Which option gives the correct further reasoning after substituting (p=3k) in the proof of (\sqrt{3})?

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Answer and explanation

Correct answer: (9k^2=3q^2), so (q^2=3k^2), hence (q) is divisible by (3)

Step 1: If (p=3k), then (p^2=9k^2). Step 2: From (9k^2=3q^2), we get (q^2=3k^2). Step 3: By the prime rule, (q) is divisible by (3).

What is the correct answer to this question?

(9k^2=3q^2), so (q^2=3k^2), hence (q) is divisible by (3)

Why is this the correct answer?

Step 1: If (p=3k), then (p^2=9k^2). Step 2: From (9k^2=3q^2), we get (q^2=3k^2). Step 3: By the prime rule, (q) is divisible by (3).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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