Concept-wise Practice

surd addition MCQ Questions for Class 10

surd addition se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with surd addition.

संख्या रेखा पर \(\sqrt{2}+\sqrt{3}\) किस अंतराल में होगा?

On the number line, in which interval will \(\sqrt{2}+\sqrt{3}\) lie?

Explanation opens after your attempt
Correct Answer

A. ((3,4))

Step 1

Concept

\(\sqrt{2}\approx1.414\) and \(\sqrt{3}\approx1.732\), so the sum is about (3.146). Add approximate values for sums.

Step 2

Why this answer is correct

The correct answer is A. ((3,4)). \(\sqrt{2}\approx1.414\) and \(\sqrt{3}\approx1.732\), so the sum is about (3.146). Add approximate values for sums.

Step 3

Exam Tip

\(\sqrt{2}\approx1.414\) और \(\sqrt{3}\approx1.732\), इसलिए योग लगभग (3.146) है। योग के लिए अनुमानित मान जोड़ें।

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किस विकल्प में \(\sqrt{3}\) और \(\sqrt{12}\) का योग परिमेय गुणांक वाले सरल अपरिमेय रूप में सही लिखा गया है?

In which option is the sum of \(\sqrt{3}\) and \(\sqrt{12}\) correctly written as a simple irrational form with rational coefficient?

Explanation opens after your attempt
Correct Answer

A. \(3\sqrt{3}\)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\), so \(\sqrt{3}+\sqrt{12}=3\sqrt{3}\). In exams make radicals like terms before adding.

Step 2

Why this answer is correct

The correct answer is A. \(3\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\), so \(\sqrt{3}+\sqrt{12}=3\sqrt{3}\). In exams make radicals like terms before adding.

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\), इसलिए \(\sqrt{3}+\sqrt{12}=3\sqrt{3}\) है। परीक्षा में मूलों को जोड़ने से पहले समान मूल बनाएं।

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कौन सा व्यंजक परिमेय संख्या नहीं है?

Which expression is not a rational number?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{20}+\sqrt{45}\)

Step 1

Concept

\(\sqrt{20}+\sqrt{45}=2\sqrt{5}+3\sqrt{5}=5\sqrt{5}\), which is irrational. In exams do not treat addition like multiplication.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{20}+\sqrt{45}\). \(\sqrt{20}+\sqrt{45}=2\sqrt{5}+3\sqrt{5}=5\sqrt{5}\), which is irrational. In exams do not treat addition like multiplication.

Step 3

Exam Tip

\(\sqrt{20}+\sqrt{45}=2\sqrt{5}+3\sqrt{5}=5\sqrt{5}\), जो अपरिमेय है। परीक्षा में योग को गुणन जैसा न मानें।

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यदि \(x=\sqrt{6}+\sqrt{24}\), तो (x) किसके बराबर है?

If \(x=\sqrt{6}+\sqrt{24}\), what is (x) equal to?

Explanation opens after your attempt
Correct Answer

B. \(3\sqrt{6}\)

Step 1

Concept

\(\sqrt{24}=2\sqrt{6}\).

Step 2

Why this answer is correct

So \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), which is irrational.

Step 3

Exam Tip

Simplify radicals to like terms before adding. चरण 1: \(\sqrt{24}=2\sqrt{6}\) है। चरण 2: इसलिए \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), जो अपरिमेय है। चरण 3: मूल को सरल करके समान पद बनाएँ, फिर जोड़ें।

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