100 results found for "monic-polynomial" in Class 10.
यदि किसी द्विघात बहुपद के शून्यक (2) और (5) हैं, तो एक मोनिक बहुपद क्या होगा?
If the zeroes of a quadratic polynomial are (2) and (5), what is one monic polynomial?
#construct-polynomial
#zeroes
#monic
A \(x^2-7x+10\)
B \(x^2+7x+10\)
C \(x^2-10x+7\)
D \(x^2+10x-7\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x+10\)
Step 1
Concept
With zeroes (2) and (5), the polynomial is ((x-2)(x-5)=x-2 -7x+10). A monic polynomial has leading coefficient (1).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-7x+10\). With zeroes (2) and (5), the polynomial is ((x-2)(x-5)=x-2 -7x+10). A monic polynomial has leading coefficient (1).
Step 3
Exam Tip
शून्यक (2) और (5) होने पर बहुपद ((x-2)(x-5)=x-2 -7x+10) है। मोनिक बहुपद में \(x^2\) का गुणांक (1) होता है।
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यदि \(\sqrt{3}\) और \(\sqrt{12}\) किसी द्विघात बहुपद के शून्यक हैं, तो एकक बहुपद में (x) का गुणांक क्या होगा?
If \(\sqrt{3}\) and \(\sqrt{12}\) are zeroes of a monic quadratic polynomial, what will be the coefficient of (x)?
#radical-simplification
#monic-polynomial
#coefficient
A \(-3\sqrt{3}\)
B \(-\sqrt{15}\)
C \(3\sqrt{3}\)
D \(-2\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(-3\sqrt{3}\)
Step 1
Concept
\(\sqrt{12}=2\sqrt{3}\), so the sum is \(3\sqrt{3}\). In a monic polynomial, the coefficient of (x) is the negative of the sum of zeroes.
Step 2
Why this answer is correct
The correct answer is A. \(-3\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\), so the sum is \(3\sqrt{3}\). In a monic polynomial, the coefficient of (x) is the negative of the sum of zeroes.
Step 3
Exam Tip
\(\sqrt{12}=2\sqrt{3}\), इसलिए योग \(3\sqrt{3}\) है। एकक बहुपद में (x) का गुणांक शून्यकों के योग का ऋणात्मक होता है।
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यदि किसी द्विघात बहुपद के शून्यक \(2+\sqrt{3}\) और \(2-\sqrt{3}\) हैं, तो मोनिक बहुपद कौन-सा है?
If the zeroes of a quadratic polynomial are \(2+\sqrt{3}\) and \(2-\sqrt{3}\), which is the monic polynomial?
#construct-polynomial
#surd-zeroes
#quadratic
A \(x^2-4x+1\)
B \(x^2+4x+1\)
C \(x^2-2x+3\)
D \(x^2-4x+7\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x+1\)
Step 1
Concept
The sum is (4) and the product is (1). Therefore the monic polynomial is \(x^2-4x+1\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x+1\). The sum is (4) and the product is (1). Therefore the monic polynomial is \(x^2-4x+1\).
Step 3
Exam Tip
योग (4) और गुणनफल (1) है। अतः मोनिक बहुपद \(x^2-4x+1\) होगा।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को (x=-2), (x=0) और (x=3) पर काटता है, तो सबसे कम घात का मोनिक बहुपद कौन-सा है?
If the graph of a polynomial cuts the (x)-axis at (x=-2), (x=0), and (x=3), which is the monic polynomial of least degree?
#graph-zeroes
#least-degree
#polynomial
A \(x^3-x^2-6x\)
B \(x^3+x^2-6x\)
C \(x^3-6x\)
D \(x^3+6x^2-x\)
Explanation opens after your attempt
Correct Answer
A. \(x^3-x^2-6x\)
Step 1
Concept
The zeroes are (-2,0,3), so the polynomial is (x(x+2)(x-3)=x-3 -x-2 -6x). Intersections with the (x)-axis give zeroes.
Step 2
Why this answer is correct
The correct answer is A. \(x^3-x^2-6x\). The zeroes are (-2,0,3), so the polynomial is (x(x+2)(x-3)=x-3 -x-2 -6x). Intersections with the (x)-axis give zeroes.
Step 3
Exam Tip
शून्यक (-2,0,3) हैं, इसलिए बहुपद (x(x+2)(x-3)=x-3 -x-2 -6x) है। (x)-अक्ष काटने के बिंदु शून्यक बताते हैं।
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यदि (x=3) और (x=8) किसी मोनिक द्विघात समीकरण के मूल हैं तो (x) का गुणांक क्या होगा?
If (x=3) and (x=8) are roots of a monic quadratic equation, what will be the coefficient of (x)?
#roots
#coefficient_from_roots
#monic
A (-11)
B (11)
C (24)
D (-24)
Explanation opens after your attempt
Step 1
Concept
\(The sum of roots is (3+8=11). In a monic equation the coefficient of (x) is (-(\)sum\()=-11).\)
Step 2
Why this answer is correct
\(The correct answer is A. (-11). The sum of roots is (3+8=11). In a monic equation the coefficient of (x) is (-(\)sum\()=-11).\)
Step 3
Exam Tip
मूलों का योग (3+8=11) है। मोनिक समीकरण में (x) का गुणांक (-(योग\()=-11) होता है\)।
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यदि मूलों का योग (11) और गुणनफल (28) है तो मोनिक द्विघात समीकरण कौन सा होगा?
If the sum of roots is (11) and product is (28), which monic quadratic equation is formed?
#roots
#equation_from_sum_product
#monic
A \(x^2-11x+28=0\)
B \(x^2+11x+28=0\)
C \(x^2-28x+11=0\)
D \(x^2+28x+11=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-11x+28=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-11x+28=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2-11x+28=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-11x+28=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2-11x+28=0) सही है\)।
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यदि (x=2) और (x=7) किसी मोनिक द्विघात समीकरण के मूल हैं तो (x) का गुणांक क्या होगा?
If (x=2) and (x=7) are roots of a monic quadratic equation, what will be the coefficient of (x)?
#roots
#coefficient_from_roots
#monic
A (-9)
B (9)
C (14)
D (-14)
Explanation opens after your attempt
Step 1
Concept
\(The sum of roots is (2+7=9). In a monic equation the coefficient of (x) is (-(\)sum\()=-9).\)
Step 2
Why this answer is correct
\(The correct answer is A. (-9). The sum of roots is (2+7=9). In a monic equation the coefficient of (x) is (-(\)sum\()=-9).\)
Step 3
Exam Tip
मूलों का योग (2+7=9) है। मोनिक समीकरण में (x) का गुणांक (-(योग\()=-9) होता है\)।
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यदि मूलों का योग (9) और गुणनफल (18) है तो मोनिक द्विघात समीकरण कौन सा होगा?
If the sum of roots is (9) and product is (18), which monic quadratic equation is formed?
#roots
#equation_from_sum_product
#monic
A \(x^2-9x+18=0\)
B \(x^2+9x+18=0\)
C \(x^2-18x+9=0\)
D \(x^2+18x+9=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-9x+18=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-9x+18=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2-9x+18=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-9x+18=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2-9x+18=0) सही है\)।
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यदि (x=1) और (x=4) किसी मोनिक द्विघात समीकरण के मूल हैं तो (x) का गुणांक क्या होगा?
If (x=1) and (x=4) are roots of a monic quadratic equation, what will be the coefficient of (x)?
#roots
#coefficient_from_roots
#monic
A (-5)
B (5)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
\(The sum of roots is (1+4=5). In a monic equation the coefficient of (x) is (-(\)sum\()=-5).\)
Step 2
Why this answer is correct
\(The correct answer is A. (-5). The sum of roots is (1+4=5). In a monic equation the coefficient of (x) is (-(\)sum\()=-5).\)
Step 3
Exam Tip
मूलों का योग (1+4=5) है। मोनिक समीकरण में (x) का गुणांक (-(योग\()=-5) होता है\)।
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यदि मूलों का योग (7) और गुणनफल (10) है तो मोनिक द्विघात समीकरण कौन सा होगा?
If the sum of roots is (7) and product is (10), which monic quadratic equation is formed?
#roots
#equation_from_sum_product
#monic
A \(x^2-7x+10=0\)
B \(x^2+7x+10=0\)
C \(x^2-10x+7=0\)
D \(x^2+10x+7=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x+10=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-7x+10=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2-7x+10=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-7x+10=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2-7x+10=0) सही है\)।
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जिस मोनिक द्विघात समीकरण के मूलों का योग (10) और गुणनफल (21) है वह कौन सा है?
Which monic quadratic equation has sum of roots (10) and product of roots (21)?
#roots
#equation_from_sum_product
#monic
A \(x^2+10x+21=0\)
B \(x^2-10x+21=0\)
C \(x^2-21x+10=0\)
D \(x^2+21x+10=0\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-10x+21=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-10x+21=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is B. (x^2-10x+21=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-10x+21=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2-10x+21=0) सही है\)।
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जिस मोनिक द्विघात समीकरण के मूलों का योग (-9) और गुणनफल (20) है वह कौन सा है?
Which monic quadratic equation has sum of roots (-9) and product of roots (20)?
#roots
#equation_from_sum_product
#monic
A \(x^2+9x+20=0\)
B \(x^2-9x+20=0\)
C \(x^2+20x+9=0\)
D \(x^2-20x+9=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+9x+20=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2+9x+20=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+9x+20=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2+9x+20=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2+9x+20=0) सही है\)।
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यदि किसी मोनिक द्विघात समीकरण के मूल (3r) और (4r) हैं तथा उनका योग (28) है, तो उस समीकरण का स्थिर पद क्या होगा?
If the roots of a monic quadratic equation are (3r) and (4r), and their sum is (28), what will be the constant term?
#quadratic-equations
#roots
#monic-equation
#expert
A (192)
B (28)
C (112)
D (84)
Explanation opens after your attempt
Step 1
Concept
From (3r+4r=28), we get (r=4), so the roots are (12) and (16). The constant term is the product of roots (192).
Step 2
Why this answer is correct
The correct answer is A. (192). From (3r+4r=28), we get (r=4), so the roots are (12) and (16). The constant term is the product of roots (192).
Step 3
Exam Tip
(3r+4r=28) से (r=4) मिलता है, इसलिए मूल (12) और (16) हैं। स्थिर पद मूलों का गुणनफल (192) होगा।
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यदि किसी मोनिक द्विघात समीकरण के मूल (2r) और (5r) हैं तथा उनका योग (21) है, तो उस समीकरण का स्थिर पद क्या होगा?
If the roots of a monic quadratic equation are (2r) and (5r), and their sum is (21), what will be the constant term?
#quadratic-equations
#roots
#monic-equation
#expert
A (90)
B (21)
C (45)
D (63)
Explanation opens after your attempt
Step 1
Concept
From (2r+5r=21), we get (r=3), so the roots are (6) and (15). The constant term is the product of roots (90).
Step 2
Why this answer is correct
The correct answer is A. (90). From (2r+5r=21), we get (r=3), so the roots are (6) and (15). The constant term is the product of roots (90).
Step 3
Exam Tip
(2r+5r=21) से (r=3) मिलता है, इसलिए मूल (6) और (15) हैं। स्थिर पद मूलों का गुणनफल (90) होगा।
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यदि किसी मोनिक द्विघात समीकरण के मूल (r) और (3r) हैं तथा उनका योग (16) है, तो उस समीकरण का स्थिर पद क्या होगा?
