Class 10 symbolic MCQ Questions

Question 1/22 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

यदि किसी समान्तर श्रेणी का (m)वां पद (2m+3) और (d=2) है तो ((m+5))वां पद क्या होगा?

If the (m)th term of an AP is (2m+3) and (d=2), what is the ((m+5))th term?

Explanation opens after your attempt

Correct Answer

D. (2m+13)

Step 1

Concept

The ((m+5))th term is (5d) ahead of the (m)th term, so (2m+3+10=2m+13). In symbolic terms, look at the position gap.

Step 2

Why this answer is correct

The correct answer is D. (2m+13). The ((m+5))th term is (5d) ahead of the (m)th term, so (2m+3+10=2m+13). In symbolic terms, look at the position gap.

Step 3

Exam Tip

((m+5))वां पद (m)वें पद से (5d) आगे है इसलिए (2m+3+10=2m+13)। प्रतीकात्मक पदों में भी स्थान अंतर देखें।

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Question 2/22 Medium Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 64

यदि किसी AP का (p)वां पद (q) और (q)वां पद (p) है, तो उसका ((p+q))वां पद क्या होगा?

If the (p)th term of an AP is (q) and the (q)th term is (p), what is its ((p+q))th term?

Explanation opens after your attempt

Correct Answer

A. (0)

Step 1

Concept

Subtracting the relations gives (d=-1), and substitution gives $a_{p+q}=0$. Even in symbolic APs, use (a_n=a+(n-1)d).

Step 2

Why this answer is correct

The correct answer is A. (0). Subtracting the relations gives (d=-1), and substitution gives $a_{p+q}=0$. Even in symbolic APs, use (a_n=a+(n-1)d).

Step 3

Exam Tip

संबंधों को घटाने पर (d=-1) और आगे रखने पर $a_{p+q}=0$ मिलता है। प्रतीकात्मक AP में भी (a_n=a+(n-1)d) ही लगाएं।

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Question 3/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

(49x^-2-49(r+s)x+49rs=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (49x^-2-49(r+s)x+49rs=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=r,s)

Step 1

Concept

Dividing the whole equation by (49) gives (x^-2-(r+s)x+rs=0). In exams, removing the common factor first shortens the solution.

Step 2

Why this answer is correct

The correct answer is A. (x=r,s). Dividing the whole equation by (49) gives (x^-2-(r+s)x+rs=0). In exams, removing the common factor first shortens the solution.

Step 3

Exam Tip

पूरे समीकरण को (49) से भाग देने पर (x^-2-(r+s)x+rs=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना हल को छोटा करता है।

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Question 4/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

यदि $x^2-2ux+u^2-v^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2ux+u^2-v^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=u+v,u-v)

Step 1

Concept

It is ((x-u)²-v^-2=0), so $x-u=\pm v$ and $x=u\pm v$. In exams, quickly recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=u+v,u-v). It is ((x-u)²-v^-2=0), so $x-u=\pm v$ and $x=u\pm v$. In exams, quickly recognize the difference of squares.

Step 3

Exam Tip

यह ((x-u)²-v^-2=0) है, इसलिए $x-u=\pm v$ और $x=u\pm v$ हैं। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।

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Question 5/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

(x^-2-(p+q)x+pq=0) के मूल कौनसे हैं?

What are the roots of (x^-2-(p+q)x+pq=0)?

Explanation opens after your attempt

Correct Answer

A. (x=p,q)

Step 1

Concept

The equation is equivalent to ((x-p)(x-q)=0), so the roots are (p) and (q). In exams, apply zero product rule to symbolic factors too.

Step 2

Why this answer is correct

The correct answer is A. (x=p,q). The equation is equivalent to ((x-p)(x-q)=0), so the roots are (p) and (q). In exams, apply zero product rule to symbolic factors too.

Step 3

Exam Tip

यह समीकरण ((x-p)(x-q)=0) के बराबर है, इसलिए मूल (p) और (q) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।

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Question 6/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

(36x^-2-36(m+n)x+36mn=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (36x^-2-36(m+n)x+36mn=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=m,n)

Step 1

Concept

Dividing the whole equation by (36) gives (x^-2-(m+n)x+mn=0). In exams, removing the common factor first shortens the solution.

Step 2

Why this answer is correct

The correct answer is A. (x=m,n). Dividing the whole equation by (36) gives (x^-2-(m+n)x+mn=0). In exams, removing the common factor first shortens the solution.

Step 3

Exam Tip

पूरे समीकरण को (36) से भाग देने पर (x^-2-(m+n)x+mn=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना हल को छोटा करता है।

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Question 7/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

यदि $x^2-2rx+r^2-s^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2rx+r^2-s^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=r+s,r-s)

Step 1

Concept

It is ((x-r)²-s^-2=0), so $x-r=\pm s$ and $x=r\pm s$. In exams, quickly recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=r+s,r-s). It is ((x-r)²-s^-2=0), so $x-r=\pm s$ and $x=r\pm s$. In exams, quickly recognize the difference of squares.

