटाएँ।

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यदि \(a=\sqrt{2}\), \(b=\sqrt{3}\), और \(c=\sqrt{5}\), तो संख्या रेखा पर बाएँ से दाएँ सही क्रम कौन सा है?

If \(a=\sqrt{2}\), \(b=\sqrt{3}\), and \(c=\sqrt{5}\), what is the correct left-to-right order on the number line?

Explanation opens after your attempt
Correct Answer

A. (a,b,c)

Step 1

Concept

Since (2<3<5), \( \sqrt{2}<\sqrt{3}<\sqrt{5}\). For positive square roots, order follows the radicand.

Step 2

Why this answer is correct

The correct answer is A. (a,b,c). Since (2<3<5), \( \sqrt{2}<\sqrt{3}<\sqrt{5}\). For positive square roots, order follows the radicand.

Step 3

Exam Tip

क्योंकि (2<3<5), इसलिए \( \sqrt{2}<\sqrt{3}<\sqrt{5}\)। धनात्मक वर्गमूल में अंदर की संख्या से क्रम तय होता है।

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संख्या रेखा पर \( \sqrt{18} \) को सबसे सही किस दो लगातार पूर्णांकों के बीच दिखाया जाएगा?

Between which two consecutive integers should \( \sqrt{18} \) be shown most accurately on the number line?

Explanation opens after your attempt
Correct Answer

A. (4) और (5)(4) and (5)

Step 1

Concept

Since (16<18<25), we get \(4<\sqrt{18}<5\). In exams, compare perfect squares first.

Step 2

Why this answer is correct

The correct answer is A. (4) और (5) / (4) and (5). Since (16<18<25), we get \(4<\sqrt{18}<5\). In exams, compare perfect squares first.

Step 3

Exam Tip

क्योंकि (16<18<25), इसलिए \(4<\sqrt{18}<5\)। परीक्षा में वर्गों की तुलना पहले करें।

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किस विकल्प में \(\sqrt{11}\) और \(\sqrt{15}\) के बीच संख्या रेखा पर स्थित संख्या है?

Which option lies between \(\sqrt{11}\) and \(\sqrt{15}\) on the number line?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{13}\)

Step 1

Concept

Because (11<13<15), \(\sqrt{11}<\sqrt{13}<\sqrt{15}\). For positive square roots, the order of radicands is preserved.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{13}\). Because (11<13<15), \(\sqrt{11}<\sqrt{13}<\sqrt{15}\). For positive square roots, the order of radicands is preserved.

Step 3

Exam Tip

क्योंकि (11<13<15), इसलिए \(\sqrt{11}<\sqrt{13}<\sqrt{15}\)। धनात्मक वर्गमूल में मूल संख्या का क्रम बना रहता है।

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संख्या रेखा पर \(\sqrt{15}\) किस दो पूर्णांकों के बीच स्थित होगा?

Between which two integers will \(\sqrt{15}\) lie on the number line?

Explanation opens after your attempt
Correct Answer

B. (3) और (4)(3) and (4)

Step 1

Concept

Since \(3^2=9\) and \(4^2=16\), \(\sqrt{15}\) lies between (3) and (4). In exams, use nearby perfect squares to locate square roots.

Step 2

Why this answer is correct

The correct answer is B. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{15}\) lies between (3) and (4). In exams, use nearby perfect squares to locate square roots.

Step 3

Exam Tip

क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{15}\) (3) और (4) के बीच है। परीक्षा में वर्गमूल की स्थिति के लिए नजदीकी पूर्ण वर्ग देखें।

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संख्या रेखा पर \(-\sqrt{16}\) किस संख्या के बराबर स्थान पर होगा?

On the number line, \(-\sqrt{16}\) will be at the same position as which number?

Explanation opens after your attempt
Correct Answer

C. (-4)

Step 1

Concept

\(\sqrt{16}=4\), so \(-\sqrt{16}=-4\). In exams, apply the outside negative sign after finding the square root.

Step 2

Why this answer is correct

The correct answer is C. (-4). \(\sqrt{16}=4\), so \(-\sqrt{16}=-4\). In exams, apply the outside negative sign after finding the square root.

Step 3

Exam Tip

\(\sqrt{16}=4\), इसलिए \(-\sqrt{16}=-4\) है। परीक्षा में वर्गमूल निकालने के बाद बाहर का ऋण चिह्न लगाएं।

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संख्या रेखा पर \(\sqrt{9}\) किस संख्या के बराबर स्थान पर होगा?

On the number line, \(\sqrt{9}\) will be at the same position as which number?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

\(\sqrt{9}=3\), so its position is at (3). In exams, identify square roots of perfect squares quickly.

Step 2

Why this answer is correct

The correct answer is B. (3). \(\sqrt{9}=3\), so its position is at (3). In exams, identify square roots of perfect squares quickly.