If the roots of a monic quadratic equation are (r) and (3r), and their sum is (16), what will be the constant term?
#quadratic-equations
#roots
#monic-equation
#expert
A (48)
B (16)
C (64)
D (32)
Explanation opens after your attempt
Step 1
Concept
From (r+3r=16), we get (r=4), so the roots are (4) and (12). The constant term is the product of roots (48).
Step 2
Why this answer is correct
The correct answer is A. (48). From (r+3r=16), we get (r=4), so the roots are (4) and (12). The constant term is the product of roots (48).
Step 3
Exam Tip
(r+3r=16) से (r=4) मिलता है, इसलिए मूल (4) और (12) हैं। स्थिर पद मूलों का गुणनफल (48) होगा।
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यदि किसी मोनिक द्विघात समीकरण के मूल (r) और (2r) हैं तथा उनका योग (9) है, तो उस समीकरण में स्थिर पद क्या होगा?
If the roots of a monic quadratic equation are (r) and (2r), and their sum is (9), what will be the constant term?
#quadratic-equations
#roots
#monic-equation
#hard
A (18)
B (9)
C (27)
D (36)
Explanation opens after your attempt
Step 1
Concept
From (r+2r=9), we get (r=3), so the roots are (3) and (6). The constant term will be the product of roots (18).
Step 2
Why this answer is correct
The correct answer is A. (18). From (r+2r=9), we get (r=3), so the roots are (3) and (6). The constant term will be the product of roots (18).
Step 3
Exam Tip
(r+2r=9) से (r=3) मिलता है, इसलिए मूल (3) और (6) हैं। स्थिर पद मूलों का गुणनफल (18) होगा।
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यदि मूल (-5) और (4) हैं, तो मोनिक द्विघात समीकरण कौन-सा होगा?
If the roots are (-5) and (4), what will be the monic quadratic equation?
#quadratic-equations
#monic
#roots
#medium
A \(x^2+x-20=0\)
B \(x^2-x-20=0\)
C \(x^2+9x+20=0\)
D \(x^2-9x+20=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+x-20=0\)
Step 1
Concept
The factors are ((x+5)) and ((x-4)). Multiplying them gives \(x^2+x-20=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+x-20=0\). The factors are ((x+5)) and ((x-4)). Multiplying them gives \(x^2+x-20=0\).
Step 3
Exam Tip
गुणनखंड ((x+5)) और ((x-4)) होंगे। इन्हें गुणा करने पर \(x^2+x-20=0\) मिलता है।
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यदि मूल (-4) और (3) हैं, तो मोनिक द्विघात समीकरण कौन-सा होगा?
If the roots are (-4) and (3), what will be the monic quadratic equation?
#quadratic-equations
#monic
#roots
#medium
A \(x^2+x-12=0\)
B \(x^2-x-12=0\)
C \(x^2+7x+12=0\)
D \(x^2-7x+12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+x-12=0\)
Step 1
Concept
The factors will be ((x+4)) and ((x-3)). These give \(x^2+x-12=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+x-12=0\). The factors will be ((x+4)) and ((x-3)). These give \(x^2+x-12=0\).
Step 3
Exam Tip
गुणनखंड ((x+4)) और ((x-3)) होंगे। इनसे \(x^2+x-12=0\) मिलता है।
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यदि मूल (-2) और (5) हैं, तो मोनिक द्विघात समीकरण कौन-सा होगा?
If the roots are (-2) and (5), what will be the monic quadratic equation?
#quadratic-equations
#monic
#roots
#medium
A \(x^2-3x-10=0\)
B \(x^2+3x-10=0\)
C \(x^2-7x+10=0\)
D \(x^2+7x+10=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-10=0\)
Step 1
Concept
The factors are ((x+2)) and ((x-5)), giving \(x^2-3x-10=0\). Make factors with signs opposite to the roots.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-10=0\). The factors are ((x+2)) and ((x-5)), giving \(x^2-3x-10=0\). Make factors with signs opposite to the roots.
Step 3
Exam Tip
गुणनखंड ((x+2)) और ((x-5)) होंगे, जिनसे \(x^2-3x-10=0\) मिलता है। मूल के विपरीत चिन्ह वाले गुणनखंड बनाएं।
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निम्न में से मोनिक द्विघात समीकरण कौन-सा है?
Which of the following is a monic quadratic equation?
#quadratic-equations
#monic-quadratic
#easy
A \(x^2+5x+6=0\)
B \(2x^2+x+1=0\)
C \(-3x^2+x=0\)
D \(4x^2-1=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+5x+6=0\)
Step 1
Concept
In a monic quadratic equation, the coefficient of \(x^2\) is (1). So \(x^2+5x+6=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+5x+6=0\). In a monic quadratic equation, the coefficient of \(x^2\) is (1). So \(x^2+5x+6=0\) is correct.
Step 3
Exam Tip
मोनिक द्विघात में \(x^2\) का गुणांक (1) होता है। इसलिए \(x^2+5x+6=0\) सही है।
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यदि \(\alpha+\beta=6\) और \(\alpha\beta=8\), तो शून्यक \(\alpha+1\) और \(\beta+1\) वाला मोनिक बहुपद कौन-सा है?
If \(\alpha+\beta=6\) and \(\alpha\beta=8\), which monic polynomial has zeroes \(\alpha+1\) and \(\beta+1\)?
#transformed-zeroes
#construct-polynomial
#expert
A \(x^2-8x+15\)
B \(x^2-6x+8\)
C \(x^2+8x+15\)
D \(x^2-7x+14\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x+15\)
Step 1
Concept
The new sum is \(\alpha+\beta+2=8\) and product is \(\alpha\beta+\alpha+\beta+1=15\). Thus the polynomial is \(x^2-8x+15\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x+15\). The new sum is \(\alpha+\beta+2=8\) and product is \(\alpha\beta+\alpha+\beta+1=15\). Thus the polynomial is \(x^2-8x+15\).
Step 3
Exam Tip
नए शून्यकों का योग \(\alpha+\beta+2=8\) और गुणनफल \(\alpha\beta+\alpha+\beta+1=15\) है। अतः बहुपद \(x^2-8x+15\) है।
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यदि शून्यकों का योग (-4) और गुणनफल (7) है, तो मोनिक द्विघात बहुपद कौन-सा है?
If the sum of zeroes is (-4) and product is (7), which is the monic quadratic polynomial?
#sum-product
#construct-polynomial
#quadratic
A \(x^2+4x+7\)
B \(x^2-4x+7\)
C \(x^2+7x-4\)
D \(x^2-7x+4\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+4x+7\)
Step 1
Concept
\(A monic quadratic is (x^2-(\)sum)x+product\(). Hence (x^2-(-4)x+7=x^2+4x+7).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+4x+7). A monic quadratic is (x^2-(\)sum)x+product\(). Hence (x^2-(-4)x+7=x^2+4x+7).\)
Step 3
Exam Tip
\(मोनिक द्विघात (x^2-(\)योग)x+गुणनफल) होता है। \(इसलिए (x^2-(-4)x+7=x^2+4x+7) है\)।
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यदि द्विघात बहुपद के शून्यक \(\alpha\) और \(\beta\) हैं तथा \(\alpha+\beta=5\), \(\alpha\beta=6\), तो मोनिक बहुपद क्या है?
If a quadratic polynomial has zeroes \(\alpha\) and \(\beta\), with \(\alpha+\beta=5\) and \(\alpha\beta=6\), what is the monic polynomial?
#polynomials
#monic
#formation
#hard
A \(x^2-5x+6\)
B \(x^2+5x+6\)
C \(x^2-6x+5\)
D \(x^2+6x+5\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-5x+6\)
Step 1
Concept
The monic polynomial is (x-2 -\(\alpha+\beta\)x+\alpha\beta). Hence \(x^2-5x+6\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-5x+6\). The monic polynomial is (x-2 -\(\alpha+\beta\)x+\alpha\beta). Hence \(x^2-5x+6\) is correct.
Step 3
Exam Tip
मोनिक बहुपद (x-2 -\(\alpha+\beta\)x+\alpha\beta) होता है। इसलिए \(x^2-5x+6\) सही है।
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शून्यकों \(2+\sqrt{6}\) और \(2-\sqrt{6}\) वाला एक मानक द्विघात बहुपद कौन सा है?
Which monic quadratic polynomial has zeroes \(2+\sqrt{6}\) and \(2-\sqrt{6}\)?
#forming polynomial
#irrational zeroes
#quadratic
A \(x^2-4x-2\)
B \(x^2+4x-2\)
C \(x^2-2x+4\)
D \(x^2-4x+10\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-2\)
Step 1
Concept
The sum is (4) and the product is (4-6=-2), so the polynomial is \(x^2-4x-2\). Remember the formula \(x^2-Sx+P\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-2\). The sum is (4) and the product is (4-6=-2), so the polynomial is \(x^2-4x-2\). Remember the formula \(x^2-Sx+P\).
Step 3
Exam Tip
योग (4) और गुणनफल (4-6=-2) है, इसलिए बहुपद \(x^2-4x-2\) है। परीक्षा में \(x^2-Sx+P\) सूत्र याद रखें।
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यदि शून्यक \(\frac{3+\sqrt{5}}{2}\) और \(\frac{3-\sqrt{5}}{2}\) हैं, तो एकक बहुपद क्या है?
If the zeroes are \(\frac{3+\sqrt{5}}{2}\) and \(\frac{3-\sqrt{5}}{2}\), what is the monic polynomial?
#polynomial-formation
#fractional-conjugates
#irrational
A \(x^2-3x+1\)
B \(x^2+3x+1\)
C \(x^2-3x-1\)
D \(x^2-\frac{3}{2}x+1\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x+1\)
Step 1
Concept
The sum is (3) and the product is \(\frac{9-5}{4}=1\). Therefore the polynomial is \(x^2-3x+1\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x+1\). The sum is (3) and the product is \(\frac{9-5}{4}=1\). Therefore the polynomial is \(x^2-3x+1\).
Step 3
Exam Tip
योग (3) और गुणनफल \(\frac{9-5}{4}=1\) है। इसलिए बहुपद \(x^2-3x+1\) है।
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यदि (p(x)=x-2 -6x+8), तो शून्यकों के वर्गों से बना मोनिक बहुपद कौन-सा है?
If (p(x)=x-2 -6x+8), which monic polynomial has the squares of its zeroes as zeroes?
#transformed-zeroes
#squares
#quadratic
A \(x^2-20x+64\)
B \(x^2-6x+8\)
C \(x^2-12x+16\)
D \(x^2-16x+64\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-20x+64\)
Step 1
Concept
The original zeroes are (2) and (4), so the new zeroes are (4) and (16). The new polynomial is \(x^2-20x+64\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-20x+64\). The original zeroes are (2) and (4), so the new zeroes are (4) and (16). The new polynomial is \(x^2-20x+64\).
Step 3
Exam Tip
मूल शून्यक (2) और (4) हैं, इसलिए नए शून्यक (4) और (16) हैं। नया बहुपद \(x^2-20x+64\) है।
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यदि किसी एकक द्विघात बहुपद के शून्यक \(a+\sqrt{b}\) और \(a-\sqrt{b}\) हैं, तो उसके विविक्तकर का मान क्या होगा?
If the zeroes of a monic quadratic polynomial are \(a+\sqrt{b}\) and \(a-\sqrt{b}\), what will be its discriminant?
