If a is rational and b is irrational, when is a + b definitely irrational?
Answer and explanation
Correct answer: When a is any rational number
The sum of a rational number and an irrational number is always irrational. To see why, suppose a + b were rational. Since a is rational, subtracting a from the rational number a + b would make b = (a + b) - a rational, contradicting the given fact that b is irrational. Therefore a + b must be irrational for every rational value of a, including 0, 1, negative rationals, and fractions. Option A is correct. Option B and option C mention special choices that are sufficient but unnecessarily restrictive; the result does not depend on a being one particular rational number. Option D is the exact opposite of the closure argument. This property concerns addition, not multiplication or division, where different conditions may be needed.
Frequently asked questions
What is the correct answer to this question?
When a is any rational number
Why is this the correct answer?
The sum of a rational number and an irrational number is always irrational. To see why, suppose a + b were rational. Since a is rational, subtracting a from the rational number a + b would make b = (a + b) - a rational, contradicting the given fact that b is irrational. Therefore a + b must be irrational for every rational value of a, including 0, 1, negative rationals, and fractions. Option A is correct. Option B and option C mention special choices that are sufficient but unnecessarily restrictive; the result does not depend on a being one particular rational number. Option D is the exact opposite of the closure argument. This property concerns addition, not multiplication or division, where different conditions may be needed.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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