Concept-wise Practice

leading coefficient MCQ Questions for Class 10

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Practice Questions

15 questions tagged with leading coefficient.

बहुपद (p(z)=-6z-5+4z-4-z+8) का अग्र गुणांक क्या है?

What is the leading coefficient of (p(z)=-6z-5+4z-4-z+8)?

Explanation opens after your attempt
Correct Answer

A. (-6)

Step 1

Concept

The coefficient of the highest power term \(z^5\) is (-6). The leading coefficient is written with its sign.

Step 2

Why this answer is correct

The correct answer is A. (-6). The coefficient of the highest power term \(z^5\) is (-6). The leading coefficient is written with its sign.

Step 3

Exam Tip

सबसे बड़ी घात \(z^5\) के पद का गुणांक (-6) है। अग्र गुणांक संकेत सहित लिखा जाता है।

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निम्न में से किस बहुपद में प्रमुख गुणांक (1) नहीं है?

Which of the following polynomials does not have leading coefficient (1)?

Explanation opens after your attempt
Correct Answer

C. \(3x^2+x+1\)

Step 1

Concept

The leading term of \(3x^2+x+1\) is \(3x^2\). Its leading coefficient is (3), not (1).

Step 2

Why this answer is correct

The correct answer is C. \(3x^2+x+1\). The leading term of \(3x^2+x+1\) is \(3x^2\). Its leading coefficient is (3), not (1).

Step 3

Exam Tip

\(3x^2+x+1\) का प्रमुख पद \(3x^2\) है। इसका प्रमुख गुणांक (3) है, (1) नहीं।

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बहुपद \(3x^4-5x^2+2x-8\) का प्रमुख गुणांक क्या है?

What is the leading coefficient of \(3x^4-5x^2+2x-8\)?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

The leading term is \(3x^4\). Therefore the leading coefficient is (3).

Step 2

Why this answer is correct

The correct answer is A. (3). The leading term is \(3x^4\). Therefore the leading coefficient is (3).

Step 3

Exam Tip

प्रमुख पद \(3x^4\) है। इसलिए प्रमुख गुणांक (3) है।

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निम्न में से किस बहुपद का प्रमुख गुणांक (-2) है?

Which polynomial has leading coefficient (-2)?

Explanation opens after your attempt
Correct Answer

B. \(-2x^3+4x+7\)

Step 1

Concept

The leading term of \(-2x^3+4x+7\) is \(-2x^3\). So the leading coefficient is (-2).

Step 2

Why this answer is correct

The correct answer is B. \(-2x^3+4x+7\). The leading term of \(-2x^3+4x+7\) is \(-2x^3\). So the leading coefficient is (-2).

Step 3

Exam Tip

\(-2x^3+4x+7\) का प्रमुख पद \(-2x^3\) है। इसलिए प्रमुख गुणांक (-2) है।

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बहुपद (p(y)=9y-4-y-2+5y-6) का अग्र गुणांक क्या है?

What is the leading coefficient of (p(y)=9y-4-y-2+5y-6)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

The coefficient of the highest power term \(y^4\) is (9). That is the leading coefficient.

Step 2

Why this answer is correct

The correct answer is A. (9). The coefficient of the highest power term \(y^4\) is (9). That is the leading coefficient.

Step 3

Exam Tip

सबसे बड़ी घात \(y^4\) के पद का गुणांक (9) है। अग्र गुणांक वही होता है।

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\(3x^2-5x+7\) में प्रमुख गुणांक क्या है?

What is the leading coefficient of \(3x^2-5x+7\)?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

The leading term is \(3x^2\), so the leading coefficient is (3). The coefficient of the highest degree term is the leading coefficient.

Step 2

Why this answer is correct

The correct answer is A. (3). The leading term is \(3x^2\), so the leading coefficient is (3). The coefficient of the highest degree term is the leading coefficient.

Step 3

Exam Tip

प्रमुख पद \(3x^2\) है इसलिए प्रमुख गुणांक (3) है। सबसे बड़ी घात वाले पद का गुणांक प्रमुख गुणांक कहलाता है।

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बहुपद \(2x^2-7x+1\) में अग्र गुणांक क्या है?

What is the leading coefficient of \(2x^2-7x+1\)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

The coefficient of the highest-degree term \(2x^2\) is (2). This is called the leading coefficient.

Step 2

Why this answer is correct

The correct answer is A. (2). The coefficient of the highest-degree term \(2x^2\) is (2). This is called the leading coefficient.

Step 3

Exam Tip

सबसे बड़ी घात वाले पद \(2x^2\) का गुणांक (2) है। इसी को अग्र गुणांक कहते हैं।

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बहुपद \(6x^5+x^2-4\) का अग्र गुणांक क्या है?

What is the leading coefficient of \(6x^5+x^2-4\)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

The term with the highest power is \(6x^5\). So the leading coefficient is (6).

Step 2

Why this answer is correct

The correct answer is A. (6). The term with the highest power is \(6x^5\). So the leading coefficient is (6).

Step 3

Exam Tip

सबसे बड़ी घात वाला पद \(6x^5\) है। इसलिए अग्र गुणांक (6) है।

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समीकरण \(kx^2-6x+k=0\) के वास्तविक और भिन्न मूलों के लिए सही शर्त क्या है?

What is the correct condition for real and distinct roots of \(kx^2-6x+k=0\)?