#general-discriminant
#conjugates
#expert
A (4b)
B (b)
C (2b)
D \(a^2-b\)
Explanation opens after your attempt
Step 1
Concept
The polynomial is (x-2 -2ax+\(a^2-b\)). Its discriminant is (4a-2 -4\(a^2-b\)=4b).
Step 2
Why this answer is correct
The correct answer is A. (4b). The polynomial is (x-2 -2ax+\(a^2-b\)). Its discriminant is (4a-2 -4\(a^2-b\)=4b).
Step 3
Exam Tip
बहुपद (x-2 -2ax+\(a^2-b\)) होगा। इसका विविक्तकर (4a-2 -4\(a^2-b\)=4b) है।
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यदि किसी एकक द्विघात बहुपद के शून्यक \(4+\sqrt{11}\) और \(4-\sqrt{11}\) हैं, तो स्थिर पद क्या होगा?
If the zeroes of a monic quadratic polynomial are \(4+\sqrt{11}\) and \(4-\sqrt{11}\), what will be the constant term?
#conjugate-zeroes
#constant-term
#quadratic
A (5)
B (27)
C (8)
D \(16+\sqrt{11}\)
Explanation opens after your attempt
Step 1
Concept
The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.
Step 2
Why this answer is correct
The correct answer is A. (5). The constant term is the product, and (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5). In conjugate products, the irrational middle part cancels.
Step 3
Exam Tip
स्थिर पद गुणनफल है और (\(4+\sqrt{11}\)\(4-\sqrt{11}\)=16-11=5)। संयुग्मी गुणनफल में बीच का अपरिमेय भाग हट जाता है।
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यदि \(a+\sqrt{b}\) और \(a-\sqrt{b}\) किसी एकक द्विघात बहुपद के शून्यक हैं, तो स्थिर पद क्या होगा?
If \(a+\sqrt{b}\) and \(a-\sqrt{b}\) are zeroes of a monic quadratic polynomial, what is the constant term?
#general-form
#conjugates
#constant-term
A \(a^2-b\)
B \(a^2+b\)
C (2a)
D (-2a)
Explanation opens after your attempt
Correct Answer
A. \(a^2-b\)
Step 1
Concept
In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b).
Step 2
Why this answer is correct
The correct answer is A. \(a^2-b\). In a monic polynomial, the constant term is the product of zeroes. Here the product is (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b).
Step 3
Exam Tip
एकक बहुपद में स्थिर पद शून्यकों का गुणनफल होता है। यहाँ गुणनफल (\(a+\sqrt{b}\)\(a-\sqrt{b}\)=a-2 -b) है।
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यदि शून्यकों का योग \(2\sqrt{5}\) और गुणनफल (4) है, तो एक मानक द्विघात बहुपद कौन सा होगा?
If the sum of zeroes is \(2\sqrt{5}\) and the product is (4), which is a monic quadratic polynomial?
#polynomial-formation
#sum-product
#irrational
A \(x^2-2\sqrt{5}x+4\)
B \(x^2+2\sqrt{5}x+4\)
C \(x^2-4x+2\sqrt{5}\)
D \(x^2+4x-2\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-2\sqrt{5}x+4\)
Step 1
Concept
\(A monic polynomial is (x^2-(\)sum)x+product\(). So the answer is (x^2-2\sqrt{5}x+4).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2-2\sqrt{5}x+4). A monic polynomial is (x^2-(\)sum)x+product\(). So the answer is (x^2-2\sqrt{5}x+4).\)
Step 3
Exam Tip
\(मानक बहुपद (x^2-(\)योग)x+गुणनफल) होता है। \(इसलिए उत्तर (x^2-2\sqrt{5}x+4) है\)।
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यदि \(x^2-7x+10=0\) के मूलों को उलटकर नया समीकरण बनाया जाए तो नया मोनिक समीकरण कौन सा होगा?
If a new equation is formed by taking reciprocals of the roots of \(x^2-7x+10=0\), which monic equation is obtained?
#roots
#reciprocal_roots
#new_equation
A \(x^2-\frac{7}{10}x+\frac{1}{10}=0\)
B \(x^2-7x+10=0\)
C \(x^2+\frac{7}{10}x+\frac{1}{10}=0\)
D \(x^2-\frac{1}{10}x+\frac{7}{10}=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-\frac{7}{10}x+\frac{1}{10}=0\)
Step 1
Concept
The old sum is (7) and product is (10). The reciprocal roots have sum \(\frac{7}{10}\) and product \(\frac{1}{10}\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-\frac{7}{10}x+\frac{1}{10}=0\). The old sum is (7) and product is (10). The reciprocal roots have sum \(\frac{7}{10}\) and product \(\frac{1}{10}\).
Step 3
Exam Tip
पुराने योग (7) और गुणनफल (10) हैं। उलटे मूलों का योग \(\frac{7}{10}\) और गुणनफल \(\frac{1}{10}\) होगा।
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यदि \(x^2-6x-16=0\) के मूलों को (1) बढ़ा दिया जाए तो नए मूलों से बना मोनिक समीकरण कौन सा होगा?
If each root of \(x^2-6x-16=0\) is increased by (1), which monic equation is formed from the new roots?
#roots
#transformed_roots
#new_equation
A \(x^2-8x-9=0\)
B \(x^2-6x-16=0\)
C \(x^2-4x-9=0\)
D \(x^2+8x-9=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x-9=0\)
Step 1
Concept
The old roots are (8) and (-2). The new roots are (9) and (-1), so the equation is \(x^2-8x-9=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x-9=0\). The old roots are (8) and (-2). The new roots are (9) and (-1), so the equation is \(x^2-8x-9=0\).
Step 3
Exam Tip
पुराने मूल (8) और (-2) हैं। नए मूल (9) और (-1) होंगे इसलिए समीकरण \(x^2-8x-9=0\) है।
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यदि \(x^2-5x+6=0\) के मूलों को उलटकर नया समीकरण बनाया जाए तो नया मोनिक समीकरण कौन सा होगा?
If a new equation is formed by taking reciprocals of the roots of \(x^2-5x+6=0\), which monic equation is obtained?
#roots
#reciprocal_roots
#new_equation
A \(x^2-\frac{5}{6}x+\frac{1}{6}=0\)
B \(x^2-5x+6=0\)
C \(x^2+\frac{5}{6}x+\frac{1}{6}=0\)
D \(x^2-\frac{1}{6}x+\frac{5}{6}=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-\frac{5}{6}x+\frac{1}{6}=0\)
Step 1
Concept
The old sum is (5) and product is (6). The reciprocal roots have sum \(\frac{5}{6}\) and product \(\frac{1}{6}\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-\frac{5}{6}x+\frac{1}{6}=0\). The old sum is (5) and product is (6). The reciprocal roots have sum \(\frac{5}{6}\) and product \(\frac{1}{6}\).
Step 3
Exam Tip
पुराने योग (5) और गुणनफल (6) हैं। उलटे मूलों का योग \(\frac{5}{6}\) और गुणनफल \(\frac{1}{6}\) होगा।
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यदि \(x^2-4x-12=0\) के मूलों को (1) बढ़ा दिया जाए तो नए मूलों से बना मोनिक समीकरण कौन सा होगा?
If each root of \(x^2-4x-12=0\) is increased by (1), which monic equation is formed from the new roots?
#roots
#transformed_roots
#new_equation
A \(x^2-6x-15=0\)
B \(x^2-4x-12=0\)
C \(x^2-2x-15=0\)
D \(x^2+6x-15=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-6x-15=0\)
Step 1
Concept
The old roots are (6) and (-2). The new roots are (7) and (-1), so the equation is \(x^2-6x-7=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-6x-15=0\). The old roots are (6) and (-2). The new roots are (7) and (-1), so the equation is \(x^2-6x-7=0\).
Step 3
Exam Tip
पुराने मूल (6) और (-2) हैं। नए मूल (7) और (-1) होंगे इसलिए समीकरण \(x^2-6x-7=0\) नहीं बल्कि \(x^2-6x-7=0\) होता है।
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यदि \(\alpha+\beta=-7\) और \(\alpha\beta=-18\) है तो \(\alpha\) और \(\beta\) के लिए मोनिक समीकरण कौन सा है?
If \(\alpha+\beta=-7\) and \(\alpha\beta=-18\), which monic equation has roots \(\alpha\) and \(\beta\)?
#roots
#equation_from_roots
#sum_product
A \(x^2+7x-18=0\)
B \(x^2-7x-18=0\)
C \(x^2+18x-7=0\)
D \(x^2-18x+7=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+7x-18=0\)
Step 1
Concept
The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+7x-18=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+7x-18=0\). The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+7x-18=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+7x-18=0\) सही है।
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यदि मूलों का योग (0) और गुणनफल (-36) है तो मोनिक समीकरण कौन सा होगा?
If the sum of roots is (0) and product is (-36), which monic equation is formed?
#roots
#equation_from_sum_product
#zero_sum
A \(x^2-36=0\)
B \(x^2+36=0\)
C \(x^2-36x=0\)
D \(x^2+36x=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-36=0\)
Step 1
Concept
The monic equation is (x-2 -(0)x+(-36)=0). Therefore \(x^2-36=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-36=0\). The monic equation is (x-2 -(0)x+(-36)=0). Therefore \(x^2-36=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -(0)x+(-36)=0) होगा। इसलिए \(x^2-36=0\) सही है।
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यदि \(\alpha+\beta=-5\) और \(\alpha\beta=-14\) है तो \(\alpha\) और \(\beta\) के लिए मोनिक समीकरण कौन सा है?
If \(\alpha+\beta=-5\) and \(\alpha\beta=-14\), which monic equation has roots \(\alpha\) and \(\beta\)?
#roots
#equation_from_roots
#sum_product
A \(x^2+5x-14=0\)
B \(x^2-5x-14=0\)
C \(x^2+14x-5=0\)
D \(x^2-14x+5=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+5x-14=0\)
Step 1
Concept
The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+5x-14=0\). The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+5x-14=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+5x-14=0\) सही है।
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यदि मूलों का योग (0) और गुणनफल (-25) है तो मोनिक समीकरण कौन सा होगा?
If the sum of roots is (0) and product is (-25), which monic equation is formed?
#roots
#equation_from_sum_product
#zero_sum
A \(x^2-25=0\)
B \(x^2+25=0\)
C \(x^2-25x=0\)
D \(x^2+25x=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-25=0\)
Step 1
Concept
The monic equation is (x-2 -(0)x+(-25)=0). Therefore \(x^2-25=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-25=0\). The monic equation is (x-2 -(0)x+(-25)=0). Therefore \(x^2-25=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -(0)x+(-25)=0) होगा। इसलिए \(x^2-25=0\) सही है।
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यदि \(\alpha+\beta=-3\) और \(\alpha\beta=-10\) है तो \(\alpha\) और \(\beta\) के लिए मोनिक समीकरण कौन सा है?
If \(\alpha+\beta=-3\) and \(\alpha\beta=-10\), which monic equation has roots \(\alpha\) and \(\beta\)?
#roots
#equation_from_roots
#sum_product
A \(x^2+3x-10=0\)
B \(x^2-3x-10=0\)
C \(x^2+10x-3=0\)
D \(x^2-10x+3=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+3x-10=0\)
Step 1
Concept
The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+3x-10=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+3x-10=0\). The monic equation is (x-2 -\(\alpha+\beta\)x+\alpha\beta=0). Therefore \(x^2+3x-10=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -\(\alpha+\beta\)x+\alpha\beta=0) होता है। इसलिए \(x^2+3x-10=0\) सही है।
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यदि मूलों का योग (0) और गुणनफल (-16) है तो मोनिक समीकरण कौन सा होगा?