Step 3

Exam Tip

\(\sqrt{9}=3\), इसलिए इसका स्थान (3) पर होगा। परीक्षा में पूर्ण वर्गों के वर्गमूल तुरंत पहचानें।

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संख्या रेखा पर \(\sqrt{13}\) किस दो पूर्णांकों के बीच स्थित होगा?

Between which two integers will \(\sqrt{13}\) lie on the number line?

Explanation opens after your attempt
Correct Answer

A. (3) और (4)(3) and (4)

Step 1

Concept

Since \(3^2=9\) and \(4^2=16\), \(\sqrt{13}\) lies between (3) and (4). Use nearby perfect squares to locate square roots.

Step 2

Why this answer is correct

The correct answer is A. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{13}\) lies between (3) and (4). Use nearby perfect squares to locate square roots.

Step 3

Exam Tip

क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{13}\) (3) और (4) के बीच है। वर्गमूल की स्थिति के लिए निकट पूर्ण वर्ग देखें।

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संख्या रेखा पर \(\sqrt{7}\) को किसके बीच रखा जाएगा?

Between which numbers will \(\sqrt{7}\) be placed on the number line?

Explanation opens after your attempt
Correct Answer

A. (2) और (3)(2) and (3)

Step 1

Concept

Since \(2^2=4\) and \(3^2=9\), \(\sqrt{7}\) lies between (2) and (3). Bound the number using nearby squares.

Step 2

Why this answer is correct

The correct answer is A. (2) और (3) / (2) and (3). Since \(2^2=4\) and \(3^2=9\), \(\sqrt{7}\) lies between (2) and (3). Bound the number using nearby squares.

Step 3

Exam Tip

क्योंकि \(2^2=4\) और \(3^2=9\), इसलिए \(\sqrt{7}\) (2) और (3) के बीच है। संख्या को निकट वर्गों से घेरें।

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संख्या रेखा पर \(\sqrt{16}\) और (4) के बारे में कौन-सा कथन सही है?

Which statement about \(\sqrt{16}\) and (4) on the number line is correct?

Explanation opens after your attempt
Correct Answer

A. दोनों एक ही बिंदु पर हैंboth are at the same point

Step 1

Concept

\(\sqrt{16}=4\), so both have the same position. Identify square roots of perfect squares directly.

Step 2

Why this answer is correct

The correct answer is A. दोनों एक ही बिंदु पर हैं / both are at the same point. \(\sqrt{16}=4\), so both have the same position. Identify square roots of perfect squares directly.

Step 3

Exam Tip

\(\sqrt{16}=4\), इसलिए दोनों की स्थिति समान है। पूर्ण वर्ग का वर्गमूल सीधे पहचानें।

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\(\sqrt{10}\) को संख्या रेखा पर रखने के लिए उसका मान किसके बीच होगा?

To place \(\sqrt{10}\) on the number line, its value will be between which numbers?

Explanation opens after your attempt
Correct Answer

A. (3) और (4)(3) and (4)

Step 1

Concept

Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). Use perfect squares to locate square roots.

Step 2

Why this answer is correct

The correct answer is A. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). Use perfect squares to locate square roots.

Step 3

Exam Tip

क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{10}\) (3) और (4) के बीच है। वर्गमूल की स्थिति पूर्ण वर्गों से पहचानें।

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\(\sqrt{5}\) संख्या रेखा पर किन दो पूर्णांकों के बीच होगा?

Between which two integers will \(\sqrt{5}\) lie on the number line?

Explanation opens after your attempt
Correct Answer

A. (2) और (3)(2) and (3)

Step 1

Concept

Since \(2^2=4\) and \(3^2=9\), \(\sqrt{5}\) lies between (2) and (3). Look at the nearest perfect squares.

Step 2

Why this answer is correct

The correct answer is A. (2) और (3) / (2) and (3). Since \(2^2=4\) and \(3^2=9\), \(\sqrt{5}\) lies between (2) and (3). Look at the nearest perfect squares.

Step 3

Exam Tip

क्योंकि \(2^2=4\) और \(3^2=9\), इसलिए \(\sqrt{5}\) (2) और (3) के बीच है। निकटतम पूर्ण वर्ग देखें।

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संख्या रेखा पर \(\sqrt{9}\) की स्थिति क्या होगी?

What is the position of \(\sqrt{9}\) on the number line?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

\(\sqrt{9}=3\), so it is shown at (3). The principal square root is always non-negative.

Step 2

Why this answer is correct

The correct answer is A. (3). \(\sqrt{9}=3\), so it is shown at (3). The principal square root is always non-negative.

