यदि \(x^2-5x+6=0\) के मूलों को उलटकर नया समीकरण बनाया जाए तो नया मोनिक समीकरण कौन सा होगा?
If a new equation is formed by taking reciprocals of the roots of \(x^2-5x+6=0\), which monic equation is obtained?
Explanation opens after your attempt
Correct Answer
A. \(x^2-\frac{5}{6}x+\frac{1}{6}=0\)
Concept
The old sum is (5) and product is (6). The reciprocal roots have sum \(\frac{5}{6}\) and product \(\frac{1}{6}\).
Why this answer is correct
The correct answer is A. \(x^2-\frac{5}{6}x+\frac{1}{6}=0\). The old sum is (5) and product is (6). The reciprocal roots have sum \(\frac{5}{6}\) and product \(\frac{1}{6}\).
Exam Tip
पुराने योग (5) और गुणनफल (6) हैं। उलटे मूलों का योग \(\frac{5}{6}\) और गुणनफल \(\frac{1}{6}\) होगा।
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