If the sum of roots is (0) and product is (-16), which monic equation is formed?
#roots
#equation_from_sum_product
#zero_sum
A \(x^2-16=0\)
B \(x^2+16=0\)
C \(x^2-16x=0\)
D \(x^2+16x=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-16=0\)
Step 1
Concept
The monic equation is (x-2 -(0)x+(-16)=0). Therefore \(x^2-16=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-16=0\). The monic equation is (x-2 -(0)x+(-16)=0). Therefore \(x^2-16=0\) is correct.
Step 3
Exam Tip
मोनिक समीकरण (x-2 -(0)x+(-16)=0) होगा। इसलिए \(x^2-16=0\) सही है।
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यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (5) और (5) हैं तो समीकरण कौन सा है?
If both roots of a monic quadratic equation are (5) and (5), which equation is it?
#roots
#equal_roots
#equation_from_roots
A \(x^2-10x+25=0\)
B \(x^2+10x+25=0\)
C \(x^2-5x+25=0\)
D \(x^2+5x-25=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+25=0\)
Step 1
Concept
If both roots are (5), the equation is ((x-5)2 =0). Expanding it gives \(x^2-10x+25=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+25=0\). If both roots are (5), the equation is ((x-5)2 =0). Expanding it gives \(x^2-10x+25=0\).
Step 3
Exam Tip
दोनों मूल (5) हों तो समीकरण ((x-5)2 =0) होगा। इसे खोलने पर \(x^2-10x+25=0\) मिलता है।
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यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (-4) और (-4) हैं तो समीकरण कौन सा है?
If both roots of a monic quadratic equation are (-4) and (-4), which equation is it?
#roots
#equal_roots
#equation_from_roots
A \(x^2+8x+16=0\)
B \(x^2-8x+16=0\)
C \(x^2+4x+16=0\)
D \(x^2-4x-16=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+8x+16=0\)
Step 1
Concept
If both roots are (-4), the equation is ((x+4)2 =0). Expanding it gives \(x^2+8x+16=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+8x+16=0\). If both roots are (-4), the equation is ((x+4)2 =0). Expanding it gives \(x^2+8x+16=0\).
Step 3
Exam Tip
दोनों मूल (-4) हों तो समीकरण ((x+4)2 =0) होगा। इसे खोलने पर \(x^2+8x+16=0\) मिलता है।
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यदि किसी मोनिक द्विघात समीकरण के दोनों मूल (7) और (7) हैं तो समीकरण कौन सा है?
If both roots of a monic quadratic equation are (7) and (7) then which equation is it?
#roots
#equal_roots
#equation_from_roots
A \(x^2-14x+49=0\)
B \(x^2+14x+49=0\)
C \(x^2-7x+49=0\)
D \(x^2+7x-49=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-14x+49=0\)
Step 1
Concept
With both roots (7) we get ((x-7)2 =0) which is \(x^2-14x+49=0\). Form a perfect square from repeated roots.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-14x+49=0\). With both roots (7) we get ((x-7)2 =0) which is \(x^2-14x+49=0\). Form a perfect square from repeated roots.
Step 3
Exam Tip
दोनों मूल (7) होने पर ((x-7)2 =0) मिलता है जो \(x^2-14x+49=0\) है। दोहराए मूल से पूर्ण वर्ग बनाएं।
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मूलों का योग (-15) और गुणनफल (56) वाला मोनिक द्विघात समीकरण कौन-सा है?
Which monic quadratic equation has sum of roots (-15) and product (56)?
#quadratic-equations
#sum-product
#forming-equation
#expert
A \(x^2+15x+56=0\)
B \(x^2-15x+56=0\)
C \(x^2+56x+15=0\)
D \(x^2-56x+15=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+15x+56=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-15) gives (x^2+15x+56=0).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+15x+56=0). A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-15) gives (x^2+15x+56=0).\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(योग (-15) रखने पर (x^2+15x+56=0) मिलता है\)।
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मूलों का योग (-13) और गुणनफल (42) वाला मोनिक द्विघात समीकरण कौन-सा है?
Which monic quadratic equation has sum of roots (-13) and product (42)?
#quadratic-equations
#sum-product
#forming-equation
#expert
A \(x^2+13x+42=0\)
B \(x^2-13x+42=0\)
C \(x^2+42x+13=0\)
D \(x^2-42x+13=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+13x+42=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-13) gives (x^2+13x+42=0).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+13x+42=0). A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-13) gives (x^2+13x+42=0).\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(योग (-13) रखने पर (x^2+13x+42=0) मिलता है\)।
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मूलों का योग (-11) और गुणनफल (30) वाला मोनिक द्विघात समीकरण कौन-सा है?
Which monic quadratic equation has sum of roots (-11) and product (30)?
#quadratic-equations
#sum-product
#forming-equation
#expert
A \(x^2+11x+30=0\)
B \(x^2-11x+30=0\)
C \(x^2+30x+11=0\)
D \(x^2-30x+11=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+11x+30=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-11) gives (x^2+11x+30=0).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+11x+30=0). A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-11) gives (x^2+11x+30=0).\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(योग (-11) रखने पर (x^2+11x+30=0) मिलता है\)।
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मूलों का योग (-9) और गुणनफल (20) वाला मोनिक द्विघात समीकरण कौन-सा है?
Which monic quadratic equation has sum of roots (-9) and product (20)?
#quadratic-equations
#sum-product
#forming-equation
#hard
A \(x^2+9x+20=0\)
B \(x^2-9x+20=0\)
C \(x^2+20x+9=0\)
D \(x^2-20x+9=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+9x+20=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-9) gives (x^2+9x+20=0).\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2+9x+20=0). A monic equation is (x^2-(\)sum)x+product\(=0). Substituting sum (-9) gives (x^2+9x+20=0).\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(योग (-9) रखने पर (x^2+9x+20=0) मिलता है\)।
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मूलों का योग (7) और गुणनफल (10) वाला मोनिक द्विघात समीकरण कौन-सा है?
Which monic quadratic equation has sum of roots (7) and product (10)?
#quadratic-equations
#sum-product
#forming-equation
#hard
A \(x^2-7x+10=0\)
B \(x^2+7x+10=0\)
C \(x^2-10x+7=0\)
D \(x^2+10x-7=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x+10=0\)
Step 1
Concept
\(A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-7x+10=0) is correct.\)
Step 2
Why this answer is correct
\(The correct answer is A. (x^2-7x+10=0). A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2-7x+10=0) is correct.\)
Step 3
Exam Tip
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। \(इसलिए (x^2-7x+10=0) सही है\)।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को चार बार काटता दिखे, तो यह किस प्रकार के बहुपद के लिए संभव हो सकता है?
If a polynomial graph appears to cut the (x)-axis four times, for which type of polynomial can this be possible?
#degree
#zero count
#graph
A रैखिक बहुपद / Linear polynomial
B द्विघात बहुपद / Quadratic polynomial
C चतुर्थ घात बहुपद / Fourth degree polynomial
D अशून्य स्थिर बहुपद / Non-zero constant polynomial
Explanation opens after your attempt
Correct Answer
C. चतुर्थ घात बहुपद / Fourth degree polynomial
Step 1
Concept
A degree (4) polynomial can have at most (4) real zeroes. Tip: the number of real zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is C. चतुर्थ घात बहुपद / Fourth degree polynomial. A degree (4) polynomial can have at most (4) real zeroes. Tip: the number of real zeroes cannot exceed the degree.
Step 3
Exam Tip
घात (4) वाला बहुपद अधिकतम (4) वास्तविक शून्यक रख सकता है। टिप: वास्तविक शून्यकों की संख्या घात से अधिक नहीं होती।
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कौन सा बहुपद (x=0) को शून्य बनाता है लेकिन शून्य बहुपद नहीं है?
Which polynomial makes (x=0) a zero but is not the zero polynomial?
#zero at zero
#constant term
#polynomial
A \(x^2+9\)
B \(4x^3-7x\)
C (5)
D \(x^4+1\)
Explanation opens after your attempt
Correct Answer
B. \(4x^3-7x\)
Step 1
Concept
Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(4x^3-7x\). Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 3
Exam Tip
\(4x^3-7x\) में (x=0) रखने पर (0) मिलता है और यह शून्य बहुपद नहीं है। (x=0) के लिए अचर पद (0) होना चाहिए।
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यदि किसी द्विघात बहुपद के शून्यक \(5+\sqrt{2}\) और \(5-\sqrt{2}\) हैं, तो बहुपद क्या होगा?
If the zeroes of a quadratic polynomial are \(5+\sqrt{2}\) and \(5-\sqrt{2}\), what is the polynomial?
#conjugate-zeroes
#polynomial-formation
#irrational
A \(x^2-10x+23\)
B \(x^2+10x+23\)
C \(x^2-10x+27\)
D \(x^2+10x-23\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+23\)
Step 1
Concept
The sum is (10) and the product is (25-2=23). Therefore the polynomial is \(x^2-10x+23\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+23\). The sum is (10) and the product is (25-2=23). Therefore the polynomial is \(x^2-10x+23\).
Step 3
Exam Tip
योग (10) और गुणनफल (25-2=23) है। इसलिए बहुपद \(x^2-10x+23\) होगा।
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यदि \(2+\sqrt{3}\) और \(2-\sqrt{3}\) किसी द्विघात बहुपद के शून्यक हैं, तो बहुपद क्या होगा?
If \(2+\sqrt{3}\) and \(2-\sqrt{3}\) are zeroes of a quadratic polynomial, what is the polynomial?
#conjugate-zeroes
#polynomial-formation
#real-numbers
A \(x^2-4x+1\)
B \(x^2+4x+1\)
C \(x^2-2x+3\)
D \(x^2+2x-3\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x+1\)
Step 1
Concept
The sum is (4) and the product is (1). Therefore the polynomial is \(x^2-4x+1\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x+1\). The sum is (4) and the product is (1). Therefore the polynomial is \(x^2-4x+1\).
Step 3
Exam Tip
योग (4) और गुणनफल (1) है। अतः बहुपद \(x^2-4x+1\) है।
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शून्य बहुपद (p(x)=0) के ग्राफ के बारे में कौन सा कथन सही है?
Which statement is correct about the graph of the zero polynomial (p(x)=0)?
#zero-polynomial
#graph
#conceptual
A पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis
B ग्राफ (y)-अक्ष है / The graph is the (y)-axis
C कोई बिंदु नहीं है / There is no point
D केवल ((0,0)) है / It is only ((0,0))
Explanation opens after your attempt
Correct Answer
A. पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis
Step 1
Concept
(p(x)=0) gives (y=0) for every (x). Therefore the whole (x)-axis is the graph.
Step 2
Why this answer is correct
The correct answer is A. पूरा ग्राफ (x)-अक्ष है / The whole graph is the (x)-axis. (p(x)=0) gives (y=0) for every (x). Therefore the whole (x)-axis is the graph.
Step 3
Exam Tip
(p(x)=0) हर (x) के लिए (y=0) देता है। इसलिए पूरा (x)-अक्ष ग्राफ है।
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स्थिर बहुपद (p(x)=5) के ग्राफ के वास्तविक शून्यक कितने हैं?
How many real zeroes does the constant polynomial (p(x)=5) have?
