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If the zeroes of a quadratic polynomial are \(\alpha\) and \(\beta\), and \(\alpha+\beta=5\) and \(\alpha\beta=6\), which monic polynomial has these zeroes?

Answer and explanation

Correct answer: \(x^2-5x+6\)

The monic quadratic with zeroes \(\alpha\) and \(\beta\) is \(x^2-(\alpha+\beta)x+\alpha\beta\). Substituting the given values gives \(x^2-5x+6\), so option A is correct. Option B has a positive coefficient of \(x\), but the coefficient must be the negative of the sum of the zeroes. Exam tip: for a monic quadratic, the coefficient of \(x\) is the negative of the sum of the zeroes, and the constant term is their product.

Related tags

PolynomialsMonic PolynomialZeroes And CoefficientsQuadratic PolynomialPolynomials In One VariableMathematicsClass 10 Mcq

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