Step 3

Exam Tip

यह ((x-r)²-s^-2=0) है, इसलिए $x-r=\pm s$ और $x=r\pm s$ हैं। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।

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Question 8/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

(x^-2-(s+t)x+st=0) के मूल कौनसे हैं?

What are the roots of (x^-2-(s+t)x+st=0)?

Explanation opens after your attempt

Correct Answer

A. (x=s,t)

Step 1

Concept

The equation is equivalent to ((x-s)(x-t)=0), so the roots are (s) and (t). In exams, apply zero product rule to symbolic factors too.

Step 2

Why this answer is correct

The correct answer is A. (x=s,t). The equation is equivalent to ((x-s)(x-t)=0), so the roots are (s) and (t). In exams, apply zero product rule to symbolic factors too.

Step 3

Exam Tip

यह समीकरण ((x-s)(x-t)=0) के बराबर है, इसलिए मूल (s) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।

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Question 9/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

(25x^-2-25(a+b)x+25ab=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (25x^-2-25(a+b)x+25ab=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=a,b)

Step 1

Concept

Dividing the whole equation by (25) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first shortens the solution.

Step 2

Why this answer is correct

The correct answer is A. (x=a,b). Dividing the whole equation by (25) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first shortens the solution.

Step 3

Exam Tip

पूरे समीकरण को (25) से भाग देने पर (x^-2-(a+b)x+ab=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना हल को छोटा करता है।

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Question 10/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

यदि $x^2-2cx+c^2-d^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2cx+c^2-d^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=c+d,c-d)

Step 1

Concept

It is ((x-c)²-d^-2=0), so $x-c=\pm d$ and $x=c\pm d$. In exams, quickly recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=c+d,c-d). It is ((x-c)²-d^-2=0), so $x-c=\pm d$ and $x=c\pm d$. In exams, quickly recognize the difference of squares.

Step 3

Exam Tip

यह ((x-c)²-d^-2=0) है, इसलिए $x-c=\pm d$ और $x=c\pm d$ हैं। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।

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Question 11/22 Expert Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

(x^-2-(r+t)x+rt=0) के मूल कौनसे हैं?

What are the roots of (x^-2-(r+t)x+rt=0)?

Explanation opens after your attempt

Correct Answer

A. (x=r,t)

Step 1

Concept

The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

Step 2

Why this answer is correct

The correct answer is A. (x=r,t). The equation is equivalent to ((x-r)(x-t)=0), so the roots are (r) and (t). In exams, apply zero product rule to symbolic factors too.

Step 3

Exam Tip

यह समीकरण ((x-r)(x-t)=0) के बराबर है, इसलिए मूल (r) और (t) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी शून्य गुणनफल नियम लगाएं।

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Question 12/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

(16x^-2-16(a+b)x+16ab=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (16x^-2-16(a+b)x+16ab=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=a,b)

Step 1

Concept

Dividing the whole equation by (16) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first makes solving easier.

Step 2

Why this answer is correct

The correct answer is A. (x=a,b). Dividing the whole equation by (16) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first makes solving easier.

Step 3

Exam Tip

पूरे समीकरण को (16) से भाग देने पर (x^-2-(a+b)x+ab=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना हल को आसान करता है।

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Question 13/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

यदि $x^2-2mx+m^2-n^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2mx+m^2-n^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=m+n,m-n)

Step 1

Concept

It is ((x-m)²-n^-2=0), so $x-m=\pm n$ and $x=m\pm n$. In exams, recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=m+n,m-n). It is ((x-m)²-n^-2=0), so $x-m=\pm n$ and $x=m\pm n$. In exams, recognize the difference of squares.

Step 3

Exam Tip

यह ((x-m)²-n^-2=0) है, इसलिए $x-m=\pm n$ और $x=m\pm n$ हैं। परीक्षा में वर्गों के अंतर को पहचानें।

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Question 14/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

(x^-2-(u+v)x+uv=0) के मूल कौनसे हैं?

What are the roots of (x^-2-(u+v)x+uv=0)?

Explanation opens after your attempt

Correct Answer

A. (x=u,v)

Step 1

Concept

The equation is equivalent to ((x-u)(x-v)=0), so the roots are (u) and (v). In exams, apply the same rule to symbolic factors.

Step 2

Why this answer is correct

The correct answer is A. (x=u,v). The equation is equivalent to ((x-u)(x-v)=0), so the roots are (u) and (v). In exams, apply the same rule to symbolic factors.

