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real distinct roots MCQ Questions for Class 10

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Practice Questions

16 questions tagged with real distinct roots.

समीकरण ((p+4)x-2-2(p+1)x+(p-2)=0) के मूलों के बारे में सही कथन क्या है, यदि \(p\neq-4\)?

What is the correct statement about the roots of ((p+4)x-2-2(p+1)x+(p-2)=0), if \(p\neq-4\)?

Explanation opens after your attempt
Correct Answer

A. हमेशा वास्तविक और भिन्नAlways real and distinct

Step 1

Concept

Here (D=4(p+1)2-4(p+4)(p-2)=36>0). Since \(p\neq-4\), the equation remains quadratic and roots are distinct.

Step 2

Why this answer is correct

The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=4(p+1)2-4(p+4)(p-2)=36>0). Since \(p\neq-4\), the equation remains quadratic and roots are distinct.

Step 3

Exam Tip

यहाँ (D=4(p+1)2-4(p+4)(p-2)=36>0) है। \(p\neq-4\) से समीकरण द्विघात रहता है और मूल भिन्न होते हैं।

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समीकरण (x-2-2(a-5)x+a-2-10a+21=0) के मूलों की प्रकृति क्या है?

What is the nature of roots of (x-2-2(a-5)x+a-2-10a+21=0)?

Explanation opens after your attempt
Correct Answer

A. हमेशा वास्तविक और भिन्नAlways real and distinct

Step 1

Concept

Here (D=4(a-5)2-4\(a^2-10a+21\)=16>0). Therefore the roots are real and distinct for every real (a).

Step 2

Why this answer is correct

The correct answer is A. हमेशा वास्तविक और भिन्न / Always real and distinct. Here (D=4(a-5)2-4\(a^2-10a+21\)=16>0). Therefore the roots are real and distinct for every real (a).

Step 3

Exam Tip

यहाँ (D=4(a-5)2-4\(a^2-10a+21\)=16>0) है। इसलिए हर वास्तविक (a) के लिए मूल वास्तविक और भिन्न हैं।

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यदि \(a\neq b\), तो (x-2-2(a+b)x+4ab=0) के मूलों की प्रकृति क्या होगी?

If \(a\neq b\), what will be the nature of roots of (x-2-2(a+b)x+4ab=0)?

Explanation opens after your attempt
Correct Answer

A. वास्तविक और भिन्नReal and distinct

Step 1

Concept

Here (D=4(a-b)2). When \(a\neq b\), (D>0), so roots are real and distinct.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक और भिन्न / Real and distinct. Here (D=4(a-b)2). When \(a\neq b\), (D>0), so roots are real and distinct.

Step 3

Exam Tip

यहाँ (D=4(a-b)2) है। \(a\neq b\) होने पर (D>0), इसलिए मूल वास्तविक और भिन्न होंगे।

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समीकरण (x-2-2(m-4)x+m-2-16=0) के मूल वास्तविक और भिन्न कब होंगे?

When will the roots of (x-2-2(m-4)x+m-2-16=0) be real and distinct?

Explanation opens after your attempt
Correct Answer

A. (m<4)

Step 1

Concept

Here (D=32(4-m)). For real and distinct roots (D>0), so (m<4).

Step 2

Why this answer is correct

The correct answer is A. (m<4). Here (D=32(4-m)). For real and distinct roots (D>0), so (m<4).

Step 3

Exam Tip

यहाँ (D=32(4-m)) है। वास्तविक और भिन्न मूलों के लिए (D>0), इसलिए (m<4)।

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निम्न में से किस समीकरण के दो वास्तविक और असमान मूल हैं?

Which of the following equations has two real and distinct roots?

Explanation opens after your attempt
Correct Answer

A. \(x^2-11x+18=0\)

Step 1

Concept

In option (A), (D=(-11)2-4(1)(18)=49). When (D>0), two distinct real roots exist.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-11x+18=0\). In option (A), (D=(-11)2-4(1)(18)=49). When (D>0), two distinct real roots exist.

Step 3

Exam Tip

विकल्प (A) में (D=(-11)2-4(1)(18)=49) है। (D>0) होने पर दो असमान वास्तविक मूल मिलते हैं।

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समीकरण \(x^2-2mx+3m=0\) के वास्तविक और भिन्न मूलों के लिए (m) पर क्या शर्त है?

What condition on (m) gives real and distinct roots for \(x^2-2mx+3m=0\)?

