0 reads0 ratings0 helpful
After simplifying (49x^2-49(r+s)x+49rs=0), what will be the roots?(49x^2-49(r+s)x+49rs=0) को सरल करने के बाद मूल क्या होंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=r,s)(x=r,s)
Dividing the whole equation by (49) gives (x^2-(r+s)x+rs=0). In exams, removing the common factor first shortens the solution.पूरे समीकरण को (49) से भाग देने पर (x^2-(r+s)x+rs=0) मिलता है। परीक्षा में पहले सामान्य गुणक हटाना हल को छोटा करता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
