यदि \(\sqrt{m}\) अपरिमेय है और (m) धनात्मक पूर्णांक है, तो (m) के बारे में सही निष्कर्ष कौन सा है?
If \(\sqrt{m}\) is irrational and (m) is a positive integer, which conclusion about (m) is correct?
Explanation opens after your attempt
A. (m) पूर्ण वर्ग नहीं है(m) is not a perfect square
Concept
The square root of a perfect square is an integer, so for an irrational square root (m) is not a perfect square. In exams identifying perfect squares is important.
Why this answer is correct
The correct answer is A. (m) पूर्ण वर्ग नहीं है / (m) is not a perfect square. The square root of a perfect square is an integer, so for an irrational square root (m) is not a perfect square. In exams identifying perfect squares is important.
Exam Tip
पूर्ण वर्ग का वर्गमूल पूर्णांक होता है, इसलिए अपरिमेय वर्गमूल के लिए (m) पूर्ण वर्ग नहीं होगा। परीक्षा में पूर्ण वर्ग पहचानना जरूरी है।
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