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4 results found for "irrational-coefficients" in Class 10.

Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि (p(x)=x-2-\(3+\sqrt{2}\)x+3\sqrt{2}) है, तो इसके शून्यकों का सही युग्म कौन सा है?

If (p(x)=x-2-\(3+\sqrt{2}\)x+3\sqrt{2}), which is the correct pair of zeroes?

Explanation opens after your attempt
Correct Answer

A. (3) और \(\sqrt{2}\)(3) and \(\sqrt{2}\)

Step 1

Concept

The sum is \(3+\sqrt{2}\) and the product is \(3\sqrt{2}\). These match (3) and \(\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. (3) और \(\sqrt{2}\) / (3) and \(\sqrt{2}\). The sum is \(3+\sqrt{2}\) and the product is \(3\sqrt{2}\). These match (3) and \(\sqrt{2}\).

Step 3

Exam Tip

योग \(3+\sqrt{2}\) और गुणनफल \(3\sqrt{2}\) है। ये (3) और \(\sqrt{2}\) से मिलते हैं।

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Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि (p(x)=x-2-\(\sqrt{5}+\sqrt{7}\)x+\sqrt{35}) है, तो शून्यकों का सही युग्म कौन सा है?

If (p(x)=x-2-\(\sqrt{5}+\sqrt{7}\)x+\sqrt{35}), which is the correct pair of zeroes?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{5}\) और \(\sqrt{7}\)\(\sqrt{5}\) and \(\sqrt{7}\)

Step 1

Concept

The sum is \(\sqrt{5}+\sqrt{7}\) and the product is \(\sqrt{35}\). Both match \(\sqrt{5}\) and \(\sqrt{7}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{5}\) और \(\sqrt{7}\) / \(\sqrt{5}\) and \(\sqrt{7}\). The sum is \(\sqrt{5}+\sqrt{7}\) and the product is \(\sqrt{35}\). Both match \(\sqrt{5}\) and \(\sqrt{7}\).

Step 3

Exam Tip

योग \(\sqrt{5}+\sqrt{7}\) और गुणनफल \(\sqrt{35}\) है। ये दोनों \(\sqrt{5}\) और \(\sqrt{7}\) से मिलते हैं।

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Question Hard Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 27

यदि (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), तो शून्यक कौन से हैं?

If (p(x)=x-2-\(\sqrt{2}+\sqrt{3}\)x+\sqrt{6}), what are the zeroes?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\) और \(\sqrt{3}\)\(\sqrt{2}\) and \(\sqrt{3}\)

Step 1

Concept

The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\) और \(\sqrt{3}\) / \(\sqrt{2}\) and \(\sqrt{3}\). The sum is \(\sqrt{2}+\sqrt{3}\) and the product is \(\sqrt{6}\). These match \(\sqrt{2}\) and \(\sqrt{3}\).

Step 3

Exam Tip

योग \(\sqrt{2}+\sqrt{3}\) और गुणनफल \(\sqrt{6}\) है। ये \(\sqrt{2}\) और \(\sqrt{3}\) से मिलते हैं।

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Question Hard Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 28

किस बहुपद के शून्यक \(\sqrt{2}+\sqrt{3}\) और \(\sqrt{2}-\sqrt{3}\) हैं?

Which polynomial has zeroes \(\sqrt{2}+\sqrt{3}\) and \(\sqrt{2}-\sqrt{3}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-2\sqrt{2}x-1\)

Step 1

Concept

The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-2\sqrt{2}x-1\). The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

Step 3

Exam Tip

योग \(2\sqrt{2}\) और गुणनफल (2-3=-1) है। इसलिए बहुपद \(x^2-2\sqrt{2}x-1\) बनेगा।

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