कौन सा विकल्प बताता है कि \(\sqrt{2}+\sqrt{8}\) अपरिमेय है?
Which option shows that \(\sqrt{2}+\sqrt{8}\) is irrational?
Explanation opens after your attempt
A. यह \(3\sqrt{2}\) हैIt is \(3\sqrt{2}\)
Concept
\(\sqrt{8}=2\sqrt{2}\), so the sum is \(3\sqrt{2}\). A non zero rational multiple of \(\sqrt{2}\) remains irrational.
Why this answer is correct
The correct answer is A. यह \(3\sqrt{2}\) है / It is \(3\sqrt{2}\). \(\sqrt{8}=2\sqrt{2}\), so the sum is \(3\sqrt{2}\). A non zero rational multiple of \(\sqrt{2}\) remains irrational.
Exam Tip
\(\sqrt{8}=2\sqrt{2}\), इसलिए योग \(3\sqrt{2}\) है। गैर शून्य परिमेय गुणक के साथ \(\sqrt{2}\) अपरिमेय रहता है।
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