#constant-polynomial
#no-zero
#graph
A शून्य / Zero
B एक / One
C पाँच / Five
D अनंत / Infinite
Explanation opens after your attempt
Correct Answer
A. शून्य / Zero
Step 1
Concept
The line (y=5) is parallel to the (x)-axis and does not meet it. So it has no real zero.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. The line (y=5) is parallel to the (x)-axis and does not meet it. So it has no real zero.
Step 3
Exam Tip
रेखा (y=5) (x)-अक्ष के समानांतर है और उससे नहीं मिलती। इसलिए कोई वास्तविक शून्यक नहीं है।
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यदि बहुपद का ग्राफ (x)-अक्ष को चार अलग बिंदुओं पर काटता है तो डिग्री के बारे में कौन सा कथन सही है?
If the graph of a polynomial cuts the (x)-axis at four distinct points, which statement about its degree is correct?
#degree
#maximum-zeroes
#polynomial
A डिग्री कम से कम (4) होगी / The degree is at least (4)
B डिग्री ठीक (2) होगी / The degree is exactly (2)
C डिग्री (1) हो सकती है / The degree may be (1)
D डिग्री शून्य होगी / The degree will be zero
Explanation opens after your attempt
Correct Answer
A. डिग्री कम से कम (4) होगी / The degree is at least (4)
Step 1
Concept
Four distinct real zeroes need degree at least four. The number of zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is A. डिग्री कम से कम (4) होगी / The degree is at least (4). Four distinct real zeroes need degree at least four. The number of zeroes cannot exceed the degree.
Step 3
Exam Tip
चार अलग वास्तविक शून्यक के लिए डिग्री कम से कम चार चाहिए। शून्यकों की संख्या डिग्री से अधिक नहीं होती।
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द्विघात बहुपद (p(x)=x-2 +4) के ग्राफ के बारे में कौन सा कथन सही है?
Which statement is correct about the graph of the quadratic polynomial (p(x)=x-2 +4)?
#quadratic
#no-zero
#positive-polynomial
A यह (x)-अक्ष को नहीं काटता / It does not cut the (x)-axis
B यह (x)-अक्ष को दो बिंदुओं पर काटता / It cuts the (x)-axis at two points
C यह (x)-अक्ष को एक बिंदु पर छूता / It touches the (x)-axis at one point
D यह (x)-अक्ष ही है / It is the (x)-axis
Explanation opens after your attempt
Correct Answer
A. यह (x)-अक्ष को नहीं काटता / It does not cut the (x)-axis
Step 1
Concept
\(x^2+4\) is always positive so (y=0) never occurs. Count a zero only when the graph meets the axis.
Step 2
Why this answer is correct
The correct answer is A. यह (x)-अक्ष को नहीं काटता / It does not cut the (x)-axis. \(x^2+4\) is always positive so (y=0) never occurs. Count a zero only when the graph meets the axis.
Step 3
Exam Tip
\(x^2+4\) हमेशा धनात्मक है इसलिए (y=0) नहीं होता। ग्राफ से शून्यक तभी मानें जब अक्ष से मिलन हो।
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यदि किसी रैखिक बहुपद का ग्राफ (x)-अक्ष के समानांतर है और (x)-अक्ष पर नहीं है तो उसके शून्यक कितने होंगे?
If the graph of a linear polynomial is parallel to the (x)-axis and not on the (x)-axis, how many zeroes will it have?
#linear-polynomial
#no-zero
#graph
A शून्य / Zero
B एक / One
C दो / Two
D अनंत / Infinite
Explanation opens after your attempt
Correct Answer
A. शून्य / Zero
Step 1
Concept
Such a line never meets the (x)-axis so it has no zero. First check the intercept from the graph.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. Such a line never meets the (x)-axis so it has no zero. First check the intercept from the graph.
Step 3
Exam Tip
ऐसी रेखा कभी (x)-अक्ष से नहीं मिलती इसलिए कोई शून्यक नहीं होता। ग्राफ से पहले प्रतिच्छेद देखें।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को तीन अलग बिंदुओं पर काटता है, तो बहुपद की न्यूनतम संभावित घात क्या हो सकती है?
If a polynomial graph cuts the (x)-axis at three distinct points, what can be the minimum possible degree of the polynomial?
#degree
#minimum degree
#zeroes
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
For three distinct real zeroes, the degree must be at least (3). Tip: the number of distinct zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is C. (3). For three distinct real zeroes, the degree must be at least (3). Tip: the number of distinct zeroes cannot exceed the degree.
Step 3
Exam Tip
तीन अलग वास्तविक शून्यकों के लिए घात कम से कम (3) होनी चाहिए। टिप: अलग शून्यकों की संख्या घात से अधिक नहीं हो सकती।
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यदि (p(x)=0) शून्य बहुपद है तो उसके शून्यकों के बारे में कौन सा कथन सही है?
If (p(x)=0) is the zero polynomial, which statement about its zeroes is correct?
#zero polynomial all zeroes
A केवल (0) शून्यक है / Only (0) is a zero
B हर वास्तविक (x) शून्यक है / Every real (x) is a zero
C कोई शून्यक नहीं है / There is no zero
D केवल धनात्मक (x) शून्यक हैं / Only positive (x) values are zeroes
Explanation opens after your attempt
Correct Answer
B. हर वास्तविक (x) शून्यक है / Every real (x) is a zero
Step 1
Concept
The zero polynomial gives (0) for every (x). Tip: treat it differently from a usual constant polynomial.
Step 2
Why this answer is correct
The correct answer is B. हर वास्तविक (x) शून्यक है / Every real (x) is a zero. The zero polynomial gives (0) for every (x). Tip: treat it differently from a usual constant polynomial.
Step 3
Exam Tip
शून्य बहुपद हर (x) पर (0) देता है। टिप: इसे सामान्य स्थिर बहुपद से अलग समझें।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को पाँच अलग बिंदुओं पर काटता है तो बहुपद की न्यूनतम घात क्या हो सकती है?
If a polynomial graph cuts the (x)-axis at five distinct points, what can be the minimum degree of the polynomial?
#degree zero count
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
For five distinct real zeroes the degree must be at least (5). Tip: the number of zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is D. (5). For five distinct real zeroes the degree must be at least (5). Tip: the number of zeroes cannot exceed the degree.
Step 3
Exam Tip
पाँच अलग वास्तविक शून्यकों के लिए घात कम से कम (5) होनी चाहिए। टिप: शून्यकों की संख्या घात से अधिक नहीं हो सकती।
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यदि (p(x)=0) शून्य बहुपद है तो उसके आलेख पर कौन सा कथन सही है?
If (p(x)=0) is the zero polynomial, which statement about its graph is correct?
#zero polynomial graph
A आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself
B आलेख (y)-अक्ष ही है / The graph is the (y)-axis itself
C आलेख (x)-अक्ष के ऊपर है / The graph is above the (x)-axis
D आलेख (x)-अक्ष को नहीं छूता / The graph does not touch the (x)-axis
Explanation opens after your attempt
Correct Answer
A. आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself
Step 1
Concept
For the zero polynomial, (y=0) for every (x). Tip: this is a special case.
Step 2
Why this answer is correct
The correct answer is A. आलेख (x)-अक्ष ही है / The graph is the (x)-axis itself. For the zero polynomial, (y=0) for every (x). Tip: this is a special case.
Step 3
Exam Tip
शून्य बहुपद में हर (x) पर (y=0) होता है। टिप: यह विशेष स्थिति है।
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अशून्य स्थिर बहुपद (p(x)=5) के आलेख का (x)-अक्ष से संबंध क्या है?
What is the relation of the graph of the non-zero constant polynomial (p(x)=5) with the (x)-axis?
#constant polynomial graph
A यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
B यह (x)-अक्ष को दो बार काटता है / It cuts the (x)-axis twice
C यह मूल बिंदु से गुजरता है / It passes through the origin
D यह (y)-अक्ष के समांतर है / It is parallel to the (y)-axis
Explanation opens after your attempt
Correct Answer
A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it
Step 1
Concept
The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 2
Why this answer is correct
The correct answer is A. यह (x)-अक्ष के समांतर है और उसे नहीं काटता / It is parallel to the (x)-axis and does not cut it. The value (p(x)=5) is never (0) so it has no zero. Tip: a non-zero constant polynomial has no zero.
Step 3
Exam Tip
(p(x)=5) कभी (0) नहीं होता इसलिए शून्यक नहीं है। टिप: अशून्य स्थिर बहुपद का शून्यक नहीं होता।
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शून्य बहुपद (p(x)=0) का हर (x)-मान क्या कहलाता है?
For the zero polynomial (p(x)=0) what is every (x)-value called?
#zero polynomial concept
A शून्यक / Zero
B केवल धनात्मक संख्या / Only positive number
C केवल ऋणात्मक संख्या / Only negative number
D कोई शून्यक नहीं / No zero
Explanation opens after your attempt
Correct Answer
A. शून्यक / Zero
Step 1
Concept
For the zero polynomial the value is (0) for every (x). Tip: this is a special case.
Step 2
Why this answer is correct
The correct answer is A. शून्यक / Zero. For the zero polynomial the value is (0) for every (x). Tip: this is a special case.
Step 3
Exam Tip
शून्य बहुपद में हर (x) पर मान (0) होता है। टिप: यह विशेष स्थिति है।
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किसी स्थिर अशून्य बहुपद (p(x)=-3) का ग्राफ (x)-अक्ष को क्यों नहीं काटता?
Why does the graph of the non-zero constant polynomial (p(x)=-3) not cut the (x)-axis?
#constant-polynomial
#no-zero
#x-axis
#easy
A क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
B क्योंकि (x) हमेशा (-3) रहता है / Because (x) always remains (-3)
C क्योंकि ग्राफ पर कोई बिंदु नहीं होता / Because the graph has no point
D क्योंकि यह परवलय है / Because it is a parabola
Explanation opens after your attempt
Correct Answer
A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3)
Step 1
Concept
For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (y) हमेशा (-3) रहता है / Because (y) always remains (-3). For (p(x)=-3), the (y)-value is never (0). So the graph does not cut the (x)-axis and has no zero.
Step 3
Exam Tip
(p(x)=-3) का (y)-मान कभी (0) नहीं होता। इसलिए ग्राफ (x)-अक्ष को नहीं काटता और कोई शून्यक नहीं है।
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किस बहुपद का ग्राफ (x)-अक्ष को (x=0) पर काटेगा?
Which polynomial graph will cut the (x)-axis at (x=0)?
#condition-for-zero
#origin
#x-axis
#polynomial
A जिसके लिए (p(0)=0) / One for which (p(0)=0)
B जिसके लिए (p(0)=5) / One for which (p(0)=5)
C जिसके लिए (p(1)=0) / One for which (p(1)=0)
D जिसके लिए (p(-1)=1) / One for which (p(-1)=1)
Explanation opens after your attempt
Correct Answer
A. जिसके लिए (p(0)=0) / One for which (p(0)=0)
Step 1
Concept
To cut the (x)-axis at (x=0), the (y)-value must be (0). Hence (p(0)=0) is required.
Step 2
Why this answer is correct
The correct answer is A. जिसके लिए (p(0)=0) / One for which (p(0)=0). To cut the (x)-axis at (x=0), the (y)-value must be (0). Hence (p(0)=0) is required.