Step 3

Exam Tip

यह समीकरण ((x-u)(x-v)=0) के बराबर है, इसलिए मूल (u) और (v) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी वही नियम लागू करें।

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Question 15/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

(9x^-2-9(r+s)x+9rs=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (9x^-2-9(r+s)x+9rs=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=r,s)

Step 1

Concept

Dividing the whole equation by (9) gives (x^-2-(r+s)x+rs=0). In exams, removing the common factor first makes solving easier.

Step 2

Why this answer is correct

The correct answer is A. (x=r,s). Dividing the whole equation by (9) gives (x^-2-(r+s)x+rs=0). In exams, removing the common factor first makes solving easier.

Step 3

Exam Tip

पूरे समीकरण को (9) से भाग देने पर (x^-2-(r+s)x+rs=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाने से हल आसान होता है।

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Question 16/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

यदि $x^2-2px+p^2-q^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2px+p^2-q^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=p+q,p-q)

Step 1

Concept

It is ((x-p)²-q^-2=0), so $x-p=\pm q$ and $x=p\pm q$. In exams, recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=p+q,p-q). It is ((x-p)²-q^-2=0), so $x-p=\pm q$ and $x=p\pm q$. In exams, recognize the difference of squares.

Step 3

Exam Tip

यह ((x-p)²-q^-2=0) है, इसलिए $x-p=\pm q$ और $x=p\pm q$ हैं। परीक्षा में वर्गों के अंतर को पहचानें।

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Question 17/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

(x^-2-(m+n)x+mn=0) के मूल कौनसे हैं?

What are the roots of (x^-2-(m+n)x+mn=0)?

Explanation opens after your attempt

Correct Answer

A. (x=m,n)

Step 1

Concept

The equation is equivalent to ((x-m)(x-n)=0), so the roots are (m) and (n). In exams, the same rule applies to symbolic factors.

Step 2

Why this answer is correct

The correct answer is A. (x=m,n). The equation is equivalent to ((x-m)(x-n)=0), so the roots are (m) and (n). In exams, the same rule applies to symbolic factors.

Step 3

Exam Tip

यह समीकरण ((x-m)(x-n)=0) के बराबर है, इसलिए मूल (m) और (n) हैं। परीक्षा में प्रतीकात्मक गुणनखंडों पर भी वही नियम लागू होता है।

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Question 18/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

(4x^-2-4(a+b)x+4ab=0) को सरल करने के बाद मूल क्या होंगे?

After simplifying (4x^-2-4(a+b)x+4ab=0), what will be the roots?

Explanation opens after your attempt

Correct Answer

A. (x=a,b)

Step 1

Concept

Dividing the whole equation by (4) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first is easier.

Step 2

Why this answer is correct

The correct answer is A. (x=a,b). Dividing the whole equation by (4) gives (x^-2-(a+b)x+ab=0). In exams, removing the common factor first is easier.

Step 3

Exam Tip

पूरे समीकरण को (4) से भाग देने पर (x^-2-(a+b)x+ab=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना आसान रहता है।

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Question 19/22 Hard Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

यदि $x^2-2ax+a^2-b^2=0$, तो इसके मूल कौनसे हैं?

If $x^2-2ax+a^2-b^2=0$, what are its roots?

Explanation opens after your attempt

Correct Answer

A. (x=a+b,a-b)

Step 1

Concept

It is ((x-a)²-b^-2=0), so $x-a=\pm b$ and $x=a\pm b$. In exams, use the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. (x=a+b,a-b). It is ((x-a)²-b^-2=0), so $x-a=\pm b$ and $x=a\pm b$. In exams, use the difference of squares.

Step 3

Exam Tip

यह ((x-a)²-b^-2=0) है, इसलिए $x-a=\pm b$ और $x=a\pm b$ हैं। परीक्षा में वर्गों के अंतर का प्रयोग करें।

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Question 20/22 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि किसी द्विघात का ग्राफ (x)-अक्ष को ((m,0)) और ((n,0)) पर काटता है तो कौन सा बहुपद उन्हीं शून्यकों वाला हो सकता है?

If a quadratic graph cuts the (x)-axis at ((m,0)) and ((n,0)), which polynomial can have the same zeroes?

Explanation opens after your attempt

Correct Answer

A. (k(x-m)(x-n)), जहाँ $k\neq0$(k(x-m)(x-n)), where $k\neq0$

Step 1

Concept

For zeroes (m) and (n), the factors are ((x-m)) and ((x-n)). A non-zero multiplier does not change zeroes.

Step 2

Why this answer is correct

The correct answer is A. (k(x-m)(x-n)), जहाँ $k\neq0$ / (k(x-m)(x-n)), where $k\neq0$. For zeroes (m) and (n), the factors are ((x-m)) and ((x-n)). A non-zero multiplier does not change zeroes.