Explanation opens after your attempt
Correct Answer

A. (m<0) या (m>3)(m<0) or (m>3)

Step 1

Concept

Here (D=4m(m-3)). From (D>0), (m<0) or (m>3).

Step 2

Why this answer is correct

The correct answer is A. (m<0) या (m>3) / (m<0) or (m>3). Here (D=4m(m-3)). From (D>0), (m<0) or (m>3).

Step 3

Exam Tip

यहाँ (D=4m(m-3)) है। (D>0) से (m<0) या (m>3) मिलता है।

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यदि (x-2-2\(\alpha+2\)x+\alpha-2=0) के मूल वास्तविक और भिन्न हैं, तो \(\alpha\) पर शर्त क्या है?

If (x-2-2\(\alpha+2\)x+\alpha-2=0) has real and distinct roots, what is the condition on \(\alpha\)?

Explanation opens after your attempt
Correct Answer

A. \(\alpha>-1\)

Step 1

Concept

(D=4\(\alpha+2\)2-4\alpha-2=16\(\alpha+1\)). From (D>0), \(\alpha>-1\).

Step 2

Why this answer is correct

The correct answer is A. \(\alpha>-1\). (D=4\(\alpha+2\)2-4\alpha-2=16\(\alpha+1\)). From (D>0), \(\alpha>-1\).

Step 3

Exam Tip

(D=4\(\alpha+2\)2-4\alpha-2=16\(\alpha+1\)) है। (D>0) से \(\alpha>-1\) मिलता है।

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किस शर्त पर \(x^2-2sx+s+2=0\) के मूल वास्तविक और भिन्न होंगे?

Under which condition will \(x^2-2sx+s+2=0\) have real and distinct roots?

Explanation opens after your attempt
Correct Answer

A. (s<-1) या (s>2)(s<-1) or (s>2)

Step 1

Concept

Here (D=4s-2-4(s+2)=4(s-2)(s+1)). From (D>0), (s<-1) or (s>2).

Step 2

Why this answer is correct

The correct answer is A. (s<-1) या (s>2) / (s<-1) or (s>2). Here (D=4s-2-4(s+2)=4(s-2)(s+1)). From (D>0), (s<-1) or (s>2).

Step 3

Exam Tip

यहाँ (D=4s-2-4(s+2)=4(s-2)(s+1)) है। (D>0) से (s<-1) या (s>2) मिलता है।

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समीकरण \(kx^2-6x+k=0\) के वास्तविक और भिन्न मूलों के लिए सही शर्त क्या है?

What is the correct condition for real and distinct roots of \(kx^2-6x+k=0\)?

Explanation opens after your attempt
Correct Answer

A. \(k^2<9\) और \(k\neq0\)\(k^2<9\) and \(k\neq0\)

Step 1

Concept

Here \(D=36-4k^2\). For real and distinct roots (D>0) and \(k\neq0\), hence \(k^2<9\).

Step 2

Why this answer is correct

The correct answer is A. \(k^2<9\) और \(k\neq0\) / \(k^2<9\) and \(k\neq0\). Here \(D=36-4k^2\). For real and distinct roots (D>0) and \(k\neq0\), hence \(k^2<9\).

Step 3

Exam Tip

यहाँ \(D=36-4k^2\) है। वास्तविक और भिन्न मूलों के लिए (D>0) और \(k\neq0\), अतः \(k^2<9\)।

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समीकरण (x-2-2(k+1)x+k-2=0) के मूल वास्तविक और भिन्न कब होंगे?

When will the roots of (x-2-2(k+1)x+k-2=0) be real and distinct?

Explanation opens after your attempt
Correct Answer

A. \(k>-\frac{1}{2}\)

Step 1

Concept

Here (D=4(k+1)2-4k-2=4(2k+1)). For distinct real roots (D>0), so \(k>-\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(k>-\frac{1}{2}\). Here (D=4(k+1)2-4k-2=4(2k+1)). For distinct real roots (D>0), so \(k>-\frac{1}{2}\).

Step 3

Exam Tip

यहाँ (D=4(k+1)2-4k-2=4(2k+1)) है। भिन्न वास्तविक मूलों के लिए (D>0), इसलिए \(k>-\frac{1}{2}\)।

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समीकरण \(x^2-2x-3=0\) के मूल कैसे होंगे?

How will the roots of \(x^2-2x-3=0\) be?