Step 3
Exam Tip
(x=0) पर (x)-अक्ष से कटने के लिए (y=0) होना चाहिए। इसलिए (p(0)=0) होना जरूरी है।
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यदि रेखा (y=2x-6) (x)-अक्ष को काटती है, तो संबंधित रैखिक बहुपद का शून्यक क्या है?
If the line (y=2x-6) cuts the (x)-axis, what is the zero of the related linear polynomial?
#linear-graph
#x-intercept
#zero
#polynomial
A (3)
B (-3)
C (6)
D (-6)
Explanation opens after your attempt
Step 1
Concept
On the (x)-axis, (y=0), so (2x-6=0) gives (x=3). This is the graphical zero.
Step 2
Why this answer is correct
The correct answer is A. (3). On the (x)-axis, (y=0), so (2x-6=0) gives (x=3). This is the graphical zero.
Step 3
Exam Tip
(x)-अक्ष पर (y=0), इसलिए (2x-6=0) से (x=3) मिलता है। यही ग्राफीय शून्यक है।
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यदि किसी द्विघात बहुपद का ग्राफ (x)-अक्ष को ((2,0)) और ((7,0)) पर काटता है, तो शून्यक कौन-से हैं?
If the graph of a quadratic polynomial cuts the (x)-axis at ((2,0)) and ((7,0)), what are the zeroes?
#quadratic-polynomial
#x-intercepts
#zeroes
#graph
A (2) और (7) / (2) and (7)
B (-2) और (-7) / (-2) and (-7)
C (0) और (7) / (0) and (7)
D (2) और (0) / (2) and (0)
Explanation opens after your attempt
Correct Answer
A. (2) और (7) / (2) and (7)
Step 1
Concept
Zeroes are the (x)-coordinates of the points where the graph cuts the (x)-axis. So the zeroes are (2) and (7).
Step 2
Why this answer is correct
The correct answer is A. (2) और (7) / (2) and (7). Zeroes are the (x)-coordinates of the points where the graph cuts the (x)-axis. So the zeroes are (2) and (7).
Step 3
Exam Tip
शून्यक (x)-अक्ष पर कटने वाले बिंदुओं के (x)-निर्देशांक होते हैं। इसलिए शून्यक (2) और (7) हैं।
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किस स्थिति में (x=2) बहुपद (p(x)) का शून्यक कहलाएगा?
In which situation will (x=2) be called a zero of polynomial (p(x))?
#definition
#zero-of-polynomial
#value-test
#easy
A जब (p(2)=0) हो / When (p(2)=0)
B जब (p(0)=2) हो / When (p(0)=2)
C जब (p(2)=2) हो / When (p(2)=2)
D जब (p(x)=2) हो / When (p(x)=2)
Explanation opens after your attempt
Correct Answer
A. जब (p(2)=0) हो / When (p(2)=0)
Step 1
Concept
A value is called a zero only when the polynomial value at that point is (0). So for (x=2), (p(2)=0) is required.
Step 2
Why this answer is correct
The correct answer is A. जब (p(2)=0) हो / When (p(2)=0). A value is called a zero only when the polynomial value at that point is (0). So for (x=2), (p(2)=0) is required.
Step 3
Exam Tip
किसी मान को शून्यक तभी कहते हैं जब उस पर बहुपद का मान (0) हो। इसलिए (x=2) के लिए (p(2)=0) होना चाहिए।
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यदि किसी बहुपद के ग्राफ के (x)-अक्ष से दो कटाव हैं, तो उसके वास्तविक शून्यकों की संख्या क्या होगी?
If a polynomial graph has two intersections with the (x)-axis, how many real zeroes does it have?
#real-zeroes
#x-axis-intersections
#polynomial-graph
#easy
A दो / Two
B एक / One
C कोई नहीं / None
D चार / Four
Explanation opens after your attempt
Step 1
Concept
Each distinct intersection with the (x)-axis gives one real zero. With two intersections, there are two real zeroes.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. Each distinct intersection with the (x)-axis gives one real zero. With two intersections, there are two real zeroes.
Step 3
Exam Tip
(x)-अक्ष से प्रत्येक अलग कटाव एक वास्तविक शून्यक देता है। दो कटाव होने पर दो वास्तविक शून्यक होंगे।
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किसी स्थिर अशून्य बहुपद जैसे (p(x)=5) के ग्राफ से शून्यकों के बारे में क्या पता चलता है?
What does the graph of a non-zero constant polynomial like (p(x)=5) show about its zeroes?
#constant-polynomial
#no-zero
#graph
#easy
A कोई शून्यक नहीं / No zero
B एक शून्यक / One zero
C दो शून्यक / Two zeroes
D अनंत शून्यक / Infinite zeroes
Explanation opens after your attempt
Correct Answer
A. कोई शून्यक नहीं / No zero
Step 1
Concept
The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 2
Why this answer is correct
The correct answer is A. कोई शून्यक नहीं / No zero. The graph of (p(x)=5) is a line parallel to the (x)-axis and does not cut it. Hence it has no zero.
Step 3
Exam Tip
(p(x)=5) का ग्राफ (x)-अक्ष के समानांतर रेखा है जो (x)-अक्ष को नहीं काटती। इसलिए इसका कोई शून्यक नहीं है।
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यदि ग्राफ (x)-अक्ष को ((0,0)) पर काटता है, तो बहुपद का एक शून्यक क्या होगा?
If a graph cuts the (x)-axis at ((0,0)), what is one zero of the polynomial?
#origin
#zero-of-polynomial
#x-intercept
#easy
A (0)
B (1)
C (-1)
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
The (x)-coordinate of ((0,0)) is (0). Therefore (0) is one zero of the polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). The (x)-coordinate of ((0,0)) is (0). Therefore (0) is one zero of the polynomial.
Step 3
Exam Tip
बिंदु ((0,0)) का (x)-निर्देशांक (0) है। इसलिए (0) बहुपद का एक शून्यक होगा।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को नहीं काटता और नहीं छूता, तो उसके वास्तविक शून्यकों की संख्या क्या होगी?
If the graph of a polynomial neither cuts nor touches the (x)-axis, how many real zeroes does it have?
#real-zeroes
#no-intersection
#polynomial-graph
#easy
A (0)
B (1)
C (2)
D अनंत / Infinite
Explanation opens after your attempt
Step 1
Concept
Real zeroes appear only where the graph meets the (x)-axis. If it does not meet the (x)-axis, it has no real zero.
Step 2
Why this answer is correct
The correct answer is A. (0). Real zeroes appear only where the graph meets the (x)-axis. If it does not meet the (x)-axis, it has no real zero.
Step 3
Exam Tip
वास्तविक शून्यक तभी दिखते हैं जब ग्राफ (x)-अक्ष से मिले। यदि ग्राफ (x)-अक्ष से नहीं मिलता, तो वास्तविक शून्यक नहीं होंगे।
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यदि किसी रैखिक बहुपद का ग्राफ (x)-अक्ष को केवल एक बार काटता है, तो उसके कितने शून्यक होंगे?
If the graph of a linear polynomial cuts the (x)-axis only once, how many zeroes will it have?
#linear-polynomial
#zeroes
#graph
#easy
A एक / One
B दो / Two
C तीन / Three
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
The graph of a linear polynomial is a line and usually cuts the (x)-axis once. Therefore it has one zero.
Step 2
Why this answer is correct
The correct answer is A. एक / One. The graph of a linear polynomial is a line and usually cuts the (x)-axis once. Therefore it has one zero.
Step 3
Exam Tip
रैखिक बहुपद का ग्राफ एक रेखा होता है और सामान्यतः (x)-अक्ष को एक बार काटता है। इसलिए उसका एक शून्यक होता है।
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यदि ग्राफ (x)-अक्ष को ((-2,0)) और ((4,0)) पर काटता है, तो बहुपद के शून्यक कौन-से हैं?
If a graph cuts the (x)-axis at ((-2,0)) and ((4,0)), what are the zeroes of the polynomial?
#x-intercepts
#zeroes
#polynomial-graph
#class-10
A (-2) और (4) / (-2) and (4)
B (2) और (-4) / (2) and (-4)
C (0) और (4) / (0) and (4)
D (-2) और (0) / (-2) and (0)
Explanation opens after your attempt
Correct Answer
A. (-2) और (4) / (-2) and (4)
Step 1
Concept
Zeroes are the (x)-coordinates of the points where the graph meets the (x)-axis. So the zeroes are (-2) and (4).
Step 2
Why this answer is correct
The correct answer is A. (-2) और (4) / (-2) and (4). Zeroes are the (x)-coordinates of the points where the graph meets the (x)-axis. So the zeroes are (-2) and (4).
Step 3
Exam Tip
शून्यक हमेशा (x)-अक्ष पर कटने वाले बिंदुओं के (x)-निर्देशांक होते हैं। इसलिए शून्यक (-2) और (4) हैं।
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निम्न में से किस बहुपद में प्रमुख गुणांक (1) नहीं है?
Which of the following polynomials does not have leading coefficient (1)?
#leading-coefficient
#monic-polynomial
#classification
A \(x^3+2x+5\)
B \(x^2-4\)
C \(3x^2+x+1\)
D \(x^5-x\)
Explanation opens after your attempt
Correct Answer
C. \(3x^2+x+1\)
Step 1
Concept
The leading term of \(3x^2+x+1\) is \(3x^2\). Its leading coefficient is (3), not (1).
Step 2
Why this answer is correct
The correct answer is C. \(3x^2+x+1\). The leading term of \(3x^2+x+1\) is \(3x^2\). Its leading coefficient is (3), not (1).
Step 3
Exam Tip
\(3x^2+x+1\) का प्रमुख पद \(3x^2\) है। इसका प्रमुख गुणांक (3) है, (1) नहीं।
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यदि (x-a), (x-b) और (x-c) किसी घन बहुपद के गुणनखंड हैं, तो उसका एक संभावित बहुपद कौन सा है?
If (x-a), (x-b), and (x-c) are factors of a cubic polynomial, which is a possible polynomial?
#polynomials
#cubic
#factors
#hard
A (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
B (x-3 +(a+b+c)x-2 +(ab+bc+ca)x+abc)
C (x-3 -(ab+bc+ca)x-2 +(a+b+c)x-abc)
D (x-3 +abcx-2 -(a+b+c)x+ab+bc+ca)
Explanation opens after your attempt
Correct Answer
A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
Step 1
Concept
Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 2
Why this answer is correct
The correct answer is A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc). Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 3
Exam Tip
((x-a)(x-b)(x-c)) फैलाने पर पहला रूप मिलता है। शून्यकों और गुणनखंडों का संबंध याद रखें।
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बहुपद (p(x)=ax-3 +bx-2 +cx+d) में \(a\ne0\) है। यदि (p(x)) को रैखिक बहुपद कहा जाए, तो यह कथन क्यों गलत है?
In the polynomial (p(x)=ax-3 +bx-2 +cx+d), \(a\ne0\). Why is it wrong to call (p(x)) a linear polynomial?
#polynomials
#degree
#cubic
#hard
A क्योंकि घात (1) है / Because degree is (1)
B क्योंकि घात (2) है / Because degree is (2)
C क्योंकि घात (3) है / Because degree is (3)
D क्योंकि स्थिर पद (d) है / Because constant term is (d)
Explanation opens after your attempt
Correct Answer
C. क्योंकि घात (3) है / Because degree is (3)
Step 1
Concept
The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि घात (3) है / Because degree is (3). The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद घन है। परीक्षा में हमेशा सबसे बड़े शून्येतर घातांक को देखें।
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कौन-सा बहुपद स्थिर बहुपद है?
