यदि \(x^2-2px+p^2-q^2=0\), तो इसके मूल कौनसे हैं?
If \(x^2-2px+p^2-q^2=0\), what are its roots?
Explanation opens after your attempt
Correct Answer
A. (x=p+q,p-q)
Concept
It is ((x-p)2-q-2=0), so \(x-p=\pm q\) and \(x=p\pm q\). In exams, recognize the difference of squares.
Why this answer is correct
The correct answer is A. (x=p+q,p-q). It is ((x-p)2-q-2=0), so \(x-p=\pm q\) and \(x=p\pm q\). In exams, recognize the difference of squares.
Exam Tip
यह ((x-p)2-q-2=0) है, इसलिए \(x-p=\pm q\) और \(x=p\pm q\) हैं। परीक्षा में वर्गों के अंतर को पहचानें।
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