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What type of number is \(\sqrt{49}\)?

Answer and explanation

Correct answer: Rational number

\(\sqrt{49}=7\). Since 7 can be written as \(\frac{7}{1}\), it is a rational number. The square root of a perfect square is an integer (hence rational). Option B is incorrect because irrational numbers have non-terminating, non-repeating decimals (e.g. \(\sqrt{2}\)); here the result is a whole integer. Option C is wrong because non-real complex numbers have a nonzero imaginary part; 7 has zero imaginary part. Option D is wrong because the value is well defined. Exam tip: first check if the radicand is a perfect square — then the square root will be an integer/rational.

Related tags

Square-RootRational-NumbersPerfect-SquareReal-NumbersIrrational Numbers And Real NumbersPolynomialsMathematicsClass 10 Mcq

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