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If (x^2-2ux+u^2-v^2=0), what are its roots?यदि (x^2-2ux+u^2-v^2=0), तो इसके मूल कौनसे हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=u+v,u-v)(x=u+v,u-v)
It is ((x-u)^2-v^2=0), so (x-u=\pm v) and (x=u\pm v). In exams, quickly recognize the difference of squares.यह ((x-u)^2-v^2=0) है, इसलिए (x-u=\pm v) और (x=u\pm v) हैं। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।
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