यदि \(x=\sqrt{6}+\sqrt{24}\), तो (x) किसके बराबर है?
If \(x=\sqrt{6}+\sqrt{24}\), what is (x) equal to?
Explanation opens after your attempt
B. \(3\sqrt{6}\)
Concept
\(\sqrt{24}=2\sqrt{6}\).
Why this answer is correct
So \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), which is irrational.
Exam Tip
Simplify radicals to like terms before adding. चरण 1: \(\sqrt{24}=2\sqrt{6}\) है। चरण 2: इसलिए \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), जो अपरिमेय है। चरण 3: मूल को सरल करके समान पद बनाएँ, फिर जोड़ें।
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