Step 3

Exam Tip

शून्यक (m) और (n) के लिए गुणनखंड ((x-m)) और ((x-n)) होते हैं। गैर शून्य गुणक शून्यक नहीं बदलता।

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Question 21/22 Expert Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

किसी बहुपद का ग्राफ (x)-अक्ष को ((r,0)) पर मिलता है। कौन सा कथन हमेशा सत्य है?

A polynomial graph meets the (x)-axis at ((r,0)). Which statement is always true?

Explanation opens after your attempt

Correct Answer

A. (p(r)=0)

Step 1

Concept

((r,0)) means (y=0) when (x=r). This is the definition of a zero.

Step 2

Why this answer is correct

The correct answer is A. (p(r)=0). ((r,0)) means (y=0) when (x=r). This is the definition of a zero.

Step 3

Exam Tip

((r,0)) का अर्थ (x=r) पर (y=0) है। यही शून्यक की परिभाषा है।

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Question 22/22 Hard Mathematics Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि किसी बहुपद के ग्राफ का (x)-अक्ष कटान ((0,0)) और ((a,0)) है, जहाँ $a\neq0$, तो शून्यकों का गुणनफल क्या होगा?

If a polynomial graph has (x)-axis intersections ((0,0)) and ((a,0)), where $a\neq0$, what will be the product of the zeroes?

Explanation opens after your attempt

Correct Answer

B. (0)

Step 1

Concept

The zeroes are (0) and (a), so the product is (0). Tip: if (0) is included, the product is (0).

Step 2

Why this answer is correct

The correct answer is B. (0). The zeroes are (0) and (a), so the product is (0). Tip: if (0) is included, the product is (0).

Step 3

Exam Tip

शून्यक (0) और (a) हैं, इसलिए गुणनफल (0) है। टिप: (0) शामिल हो तो गुणनफल (0) होगा।

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symbolic MCQ Questions for Class 10

Practice Questions

यदि किसी समान्तर श्रेणी का (m)वां पद (2m+3) और (d=2) है तो ((m+5))वां पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

यदि किसी AP का (p)वां पद (q) और (q)वां पद (p) है, तो उसका ((p+q))वां पद क्या होगा?

Concept

Why this answer is correct

Exam Tip

(49x-2-49(r+s)x+49rs=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2ux+u^2-v^2=0\), तो इसके मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(x-2-(p+q)x+pq=0) के मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(36x-2-36(m+n)x+36mn=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2rx+r^2-s^2=0\), तो इसके मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(x-2-(s+t)x+st=0) के मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(25x-2-25(a+b)x+25ab=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2cx+c^2-d^2=0\), तो इसके मूल कौनसे हैं?

Concept

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Exam Tip

(x-2-(r+t)x+rt=0) के मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(16x-2-16(a+b)x+16ab=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2mx+m^2-n^2=0\), तो इसके मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(x-2-(u+v)x+uv=0) के मूल कौनसे हैं?

Concept

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Exam Tip

(9x-2-9(r+s)x+9rs=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2px+p^2-q^2=0\), तो इसके मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(x-2-(m+n)x+mn=0) के मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

(4x-2-4(a+b)x+4ab=0) को सरल करने के बाद मूल क्या होंगे?

Concept

Why this answer is correct

Exam Tip

यदि \(x^2-2ax+a^2-b^2=0\), तो इसके मूल कौनसे हैं?

Concept

Why this answer is correct

Exam Tip

यदि किसी द्विघात का ग्राफ (x)-अक्ष को ((m,0)) और ((n,0)) पर काटता है तो कौन सा बहुपद उन्हीं शून्यकों वाला हो सकता है?

Concept

(49x^-2-49(r+s)x+49rs=0) को सरल करने के बाद मूल क्या होंगे?

(x^-2-(p+q)x+pq=0) के मूल कौनसे हैं?

(36x^-2-36(m+n)x+36mn=0) को सरल करने के बाद मूल क्या होंगे?

(x^-2-(s+t)x+st=0) के मूल कौनसे हैं?

(25x^-2-25(a+b)x+25ab=0) को सरल करने के बाद मूल क्या होंगे?

(x^-2-(r+t)x+rt=0) के मूल कौनसे हैं?

(16x^-2-16(a+b)x+16ab=0) को सरल करने के बाद मूल क्या होंगे?

(x^-2-(u+v)x+uv=0) के मूल कौनसे हैं?

(9x^-2-9(r+s)x+9rs=0) को सरल करने के बाद मूल क्या होंगे?

(x^-2-(m+n)x+mn=0) के मूल कौनसे हैं?

(4x^-2-4(a+b)x+4ab=0) को सरल करने के बाद मूल क्या होंगे?