Which polynomial is a constant polynomial?
#constant_polynomial
#classification
#basics
A (3x+2)
B \(x^2-1\)
C \(-7\)
D \(x^3\)
Explanation opens after your attempt
Step 1
Concept
A constant polynomial has no variable. The number (-7) is a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is C. \(-7\). A constant polynomial has no variable. The number (-7) is a non-zero constant polynomial.
Step 3
Exam Tip
स्थिर बहुपद में चर नहीं होता। (-7) शून्य से भिन्न स्थिर बहुपद है।
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कौन-सा बहुपद घन बहुपद है?
Which polynomial is a cubic polynomial?
#cubic_polynomial
#degree
#classification
A \(x^3-2x+1\)
B \(x^2+4\)
C (7x-9)
D (5)
Explanation opens after your attempt
Correct Answer
A. \(x^3-2x+1\)
Step 1
Concept
A cubic polynomial has degree (3). The highest power in \(x^3-2x+1\) is (3).
Step 2
Why this answer is correct
The correct answer is A. \(x^3-2x+1\). A cubic polynomial has degree (3). The highest power in \(x^3-2x+1\) is (3).
Step 3
Exam Tip
घन बहुपद की घात (3) होती है। \(x^3-2x+1\) की सबसे बड़ी घात (3) है।
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कौन-सा बहुपद रैखिक बहुपद है?
Which polynomial is a linear polynomial?
#linear_polynomial
#degree
#classification
A \(x^2+1\)
B (3x-8)
C \(x^3+x\)
D (6)
Explanation opens after your attempt
Step 1
Concept
A linear polynomial has degree (1). The highest power in (3x-8) is (1).
Step 2
Why this answer is correct
The correct answer is B. (3x-8). A linear polynomial has degree (1). The highest power in (3x-8) is (1).
Step 3
Exam Tip
रैखिक बहुपद की घात (1) होती है। (3x-8) की सबसे बड़ी घात (1) है।
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कौन-सा बहुपद द्विघात बहुपद है?
Which polynomial is a quadratic polynomial?
#quadratic_polynomial
#degree
#classification
A (2x+5)
B \(x^2-4x+1\)
C \(x^3+1\)
D (8)
Explanation opens after your attempt
Correct Answer
B. \(x^2-4x+1\)
Step 1
Concept
A quadratic polynomial has degree (2). In \(x^2-4x+1\), the highest power is (2).
Step 2
Why this answer is correct
The correct answer is B. \(x^2-4x+1\). A quadratic polynomial has degree (2). In \(x^2-4x+1\), the highest power is (2).
Step 3
Exam Tip
द्विघात बहुपद की घात (2) होती है। \(x^2-4x+1\) में सबसे बड़ी घात (2) है।
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यदि \(5+\sqrt{21}\) किसी परिमेय गुणांक वाले द्विघात बहुपद का शून्यक है, तो उस बहुपद का एक संभव रूप कौन सा है?
If \(5+\sqrt{21}\) is a zero of a quadratic polynomial with rational coefficients, which is one possible form of that polynomial?
#polynomial-from-zero
#conjugate-roots
#irrational-numbers
A \(x^2-10x+4\)
B \(x^2+10x+4\)
C \(x^2-5x+21\)
D \(x^2-10x+46\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+4\)
Step 1
Concept
The other zero will be \(5-\sqrt{21}\). Sum (10) and product (25-21=4) give the polynomial \(x^2-10x+4\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+4\). The other zero will be \(5-\sqrt{21}\). Sum (10) and product (25-21=4) give the polynomial \(x^2-10x+4\).
Step 3
Exam Tip
दूसरा शून्यक \(5-\sqrt{21}\) होगा। योग (10) और गुणनफल (25-21=4) से बहुपद \(x^2-10x+4\) बनता है।
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यदि किसी परिमेय गुणांकों वाले द्विघात बहुपद का एक शून्यक \(6-2\sqrt{5}\) है, तो उस बहुपद का एक संभव रूप क्या है?
If one zero of a quadratic polynomial with rational coefficients is \(6-2\sqrt{5}\), what is one possible form of that polynomial?
#conjugate-zeroes
#polynomial-formation
#final
A \(x^2-12x+16\)
B \(x^2-6x+20\)
C \(x^2+12x+16\)
D \(x^2-12x+20\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-12x+16\)
Step 1
Concept
The other zero is \(6+2\sqrt{5}\). The sum is (12) and product is (36-20=16), so the polynomial is \(x^2-12x+16\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-12x+16\). The other zero is \(6+2\sqrt{5}\). The sum is (12) and product is (36-20=16), so the polynomial is \(x^2-12x+16\).
Step 3
Exam Tip
दूसरा शून्यक \(6+2\sqrt{5}\) होगा। योग (12) और गुणनफल (36-20=16), इसलिए बहुपद \(x^2-12x+16\) है।
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यदि किसी बहुपद के ग्राफ में (x)-अक्ष के साथ प्रतिच्छेद बिंदुओं की संख्या (0), (1), या (2) हो सकती है और वह द्विघात है तो कौन सा कथन सबसे सही है?
If a quadratic polynomial graph may have (0), (1), or (2) intersection points with the (x)-axis, which statement is most correct?
#quadratic-summary
#geometrical-meaning
#conceptual
A वास्तविक शून्यकों की संख्या प्रतिच्छेदों की संख्या के बराबर होती है / The number of real zeroes equals the number of intersection points
B हर द्विघात के ठीक दो वास्तविक शून्यक होते हैं / Every quadratic has exactly two real zeroes
C हर द्विघात का कोई वास्तविक शून्यक नहीं होता / Every quadratic has no real zero
D प्रतिच्छेदों से शून्यक नहीं मिलते / Intersections do not give zeroes
Explanation opens after your attempt
Correct Answer
A. वास्तविक शून्यकों की संख्या प्रतिच्छेदों की संख्या के बराबर होती है / The number of real zeroes equals the number of intersection points
Step 1
Concept
Geometrically each (x)-axis intersection gives one real zero. A quadratic may have (0), (1), or (2) real zeroes.
Step 2
Why this answer is correct
The correct answer is A. वास्तविक शून्यकों की संख्या प्रतिच्छेदों की संख्या के बराबर होती है / The number of real zeroes equals the number of intersection points. Geometrically each (x)-axis intersection gives one real zero. A quadratic may have (0), (1), or (2) real zeroes.
Step 3
Exam Tip
ज्यामितीय अर्थ में हर (x)-अक्ष प्रतिच्छेद एक वास्तविक शून्यक देता है। द्विघात में वास्तविक शून्यक (0), (1), या (2) हो सकते हैं।
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किसी द्विघात बहुपद का ग्राफ (x)-अक्ष को नहीं छूता। उसके विविक्त वास्तविक शून्यकों की संख्या क्या होगी?
A quadratic polynomial graph does not touch the (x)-axis. What is the number of distinct real zeroes?
#quadratic
#no-intersection
#real-zeroes
A शून्य / Zero
B एक / One
C दो / Two
D अनंत / Infinite
Explanation opens after your attempt
Correct Answer
A. शून्य / Zero
Step 1
Concept
For a real zero the graph must meet the (x)-axis. No meeting means no real zero.
Step 2
Why this answer is correct
The correct answer is A. शून्य / Zero. For a real zero the graph must meet the (x)-axis. No meeting means no real zero.
Step 3
Exam Tip
वास्तविक शून्यक के लिए ग्राफ का (x)-अक्ष से मिलना जरूरी है। कोई मिलन नहीं तो कोई वास्तविक शून्यक नहीं।
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यदि बहुपद का ग्राफ (x)-अक्ष को \(\frac{1}{2}\) पर छूता है तो कौन सा कथन सही है?
If the graph of a polynomial touches the (x)-axis at \(\frac{1}{2}\), which statement is correct?
#fractional-zero
#touching
#conceptual
A \(\frac{1}{2}\) शून्यक है / \(\frac{1}{2}\) is a zero
B केवल पूर्णांक शून्यक होते हैं / Only integers are zeroes
C यह शून्यक नहीं है क्योंकि ग्राफ नहीं काटता / It is not a zero because the graph does not cross
D शून्यक (2) है / The zero is (2)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\) शून्यक है / \(\frac{1}{2}\) is a zero
Step 1
Concept
A zero can be a fraction and touching is enough. The key point is (p\left\(\frac{1}{2}\right\)=0).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\) शून्यक है / \(\frac{1}{2}\) is a zero. A zero can be a fraction and touching is enough. The key point is (p\left\(\frac{1}{2}\right\)=0).
Step 3
Exam Tip
शून्यक भिन्न भी हो सकता है और छूना पर्याप्त है। जरूरी बात (p\left\(\frac{1}{2}\right\)=0) है।
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किसी बहुपद का ग्राफ (x)-अक्ष को केवल सम संख्याओं (-4), (2), और (8) पर काटता है। शून्यकों की संख्या क्या है?
A polynomial graph cuts the (x)-axis only at the even numbers (-4), (2), and (8). What is the number of zeroes?
#counting-zeroes
#graph
#integer-zeroes
A तीन / Three
B दो / Two
C छह / Six
D एक / One
Explanation opens after your attempt
Correct Answer
A. तीन / Three
Step 1
Concept
Three distinct (x)-intercepts give three zeroes. Count by intersections not by the type of numbers.
Step 2
Why this answer is correct
The correct answer is A. तीन / Three. Three distinct (x)-intercepts give three zeroes. Count by intersections not by the type of numbers.
Step 3
Exam Tip
तीन अलग (x)-प्रतिच्छेद तीन शून्यक देते हैं। संख्या के प्रकार से नहीं बल्कि प्रतिच्छेदों से गिनें।
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यदि किसी द्विघात का ग्राफ (x)-अक्ष को ((m,0)) और ((n,0)) पर काटता है तो कौन सा बहुपद उन्हीं शून्यकों वाला हो सकता है?
If a quadratic graph cuts the (x)-axis at ((m,0)) and ((n,0)), which polynomial can have the same zeroes?
#factor-form
#symbolic
#quadratic
A (k(x-m)(x-n)), जहाँ \(k\neq0\) / (k(x-m)(x-n)), where \(k\neq0\)
B (k(x+m)(x+n)) हमेशा / (k(x+m)(x+n)) always
C (k(x-m+n))
D (k\(x^2+m+n\))
Explanation opens after your attempt
Correct Answer
A. (k(x-m)(x-n)), जहाँ \(k\neq0\) / (k(x-m)(x-n)), where \(k\neq0\)
Step 1
Concept
For zeroes (m) and (n), the factors are ((x-m)) and ((x-n)). A non-zero multiplier does not change zeroes.
Step 2
Why this answer is correct
The correct answer is A. (k(x-m)(x-n)), जहाँ \(k\neq0\) / (k(x-m)(x-n)), where \(k\neq0\). For zeroes (m) and (n), the factors are ((x-m)) and ((x-n)). A non-zero multiplier does not change zeroes.
Step 3
Exam Tip
शून्यक (m) और (n) के लिए गुणनखंड ((x-m)) और ((x-n)) होते हैं। गैर शून्य गुणक शून्यक नहीं बदलता।
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किसी बहुपद का ग्राफ (x)-अक्ष को ((r,0)) पर मिलता है। कौन सा कथन हमेशा सत्य है?
A polynomial graph meets the (x)-axis at ((r,0)). Which statement is always true?