Explanation opens after your attempt
Correct Answer

A. \(k^2<9\) और \(k\neq0\)\(k^2<9\) and \(k\neq0\)

Step 1

Concept

Here \(D=36-4k^2\). For real and distinct roots (D>0) and \(k\neq0\), hence \(k^2<9\).

Step 2

Why this answer is correct

The correct answer is A. \(k^2<9\) और \(k\neq0\) / \(k^2<9\) and \(k\neq0\). Here \(D=36-4k^2\). For real and distinct roots (D>0) and \(k\neq0\), hence \(k^2<9\).

Step 3

Exam Tip

यहाँ \(D=36-4k^2\) है। वास्तविक और भिन्न मूलों के लिए (D>0) और \(k\neq0\), अतः \(k^2<9\)।

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यदि किसी द्विघात समीकरण की जड़ें (3) और (-2) हैं और \(x^2\) का गुणांक (2) है, तो समीकरण कौन-सा है?

If the roots of a quadratic equation are (3) and (-2), and the coefficient of \(x^2\) is (2), which is the equation?

Explanation opens after your attempt
Correct Answer

A. \(2x^2-2x-12=0\)

Step 1

Concept

The monic equation is \(x^2-x-6=0\). Since the coefficient of \(x^2\) must be (2), multiply the whole equation by (2).

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-2x-12=0\). The monic equation is \(x^2-x-6=0\). Since the coefficient of \(x^2\) must be (2), multiply the whole equation by (2).

Step 3

Exam Tip

मॉनिक समीकरण \(x^2-x-6=0\) है। \(x^2\) का गुणांक (2) चाहिए, इसलिए पूरे समीकरण को (2) से गुणा करें।

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यदि (x=4) समीकरण \(ax^2-10x+8=0\) का मूल है तो (a) का मान क्या है?

If (x=4) is a root of \(ax^2-10x+8=0\), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Putting (x=4) gives (16a-40+8=0), so (16a=32) and (a=2). Substitute when a coefficient is unknown.

Step 2

Why this answer is correct

The correct answer is A. (2). Putting (x=4) gives (16a-40+8=0), so (16a=32) and (a=2). Substitute when a coefficient is unknown.

Step 3

Exam Tip

(x=4) रखने पर (16a-40+8=0) इसलिए (16a=32) और (a=2)। अज्ञात गुणांक में प्रतिस्थापन करें।

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यदि (x=3) समीकरण \(ax^2-8x+6=0\) का मूल है तो (a) का मान क्या है?

If (x=3) is a root of \(ax^2-8x+6=0\), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Putting (x=3) gives (9a-24+6=0), so (9a=18) and (a=2). Substitute in questions with an unknown coefficient.

Step 2

Why this answer is correct

The correct answer is A. (2). Putting (x=3) gives (9a-24+6=0), so (9a=18) and (a=2). Substitute in questions with an unknown coefficient.

Step 3

Exam Tip

(x=3) रखने पर (9a-24+6=0) इसलिए (9a=18) और (a=2)। अज्ञात गुणांक वाले प्रश्न में प्रतिस्थापन करें।

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यदि (x=2) समीकरण \(ax^2-5x+2=0\) का मूल है तो (a) का मान क्या है?

If (x=2) is a root of \(ax^2-5x+2=0\), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Putting (x=2) gives (4a-10+2=0), so (4a=8) and (a=2). Substitute in questions with an unknown coefficient.

Step 2

Why this answer is correct

The correct answer is A. (2). Putting (x=2) gives (4a-10+2=0), so (4a=8) and (a=2). Substitute in questions with an unknown coefficient.

Step 3

Exam Tip

(x=2) रखने पर (4a-10+2=0) इसलिए (4a=8) और (a=2)। अज्ञात गुणांक वाले प्रश्न में प्रतिस्थापन करें।

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समीकरण ((k-1)x-2+3x+2=0) द्विघात रहे इसके लिए कौन सी शर्त सही है?

Which condition is correct for ((k-1)x-2+3x+2=0) to remain quadratic?

Explanation opens after your attempt
Correct Answer

B. \(k\neq1\)

Step 1

Concept

The coefficient of the quadratic term is ((k-1)), which must not be (0). Hence \(k\neq1\) is necessary.

Step 2

Why this answer is correct

The correct answer is B. \(k\neq1\). The coefficient of the quadratic term is ((k-1)), which must not be (0). Hence \(k\neq1\) is necessary.

Step 3

Exam Tip

द्विघात पद का गुणांक ((k-1)) है जो (0) नहीं होना चाहिए। इसलिए \(k\neq1\) होना जरूरी है।

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किस शर्त पर \(px^2+qx+r=0\) द्विघात समीकरण होगा?

Under which condition will \(px^2+qx+r=0\) be a quadratic equation?

Explanation opens after your attempt
Correct Answer

B. \(p\neq0\)

Step 1

Concept

The quadratic term \(px^2\) must remain, so \(p\neq0\). If (p=0), degree (2) will not remain.

Step 2

Why this answer is correct

The correct answer is B. \(p\neq0\). The quadratic term \(px^2\) must remain, so \(p\neq0\). If (p=0), degree (2) will not remain.

Step 3

Exam Tip

द्विघात पद \(px^2\) बना रहे इसलिए \(p\neq0\) होना चाहिए। यदि (p=0) हो तो घात (2) नहीं रहेगी।

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