Step 3

Exam Tip

\(\sqrt{9}=3\) है, इसलिए इसे (3) पर दिखाते हैं। मुख्य वर्गमूल हमेशा अऋणात्मक लिया जाता है।

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संख्या रेखा पर \(\sqrt{4}\) किस बिंदु पर होगा?

At which point will \(\sqrt{4}\) lie on the number line?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

\(\sqrt{4}=2\), so the point is (2). Remember square roots of perfect squares.

Step 2

Why this answer is correct

The correct answer is A. (2). \(\sqrt{4}=2\), so the point is (2). Remember square roots of perfect squares.

Step 3

Exam Tip

\(\sqrt{4}=2\) होता है, इसलिए बिंदु (2) पर होगा। पूर्ण वर्गों के वर्गमूल याद रखें।

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समीकरण \(x^2=9\) के मूल कौन-से हैं?

What are the roots of \(x^2=9\)?

Explanation opens after your attempt
Correct Answer

C. (-3,3)

Step 1

Concept

From \(x^2=9\), we get \(x=\pm3\). While taking square roots, take both positive and negative values.

Step 2

Why this answer is correct

The correct answer is C. (-3,3). From \(x^2=9\), we get \(x=\pm3\). While taking square roots, take both positive and negative values.

Step 3

Exam Tip

\(x^2=9\) से \(x=\pm3\) मिलता है। वर्गमूल लेते समय धन और ऋण दोनों मान लें।

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कौन सा विकल्प \(\sqrt{2}\), \(\sqrt{3}\), और \(\sqrt{5}\) के प्रमाणों में सबसे बड़ा सामान्य भ्रम है?

Which option is the biggest common misconception in the proofs of \(\sqrt{2}\), \(\sqrt{3}\), and \(\sqrt{5}\)?

Explanation opens after your attempt
Correct Answer

A. वर्गमूल को उसके अंदर की संख्या के बराबर मान लेनाTreating the square root as equal to the number inside it

Step 1

Concept

Writing \(\sqrt{2}=2\), \(\sqrt{3}=3\), or \(\sqrt{5}=5\) is wrong.

Step 2

Why this answer is correct

In the correct proof, the square root is assumed as a fraction and then squared.

Step 3

Exam Tip

Do not confuse the square root with the number inside it. चरण 1: \(\sqrt{2}=2\), \(\sqrt{3}=3\), या \(\sqrt{5}=5\) लिखना गलत है। चरण 2: सही प्रमाण में वर्गमूल को भिन्न के रूप में मानकर वर्ग किया जाता है। चरण 3: वर्गमूल और अंदर की संख्या को समान न समझें।

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कौन-सा विकल्प \(\sqrt{a}+\sqrt{b}=\sqrt{a+b}\) जैसी गलत सोच को खंडित करता है?

Which option disproves the wrong idea \(\sqrt{a}+\sqrt{b}=\sqrt{a+b}\)?

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Correct Answer

A. (a=4,b=9)

Step 1

Concept

For (a=4,b=9), the left side is (2+3=5).

Step 2

Why this answer is correct

The right side is \(\sqrt{13}\), which is not (5).

Step 3

Exam Tip

When adding square roots, the numbers inside the roots are not added directly. चरण 1: (a=4,b=9) रखने पर बायाँ पक्ष (2+3=5) है। चरण 2: दायाँ पक्ष \(\sqrt{13}\) है, जो (5) नहीं है। चरण 3: वर्गमूलों को जोड़ते समय अंदर की संख्याएँ सीधे नहीं जोड़ी जातीं।

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यदि (a) और (b) धनात्मक पूर्णांक हैं तथा \(\sqrt{a}+\sqrt{b}\) परिमेय है, जबकि (a) पूर्ण वर्ग नहीं है, तो (b) के बारे में कौन-सा निष्कर्ष निश्चित रूप से सही हो सकता है?

If (a) and (b) are positive integers and \(\sqrt{a}+\sqrt{b}\) is rational, while (a) is not a perfect square, which conclusion about (b) can definitely be true?

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Correct Answer

C. ऐसा होना संभव नहीं हैThis is not possible

Step 1

Concept

Since (a) is not a perfect square, \(\sqrt{a}\) is irrational.

Step 2

Why this answer is correct

A sum of two positive square roots could become rational only if irrational parts cancel, but both terms are positive here.

Step 3

Exam Tip

Without opposite signs, irrational surd parts remain in the sum. चरण 1: (a) पूर्ण वर्ग नहीं है, इसलिए \(\sqrt{a}\) अपरिमेय है। चरण 2: दो धनात्मक वर्गमूलों का योग परिमेय तभी हो सकता है जब अपरिमेय भाग कटे, पर यहाँ दोनों पद धनात्मक हैं इसलिए कटना संभव नहीं है। चरण 3: धनात्मक मूलों के योग में विपरीत चिह्न न होने पर अपरिमेय भाग बचता है।

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