Explanation opens after your attempt
Correct Answer

A. दो वास्तविक और असमान ((D=16))Two real and distinct ((D=16))

Step 1

Concept

Here (D=(-2)2-4(1)(-3)=16). A positive perfect-square (D) gives two rational distinct roots.

Step 2

Why this answer is correct

The correct answer is A. दो वास्तविक और असमान ((D=16)) / Two real and distinct ((D=16)). Here (D=(-2)2-4(1)(-3)=16). A positive perfect-square (D) gives two rational distinct roots.

Step 3

Exam Tip

यहाँ (D=(-2)2-4(1)(-3)=16) है। धनात्मक पूर्ण वर्ग (D) से दो परिमेय असमान मूल मिलते हैं।

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यदि \(x^2+px+6=0\) के मूल वास्तविक और भिन्न हैं तो (p) के लिए कौन सी शर्त सही है?

If the roots of \(x^2+px+6=0\) are real and distinct, which condition is correct for (p)?

Explanation opens after your attempt
Correct Answer

A. \(p^2>24\)

Step 1

Concept

For real and distinct roots (D>0). So \(p^2-24>0\), that is \(p^2>24\).

Step 2

Why this answer is correct

The correct answer is A. \(p^2>24\). For real and distinct roots (D>0). So \(p^2-24>0\), that is \(p^2>24\).

Step 3

Exam Tip

वास्तविक और भिन्न मूलों के लिए (D>0) होता है। इसलिए \(p^2-24>0\), अर्थात \(p^2>24\)।

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यदि \(x^2+px+4=0\) के मूल वास्तविक और भिन्न हैं तो (p) के लिए सही शर्त क्या है?

If the roots of \(x^2+px+4=0\) are real and distinct, what is the correct condition for (p)?

Explanation opens after your attempt
Correct Answer

A. \(p^2>16\)

Step 1

Concept

For real and distinct roots (D>0), so \(p^2-16>0\). Therefore \(p^2>16\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(p^2>16\). For real and distinct roots (D>0), so \(p^2-16>0\). Therefore \(p^2>16\) is correct.

Step 3

Exam Tip

वास्तविक और भिन्न मूलों के लिए (D>0) होता है इसलिए \(p^2-16>0\)। अतः \(p^2>16\) सही है।

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समीकरण \(x^2+7x+10=0\) की प्रकृति क्या होगी?

What will be the nature of the equation \(x^2+7x+10=0\)?

Explanation opens after your attempt
Correct Answer

A. दो वास्तविक और भिन्न मूलTwo real and distinct roots

Step 1

Concept

Since (D=9>0), two real and distinct roots are obtained. (D>0) means two different real roots.

Step 2

Why this answer is correct

The correct answer is A. दो वास्तविक और भिन्न मूल / Two real and distinct roots. Since (D=9>0), two real and distinct roots are obtained. (D>0) means two different real roots.

Step 3

Exam Tip

(D=9>0) होने से दो वास्तविक और भिन्न मूल मिलेंगे। (D>0) का अर्थ दो अलग वास्तविक मूल है।

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समीकरण \(x^2-2x-3=0\) के मूलों की प्रकृति क्या है?

What is the nature of roots of the equation \(x^2-2x-3=0\)?

Explanation opens after your attempt
Correct Answer

A. वास्तविक और भिन्नReal and distinct

Step 1

Concept

Since (D=16>0), the roots are real and distinct. Positive (D) always gives distinct real roots.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक और भिन्न / Real and distinct. Since (D=16>0), the roots are real and distinct. Positive (D) always gives distinct real roots.

Step 3

Exam Tip

(D=16>0) है इसलिए मूल वास्तविक और भिन्न हैं। धनात्मक (D) हमेशा भिन्न वास्तविक मूल देता है।

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यदि किसी द्विघात समीकरण में \(b^2-4ac=9\) है तो मूलों की प्रकृति क्या होगी?

If \(b^2-4ac=9\) in a quadratic equation, what will be the nature of roots?

Explanation opens after your attempt
Correct Answer

A. वास्तविक और भिन्नReal and distinct

Step 1

Concept

Since (9>0), we have (D>0). Therefore the roots are real and distinct.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक और भिन्न / Real and distinct. Since (9>0), we have (D>0). Therefore the roots are real and distinct.

Step 3

Exam Tip

क्योंकि (9>0) है इसलिए (D>0) होगा। अतः मूल वास्तविक और भिन्न होंगे।

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