#symbolic
#definition
#x-intercept
A (p(r)=0)
B (p(0)=r)
C (r=0)
D (p(r)=r)
Explanation opens after your attempt
Correct Answer
A. (p(r)=0)
Step 1
Concept
((r,0)) means (y=0) when (x=r). This is the definition of a zero.
Step 2
Why this answer is correct
The correct answer is A. (p(r)=0). ((r,0)) means (y=0) when (x=r). This is the definition of a zero.
Step 3
Exam Tip
((r,0)) का अर्थ (x=r) पर (y=0) है। यही शून्यक की परिभाषा है।
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किसी बहुपद के ग्राफ में (y)-अक्ष से प्रतिच्छेद ((0,-8)) है। इससे शून्यक के बारे में कौन सा निष्कर्ष सही है?
A polynomial graph has (y)-intercept ((0,-8)). Which conclusion about zeroes is correct?
#y-intercept
#common-mistake
#zeroes
A इससे शून्यक निश्चित नहीं होता / A zero cannot be determined from this alone
B शून्यक (-8) है / The zero is (-8)
C शून्यक (0) है / The zero is (0)
D शून्यक (8) है / The zero is (8)
Explanation opens after your attempt
Correct Answer
A. इससे शून्यक निश्चित नहीं होता / A zero cannot be determined from this alone
Step 1
Concept
The (y)-intercept tells (p(0)) not all zeroes. Zeroes need (x)-axis intersections.
Step 2
Why this answer is correct
The correct answer is A. इससे शून्यक निश्चित नहीं होता / A zero cannot be determined from this alone. The (y)-intercept tells (p(0)) not all zeroes. Zeroes need (x)-axis intersections.
Step 3
Exam Tip
(y)-प्रतिच्छेद (p(0)) बताता है न कि सभी शून्यक। शून्यक के लिए (x)-अक्ष से प्रतिच्छेद चाहिए।
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यदि किसी द्विघात बहुपद के ग्राफ का शीर्ष (x)-अक्ष पर है तो वास्तविक शून्यकों के बारे में क्या सही है?
If the vertex of a quadratic polynomial graph lies on the (x)-axis, what is correct about its real zeroes?
#vertex
#equal-zeroes
#quadratic
A दोनों वास्तविक शून्यक समान हैं / Both real zeroes are equal
B दोनों वास्तविक शून्यक भिन्न हैं / Both real zeroes are distinct
C कोई वास्तविक शून्यक नहीं है / There is no real zero
D तीन वास्तविक शून्यक हैं / There are three real zeroes
Explanation opens after your attempt
Correct Answer
A. दोनों वास्तविक शून्यक समान हैं / Both real zeroes are equal
Step 1
Concept
When the vertex lies on the (x)-axis, the parabola touches the axis at one point. Hence the zeroes are equal.
Step 2
Why this answer is correct
The correct answer is A. दोनों वास्तविक शून्यक समान हैं / Both real zeroes are equal. When the vertex lies on the (x)-axis, the parabola touches the axis at one point. Hence the zeroes are equal.
Step 3
Exam Tip
शीर्ष (x)-अक्ष पर होने पर परवलय अक्ष को एक ही बिंदु पर छूता है। इसलिए शून्यक समान होते हैं।
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एक बहुपद का ग्राफ (x)-अक्ष को ((-5,0)) पर काटता और ((2,0)) पर छूता है। उसके वास्तविक शून्यकों की संख्या क्या है?
A polynomial graph cuts the (x)-axis at ((-5,0)) and touches it at ((2,0)). What is the number of real zeroes?
#touch-cross
#real-zeroes
#graph
A दो / Two
B एक / One
C तीन / Three
D शून्य / Zero
Explanation opens after your attempt
Step 1
Concept
The two different (x)-values (-5) and (2) are zeroes. Touching also gives a zero.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. The two different (x)-values (-5) and (2) are zeroes. Touching also gives a zero.
Step 3
Exam Tip
दो अलग (x)-मान (-5) और (2) शून्यक हैं। छूना भी शून्यक देता है।
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किस स्थिति में (x=3) बहुपद (p(x)) का शून्यक कहलाएगा?
In which situation will (x=3) be called a zero of polynomial (p(x))?
#definition
#zero
#function-value
A जब (p(3)=0) / When (p(3)=0)
B जब (p(0)=3) / When (p(0)=3)
C जब ग्राफ ((0,3)) से गुजरे / When the graph passes through ((0,3))
D जब (p(3)=3) / When (p(3)=3)
Explanation opens after your attempt
Correct Answer
A. जब (p(3)=0) / When (p(3)=0)
Step 1
Concept
A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 2
Why this answer is correct
The correct answer is A. जब (p(3)=0) / When (p(3)=0). A zero is the (x)-value at which the polynomial value is zero. In exams check (p(a)=0).
Step 3
Exam Tip
शून्यक वही (x)-मान है जिस पर बहुपद का मान शून्य हो। परीक्षा में (p(a)=0) जांचें।
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किसी बहुपद का ग्राफ (x)-अक्ष से ((7,0)) पर मिलता है। उस बिंदु पर (p(x)) का मान क्या होगा?
A polynomial graph meets the (x)-axis at ((7,0)). What is the value of (p(x)) at that point?
#x-axis
#function-value
#zero
A (0)
B (7)
C (-7)
D (1)
Explanation opens after your attempt
Step 1
Concept
Every point on the (x)-axis has (y=0). Therefore (p(7)=0).
Step 2
Why this answer is correct
The correct answer is A. (0). Every point on the (x)-axis has (y=0). Therefore (p(7)=0).
Step 3
Exam Tip
(x)-अक्ष पर हर बिंदु का (y)-मान (0) होता है। इसलिए (p(7)=0) होगा।
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यदि किसी बहुपद के ग्राफ के (x)-प्रतिच्छेद ((-4,0)), ((1,0)), और ((6,0)) हैं तो शून्यकों का समुच्चय क्या है?
If the (x)-intercepts of a polynomial graph are ((-4,0)), ((1,0)), and ((6,0)), what is the set of zeroes?
#x-intercepts
#set-of-zeroes
#graph
A ({-4,1,6})
B ({0,1,6})
C ({-4,0,6})
D ({-4,1,0})
Explanation opens after your attempt
Correct Answer
A. ({-4,1,6})
Step 1
Concept
A zero is the (x)-coordinate of the intercept point. Do not write (y=0) as the zero.
Step 2
Why this answer is correct
The correct answer is A. ({-4,1,6}). A zero is the (x)-coordinate of the intercept point. Do not write (y=0) as the zero.
Step 3
Exam Tip
शून्यक प्रतिच्छेद बिंदु का (x)-निर्देशांक होता है। (y=0) को शून्यक न लिखें।
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यदि किसी घन बहुपद का ग्राफ (x)-अक्ष को (-1) पर काटता है और (2) पर छूता है तो अलग-अलग वास्तविक शून्यक कितने हैं?
If the graph of a cubic polynomial crosses the (x)-axis at (-1) and touches it at (2), how many distinct real zeroes are there?
#cubic
#distinct-zeroes
#graph
A दो / Two
B तीन / Three
C एक / One
D शून्य / Zero
Explanation opens after your attempt
Step 1
Concept
The distinct zeroes are only (-1) and (2). A touching zero may be repeated but its distinct value is counted once.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. The distinct zeroes are only (-1) and (2). A touching zero may be repeated but its distinct value is counted once.
Step 3
Exam Tip
अलग-अलग शून्यक केवल (-1) और (2) हैं। छूने वाला शून्यक दोहराया हो सकता है पर अलग मान एक ही गिना जाता है।
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एक द्विघात बहुपद का ग्राफ (x)-अक्ष को एक ही बिंदु ((4,0)) पर छूता है। उसके शून्यक कैसे होंगे?
The graph of a quadratic polynomial touches the (x)-axis at only one point ((4,0)). What type of zeroes does it have?
#quadratic
#equal-zeroes
#graph
A बराबर शून्यक (4) और (4) / Equal zeroes (4) and (4)
B भिन्न शून्यक (4) और (0) / Distinct zeroes (4) and (0)
C कोई शून्यक नहीं / No zero
D तीन शून्यक / Three zeroes
Explanation opens after your attempt
Correct Answer
A. बराबर शून्यक (4) और (4) / Equal zeroes (4) and (4)
Step 1
Concept
When a quadratic graph touches at one point its two zeroes are equal. Treat it as a repeated zero in exams.
Step 2
Why this answer is correct
The correct answer is A. बराबर शून्यक (4) और (4) / Equal zeroes (4) and (4). When a quadratic graph touches at one point its two zeroes are equal. Treat it as a repeated zero in exams.
Step 3
Exam Tip
द्विघात ग्राफ एक बिंदु पर छूता है तो दोनों शून्यक समान होते हैं। परीक्षा में इसे दोहराया शून्यक मानें।
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किसी बहुपद के ग्राफ का (x)-अक्ष को केवल छूना लेकिन पार न करना क्या दर्शाता है?
What does it indicate when the graph of a polynomial only touches the (x)-axis but does not cross it?
#polynomials
#tangent-zero
#quadratic
A वह बिंदु भी शून्यक है / That point is also a zero
B वह शून्यक नहीं है / It is not a zero
C बहुपद स्थिर है / The polynomial is constant
D डिग्री शून्य है / Degree is zero
Explanation opens after your attempt
Correct Answer
A. वह बिंदु भी शून्यक है / That point is also a zero
Step 1
Concept
For a zero it is enough that (y=0). Touching or crossing both give zeroes.
Step 2
Why this answer is correct
The correct answer is A. वह बिंदु भी शून्यक है / That point is also a zero. For a zero it is enough that (y=0). Touching or crossing both give zeroes.
Step 3
Exam Tip
शून्यक के लिए (y=0) होना पर्याप्त है। छूना या काटना दोनों शून्यक देते हैं।
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यदि किसी द्विघात बहुपद (p(x)) का ग्राफ (x)-अक्ष को (-2) और (5) पर काटता है तो उसके शून्यकों की संख्या क्या है?
If the graph of a quadratic polynomial (p(x)) cuts the (x)-axis at (-2) and (5), how many zeroes does it have?
#polynomials
#zeroes
#graphical-meaning
A दो / Two
B एक / One
C तीन / Three
D कोई नहीं / None
Explanation opens after your attempt
Step 1
Concept
A zero occurs where the graph meets the (x)-axis. In exams count the (x)-intercepts.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. A zero occurs where the graph meets the (x)-axis. In exams count the (x)-intercepts.
Step 3
Exam Tip
ग्राफ जहाँ (x)-अक्ष को काटता है वही शून्यक होता है। परीक्षा में काटने वाले बिंदुओं की संख्या गिनें।
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यदि कोई बहुपद (x)-अक्ष को आठ अलग बिंदुओं पर काटता है, तो न्यूनतम संभावित घात क्या होगी?
If a polynomial cuts the (x)-axis at eight distinct points, what is the minimum possible degree?
#minimum degree
#distinct zeroes
#graph
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
For eight distinct real zeroes, the degree must be at least (8). Tip: the number of distinct zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is C. (8). For eight distinct real zeroes, the degree must be at least (8). Tip: the number of distinct zeroes cannot exceed the degree.
Step 3
Exam Tip
आठ अलग वास्तविक शून्यकों के लिए घात कम से कम (8) होनी चाहिए। टिप: अलग शून्यकों की संख्या घात से अधिक नहीं हो सकती।
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