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If m is an integer and \(m<\sqrt{145}<m+1\), what is the value of m?

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Answer and explanation

Correct answer: 12

Since \(12^2=144<145<169=13^2\), we get \(12<\sqrt{145}<13\). Comparing this with \(m<\sqrt{145}<m+1\) gives \(m=12\). Option 13 is incorrect because \(\sqrt{145}<13\), so \(13<\sqrt{145}\) is not true. Exam tip: the integer part of a square root is the greatest integer whose square is less than or equal to the given number.

Related tags

PolynomialsNumber-LineInteger-BoundsSquare-RootsReal-Numbers

Frequently asked questions

What is the correct answer to this question?

12

Why is this the correct answer?

Since \(12^2=144<145<169=13^2\), we get \(12<\sqrt{145}<13\). Comparing this with \(m<\sqrt{145}<m+1\) gives \(m=12\). Option 13 is incorrect because \(\sqrt{145}<13\), so \(13<\sqrt{145}\) is not true. Exam tip: the integer part of a square root is the greatest integer whose square is less than or equal to the given number.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.

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