यदि \(x^2-2ux+u^2-v^2=0\), तो इसके मूल कौनसे हैं?
If \(x^2-2ux+u^2-v^2=0\), what are its roots?
Explanation opens after your attempt
Correct Answer
A. (x=u+v,u-v)
Concept
It is ((x-u)2-v-2=0), so \(x-u=\pm v\) and \(x=u\pm v\). In exams, quickly recognize the difference of squares.
Why this answer is correct
The correct answer is A. (x=u+v,u-v). It is ((x-u)2-v-2=0), so \(x-u=\pm v\) and \(x=u\pm v\). In exams, quickly recognize the difference of squares.
Exam Tip
यह ((x-u)2-v-2=0) है, इसलिए \(x-u=\pm v\) और \(x=u\pm v\) हैं। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।
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